query_id
int64
0
7k
database_id
stringclasses
140 values
table_id
sequencelengths
1
5
query
stringlengths
16
224
answer
stringlengths
18
577
difficulty
stringclasses
4 values
5,400
shop_membership
[ "branch" ]
What are the names, address roads, and cities of the branches ordered by opening year?
SELECT name , address_road , city FROM branch ORDER BY open_year
medium
5,401
shop_membership
[ "branch" ]
What are names for top three branches with most number of membership?
SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3
medium
5,402
shop_membership
[ "branch" ]
What are the names for the 3 branches that have the most memberships?
SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3
medium
5,403
shop_membership
[ "branch" ]
Show all distinct city where branches with at least 100 memberships are located.
SELECT DISTINCT city FROM branch WHERE membership_amount >= 100
easy
5,404
shop_membership
[ "branch" ]
What are the different cities that have more than 100 memberships?
SELECT DISTINCT city FROM branch WHERE membership_amount >= 100
easy
5,405
shop_membership
[ "branch" ]
List all open years when at least two shops are opened.
SELECT open_year FROM branch GROUP BY open_year HAVING count(*) >= 2
easy
5,406
shop_membership
[ "branch" ]
What are the opening years in which at least two shops opened?
SELECT open_year FROM branch GROUP BY open_year HAVING count(*) >= 2
easy
5,407
shop_membership
[ "branch" ]
Show minimum and maximum amount of memberships for all branches opened in 2011 or located at city London.
SELECT min(membership_amount) , max(membership_amount) FROM branch WHERE open_year = 2011 OR city = 'London'
hard
5,408
shop_membership
[ "branch" ]
What are the minimum and maximum membership amounts for all branches that either opened in 2011 or are located in London?
SELECT min(membership_amount) , max(membership_amount) FROM branch WHERE open_year = 2011 OR city = 'London'
hard
5,409
shop_membership
[ "branch" ]
Show the city and the number of branches opened before 2010 for each city.
SELECT city , count(*) FROM branch WHERE open_year < 2010 GROUP BY city
medium
5,410
shop_membership
[ "branch" ]
For each city, how many branches opened before 2010?
SELECT city , count(*) FROM branch WHERE open_year < 2010 GROUP BY city
medium
5,411
shop_membership
[ "member" ]
How many different levels do members have?
SELECT count(DISTINCT LEVEL) FROM member
easy
5,412
shop_membership
[ "member" ]
What are the different membership levels?
SELECT count(DISTINCT LEVEL) FROM member
easy
5,413
shop_membership
[ "member" ]
Show card number, name, and hometown for all members in a descending order of level.
SELECT card_number , name , hometown FROM member ORDER BY LEVEL DESC
medium
5,414
shop_membership
[ "member" ]
What are the card numbers, names, and hometowns of every member ordered by descending level?
SELECT card_number , name , hometown FROM member ORDER BY LEVEL DESC
medium
5,415
shop_membership
[ "member" ]
Show the membership level with most number of members.
SELECT LEVEL FROM member GROUP BY LEVEL ORDER BY count(*) DESC LIMIT 1
hard
5,416
shop_membership
[ "member" ]
What is the membership level with the most people?
SELECT LEVEL FROM member GROUP BY LEVEL ORDER BY count(*) DESC LIMIT 1
hard
5,417
shop_membership
[ "membership_register_branch", "member", "branch" ]
Show all member names and registered branch names sorted by register year.
SELECT T3.name , T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id ORDER BY T1.register_year
hard
5,418
shop_membership
[ "membership_register_branch", "member", "branch" ]
What are the names of the members and branches at which they are registered sorted by year of registration?
SELECT T3.name , T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id ORDER BY T1.register_year
hard
5,419
shop_membership
[ "membership_register_branch", "branch" ]
Show all branch names with the number of members in each branch registered after 2015.
SELECT T2.name , count(*) FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year > 2015 GROUP BY T2.branch_id
hard
5,420
shop_membership
[ "membership_register_branch", "branch" ]
For each branch id, what are the names of the branches that were registered after 2015?
SELECT T2.name , count(*) FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year > 2015 GROUP BY T2.branch_id
hard
5,421
shop_membership
[ "membership_register_branch", "member" ]
Show member names without any registered branch.
SELECT name FROM member WHERE member_id NOT IN (SELECT member_id FROM membership_register_branch)
hard
5,422
shop_membership
[ "membership_register_branch", "member" ]
What are the names of the members that have never registered at any branch?
SELECT name FROM member WHERE member_id NOT IN (SELECT member_id FROM membership_register_branch)
hard
5,423
shop_membership
[ "membership_register_branch", "branch" ]
List the branch name and city without any registered members.
SELECT name , city FROM branch WHERE branch_id NOT IN (SELECT branch_id FROM membership_register_branch)
extra
5,424
shop_membership
[ "membership_register_branch", "branch" ]
What are the names and cities of the branches that do not have any registered members?
SELECT name , city FROM branch WHERE branch_id NOT IN (SELECT branch_id FROM membership_register_branch)
extra
5,425
shop_membership
[ "membership_register_branch", "branch" ]
What is the name and open year for the branch with most number of memberships registered in 2016?
SELECT T2.name , T2.open_year FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year = 2016 GROUP BY T2.branch_id ORDER BY count(*) DESC LIMIT 1
extra
5,426
shop_membership
[ "membership_register_branch", "branch" ]
What is the name and opening year for the branch that registered the most members in 2016?
SELECT T2.name , T2.open_year FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year = 2016 GROUP BY T2.branch_id ORDER BY count(*) DESC LIMIT 1
extra
5,427
shop_membership
[ "membership_register_branch", "member" ]
Show the member name and hometown who registered a branch in 2016.
SELECT T2.name , T2.hometown FROM membership_register_branch AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T1.register_year = 2016
medium
5,428
shop_membership
[ "membership_register_branch", "member" ]
What are the member names and hometowns of those who registered at a branch in 2016?
SELECT T2.name , T2.hometown FROM membership_register_branch AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T1.register_year = 2016
medium
5,429
shop_membership
[ "branch" ]
Show all city with a branch opened in 2001 and a branch with more than 100 membership.
SELECT city FROM branch WHERE open_year = 2001 AND membership_amount > 100
medium
5,430
shop_membership
[ "branch" ]
What are the cities that have a branch that opened in 2001 and a branch with more than 100 members?
SELECT city FROM branch WHERE open_year = 2001 AND membership_amount > 100
medium
5,431
shop_membership
[ "branch" ]
Show all cities without a branch having more than 100 memberships.
SELECT city FROM branch EXCEPT SELECT city FROM branch WHERE membership_amount > 100
hard
5,432
shop_membership
[ "branch" ]
What are the cities that do not have any branches with more than 100 members?
SELECT city FROM branch EXCEPT SELECT city FROM branch WHERE membership_amount > 100
hard
5,433
shop_membership
[ "purchase", "branch" ]
What is the sum of total pounds of purchase in year 2018 for all branches in London?
SELECT sum(total_pounds) FROM purchase AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T2.city = 'London' AND T1.year = 2018
medium
5,434
shop_membership
[ "purchase", "branch" ]
How many total pounds were purchased in the year 2018 at all London branches?
SELECT sum(total_pounds) FROM purchase AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T2.city = 'London' AND T1.year = 2018
medium
5,435
shop_membership
[ "purchase", "member" ]
What is the total number of purchases for members with level 6?
SELECT count(*) FROM purchase AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T2.level = 6
medium
5,436
shop_membership
[ "purchase", "member" ]
What are the total purchases for members rated at level 6?
SELECT count(*) FROM purchase AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T2.level = 6
medium
5,437
shop_membership
[ "membership_register_branch", "member", "branch" ]
Find the name of branches where have some members whose hometown is in Louisville, Kentucky and some in Hiram, Georgia.
SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Louisville , Kentucky' INTERSECT SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Hiram , Georgia'
extra
5,438
shop_membership
[ "membership_register_branch", "member", "branch" ]
What are the names of the branches that have some members with a hometown in Louisville, Kentucky and also those from Hiram, Goergia?
SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Louisville , Kentucky' INTERSECT SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Hiram , Georgia'
extra
5,439
shop_membership
[ "member" ]
list the card number of all members whose hometown address includes word "Kentucky".
SELECT card_number FROM member WHERE Hometown LIKE "%Kentucky%"
medium
5,440
shop_membership
[ "member" ]
What are the card numbers of members from Kentucky?
SELECT card_number FROM member WHERE Hometown LIKE "%Kentucky%"
medium
5,441
voter_2
[ "STUDENT" ]
Find the number of students in total.
SELECT count(*) FROM STUDENT
easy
5,442
voter_2
[ "STUDENT" ]
How many students are there in total?
SELECT count(*) FROM STUDENT
easy
5,443
voter_2
[ "VOTING_RECORD" ]
Find the number of voting records in total.
SELECT count(*) FROM VOTING_RECORD
easy
5,444
voter_2
[ "VOTING_RECORD" ]
How many voting records do we have?
SELECT count(*) FROM VOTING_RECORD
easy
5,445
voter_2
[ "VOTING_RECORD" ]
Find the distinct number of president votes.
SELECT count(DISTINCT President_Vote) FROM VOTING_RECORD
easy
5,446
voter_2
[ "VOTING_RECORD" ]
How many distinct president votes are recorded?
SELECT count(DISTINCT President_Vote) FROM VOTING_RECORD
easy
5,447
voter_2
[ "STUDENT" ]
Find the maximum age of all the students.
SELECT max(Age) FROM STUDENT
easy
5,448
voter_2
[ "STUDENT" ]
What is the oldest age among the students?
SELECT max(Age) FROM STUDENT
easy
5,449
voter_2
[ "STUDENT" ]
Find the last names of students with major 50.
SELECT LName FROM STUDENT WHERE Major = 50
easy
5,450
voter_2
[ "STUDENT" ]
What are the last names of students studying major 50?
SELECT LName FROM STUDENT WHERE Major = 50
easy
5,451
voter_2
[ "STUDENT" ]
Find the first names of students with age above 22.
SELECT Fname FROM STUDENT WHERE Age > 22
easy
5,452
voter_2
[ "STUDENT" ]
What are the first names of all the students aged above 22?
SELECT Fname FROM STUDENT WHERE Age > 22
easy
5,453
voter_2
[ "STUDENT" ]
What are the majors of male (sex is M) students?
SELECT Major FROM STUDENT WHERE Sex = "M"
easy
5,454
voter_2
[ "STUDENT" ]
List the major of each male student.
SELECT Major FROM STUDENT WHERE Sex = "M"
easy
5,455
voter_2
[ "STUDENT" ]
What is the average age of female (sex is F) students?
SELECT avg(Age) FROM STUDENT WHERE Sex = "F"
easy
5,456
voter_2
[ "STUDENT" ]
Find the average age of female students.
SELECT avg(Age) FROM STUDENT WHERE Sex = "F"
easy
5,457
voter_2
[ "STUDENT" ]
What are the maximum and minimum age of students with major 600?
SELECT max(Age) , min(Age) FROM STUDENT WHERE Major = 600
medium
5,458
voter_2
[ "STUDENT" ]
Tell me the ages of the oldest and youngest students studying major 600.
SELECT max(Age) , min(Age) FROM STUDENT WHERE Major = 600
medium
5,459
voter_2
[ "STUDENT" ]
Who are the advisors for students that live in a city with city code "BAL"?
SELECT Advisor FROM STUDENT WHERE city_code = "BAL"
easy
5,460
voter_2
[ "STUDENT" ]
Show the advisors of the students whose city of residence has city code "BAL".
SELECT Advisor FROM STUDENT WHERE city_code = "BAL"
easy
5,461
voter_2
[ "VOTING_RECORD" ]
What are the distinct secretary votes in the fall election cycle?
SELECT DISTINCT Secretary_Vote FROM VOTING_RECORD WHERE ELECTION_CYCLE = "Fall"
easy
5,462
voter_2
[ "VOTING_RECORD" ]
Return all the distinct secretary votes made in the fall election cycle.
SELECT DISTINCT Secretary_Vote FROM VOTING_RECORD WHERE ELECTION_CYCLE = "Fall"
easy
5,463
voter_2
[ "VOTING_RECORD" ]
What are the distinct president votes on 08/30/2015?
SELECT DISTINCT PRESIDENT_Vote FROM VOTING_RECORD WHERE Registration_Date = "08/30/2015"
easy
5,464
voter_2
[ "VOTING_RECORD" ]
Show all the distinct president votes made on 08/30/2015.
SELECT DISTINCT PRESIDENT_Vote FROM VOTING_RECORD WHERE Registration_Date = "08/30/2015"
easy
5,465
voter_2
[ "VOTING_RECORD" ]
Report the distinct registration date and the election cycle.
SELECT DISTINCT Registration_Date , Election_Cycle FROM VOTING_RECORD
medium
5,466
voter_2
[ "VOTING_RECORD" ]
What are the distinct registration dates and the election cycles?
SELECT DISTINCT Registration_Date , Election_Cycle FROM VOTING_RECORD
medium
5,467
voter_2
[ "VOTING_RECORD" ]
Report the distinct president vote and the vice president vote.
SELECT DISTINCT President_Vote , VICE_President_Vote FROM VOTING_RECORD
medium
5,468
voter_2
[ "VOTING_RECORD" ]
List all the distinct president votes and the vice president votes.
SELECT DISTINCT President_Vote , VICE_President_Vote FROM VOTING_RECORD
medium
5,469
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the distinct last names of the students who have class president votes.
SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.CLASS_President_VOTE
easy
5,470
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What are the distinct last names of the students who have class president votes?
SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.CLASS_President_VOTE
easy
5,471
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the distinct first names of the students who have class senator votes.
SELECT DISTINCT T1.Fname FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.CLASS_Senator_VOTE
easy
5,472
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What are the distinct first names of the students who have class president votes?
SELECT DISTINCT T1.Fname FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.CLASS_Senator_VOTE
easy
5,473
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the distinct ages of students who have secretary votes in the fall election cycle.
SELECT DISTINCT T1.Age FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Secretary_Vote WHERE T2.Election_Cycle = "Fall"
medium
5,474
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What are the distinct ages of students who have secretary votes in the fall election cycle?
SELECT DISTINCT T1.Age FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Secretary_Vote WHERE T2.Election_Cycle = "Fall"
medium
5,475
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the distinct Advisor of students who have treasurer votes in the spring election cycle.
SELECT DISTINCT T1.Advisor FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Treasurer_Vote WHERE T2.Election_Cycle = "Spring"
medium
5,476
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Who served as an advisor for students who have treasurer votes in the spring election cycle?
SELECT DISTINCT T1.Advisor FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Treasurer_Vote WHERE T2.Election_Cycle = "Spring"
medium
5,477
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the distinct majors of students who have treasurer votes.
SELECT DISTINCT T1.Major FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Treasurer_Vote
easy
5,478
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What are the distinct majors that students with treasurer votes are studying?
SELECT DISTINCT T1.Major FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Treasurer_Vote
easy
5,479
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the first and last names of all the female (sex is F) students who have president votes.
SELECT DISTINCT T1.Fname , T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.President_VOTE WHERE T1.sex = "F"
medium
5,480
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What are the first and last names of all the female students who have president votes?
SELECT DISTINCT T1.Fname , T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.President_VOTE WHERE T1.sex = "F"
medium
5,481
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the first and last name of all the students of age 18 who have vice president votes.
SELECT DISTINCT T1.Fname , T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.VICE_President_VOTE WHERE T1.age = 18
medium
5,482
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What are the first names and last names of the students who are 18 years old and have vice president votes.
SELECT DISTINCT T1.Fname , T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.VICE_President_VOTE WHERE T1.age = 18
medium
5,483
voter_2
[ "VOTING_RECORD", "STUDENT" ]
How many male (sex is M) students have class senator votes in the fall election cycle?
SELECT count(*) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = Class_Senator_Vote WHERE T1.Sex = "M" AND T2.Election_Cycle = "Fall"
medium
5,484
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Count the number of male students who had class senator votes in the fall election cycle.
SELECT count(*) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = Class_Senator_Vote WHERE T1.Sex = "M" AND T2.Election_Cycle = "Fall"
medium
5,485
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the number of students whose city code is NYC and who have class senator votes in the spring election cycle.
SELECT count(*) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = Class_Senator_Vote WHERE T1.city_code = "NYC" AND T2.Election_Cycle = "Spring"
medium
5,486
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Which students live in the city with code "NYC" and have class senator votes in the spring election cycle? Count the numbers.
SELECT count(*) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = Class_Senator_Vote WHERE T1.city_code = "NYC" AND T2.Election_Cycle = "Spring"
medium
5,487
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the average age of students who live in the city with code "NYC" and have secretary votes in the spring election cycle.
SELECT avg(T1.Age) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = SECRETARY_Vote WHERE T1.city_code = "NYC" AND T2.Election_Cycle = "Spring"
medium
5,488
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What is the average age of students who have city code "NYC" and have secretary votes for the spring election cycle?
SELECT avg(T1.Age) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = SECRETARY_Vote WHERE T1.city_code = "NYC" AND T2.Election_Cycle = "Spring"
medium
5,489
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the average age of female (sex is F) students who have secretary votes in the spring election cycle.
SELECT avg(T1.Age) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = SECRETARY_Vote WHERE T1.Sex = "F" AND T2.Election_Cycle = "Spring"
medium
5,490
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What is the average age of the female students with secretary votes in the spring election cycle?
SELECT avg(T1.Age) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = SECRETARY_Vote WHERE T1.Sex = "F" AND T2.Election_Cycle = "Spring"
medium
5,491
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the distinct first names of all the students who have vice president votes and whose city code is not PIT.
SELECT DISTINCT T1.Fname FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.VICE_PRESIDENT_Vote EXCEPT SELECT DISTINCT Fname FROM STUDENT WHERE city_code = "PIT"
hard
5,492
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What are the distinct first names of the students who have vice president votes and reside in a city whose city code is not PIT?
SELECT DISTINCT T1.Fname FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.VICE_PRESIDENT_Vote EXCEPT SELECT DISTINCT Fname FROM STUDENT WHERE city_code = "PIT"
hard
5,493
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the distinct last names of all the students who have president votes and whose advisor is not 2192.
SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = PRESIDENT_Vote EXCEPT SELECT DISTINCT LName FROM STUDENT WHERE Advisor = "2192"
hard
5,494
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What are the distinct last names of the students who have president votes but do not have 2192 as the advisor?
SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = PRESIDENT_Vote EXCEPT SELECT DISTINCT LName FROM STUDENT WHERE Advisor = "2192"
hard
5,495
voter_2
[ "VOTING_RECORD", "STUDENT" ]
Find the distinct last names of all the students who have president votes and whose advisor is 8741.
SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = PRESIDENT_Vote INTERSECT SELECT DISTINCT LName FROM STUDENT WHERE Advisor = "8741"
hard
5,496
voter_2
[ "VOTING_RECORD", "STUDENT" ]
What are the distinct last names of the students who have president votes and have 8741 as the advisor?
SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = PRESIDENT_Vote INTERSECT SELECT DISTINCT LName FROM STUDENT WHERE Advisor = "8741"
hard
5,497
voter_2
[ "STUDENT" ]
For each advisor, report the total number of students advised by him or her.
SELECT Advisor , count(*) FROM STUDENT GROUP BY Advisor
medium
5,498
voter_2
[ "STUDENT" ]
How many students does each advisor have?
SELECT Advisor , count(*) FROM STUDENT GROUP BY Advisor
medium
5,499
voter_2
[ "STUDENT" ]
Report all advisors that advise more than 2 students.
SELECT Advisor FROM STUDENT GROUP BY Advisor HAVING COUNT(*) > 2
easy