query_id
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stringclasses 140
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sequencelengths 1
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stringlengths 16
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stringlengths 18
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|---|---|---|---|---|---|
5,300 | manufactory_1 | [
"manufacturers"
] | What are the names of companies with revenue less than the lowest revenue of any manufacturer in Austin? | SELECT name FROM manufacturers WHERE revenue < (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin') | hard |
5,301 | manufactory_1 | [
"manufacturers"
] | Find the total revenue of companies whose revenue is larger than the revenue of some companies based in Austin. | SELECT sum(revenue) FROM manufacturers WHERE revenue > (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin') | hard |
5,302 | manufactory_1 | [
"manufacturers"
] | What is the total revenue of companies with revenue greater than the lowest revenue of any manufacturer in Austin? | SELECT sum(revenue) FROM manufacturers WHERE revenue > (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin') | hard |
5,303 | manufactory_1 | [
"manufacturers"
] | Find the total revenue of companies of each founder. | SELECT sum(revenue) , founder FROM manufacturers GROUP BY founder | medium |
5,304 | manufactory_1 | [
"manufacturers"
] | What is the total revenue of companies started by founder? | SELECT sum(revenue) , founder FROM manufacturers GROUP BY founder | medium |
5,305 | manufactory_1 | [
"manufacturers"
] | Find the name and revenue of the company that earns the highest revenue in each city. | SELECT name , max(revenue) , Headquarter FROM manufacturers GROUP BY Headquarter | medium |
5,306 | manufactory_1 | [
"manufacturers"
] | What are the names and revenues of the companies with the highest revenues in each headquarter city? | SELECT name , max(revenue) , Headquarter FROM manufacturers GROUP BY Headquarter | medium |
5,307 | manufactory_1 | [
"manufacturers"
] | Find the total revenue for each manufacturer. | SELECT sum(revenue) , name FROM manufacturers GROUP BY name | medium |
5,308 | manufactory_1 | [
"manufacturers"
] | What is the total revenue of each manufacturer? | SELECT sum(revenue) , name FROM manufacturers GROUP BY name | medium |
5,309 | manufactory_1 | [
"manufacturers",
"products"
] | Find the average prices of all products from each manufacture, and list each company's name. | SELECT avg(T1.price) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name | medium |
5,310 | manufactory_1 | [
"manufacturers",
"products"
] | What are the average prices of products for each manufacturer? | SELECT avg(T1.price) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name | medium |
5,311 | manufactory_1 | [
"manufacturers",
"products"
] | Find the number of different products that are produced by companies at different headquarter cities. | SELECT count(DISTINCT T1.name) , T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter | medium |
5,312 | manufactory_1 | [
"manufacturers",
"products"
] | How many different products are produced in each headquarter city? | SELECT count(DISTINCT T1.name) , T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter | medium |
5,313 | manufactory_1 | [
"manufacturers",
"products"
] | Find number of products which Sony does not make. | SELECT count(DISTINCT name) FROM products WHERE name NOT IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony') | extra |
5,314 | manufactory_1 | [
"manufacturers",
"products"
] | How many products are not made by Sony? | SELECT count(DISTINCT name) FROM products WHERE name NOT IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony') | extra |
5,315 | manufactory_1 | [
"manufacturers",
"products"
] | Find the name of companies that do not make DVD drive. | SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive' | hard |
5,316 | manufactory_1 | [
"manufacturers",
"products"
] | What are the names of companies that do not make DVD drives? | SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive' | hard |
5,317 | manufactory_1 | [
"manufacturers",
"products"
] | Find the number of products for each manufacturer, showing the name of each company. | SELECT count(*) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name | medium |
5,318 | manufactory_1 | [
"manufacturers",
"products"
] | How many products are there for each manufacturer? | SELECT count(*) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name | medium |
5,319 | manufactory_1 | [
"Products"
] | Select the names of all the products in the store. | SELECT Name FROM Products | easy |
5,320 | manufactory_1 | [
"Products"
] | What are the names of all products? | SELECT Name FROM Products | easy |
5,321 | manufactory_1 | [
"products"
] | Select the names and the prices of all the products in the store. | SELECT name , price FROM products | medium |
5,322 | manufactory_1 | [
"products"
] | What are the names and prices of all products in the store? | SELECT name , price FROM products | medium |
5,323 | manufactory_1 | [
"products"
] | Select the name of the products with a price less than or equal to $200. | SELECT name FROM products WHERE price <= 200 | easy |
5,324 | manufactory_1 | [
"products"
] | What are the names of products with price at most 200? | SELECT name FROM products WHERE price <= 200 | easy |
5,325 | manufactory_1 | [
"products"
] | Find all information of all the products with a price between $60 and $120. | SELECT * FROM products WHERE price BETWEEN 60 AND 120 | easy |
5,326 | manufactory_1 | [
"products"
] | What is all the information of all the products that have a price between 60 and 120? | SELECT * FROM products WHERE price BETWEEN 60 AND 120 | easy |
5,327 | manufactory_1 | [
"products"
] | Compute the average price of all the products. | SELECT avg(price) FROM products | easy |
5,328 | manufactory_1 | [
"products"
] | What is the average price across all products? | SELECT avg(price) FROM products | easy |
5,329 | manufactory_1 | [
"products"
] | Compute the average price of all products with manufacturer code equal to 2. | SELECT avg(price) FROM products WHERE Manufacturer = 2 | easy |
5,330 | manufactory_1 | [
"products"
] | What is the average price of products with manufacturer codes equal to 2? | SELECT avg(price) FROM products WHERE Manufacturer = 2 | easy |
5,331 | manufactory_1 | [
"products"
] | Compute the number of products with a price larger than or equal to $180. | SELECT count(*) FROM products WHERE price >= 180 | easy |
5,332 | manufactory_1 | [
"products"
] | How many products have prices of at least 180? | SELECT count(*) FROM products WHERE price >= 180 | easy |
5,333 | manufactory_1 | [
"products"
] | Select the name and price of all products with a price larger than or equal to $180, and sort first by price (in descending order), and then by name (in ascending order). | SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC | medium |
5,334 | manufactory_1 | [
"products"
] | What are the names and prices of products that cost at least 180, sorted by price decreasing and name ascending? | SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC | medium |
5,335 | manufactory_1 | [
"Manufacturers",
"products"
] | Select all the data from the products and each product's manufacturer. | SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code | easy |
5,336 | manufactory_1 | [
"Manufacturers",
"products"
] | What is all the product data, as well as each product's manufacturer? | SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code | easy |
5,337 | manufactory_1 | [
"Products"
] | Select the average price of each manufacturer's products, showing only the manufacturer's code. | SELECT AVG(Price) , Manufacturer FROM Products GROUP BY Manufacturer | medium |
5,338 | manufactory_1 | [
"Products"
] | What are the average prices of products, grouped by manufacturer code? | SELECT AVG(Price) , Manufacturer FROM Products GROUP BY Manufacturer | medium |
5,339 | manufactory_1 | [
"Manufacturers",
"products"
] | Select the average price of each manufacturer's products, showing the manufacturer's name. | SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name | medium |
5,340 | manufactory_1 | [
"Manufacturers",
"products"
] | What are the average prices of products, grouped by manufacturer name? | SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name | medium |
5,341 | manufactory_1 | [
"Manufacturers",
"products"
] | Select the names of manufacturer whose products have an average price higher than or equal to $150. | SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150 | medium |
5,342 | manufactory_1 | [
"Manufacturers",
"products"
] | What are the names and average prices of products for manufacturers whose products cost on average 150 or more? | SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150 | medium |
5,343 | manufactory_1 | [
"Products"
] | Select the name and price of the cheapest product. | SELECT name , price FROM Products ORDER BY price ASC LIMIT 1 | medium |
5,344 | manufactory_1 | [
"Products"
] | What is the name and price of the cheapest product? | SELECT name , price FROM Products ORDER BY price ASC LIMIT 1 | medium |
5,345 | manufactory_1 | [
"Manufacturers",
"products"
] | Select the name of each manufacturer along with the name and price of its most expensive product. | SELECT T1.Name , max(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name | medium |
5,346 | manufactory_1 | [
"Manufacturers",
"products"
] | For each manufacturer name, what are the names and prices of their most expensive product? | SELECT T1.Name , max(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name | medium |
5,347 | manufactory_1 | [
"products"
] | Select the code of the product that is cheapest in each product category. | SELECT code , name , min(price) FROM products GROUP BY name | medium |
5,348 | manufactory_1 | [
"products"
] | What are the codes and names of the cheapest products in each category? | SELECT code , name , min(price) FROM products GROUP BY name | medium |
5,349 | tracking_software_problems | [
"problem_log"
] | What is the id of the problem log that is created most recently? | SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1 | medium |
5,350 | tracking_software_problems | [
"problem_log"
] | Which problem log was created most recently? Give me the log id. | SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1 | medium |
5,351 | tracking_software_problems | [
"problem_log"
] | What is the oldest log id and its corresponding problem id? | SELECT problem_log_id , problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1 | medium |
5,352 | tracking_software_problems | [
"problem_log"
] | Find the oldest log id and its corresponding problem id. | SELECT problem_log_id , problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1 | medium |
5,353 | tracking_software_problems | [
"problem_log"
] | Find all the ids and dates of the logs for the problem whose id is 10. | SELECT problem_log_id , log_entry_date FROM problem_log WHERE problem_id = 10 | medium |
5,354 | tracking_software_problems | [
"problem_log"
] | For the problem with id 10, return the ids and dates of its problem logs. | SELECT problem_log_id , log_entry_date FROM problem_log WHERE problem_id = 10 | medium |
5,355 | tracking_software_problems | [
"problem_log"
] | List all the log ids and their descriptions from the problem logs. | SELECT problem_log_id , log_entry_description FROM problem_log | medium |
5,356 | tracking_software_problems | [
"problem_log"
] | What are the log id and entry description of each problem? | SELECT problem_log_id , log_entry_description FROM problem_log | medium |
5,357 | tracking_software_problems | [
"problem_log",
"staff"
] | List the first and last names of all distinct staff members who are assigned to the problem whose id is 1. | SELECT DISTINCT staff_first_name , staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1 | medium |
5,358 | tracking_software_problems | [
"problem_log",
"staff"
] | Which staff members are assigned to the problem with id 1? Give me their first and last names. | SELECT DISTINCT staff_first_name , staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1 | medium |
5,359 | tracking_software_problems | [
"problem_log",
"staff"
] | List the problem id and log id which are assigned to the staff named Rylan Homenick. | SELECT DISTINCT T2.problem_id , T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick" | extra |
5,360 | tracking_software_problems | [
"problem_log",
"staff"
] | Which problem id and log id are assigned to the staff named Rylan Homenick? | SELECT DISTINCT T2.problem_id , T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick" | extra |
5,361 | tracking_software_problems | [
"problems",
"product"
] | How many problems are there for product voluptatem? | SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem" | medium |
5,362 | tracking_software_problems | [
"problems",
"product"
] | How many problems did the product called "voluptatem" have in record? | SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem" | medium |
5,363 | tracking_software_problems | [
"problems",
"product"
] | How many problems does the product with the most problems have? List the number of the problems and product name. | SELECT count(*) , T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count(*) DESC LIMIT 1 | extra |
5,364 | tracking_software_problems | [
"problems",
"product"
] | Which product has the most problems? Give me the number of problems and the product name. | SELECT count(*) , T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count(*) DESC LIMIT 1 | extra |
5,365 | tracking_software_problems | [
"problems",
"staff"
] | Give me a list of descriptions of the problems that are reported by the staff whose first name is Christop. | SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" | medium |
5,366 | tracking_software_problems | [
"problems",
"staff"
] | Which problems are reported by the staff with first name "Christop"? Show the descriptions of the problems. | SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" | medium |
5,367 | tracking_software_problems | [
"problems",
"staff"
] | Find the ids of the problems that are reported by the staff whose last name is Bosco. | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco" | medium |
5,368 | tracking_software_problems | [
"problems",
"staff"
] | Which problems are reported by the staff with last name "Bosco"? Show the ids of the problems. | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco" | medium |
5,369 | tracking_software_problems | [
"problems"
] | What are the ids of the problems which are reported after 1978-06-26? | SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26" | easy |
5,370 | tracking_software_problems | [
"problems"
] | Find the ids of the problems reported after 1978-06-26. | SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26" | easy |
5,371 | tracking_software_problems | [
"problems"
] | What are the ids of the problems which are reported before 1978-06-26? | SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26" | easy |
5,372 | tracking_software_problems | [
"problems"
] | Which problems are reported before 1978-06-26? Give me the ids of the problems. | SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26" | easy |
5,373 | tracking_software_problems | [
"product",
"problems"
] | For each product which has problems, what are the number of problems and the product id? | SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id | medium |
5,374 | tracking_software_problems | [
"product",
"problems"
] | For each product with some problems, list the count of problems and the product id. | SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id | medium |
5,375 | tracking_software_problems | [
"product",
"problems"
] | For each product that has problems, find the number of problems reported after 1986-11-13 and the product id? | SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id | hard |
5,376 | tracking_software_problems | [
"product",
"problems"
] | What are the products that have problems reported after 1986-11-13? Give me the product id and the count of problems reported after 1986-11-13. | SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id | hard |
5,377 | tracking_software_problems | [
"product"
] | List the names of all the distinct product names in alphabetical order? | SELECT DISTINCT product_name FROM product ORDER BY product_name | easy |
5,378 | tracking_software_problems | [
"product"
] | Sort all the distinct product names in alphabetical order. | SELECT DISTINCT product_name FROM product ORDER BY product_name | easy |
5,379 | tracking_software_problems | [
"product"
] | List all the distinct product names ordered by product id? | SELECT DISTINCT product_name FROM product ORDER BY product_id | easy |
5,380 | tracking_software_problems | [
"product"
] | What is the list of distinct product names sorted by product id? | SELECT DISTINCT product_name FROM product ORDER BY product_id | easy |
5,381 | tracking_software_problems | [
"problems",
"staff"
] | What are the id of problems reported by the staff named Dameon Frami or Jolie Weber? | SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber" | extra |
5,382 | tracking_software_problems | [
"problems",
"staff"
] | Which problems were reported by the staff named Dameon Frami or Jolie Weber? Give me the ids of the problems. | SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber" | extra |
5,383 | tracking_software_problems | [
"problems",
"staff"
] | What are the product ids for the problems reported by Christop Berge with closure authorised by Ashley Medhurst? | SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst" | extra |
5,384 | tracking_software_problems | [
"problems",
"staff"
] | For which product was there a problem reported by Christop Berge, with closure authorised by Ashley Medhurst? Return the product ids. | SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst" | extra |
5,385 | tracking_software_problems | [
"problems",
"staff"
] | What are the ids of the problems reported before the date of any problem reported by Lysanne Turcotte? | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte" ) | extra |
5,386 | tracking_software_problems | [
"problems",
"staff"
] | Which problems were reported before the date of any problem reported by the staff Lysanne Turcotte? Give me the ids of the problems. | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte" ) | extra |
5,387 | tracking_software_problems | [
"problems",
"staff"
] | What are the ids of the problems reported after the date of any problems reported by Rylan Homenick? | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick" ) | extra |
5,388 | tracking_software_problems | [
"problems",
"staff"
] | Find the ids of the problems reported after the date of any problems reported by the staff Rylan Homenick. | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick" ) | extra |
5,389 | tracking_software_problems | [
"product",
"problems"
] | Find the top 3 products which have the largest number of problems? | SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3 | extra |
5,390 | tracking_software_problems | [
"product",
"problems"
] | What are the three products that have the most problems?s | SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3 | extra |
5,391 | tracking_software_problems | [
"product",
"problems"
] | List the ids of the problems from the product "voluptatem" that are reported after 1995? | SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995" | medium |
5,392 | tracking_software_problems | [
"product",
"problems"
] | What are the ids of the problems that are from the product "voluptatem" and are reported after 1995? | SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995" | medium |
5,393 | tracking_software_problems | [
"product",
"problems",
"staff"
] | Find the first and last name of the staff members who reported problems from the product "rem" but not "aut"? | SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut" | extra |
5,394 | tracking_software_problems | [
"product",
"problems",
"staff"
] | Which staff members who reported problems from the product "rem" but not "aut"? Give me their first and last names. | SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut" | extra |
5,395 | tracking_software_problems | [
"product",
"problems",
"staff"
] | Find the products which have problems reported by both Lacey Bosco and Kenton Champlin? | SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin" | extra |
5,396 | tracking_software_problems | [
"product",
"problems",
"staff"
] | Which products have problems reported by both the staff named Lacey Bosco and the staff named Kenton Champlin? | SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin" | extra |
5,397 | shop_membership | [
"branch"
] | How many branches where have more than average number of memberships are there? | SELECT count(*) FROM branch WHERE membership_amount > (SELECT avg(membership_amount) FROM branch) | hard |
5,398 | shop_membership | [
"branch"
] | What is the number of branches that have more than the average number of memberships? | SELECT count(*) FROM branch WHERE membership_amount > (SELECT avg(membership_amount) FROM branch) | hard |
5,399 | shop_membership | [
"branch"
] | Show name, address road, and city for all branches sorted by open year. | SELECT name , address_road , city FROM branch ORDER BY open_year | medium |
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