query_id
int64 0
7k
| database_id
stringclasses 140
values | table_id
sequencelengths 1
5
| query
stringlengths 16
224
| answer
stringlengths 18
577
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
5,600 | swimming | [
"event"
] | List all the event names by year from the most recent to the oldest. | SELECT name FROM event ORDER BY YEAR DESC | easy |
5,601 | swimming | [
"event"
] | What is the name of the event that happened in the most recent year? | SELECT name FROM event ORDER BY YEAR DESC LIMIT 1 | medium |
5,602 | swimming | [
"stadium"
] | How many stadiums are there? | SELECT count(*) FROM stadium | easy |
5,603 | swimming | [
"stadium"
] | Find the name of the stadium that has the maximum capacity. | SELECT name FROM stadium ORDER BY capacity DESC LIMIT 1 | medium |
5,604 | swimming | [
"stadium"
] | Find the names of stadiums whose capacity is smaller than the average capacity. | SELECT name FROM stadium WHERE capacity < (SELECT avg(capacity) FROM stadium) | hard |
5,605 | swimming | [
"stadium"
] | Find the country that has the most stadiums. | SELECT country FROM stadium GROUP BY country ORDER BY count(*) DESC LIMIT 1 | hard |
5,606 | swimming | [
"stadium"
] | Which country has at most 3 stadiums listed? | SELECT country FROM stadium GROUP BY country HAVING count(*) <= 3 | easy |
5,607 | swimming | [
"stadium"
] | Which country has both stadiums with capacity greater than 60000 and stadiums with capacity less than 50000? | SELECT country FROM stadium WHERE capacity > 60000 INTERSECT SELECT country FROM stadium WHERE capacity < 50000 | hard |
5,608 | swimming | [
"stadium"
] | How many cities have a stadium that was opened before the year of 2006? | SELECT count(DISTINCT city) FROM stadium WHERE opening_year < 2006 | easy |
5,609 | swimming | [
"stadium"
] | How many stadiums does each country have? | SELECT country , count(*) FROM stadium GROUP BY country | medium |
5,610 | swimming | [
"stadium"
] | Which countries do not have a stadium that was opened after 2006? | SELECT country FROM stadium EXCEPT SELECT country FROM stadium WHERE opening_year > 2006 | hard |
5,611 | swimming | [
"stadium"
] | How many stadiums are not in country "Russia"? | SELECT count(*) FROM stadium WHERE country != 'Russia' | easy |
5,612 | swimming | [
"swimmer"
] | Find the names of all swimmers, sorted by their 100 meter scores in ascending order. | SELECT name FROM swimmer ORDER BY meter_100 | easy |
5,613 | swimming | [
"swimmer"
] | How many different countries are all the swimmers from? | SELECT count(DISTINCT nationality) FROM swimmer | easy |
5,614 | swimming | [
"swimmer"
] | List countries that have more than one swimmer. | SELECT nationality , count(*) FROM swimmer GROUP BY nationality HAVING count(*) > 1 | medium |
5,615 | swimming | [
"swimmer"
] | Find all 200 meter and 300 meter results of swimmers with nationality "Australia". | SELECT meter_200 , meter_300 FROM swimmer WHERE nationality = 'Australia' | medium |
5,616 | swimming | [
"swimmer",
"record"
] | Find the names of swimmers who has a result of "win". | SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Win' | medium |
5,617 | swimming | [
"stadium",
"event"
] | What is the name of the stadium which held the most events? | SELECT t1.name FROM stadium AS t1 JOIN event AS t2 ON t1.id = t2.stadium_id GROUP BY t2.stadium_id ORDER BY count(*) DESC LIMIT 1 | extra |
5,618 | swimming | [
"stadium",
"event"
] | Find the name and capacity of the stadium where the event named "World Junior" happened. | SELECT t1.name , t1.capacity FROM stadium AS t1 JOIN event AS t2 ON t1.id = t2.stadium_id WHERE t2.name = 'World Junior' | medium |
5,619 | swimming | [
"stadium",
"event"
] | Find the names of stadiums which have never had any event. | SELECT name FROM stadium WHERE id NOT IN (SELECT stadium_id FROM event) | hard |
5,620 | swimming | [
"swimmer",
"record"
] | Find the name of the swimmer who has the most records. | SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id GROUP BY t2.swimmer_id ORDER BY count(*) DESC LIMIT 1 | extra |
5,621 | swimming | [
"swimmer",
"record"
] | Find the name of the swimmer who has at least 2 records. | SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id GROUP BY t2.swimmer_id HAVING count(*) >= 2 | medium |
5,622 | swimming | [
"swimmer",
"record"
] | Find the name and nationality of the swimmer who has won (i.e., has a result of "win") more than 1 time. | SELECT t1.name , t1.nationality FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Win' GROUP BY t2.swimmer_id HAVING count(*) > 1 | hard |
5,623 | swimming | [
"swimmer",
"record"
] | Find the names of the swimmers who have no record. | SELECT name FROM swimmer WHERE id NOT IN (SELECT swimmer_id FROM record) | hard |
5,624 | swimming | [
"swimmer",
"record"
] | Find the names of the swimmers who have both "win" and "loss" results in the record. | SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Win' INTERSECT SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Loss' | extra |
5,625 | swimming | [
"swimmer",
"record",
"stadium",
"event"
] | Find the names of stadiums that some Australian swimmers have been to. | SELECT t4.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id JOIN event AS t3 ON t2.event_id = t3.id JOIN stadium AS t4 ON t4.id = t3.stadium_id WHERE t1.nationality = 'Australia' | extra |
5,626 | swimming | [
"stadium",
"record",
"event"
] | Find the names of stadiums that the most swimmers have been to. | SELECT t3.name FROM record AS t1 JOIN event AS t2 ON t1.event_id = t2.id JOIN stadium AS t3 ON t3.id = t2.stadium_id GROUP BY t2.stadium_id ORDER BY count(*) DESC LIMIT 1 | extra |
5,627 | swimming | [
"swimmer"
] | Find all details for each swimmer. | SELECT * FROM swimmer | easy |
5,628 | swimming | [
"stadium"
] | What is the average capacity of the stadiums that were opened in year 2005? | SELECT avg(capacity) FROM stadium WHERE opening_year = 2005 | easy |
5,629 | railway | [
"railway"
] | How many railways are there? | SELECT count(*) FROM railway | easy |
5,630 | railway | [
"railway"
] | List the builders of railways in ascending alphabetical order. | SELECT Builder FROM railway ORDER BY Builder ASC | easy |
5,631 | railway | [
"railway"
] | List the wheels and locations of the railways. | SELECT Wheels , LOCATION FROM railway | medium |
5,632 | railway | [
"manager"
] | What is the maximum level of managers in countries that are not "Australia"? | SELECT max(LEVEL) FROM manager WHERE Country != "Australia " | easy |
5,633 | railway | [
"manager"
] | What is the average age for all managers? | SELECT avg(Age) FROM manager | easy |
5,634 | railway | [
"manager"
] | What are the names of managers in ascending order of level? | SELECT Name FROM manager ORDER BY LEVEL ASC | easy |
5,635 | railway | [
"train"
] | What are the names and arrival times of trains? | SELECT Name , Arrival FROM train | medium |
5,636 | railway | [
"manager"
] | What is the name of the oldest manager? | SELECT Name FROM manager ORDER BY Age DESC LIMIT 1 | medium |
5,637 | railway | [
"train",
"railway"
] | Show the names of trains and locations of railways they are in. | SELECT T2.Name , T1.Location FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID | medium |
5,638 | railway | [
"train",
"railway"
] | Show the builder of railways associated with the trains named "Andaman Exp". | SELECT T1.Builder FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID WHERE T2.Name = "Andaman Exp" | medium |
5,639 | railway | [
"train",
"railway"
] | Show id and location of railways that are associated with more than one train. | SELECT T2.Railway_ID , T1.Location FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID GROUP BY T2.Railway_ID HAVING COUNT(*) > 1 | medium |
5,640 | railway | [
"train",
"railway"
] | Show the id and builder of the railway that are associated with the most trains. | SELECT T2.Railway_ID , T1.Builder FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID GROUP BY T2.Railway_ID ORDER BY COUNT(*) DESC LIMIT 1 | extra |
5,641 | railway | [
"railway"
] | Show different builders of railways, along with the corresponding number of railways using each builder. | SELECT Builder , COUNT(*) FROM railway GROUP BY Builder | medium |
5,642 | railway | [
"railway"
] | Show the most common builder of railways. | SELECT Builder FROM railway GROUP BY Builder ORDER BY COUNT(*) DESC LIMIT 1 | hard |
5,643 | railway | [
"railway"
] | Show different locations of railways along with the corresponding number of railways at each location. | SELECT LOCATION , COUNT(*) FROM railway GROUP BY LOCATION | medium |
5,644 | railway | [
"railway"
] | Show the locations that have more than one railways. | SELECT LOCATION FROM railway GROUP BY LOCATION HAVING COUNT(*) > 1 | easy |
5,645 | railway | [
"train",
"railway"
] | List the object number of railways that do not have any trains. | SELECT ObjectNumber FROM railway WHERE Railway_ID NOT IN (SELECT Railway_ID FROM train) | hard |
5,646 | railway | [
"manager"
] | Show the countries that have both managers of age above 50 and managers of age below 46. | SELECT Country FROM manager WHERE Age > 50 INTERSECT SELECT Country FROM manager WHERE Age < 46 | hard |
5,647 | railway | [
"manager"
] | Show the distinct countries of managers. | SELECT DISTINCT Country FROM manager | easy |
5,648 | railway | [
"manager"
] | Show the working years of managers in descending order of their level. | SELECT Working_year_starts FROM manager ORDER BY LEVEL DESC | easy |
5,649 | railway | [
"manager"
] | Show the countries that have managers of age above 50 or below 46. | SELECT Country FROM manager WHERE Age > 50 OR Age < 46 | medium |
5,650 | customers_and_products_contacts | [
"addresses"
] | How many addresses are there in country USA? | SELECT count(*) FROM addresses WHERE country = 'USA' | easy |
5,651 | customers_and_products_contacts | [
"addresses"
] | Show all distinct cities in the address record. | SELECT DISTINCT city FROM addresses | easy |
5,652 | customers_and_products_contacts | [
"addresses"
] | Show each state and the number of addresses in each state. | SELECT state_province_county , count(*) FROM addresses GROUP BY state_province_county | medium |
5,653 | customers_and_products_contacts | [
"customer_address_history",
"customers"
] | Show names and phones of customers who do not have address information. | SELECT customer_name , customer_phone FROM customers WHERE customer_id NOT IN (SELECT customer_id FROM customer_address_history) | extra |
5,654 | customers_and_products_contacts | [
"customer_orders",
"customers"
] | Show the name of the customer who has the most orders. | SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1 | extra |
5,655 | customers_and_products_contacts | [
"products"
] | Show the product type codes which have at least two products. | SELECT product_type_code FROM products GROUP BY product_type_code HAVING count(*) >= 2 | easy |
5,656 | customers_and_products_contacts | [
"customer_orders",
"customers"
] | Show the names of customers who have both an order in completed status and an order in part status. | SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = 'Completed' INTERSECT SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = 'Part' | extra |
5,657 | customers_and_products_contacts | [
"customers"
] | Show the name, phone, and payment method code for all customers in descending order of customer number. | SELECT customer_name , customer_phone , payment_method_code FROM customers ORDER BY customer_number DESC | medium |
5,658 | customers_and_products_contacts | [
"products",
"order_items"
] | Show the product name and total order quantity for each product. | SELECT T1.product_name , sum(T2.order_quantity) FROM products AS T1 JOIN order_items AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_id | medium |
5,659 | customers_and_products_contacts | [
"products"
] | Show the minimum, maximum, average price for all products. | SELECT min(product_price) , max(product_price) , avg(product_price) FROM products | medium |
5,660 | customers_and_products_contacts | [
"products"
] | How many products have a price higher than the average? | SELECT count(*) FROM products WHERE product_price > (SELECT avg(product_price) FROM products) | hard |
5,661 | customers_and_products_contacts | [
"addresses",
"customer_address_history",
"customers"
] | Show the customer name, customer address city, date from, and date to for each customer address history. | SELECT T2.customer_name , T3.city , T1.date_from , T1.date_to FROM customer_address_history AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id JOIN addresses AS T3 ON T1.address_id = T3.address_id | medium |
5,662 | customers_and_products_contacts | [
"customer_orders",
"customers"
] | Show the names of customers who use Credit Card payment method and have more than 2 orders. | SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T1.payment_method_code = 'Credit Card' GROUP BY T1.customer_id HAVING count(*) > 2 | hard |
5,663 | customers_and_products_contacts | [
"customer_orders",
"customers",
"order_items"
] | What are the name and phone of the customer with the most ordered product quantity? | SELECT T1.customer_name , T1.customer_phone FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id JOIN order_items AS T3 ON T3.order_id = T2.order_id GROUP BY T1.customer_id ORDER BY sum(T3.order_quantity) DESC LIMIT 1 | extra |
5,664 | customers_and_products_contacts | [
"products"
] | Show the product type and name for the products with price higher than 1000 or lower than 500. | SELECT product_type_code , product_name FROM products WHERE product_price > 1000 OR product_price < 500 | extra |
5,665 | dorm_1 | [
"dorm"
] | Find the name of dorms only for female (F gender). | SELECT dorm_name FROM dorm WHERE gender = 'F' | easy |
5,666 | dorm_1 | [
"dorm"
] | What are the names of the all-female dorms? | SELECT dorm_name FROM dorm WHERE gender = 'F' | easy |
5,667 | dorm_1 | [
"dorm"
] | Find the name of dorms that can accommodate more than 300 students. | SELECT dorm_name FROM dorm WHERE student_capacity > 300 | easy |
5,668 | dorm_1 | [
"dorm"
] | What are the names of all the dorms that can accomdate more than 300 students? | SELECT dorm_name FROM dorm WHERE student_capacity > 300 | easy |
5,669 | dorm_1 | [
"student"
] | How many female students (sex is F) whose age is below 25? | SELECT count(*) FROM student WHERE sex = 'F' AND age < 25 | medium |
5,670 | dorm_1 | [
"student"
] | How many girl students who are younger than 25? | SELECT count(*) FROM student WHERE sex = 'F' AND age < 25 | medium |
5,671 | dorm_1 | [
"student"
] | Find the first name of students who is older than 20. | SELECT fname FROM student WHERE age > 20 | easy |
5,672 | dorm_1 | [
"student"
] | What are the first names of all students who are older than 20? | SELECT fname FROM student WHERE age > 20 | easy |
5,673 | dorm_1 | [
"student"
] | Find the first name of students living in city PHL whose age is between 20 and 25. | SELECT fname FROM student WHERE city_code = 'PHL' AND age BETWEEN 20 AND 25 | medium |
5,674 | dorm_1 | [
"student"
] | What is the first name of the students who are in age 20 to 25 and living in PHL city? | SELECT fname FROM student WHERE city_code = 'PHL' AND age BETWEEN 20 AND 25 | medium |
5,675 | dorm_1 | [
"dorm"
] | How many dorms are there? | SELECT count(*) FROM dorm | easy |
5,676 | dorm_1 | [
"dorm"
] | How many dorms are in the database? | SELECT count(*) FROM dorm | easy |
5,677 | dorm_1 | [
"dorm_amenity"
] | Find the number of distinct amenities. | SELECT count(*) FROM dorm_amenity | easy |
5,678 | dorm_1 | [
"dorm_amenity"
] | How many diffrent dorm amenities are there? | SELECT count(*) FROM dorm_amenity | easy |
5,679 | dorm_1 | [
"dorm"
] | Find the total capacity of all dorms. | SELECT sum(student_capacity) FROM dorm | easy |
5,680 | dorm_1 | [
"dorm"
] | What is the total student capacity of all dorms? | SELECT sum(student_capacity) FROM dorm | easy |
5,681 | dorm_1 | [
"student"
] | How many students are there? | SELECT count(*) FROM student | easy |
5,682 | dorm_1 | [
"student"
] | How many students exist? | SELECT count(*) FROM student | easy |
5,683 | dorm_1 | [
"student"
] | Find the average age of all students living in the each city. | SELECT avg(age) , city_code FROM student GROUP BY city_code | medium |
5,684 | dorm_1 | [
"student"
] | What is the average age for each city and what are those cities? | SELECT avg(age) , city_code FROM student GROUP BY city_code | medium |
5,685 | dorm_1 | [
"dorm"
] | Find the average and total capacity of dorms for the students with gender X. | SELECT avg(student_capacity) , sum(student_capacity) FROM dorm WHERE gender = 'X' | medium |
5,686 | dorm_1 | [
"dorm"
] | What is the average and total capacity for all dorms who are of gender X? | SELECT avg(student_capacity) , sum(student_capacity) FROM dorm WHERE gender = 'X' | medium |
5,687 | dorm_1 | [
"has_amenity"
] | Find the number of dorms that have some amenity. | SELECT count(DISTINCT dormid) FROM has_amenity | easy |
5,688 | dorm_1 | [
"has_amenity"
] | How many dorms have amenities? | SELECT count(DISTINCT dormid) FROM has_amenity | easy |
5,689 | dorm_1 | [
"has_amenity",
"dorm"
] | Find the name of dorms that do not have any amenity | SELECT dorm_name FROM dorm WHERE dormid NOT IN (SELECT dormid FROM has_amenity) | hard |
5,690 | dorm_1 | [
"has_amenity",
"dorm"
] | What are the names of all the dorms that don't have any amenities? | SELECT dorm_name FROM dorm WHERE dormid NOT IN (SELECT dormid FROM has_amenity) | hard |
5,691 | dorm_1 | [
"dorm"
] | Find the number of distinct gender for dorms. | SELECT count(DISTINCT gender) FROM dorm | easy |
5,692 | dorm_1 | [
"dorm"
] | How many different genders are there in the dorms? | SELECT count(DISTINCT gender) FROM dorm | easy |
5,693 | dorm_1 | [
"dorm"
] | Find the capacity and gender type of the dorm whose name has substring ‘Donor’. | SELECT student_capacity , gender FROM dorm WHERE dorm_name LIKE '%Donor%' | medium |
5,694 | dorm_1 | [
"dorm"
] | What is the student capacity and type of gender for the dorm whose name as the phrase Donor in it? | SELECT student_capacity , gender FROM dorm WHERE dorm_name LIKE '%Donor%' | medium |
5,695 | dorm_1 | [
"dorm"
] | Find the name and gender type of the dorms whose capacity is greater than 300 or less than 100. | SELECT dorm_name , gender FROM dorm WHERE student_capacity > 300 OR student_capacity < 100 | extra |
5,696 | dorm_1 | [
"dorm"
] | What are the names and types of the dorms that have a capacity greater than 300 or less than 100? | SELECT dorm_name , gender FROM dorm WHERE student_capacity > 300 OR student_capacity < 100 | extra |
5,697 | dorm_1 | [
"student"
] | Find the numbers of different majors and cities. | SELECT count(DISTINCT major) , count(DISTINCT city_code) FROM student | medium |
5,698 | dorm_1 | [
"student"
] | How many different majors are there and how many different city codes are there for each student? | SELECT count(DISTINCT major) , count(DISTINCT city_code) FROM student | medium |
5,699 | dorm_1 | [
"has_amenity",
"dorm",
"dorm_amenity"
] | Find the name of dorms which have both TV Lounge and Study Room as amenities. | SELECT T1.dorm_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T3.amenity_name = 'TV Lounge' INTERSECT SELECT T1.dorm_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T3.amenity_name = 'Study Room' | extra |
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