query_id
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stringlengths 16
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stringlengths 18
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|---|---|---|---|---|---|
5,100 | cre_Drama_Workshop_Groups | [
"INVOICES"
] | What are the minimum, average, and maximum quantities ordered? Check all the invoices. | SELECT min(Order_Quantity) , avg(Order_Quantity) , max(Order_Quantity) FROM INVOICES | medium |
5,101 | cre_Drama_Workshop_Groups | [
"INVOICES"
] | What are the distinct payment method codes in all the invoices? | SELECT DISTINCT payment_method_code FROM INVOICES | easy |
5,102 | cre_Drama_Workshop_Groups | [
"INVOICES"
] | Show me the distinct payment method codes from the invoice record. | SELECT DISTINCT payment_method_code FROM INVOICES | easy |
5,103 | cre_Drama_Workshop_Groups | [
"Marketing_Regions"
] | What is the description of the marketing region China? | SELECT Marketing_Region_Descriptrion FROM Marketing_Regions WHERE Marketing_Region_Name = "China" | easy |
5,104 | cre_Drama_Workshop_Groups | [
"Marketing_Regions"
] | Find the marketing region description of China? | SELECT Marketing_Region_Descriptrion FROM Marketing_Regions WHERE Marketing_Region_Name = "China" | easy |
5,105 | cre_Drama_Workshop_Groups | [
"PRODUCTS"
] | Show all the distinct product names with price higher than the average. | SELECT DISTINCT Product_Name FROM PRODUCTS WHERE Product_Price > (SELECT avg(Product_Price) FROM PRODUCTS) | hard |
5,106 | cre_Drama_Workshop_Groups | [
"PRODUCTS"
] | What are the distinct names of the products that cost more than the average? | SELECT DISTINCT Product_Name FROM PRODUCTS WHERE Product_Price > (SELECT avg(Product_Price) FROM PRODUCTS) | hard |
5,107 | cre_Drama_Workshop_Groups | [
"PRODUCTS"
] | What is the name of the most expensive product? | SELECT Product_Name FROM PRODUCTS ORDER BY Product_Price DESC LIMIT 1 | medium |
5,108 | cre_Drama_Workshop_Groups | [
"PRODUCTS"
] | Tell me the name of the most pricy product. | SELECT Product_Name FROM PRODUCTS ORDER BY Product_Price DESC LIMIT 1 | medium |
5,109 | cre_Drama_Workshop_Groups | [
"Products"
] | List all product names in ascending order of price. | SELECT Product_Name FROM Products ORDER BY Product_Price ASC | easy |
5,110 | cre_Drama_Workshop_Groups | [
"Products"
] | Sort the names of products in ascending order of their price. | SELECT Product_Name FROM Products ORDER BY Product_Price ASC | easy |
5,111 | cre_Drama_Workshop_Groups | [
"PERFORMERS"
] | What is the phone number of the performer Ashley? | SELECT Customer_Phone FROM PERFORMERS WHERE Customer_Name = "Ashley" | easy |
5,112 | cre_Drama_Workshop_Groups | [
"PERFORMERS"
] | Find the phone number of performer "Ashley". | SELECT Customer_Phone FROM PERFORMERS WHERE Customer_Name = "Ashley" | easy |
5,113 | cre_Drama_Workshop_Groups | [
"INVOICES"
] | Show all payment method codes and the number of orders for each code. | SELECT payment_method_code , count(*) FROM INVOICES GROUP BY payment_method_code | medium |
5,114 | cre_Drama_Workshop_Groups | [
"INVOICES"
] | List the distinct payment method codes with the number of orders made | SELECT payment_method_code , count(*) FROM INVOICES GROUP BY payment_method_code | medium |
5,115 | cre_Drama_Workshop_Groups | [
"INVOICES"
] | What is the payment method code used by the most orders? | SELECT payment_method_code FROM INVOICES GROUP BY payment_method_code ORDER BY count(*) DESC LIMIT 1 | hard |
5,116 | cre_Drama_Workshop_Groups | [
"INVOICES"
] | Find the payment method that is used the most often in all the invoices. Give me its code. | SELECT payment_method_code FROM INVOICES GROUP BY payment_method_code ORDER BY count(*) DESC LIMIT 1 | hard |
5,117 | cre_Drama_Workshop_Groups | [
"Addresses",
"Stores"
] | Which city is the address of the store named "FJA Filming" located in? | SELECT T1.City_Town FROM Addresses AS T1 JOIN Stores AS T2 ON T1.Address_ID = T2.Address_ID WHERE T2.Store_Name = "FJA Filming" | medium |
5,118 | cre_Drama_Workshop_Groups | [
"Addresses",
"Stores"
] | Find the city the store named "FJA Filming" is in. | SELECT T1.City_Town FROM Addresses AS T1 JOIN Stores AS T2 ON T1.Address_ID = T2.Address_ID WHERE T2.Store_Name = "FJA Filming" | medium |
5,119 | cre_Drama_Workshop_Groups | [
"Addresses",
"Stores"
] | What are the states or counties of the address of the stores with marketing region code "CA"? | SELECT T1.State_County FROM Addresses AS T1 JOIN Stores AS T2 ON T1.Address_ID = T2.Address_ID WHERE T2.Marketing_Region_Code = "CA" | medium |
5,120 | cre_Drama_Workshop_Groups | [
"Addresses",
"Stores"
] | Find the states or counties where the stores with marketing region code "CA" are located. | SELECT T1.State_County FROM Addresses AS T1 JOIN Stores AS T2 ON T1.Address_ID = T2.Address_ID WHERE T2.Marketing_Region_Code = "CA" | medium |
5,121 | cre_Drama_Workshop_Groups | [
"Marketing_Regions",
"Stores"
] | What is the name of the marketing region that the store Rob Dinning belongs to? | SELECT T1.Marketing_Region_Name FROM Marketing_Regions AS T1 JOIN Stores AS T2 ON T1.Marketing_Region_Code = T2.Marketing_Region_Code WHERE T2.Store_Name = "Rob Dinning" | medium |
5,122 | cre_Drama_Workshop_Groups | [
"Marketing_Regions",
"Stores"
] | Return the name of the marketing region the store Rob Dinning is located in. | SELECT T1.Marketing_Region_Name FROM Marketing_Regions AS T1 JOIN Stores AS T2 ON T1.Marketing_Region_Code = T2.Marketing_Region_Code WHERE T2.Store_Name = "Rob Dinning" | medium |
5,123 | cre_Drama_Workshop_Groups | [
"Ref_Service_Types",
"Services"
] | What are the descriptions of the service types with product price above 100? | SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Price > 100 | medium |
5,124 | cre_Drama_Workshop_Groups | [
"Ref_Service_Types",
"Services"
] | Give me the descriptions of the service types that cost more than 100. | SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Price > 100 | medium |
5,125 | cre_Drama_Workshop_Groups | [
"Ref_Service_Types",
"Services"
] | What is the description, code and the corresponding count of each service type? | SELECT T1.Service_Type_Description , T2.Service_Type_Code , COUNT(*) FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code GROUP BY T2.Service_Type_Code | medium |
5,126 | cre_Drama_Workshop_Groups | [
"Ref_Service_Types",
"Services"
] | List the description, code and the number of services for each service type. | SELECT T1.Service_Type_Description , T2.Service_Type_Code , COUNT(*) FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code GROUP BY T2.Service_Type_Code | medium |
5,127 | cre_Drama_Workshop_Groups | [
"Ref_Service_Types",
"Services"
] | What is the description and code of the type of service that is performed the most often? | SELECT T1.Service_Type_Description , T1.Service_Type_Code FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code GROUP BY T1.Service_Type_Code ORDER BY COUNT(*) DESC LIMIT 1 | extra |
5,128 | cre_Drama_Workshop_Groups | [
"Ref_Service_Types",
"Services"
] | Find the description and code of the service type that is performed the most times. | SELECT T1.Service_Type_Description , T1.Service_Type_Code FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code GROUP BY T1.Service_Type_Code ORDER BY COUNT(*) DESC LIMIT 1 | extra |
5,129 | cre_Drama_Workshop_Groups | [
"Services",
"Drama_Workshop_Groups"
] | What are the phones and emails of workshop groups in which services are performed? | SELECT T1.Store_Phone , T1.Store_Email_Address FROM Drama_Workshop_Groups AS T1 JOIN Services AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID | medium |
5,130 | cre_Drama_Workshop_Groups | [
"Services",
"Drama_Workshop_Groups"
] | Give me all the phone numbers and email addresses of the workshop groups where services are performed. | SELECT T1.Store_Phone , T1.Store_Email_Address FROM Drama_Workshop_Groups AS T1 JOIN Services AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID | medium |
5,131 | cre_Drama_Workshop_Groups | [
"Services",
"Drama_Workshop_Groups"
] | What are the names of workshop groups in which services with product name "film" are performed? | SELECT T1.Store_Phone , T1.Store_Email_Address FROM Drama_Workshop_Groups AS T1 JOIN Services AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T2.Product_Name = "film" | medium |
5,132 | cre_Drama_Workshop_Groups | [
"Services",
"Drama_Workshop_Groups"
] | Find the names of the workshop groups where services with product name "film" are performed. | SELECT T1.Store_Phone , T1.Store_Email_Address FROM Drama_Workshop_Groups AS T1 JOIN Services AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T2.Product_Name = "film" | medium |
5,133 | cre_Drama_Workshop_Groups | [
"PRODUCTS"
] | What are the different product names? What is the average product price for each of them? | SELECT Product_Name , avg(Product_Price) FROM PRODUCTS GROUP BY Product_Name | medium |
5,134 | cre_Drama_Workshop_Groups | [
"PRODUCTS"
] | For each distinct product name, show its average product price. | SELECT Product_Name , avg(Product_Price) FROM PRODUCTS GROUP BY Product_Name | medium |
5,135 | cre_Drama_Workshop_Groups | [
"PRODUCTS"
] | What are the product names with average product price smaller than 1000000? | SELECT Product_Name FROM PRODUCTS GROUP BY Product_Name HAVING avg(Product_Price) < 1000000 | easy |
5,136 | cre_Drama_Workshop_Groups | [
"PRODUCTS"
] | Find the product names whose average product price is below 1000000. | SELECT Product_Name FROM PRODUCTS GROUP BY Product_Name HAVING avg(Product_Price) < 1000000 | easy |
5,137 | cre_Drama_Workshop_Groups | [
"ORDER_ITEMS",
"Products"
] | What are the total order quantities of photo products? | SELECT sum(T1.Order_Quantity) FROM ORDER_ITEMS AS T1 JOIN Products AS T2 ON T1.Product_ID = T2.Product_ID WHERE T2.Product_Name = "photo" | medium |
5,138 | cre_Drama_Workshop_Groups | [
"ORDER_ITEMS",
"Products"
] | Compute the total order quantities of the product "photo". | SELECT sum(T1.Order_Quantity) FROM ORDER_ITEMS AS T1 JOIN Products AS T2 ON T1.Product_ID = T2.Product_ID WHERE T2.Product_Name = "photo" | medium |
5,139 | cre_Drama_Workshop_Groups | [
"ORDER_ITEMS",
"Products"
] | What are the order details of the products with price higher than 2000? | SELECT T1.Other_Item_Details FROM ORDER_ITEMS AS T1 JOIN Products AS T2 ON T1.Product_ID = T2.Product_ID WHERE T2.Product_price > 2000 | medium |
5,140 | cre_Drama_Workshop_Groups | [
"ORDER_ITEMS",
"Products"
] | Find the order detail for the products with price above 2000. | SELECT T1.Other_Item_Details FROM ORDER_ITEMS AS T1 JOIN Products AS T2 ON T1.Product_ID = T2.Product_ID WHERE T2.Product_price > 2000 | medium |
5,141 | cre_Drama_Workshop_Groups | [
"ORDER_ITEMS",
"Customer_Orders"
] | What are the actual delivery dates of orders with quantity 1? | SELECT T1.Actual_Delivery_Date FROM Customer_Orders AS T1 JOIN ORDER_ITEMS AS T2 ON T1.Order_ID = T2.Order_ID WHERE T2.Order_Quantity = 1 | medium |
5,142 | cre_Drama_Workshop_Groups | [
"ORDER_ITEMS",
"Customer_Orders"
] | List the actual delivery date for all the orders with quantity 1 | SELECT T1.Actual_Delivery_Date FROM Customer_Orders AS T1 JOIN ORDER_ITEMS AS T2 ON T1.Order_ID = T2.Order_ID WHERE T2.Order_Quantity = 1 | medium |
5,143 | cre_Drama_Workshop_Groups | [
"ORDER_ITEMS",
"Products",
"Customer_Orders"
] | What are the order dates of orders with price higher than 1000? | SELECT T1.Order_Date FROM Customer_Orders AS T1 JOIN ORDER_ITEMS AS T2 ON T1.Order_ID = T2.Order_ID JOIN Products AS T3 ON T2.Product_ID = T3.Product_ID WHERE T3.Product_price > 1000 | hard |
5,144 | cre_Drama_Workshop_Groups | [
"ORDER_ITEMS",
"Products",
"Customer_Orders"
] | Find the order dates of the orders with price above 1000. | SELECT T1.Order_Date FROM Customer_Orders AS T1 JOIN ORDER_ITEMS AS T2 ON T1.Order_ID = T2.Order_ID JOIN Products AS T3 ON T2.Product_ID = T3.Product_ID WHERE T3.Product_price > 1000 | hard |
5,145 | cre_Drama_Workshop_Groups | [
"Drama_Workshop_Groups"
] | How many distinct currency codes are there for all drama workshop groups? | SELECT count(DISTINCT Currency_Code) FROM Drama_Workshop_Groups | easy |
5,146 | cre_Drama_Workshop_Groups | [
"Drama_Workshop_Groups"
] | Find the number of distinct currency codes used in drama workshop groups. | SELECT count(DISTINCT Currency_Code) FROM Drama_Workshop_Groups | easy |
5,147 | cre_Drama_Workshop_Groups | [
"Addresses",
"Drama_Workshop_Groups"
] | What are the names of the drama workshop groups with address in Feliciaberg city? | SELECT T2.Store_Name FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID WHERE T1.City_Town = "Feliciaberg" | medium |
5,148 | cre_Drama_Workshop_Groups | [
"Addresses",
"Drama_Workshop_Groups"
] | Return the the names of the drama workshop groups that are located in Feliciaberg city. | SELECT T2.Store_Name FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID WHERE T1.City_Town = "Feliciaberg" | medium |
5,149 | cre_Drama_Workshop_Groups | [
"Addresses",
"Drama_Workshop_Groups"
] | What are the email addresses of the drama workshop groups with address in Alaska state? | SELECT T2.Store_Email_Address FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID WHERE T1.State_County = "Alaska" | medium |
5,150 | cre_Drama_Workshop_Groups | [
"Addresses",
"Drama_Workshop_Groups"
] | List the email addresses of the drama workshop groups located in Alaska state. | SELECT T2.Store_Email_Address FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID WHERE T1.State_County = "Alaska" | medium |
5,151 | cre_Drama_Workshop_Groups | [
"Addresses",
"Drama_Workshop_Groups"
] | Show all cities along with the number of drama workshop groups in each city. | SELECT T1.City_Town , count(*) FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID GROUP BY T1.City_Town | medium |
5,152 | cre_Drama_Workshop_Groups | [
"Addresses",
"Drama_Workshop_Groups"
] | How many drama workshop groups are there in each city? Return both the city and the count. | SELECT T1.City_Town , count(*) FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID GROUP BY T1.City_Town | medium |
5,153 | cre_Drama_Workshop_Groups | [
"Drama_Workshop_Groups"
] | What is the marketing region code that has the most drama workshop groups? | SELECT Marketing_Region_Code FROM Drama_Workshop_Groups GROUP BY Marketing_Region_Code ORDER BY count(*) DESC LIMIT 1 | hard |
5,154 | cre_Drama_Workshop_Groups | [
"Drama_Workshop_Groups"
] | Which marketing region has the most drama workshop groups? Give me the region code. | SELECT Marketing_Region_Code FROM Drama_Workshop_Groups GROUP BY Marketing_Region_Code ORDER BY count(*) DESC LIMIT 1 | hard |
5,155 | cre_Drama_Workshop_Groups | [
"Addresses",
"Performers",
"Customers"
] | Show all cities where at least one customer lives in but no performer lives in. | SELECT T1.City_Town FROM Addresses AS T1 JOIN Customers AS T2 ON T1.Address_ID = T2.Address_ID EXCEPT SELECT T1.City_Town FROM Addresses AS T1 JOIN Performers AS T2 ON T1.Address_ID = T2.Address_ID | hard |
5,156 | cre_Drama_Workshop_Groups | [
"Addresses",
"Performers",
"Customers"
] | Which cities have at least one customer but no performer? | SELECT T1.City_Town FROM Addresses AS T1 JOIN Customers AS T2 ON T1.Address_ID = T2.Address_ID EXCEPT SELECT T1.City_Town FROM Addresses AS T1 JOIN Performers AS T2 ON T1.Address_ID = T2.Address_ID | hard |
5,157 | cre_Drama_Workshop_Groups | [
"BOOKINGS"
] | What is the most frequent status of bookings? | SELECT Status_Code FROM BOOKINGS GROUP BY Status_Code ORDER BY count(*) DESC LIMIT 1 | hard |
5,158 | cre_Drama_Workshop_Groups | [
"BOOKINGS"
] | Which status code is the most common of all the bookings? | SELECT Status_Code FROM BOOKINGS GROUP BY Status_Code ORDER BY count(*) DESC LIMIT 1 | hard |
5,159 | cre_Drama_Workshop_Groups | [
"Bookings",
"Drama_Workshop_Groups"
] | What are the names of the workshop groups that have bookings with status code "stop"? | SELECT T2.Store_Name FROM Bookings AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T1.Status_Code = "stop" | medium |
5,160 | cre_Drama_Workshop_Groups | [
"Bookings",
"Drama_Workshop_Groups"
] | Which workshop groups have bookings with status code "stop"? Give me the names. | SELECT T2.Store_Name FROM Bookings AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T1.Status_Code = "stop" | medium |
5,161 | cre_Drama_Workshop_Groups | [
"Clients",
"Bookings"
] | Show the names of all the clients with no booking. | SELECT Customer_Name FROM Clients EXCEPT SELECT T2.Customer_Name FROM Bookings AS T1 JOIN Clients AS T2 ON T1.Customer_ID = T2.Client_ID | hard |
5,162 | cre_Drama_Workshop_Groups | [
"Clients",
"Bookings"
] | What are the names of the clients who do not have any booking? | SELECT Customer_Name FROM Clients EXCEPT SELECT T2.Customer_Name FROM Bookings AS T1 JOIN Clients AS T2 ON T1.Customer_ID = T2.Client_ID | hard |
5,163 | cre_Drama_Workshop_Groups | [
"Invoices"
] | What is the average quantities ordered with payment method code "MasterCard" on invoices? | SELECT avg(Order_Quantity) FROM Invoices WHERE payment_method_code = "MasterCard" | easy |
5,164 | cre_Drama_Workshop_Groups | [
"Invoices"
] | Check the invoices record and compute the average quantities ordered with the payment method "MasterCard". | SELECT avg(Order_Quantity) FROM Invoices WHERE payment_method_code = "MasterCard" | easy |
5,165 | cre_Drama_Workshop_Groups | [
"INVOICES"
] | What is the product ID of the most frequently ordered item on invoices? | SELECT Product_ID FROM INVOICES GROUP BY Product_ID ORDER BY COUNT(*) DESC LIMIT 1 | hard |
5,166 | cre_Drama_Workshop_Groups | [
"INVOICES"
] | Find the id of the product ordered the most often on invoices. | SELECT Product_ID FROM INVOICES GROUP BY Product_ID ORDER BY COUNT(*) DESC LIMIT 1 | hard |
5,167 | cre_Drama_Workshop_Groups | [
"Ref_Service_Types",
"Services"
] | What is the description of the service type which offers both the photo product and the film product? | SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Name = 'photo' INTERSECT SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Name = 'film' | extra |
5,168 | cre_Drama_Workshop_Groups | [
"Ref_Service_Types",
"Services"
] | Give me the description of the service type that offers not only the photo product but also the film product. | SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Name = 'photo' INTERSECT SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Name = 'film' | extra |
5,169 | music_2 | [
"Band"
] | How many bands are there? | SELECT count(*) FROM Band | easy |
5,170 | music_2 | [
"Band"
] | Find the number of bands. | SELECT count(*) FROM Band | easy |
5,171 | music_2 | [
"Albums"
] | What are all the labels? | SELECT DISTINCT label FROM Albums | easy |
5,172 | music_2 | [
"Albums"
] | What are the different album labels listed? | SELECT DISTINCT label FROM Albums | easy |
5,173 | music_2 | [
"Albums"
] | Find all the albums in 2012. | SELECT * FROM Albums WHERE YEAR = 2012 | easy |
5,174 | music_2 | [
"Albums"
] | return all columns of the albums created in the year of 2012. | SELECT * FROM Albums WHERE YEAR = 2012 | easy |
5,175 | music_2 | [
"Band",
"Performance"
] | Find all the stage positions of the musicians with first name "Solveig" | SELECT DISTINCT T1.stageposition FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id WHERE Firstname = "Solveig" | medium |
5,176 | music_2 | [
"Band",
"Performance"
] | What are the different stage positions for all musicians whose first name is "Solveig"? | SELECT DISTINCT T1.stageposition FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id WHERE Firstname = "Solveig" | medium |
5,177 | music_2 | [
"Songs"
] | How many songs are there? | SELECT count(*) FROM Songs | easy |
5,178 | music_2 | [
"Songs"
] | Count the number of songs. | SELECT count(*) FROM Songs | easy |
5,179 | music_2 | [
"Band",
"Songs",
"Performance"
] | Find all the songs performed by artist with last name "Heilo" | SELECT T3.Title FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T2.Lastname = "Heilo" | hard |
5,180 | music_2 | [
"Band",
"Songs",
"Performance"
] | What are the names of the songs by the artist whose last name is "Heilo"? | SELECT T3.Title FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T2.Lastname = "Heilo" | hard |
5,181 | music_2 | [
"songs",
"performance",
"band"
] | Hom many musicians performed in the song "Flash"? | SELECT count(*) FROM performance AS T1 JOIN band AS T2 ON T1.bandmate = T2.id JOIN songs AS T3 ON T3.songid = T1.songid WHERE T3.Title = "Flash" | hard |
5,182 | music_2 | [
"songs",
"performance",
"band"
] | How many musicians play in the song "Flash"? | SELECT count(*) FROM performance AS T1 JOIN band AS T2 ON T1.bandmate = T2.id JOIN songs AS T3 ON T3.songid = T1.songid WHERE T3.Title = "Flash" | hard |
5,183 | music_2 | [
"Band",
"Songs",
"Performance"
] | Find all the songs produced by artists with first name "Marianne". | SELECT T3.Title FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T2.firstname = "Marianne" | hard |
5,184 | music_2 | [
"Band",
"Songs",
"Performance"
] | What are the names of all songs produced by the artist with the first name "Marianne"? | SELECT T3.Title FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T2.firstname = "Marianne" | hard |
5,185 | music_2 | [
"Band",
"Songs",
"Performance"
] | Who performed the song named "Badlands"? Show the first name and the last name. | SELECT T2.firstname , T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Badlands" | hard |
5,186 | music_2 | [
"Band",
"Songs",
"Performance"
] | What are the first and last names of the artist who perfomed the song "Badlands"? | SELECT T2.firstname , T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Badlands" | hard |
5,187 | music_2 | [
"Band",
"Songs",
"Performance"
] | Who is performing in the back stage position for the song "Badlands"? Show the first name and the last name. | SELECT T2.firstname , T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Badlands" AND T1.StagePosition = "back" | hard |
5,188 | music_2 | [
"Band",
"Songs",
"Performance"
] | What are the first and last names of the performer who was in the back stage position for the song "Badlands"? | SELECT T2.firstname , T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Badlands" AND T1.StagePosition = "back" | hard |
5,189 | music_2 | [
"albums"
] | How many unique labels are there for albums? | SELECT count(DISTINCT label) FROM albums | easy |
5,190 | music_2 | [
"albums"
] | What are the unique labels for the albums? | SELECT count(DISTINCT label) FROM albums | easy |
5,191 | music_2 | [
"albums"
] | What is the label that has the most albums? | SELECT label FROM albums GROUP BY label ORDER BY count(*) DESC LIMIT 1 | hard |
5,192 | music_2 | [
"albums"
] | What is the label with the most albums? | SELECT label FROM albums GROUP BY label ORDER BY count(*) DESC LIMIT 1 | hard |
5,193 | music_2 | [
"Band",
"Songs",
"Performance"
] | What is the last name of the musician that have produced the most number of songs? | SELECT T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId GROUP BY lastname ORDER BY count(*) DESC LIMIT 1 | extra |
5,194 | music_2 | [
"Band",
"Songs",
"Performance"
] | What is the last name of the musician who was in the most songs? | SELECT T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId GROUP BY lastname ORDER BY count(*) DESC LIMIT 1 | extra |
5,195 | music_2 | [
"Band",
"Performance"
] | What is the last name of the musician that has been at the back position the most? | SELECT T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id WHERE stageposition = "back" GROUP BY lastname ORDER BY count(*) DESC LIMIT 1 | extra |
5,196 | music_2 | [
"Band",
"Performance"
] | What is the last name of the musicians who has played back position the most? | SELECT T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id WHERE stageposition = "back" GROUP BY lastname ORDER BY count(*) DESC LIMIT 1 | extra |
5,197 | music_2 | [
"songs"
] | Find all the songs whose name contains the word "the". | SELECT title FROM songs WHERE title LIKE '% the %' | medium |
5,198 | music_2 | [
"songs"
] | What are the names of the songs whose title has the word "the"? | SELECT title FROM songs WHERE title LIKE '% the %' | medium |
5,199 | music_2 | [
"Instruments"
] | What are all the instruments used? | SELECT DISTINCT instrument FROM Instruments | easy |
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