query_id
int64 0
7k
| database_id
stringclasses 140
values | table_id
listlengths 1
5
| query
stringlengths 16
224
| answer
stringlengths 18
577
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
5,100 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
What are the minimum, average, and maximum quantities ordered? Check all the invoices.
|
SELECT min(Order_Quantity) , avg(Order_Quantity) , max(Order_Quantity) FROM INVOICES
|
medium
|
5,101 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
What are the distinct payment method codes in all the invoices?
|
SELECT DISTINCT payment_method_code FROM INVOICES
|
easy
|
5,102 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
Show me the distinct payment method codes from the invoice record.
|
SELECT DISTINCT payment_method_code FROM INVOICES
|
easy
|
5,103 |
cre_Drama_Workshop_Groups
|
[
"marketing_regions"
] |
What is the description of the marketing region China?
|
SELECT Marketing_Region_Descriptrion FROM Marketing_Regions WHERE Marketing_Region_Name = "China"
|
easy
|
5,104 |
cre_Drama_Workshop_Groups
|
[
"marketing_regions"
] |
Find the marketing region description of China?
|
SELECT Marketing_Region_Descriptrion FROM Marketing_Regions WHERE Marketing_Region_Name = "China"
|
easy
|
5,105 |
cre_Drama_Workshop_Groups
|
[
"products"
] |
Show all the distinct product names with price higher than the average.
|
SELECT DISTINCT Product_Name FROM PRODUCTS WHERE Product_Price > (SELECT avg(Product_Price) FROM PRODUCTS)
|
hard
|
5,106 |
cre_Drama_Workshop_Groups
|
[
"products"
] |
What are the distinct names of the products that cost more than the average?
|
SELECT DISTINCT Product_Name FROM PRODUCTS WHERE Product_Price > (SELECT avg(Product_Price) FROM PRODUCTS)
|
hard
|
5,107 |
cre_Drama_Workshop_Groups
|
[
"products"
] |
What is the name of the most expensive product?
|
SELECT Product_Name FROM PRODUCTS ORDER BY Product_Price DESC LIMIT 1
|
medium
|
5,108 |
cre_Drama_Workshop_Groups
|
[
"products"
] |
Tell me the name of the most pricy product.
|
SELECT Product_Name FROM PRODUCTS ORDER BY Product_Price DESC LIMIT 1
|
medium
|
5,109 |
cre_Drama_Workshop_Groups
|
[
"products"
] |
List all product names in ascending order of price.
|
SELECT Product_Name FROM Products ORDER BY Product_Price ASC
|
easy
|
5,110 |
cre_Drama_Workshop_Groups
|
[
"products"
] |
Sort the names of products in ascending order of their price.
|
SELECT Product_Name FROM Products ORDER BY Product_Price ASC
|
easy
|
5,111 |
cre_Drama_Workshop_Groups
|
[
"performers"
] |
What is the phone number of the performer Ashley?
|
SELECT Customer_Phone FROM PERFORMERS WHERE Customer_Name = "Ashley"
|
easy
|
5,112 |
cre_Drama_Workshop_Groups
|
[
"performers"
] |
Find the phone number of performer "Ashley".
|
SELECT Customer_Phone FROM PERFORMERS WHERE Customer_Name = "Ashley"
|
easy
|
5,113 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
Show all payment method codes and the number of orders for each code.
|
SELECT payment_method_code , count(*) FROM INVOICES GROUP BY payment_method_code
|
medium
|
5,114 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
List the distinct payment method codes with the number of orders made
|
SELECT payment_method_code , count(*) FROM INVOICES GROUP BY payment_method_code
|
medium
|
5,115 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
What is the payment method code used by the most orders?
|
SELECT payment_method_code FROM INVOICES GROUP BY payment_method_code ORDER BY count(*) DESC LIMIT 1
|
hard
|
5,116 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
Find the payment method that is used the most often in all the invoices. Give me its code.
|
SELECT payment_method_code FROM INVOICES GROUP BY payment_method_code ORDER BY count(*) DESC LIMIT 1
|
hard
|
5,117 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"stores"
] |
Which city is the address of the store named "FJA Filming" located in?
|
SELECT T1.City_Town FROM Addresses AS T1 JOIN Stores AS T2 ON T1.Address_ID = T2.Address_ID WHERE T2.Store_Name = "FJA Filming"
|
medium
|
5,118 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"stores"
] |
Find the city the store named "FJA Filming" is in.
|
SELECT T1.City_Town FROM Addresses AS T1 JOIN Stores AS T2 ON T1.Address_ID = T2.Address_ID WHERE T2.Store_Name = "FJA Filming"
|
medium
|
5,119 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"stores"
] |
What are the states or counties of the address of the stores with marketing region code "CA"?
|
SELECT T1.State_County FROM Addresses AS T1 JOIN Stores AS T2 ON T1.Address_ID = T2.Address_ID WHERE T2.Marketing_Region_Code = "CA"
|
medium
|
5,120 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"stores"
] |
Find the states or counties where the stores with marketing region code "CA" are located.
|
SELECT T1.State_County FROM Addresses AS T1 JOIN Stores AS T2 ON T1.Address_ID = T2.Address_ID WHERE T2.Marketing_Region_Code = "CA"
|
medium
|
5,121 |
cre_Drama_Workshop_Groups
|
[
"marketing_regions",
"stores"
] |
What is the name of the marketing region that the store Rob Dinning belongs to?
|
SELECT T1.Marketing_Region_Name FROM Marketing_Regions AS T1 JOIN Stores AS T2 ON T1.Marketing_Region_Code = T2.Marketing_Region_Code WHERE T2.Store_Name = "Rob Dinning"
|
medium
|
5,122 |
cre_Drama_Workshop_Groups
|
[
"marketing_regions",
"stores"
] |
Return the name of the marketing region the store Rob Dinning is located in.
|
SELECT T1.Marketing_Region_Name FROM Marketing_Regions AS T1 JOIN Stores AS T2 ON T1.Marketing_Region_Code = T2.Marketing_Region_Code WHERE T2.Store_Name = "Rob Dinning"
|
medium
|
5,123 |
cre_Drama_Workshop_Groups
|
[
"ref_service_types",
"services"
] |
What are the descriptions of the service types with product price above 100?
|
SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Price > 100
|
medium
|
5,124 |
cre_Drama_Workshop_Groups
|
[
"ref_service_types",
"services"
] |
Give me the descriptions of the service types that cost more than 100.
|
SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Price > 100
|
medium
|
5,125 |
cre_Drama_Workshop_Groups
|
[
"ref_service_types",
"services"
] |
What is the description, code and the corresponding count of each service type?
|
SELECT T1.Service_Type_Description , T2.Service_Type_Code , COUNT(*) FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code GROUP BY T2.Service_Type_Code
|
medium
|
5,126 |
cre_Drama_Workshop_Groups
|
[
"ref_service_types",
"services"
] |
List the description, code and the number of services for each service type.
|
SELECT T1.Service_Type_Description , T2.Service_Type_Code , COUNT(*) FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code GROUP BY T2.Service_Type_Code
|
medium
|
5,127 |
cre_Drama_Workshop_Groups
|
[
"ref_service_types",
"services"
] |
What is the description and code of the type of service that is performed the most often?
|
SELECT T1.Service_Type_Description , T1.Service_Type_Code FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code GROUP BY T1.Service_Type_Code ORDER BY COUNT(*) DESC LIMIT 1
|
extra
|
5,128 |
cre_Drama_Workshop_Groups
|
[
"ref_service_types",
"services"
] |
Find the description and code of the service type that is performed the most times.
|
SELECT T1.Service_Type_Description , T1.Service_Type_Code FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code GROUP BY T1.Service_Type_Code ORDER BY COUNT(*) DESC LIMIT 1
|
extra
|
5,129 |
cre_Drama_Workshop_Groups
|
[
"services",
"drama_workshop_groups"
] |
What are the phones and emails of workshop groups in which services are performed?
|
SELECT T1.Store_Phone , T1.Store_Email_Address FROM Drama_Workshop_Groups AS T1 JOIN Services AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID
|
medium
|
5,130 |
cre_Drama_Workshop_Groups
|
[
"services",
"drama_workshop_groups"
] |
Give me all the phone numbers and email addresses of the workshop groups where services are performed.
|
SELECT T1.Store_Phone , T1.Store_Email_Address FROM Drama_Workshop_Groups AS T1 JOIN Services AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID
|
medium
|
5,131 |
cre_Drama_Workshop_Groups
|
[
"services",
"drama_workshop_groups"
] |
What are the names of workshop groups in which services with product name "film" are performed?
|
SELECT T1.Store_Phone , T1.Store_Email_Address FROM Drama_Workshop_Groups AS T1 JOIN Services AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T2.Product_Name = "film"
|
medium
|
5,132 |
cre_Drama_Workshop_Groups
|
[
"services",
"drama_workshop_groups"
] |
Find the names of the workshop groups where services with product name "film" are performed.
|
SELECT T1.Store_Phone , T1.Store_Email_Address FROM Drama_Workshop_Groups AS T1 JOIN Services AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T2.Product_Name = "film"
|
medium
|
5,133 |
cre_Drama_Workshop_Groups
|
[
"products"
] |
What are the different product names? What is the average product price for each of them?
|
SELECT Product_Name , avg(Product_Price) FROM PRODUCTS GROUP BY Product_Name
|
medium
|
5,134 |
cre_Drama_Workshop_Groups
|
[
"products"
] |
For each distinct product name, show its average product price.
|
SELECT Product_Name , avg(Product_Price) FROM PRODUCTS GROUP BY Product_Name
|
medium
|
5,135 |
cre_Drama_Workshop_Groups
|
[
"products"
] |
What are the product names with average product price smaller than 1000000?
|
SELECT Product_Name FROM PRODUCTS GROUP BY Product_Name HAVING avg(Product_Price) < 1000000
|
easy
|
5,136 |
cre_Drama_Workshop_Groups
|
[
"products"
] |
Find the product names whose average product price is below 1000000.
|
SELECT Product_Name FROM PRODUCTS GROUP BY Product_Name HAVING avg(Product_Price) < 1000000
|
easy
|
5,137 |
cre_Drama_Workshop_Groups
|
[
"order_items",
"products"
] |
What are the total order quantities of photo products?
|
SELECT sum(T1.Order_Quantity) FROM ORDER_ITEMS AS T1 JOIN Products AS T2 ON T1.Product_ID = T2.Product_ID WHERE T2.Product_Name = "photo"
|
medium
|
5,138 |
cre_Drama_Workshop_Groups
|
[
"order_items",
"products"
] |
Compute the total order quantities of the product "photo".
|
SELECT sum(T1.Order_Quantity) FROM ORDER_ITEMS AS T1 JOIN Products AS T2 ON T1.Product_ID = T2.Product_ID WHERE T2.Product_Name = "photo"
|
medium
|
5,139 |
cre_Drama_Workshop_Groups
|
[
"order_items",
"products"
] |
What are the order details of the products with price higher than 2000?
|
SELECT T1.Other_Item_Details FROM ORDER_ITEMS AS T1 JOIN Products AS T2 ON T1.Product_ID = T2.Product_ID WHERE T2.Product_price > 2000
|
medium
|
5,140 |
cre_Drama_Workshop_Groups
|
[
"order_items",
"products"
] |
Find the order detail for the products with price above 2000.
|
SELECT T1.Other_Item_Details FROM ORDER_ITEMS AS T1 JOIN Products AS T2 ON T1.Product_ID = T2.Product_ID WHERE T2.Product_price > 2000
|
medium
|
5,141 |
cre_Drama_Workshop_Groups
|
[
"order_items",
"customer_orders"
] |
What are the actual delivery dates of orders with quantity 1?
|
SELECT T1.Actual_Delivery_Date FROM Customer_Orders AS T1 JOIN ORDER_ITEMS AS T2 ON T1.Order_ID = T2.Order_ID WHERE T2.Order_Quantity = 1
|
medium
|
5,142 |
cre_Drama_Workshop_Groups
|
[
"order_items",
"customer_orders"
] |
List the actual delivery date for all the orders with quantity 1
|
SELECT T1.Actual_Delivery_Date FROM Customer_Orders AS T1 JOIN ORDER_ITEMS AS T2 ON T1.Order_ID = T2.Order_ID WHERE T2.Order_Quantity = 1
|
medium
|
5,143 |
cre_Drama_Workshop_Groups
|
[
"order_items",
"products",
"customer_orders"
] |
What are the order dates of orders with price higher than 1000?
|
SELECT T1.Order_Date FROM Customer_Orders AS T1 JOIN ORDER_ITEMS AS T2 ON T1.Order_ID = T2.Order_ID JOIN Products AS T3 ON T2.Product_ID = T3.Product_ID WHERE T3.Product_price > 1000
|
hard
|
5,144 |
cre_Drama_Workshop_Groups
|
[
"order_items",
"products",
"customer_orders"
] |
Find the order dates of the orders with price above 1000.
|
SELECT T1.Order_Date FROM Customer_Orders AS T1 JOIN ORDER_ITEMS AS T2 ON T1.Order_ID = T2.Order_ID JOIN Products AS T3 ON T2.Product_ID = T3.Product_ID WHERE T3.Product_price > 1000
|
hard
|
5,145 |
cre_Drama_Workshop_Groups
|
[
"drama_workshop_groups"
] |
How many distinct currency codes are there for all drama workshop groups?
|
SELECT count(DISTINCT Currency_Code) FROM Drama_Workshop_Groups
|
easy
|
5,146 |
cre_Drama_Workshop_Groups
|
[
"drama_workshop_groups"
] |
Find the number of distinct currency codes used in drama workshop groups.
|
SELECT count(DISTINCT Currency_Code) FROM Drama_Workshop_Groups
|
easy
|
5,147 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"drama_workshop_groups"
] |
What are the names of the drama workshop groups with address in Feliciaberg city?
|
SELECT T2.Store_Name FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID WHERE T1.City_Town = "Feliciaberg"
|
medium
|
5,148 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"drama_workshop_groups"
] |
Return the the names of the drama workshop groups that are located in Feliciaberg city.
|
SELECT T2.Store_Name FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID WHERE T1.City_Town = "Feliciaberg"
|
medium
|
5,149 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"drama_workshop_groups"
] |
What are the email addresses of the drama workshop groups with address in Alaska state?
|
SELECT T2.Store_Email_Address FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID WHERE T1.State_County = "Alaska"
|
medium
|
5,150 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"drama_workshop_groups"
] |
List the email addresses of the drama workshop groups located in Alaska state.
|
SELECT T2.Store_Email_Address FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID WHERE T1.State_County = "Alaska"
|
medium
|
5,151 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"drama_workshop_groups"
] |
Show all cities along with the number of drama workshop groups in each city.
|
SELECT T1.City_Town , count(*) FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID GROUP BY T1.City_Town
|
medium
|
5,152 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"drama_workshop_groups"
] |
How many drama workshop groups are there in each city? Return both the city and the count.
|
SELECT T1.City_Town , count(*) FROM Addresses AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Address_ID = T2.Address_ID GROUP BY T1.City_Town
|
medium
|
5,153 |
cre_Drama_Workshop_Groups
|
[
"drama_workshop_groups"
] |
What is the marketing region code that has the most drama workshop groups?
|
SELECT Marketing_Region_Code FROM Drama_Workshop_Groups GROUP BY Marketing_Region_Code ORDER BY count(*) DESC LIMIT 1
|
hard
|
5,154 |
cre_Drama_Workshop_Groups
|
[
"drama_workshop_groups"
] |
Which marketing region has the most drama workshop groups? Give me the region code.
|
SELECT Marketing_Region_Code FROM Drama_Workshop_Groups GROUP BY Marketing_Region_Code ORDER BY count(*) DESC LIMIT 1
|
hard
|
5,155 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"performers",
"customers"
] |
Show all cities where at least one customer lives in but no performer lives in.
|
SELECT T1.City_Town FROM Addresses AS T1 JOIN Customers AS T2 ON T1.Address_ID = T2.Address_ID EXCEPT SELECT T1.City_Town FROM Addresses AS T1 JOIN Performers AS T2 ON T1.Address_ID = T2.Address_ID
|
hard
|
5,156 |
cre_Drama_Workshop_Groups
|
[
"addresses",
"performers",
"customers"
] |
Which cities have at least one customer but no performer?
|
SELECT T1.City_Town FROM Addresses AS T1 JOIN Customers AS T2 ON T1.Address_ID = T2.Address_ID EXCEPT SELECT T1.City_Town FROM Addresses AS T1 JOIN Performers AS T2 ON T1.Address_ID = T2.Address_ID
|
hard
|
5,157 |
cre_Drama_Workshop_Groups
|
[
"bookings"
] |
What is the most frequent status of bookings?
|
SELECT Status_Code FROM BOOKINGS GROUP BY Status_Code ORDER BY count(*) DESC LIMIT 1
|
hard
|
5,158 |
cre_Drama_Workshop_Groups
|
[
"bookings"
] |
Which status code is the most common of all the bookings?
|
SELECT Status_Code FROM BOOKINGS GROUP BY Status_Code ORDER BY count(*) DESC LIMIT 1
|
hard
|
5,159 |
cre_Drama_Workshop_Groups
|
[
"bookings",
"drama_workshop_groups"
] |
What are the names of the workshop groups that have bookings with status code "stop"?
|
SELECT T2.Store_Name FROM Bookings AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T1.Status_Code = "stop"
|
medium
|
5,160 |
cre_Drama_Workshop_Groups
|
[
"bookings",
"drama_workshop_groups"
] |
Which workshop groups have bookings with status code "stop"? Give me the names.
|
SELECT T2.Store_Name FROM Bookings AS T1 JOIN Drama_Workshop_Groups AS T2 ON T1.Workshop_Group_ID = T2.Workshop_Group_ID WHERE T1.Status_Code = "stop"
|
medium
|
5,161 |
cre_Drama_Workshop_Groups
|
[
"clients",
"bookings"
] |
Show the names of all the clients with no booking.
|
SELECT Customer_Name FROM Clients EXCEPT SELECT T2.Customer_Name FROM Bookings AS T1 JOIN Clients AS T2 ON T1.Customer_ID = T2.Client_ID
|
hard
|
5,162 |
cre_Drama_Workshop_Groups
|
[
"clients",
"bookings"
] |
What are the names of the clients who do not have any booking?
|
SELECT Customer_Name FROM Clients EXCEPT SELECT T2.Customer_Name FROM Bookings AS T1 JOIN Clients AS T2 ON T1.Customer_ID = T2.Client_ID
|
hard
|
5,163 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
What is the average quantities ordered with payment method code "MasterCard" on invoices?
|
SELECT avg(Order_Quantity) FROM Invoices WHERE payment_method_code = "MasterCard"
|
easy
|
5,164 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
Check the invoices record and compute the average quantities ordered with the payment method "MasterCard".
|
SELECT avg(Order_Quantity) FROM Invoices WHERE payment_method_code = "MasterCard"
|
easy
|
5,165 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
What is the product ID of the most frequently ordered item on invoices?
|
SELECT Product_ID FROM INVOICES GROUP BY Product_ID ORDER BY COUNT(*) DESC LIMIT 1
|
hard
|
5,166 |
cre_Drama_Workshop_Groups
|
[
"invoices"
] |
Find the id of the product ordered the most often on invoices.
|
SELECT Product_ID FROM INVOICES GROUP BY Product_ID ORDER BY COUNT(*) DESC LIMIT 1
|
hard
|
5,167 |
cre_Drama_Workshop_Groups
|
[
"ref_service_types",
"services"
] |
What is the description of the service type which offers both the photo product and the film product?
|
SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Name = 'photo' INTERSECT SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Name = 'film'
|
extra
|
5,168 |
cre_Drama_Workshop_Groups
|
[
"ref_service_types",
"services"
] |
Give me the description of the service type that offers not only the photo product but also the film product.
|
SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Name = 'photo' INTERSECT SELECT T1.Service_Type_Description FROM Ref_Service_Types AS T1 JOIN Services AS T2 ON T1.Service_Type_Code = T2.Service_Type_Code WHERE T2.Product_Name = 'film'
|
extra
|
5,169 |
music_2
|
[
"band"
] |
How many bands are there?
|
SELECT count(*) FROM Band
|
easy
|
5,170 |
music_2
|
[
"band"
] |
Find the number of bands.
|
SELECT count(*) FROM Band
|
easy
|
5,171 |
music_2
|
[
"albums"
] |
What are all the labels?
|
SELECT DISTINCT label FROM Albums
|
easy
|
5,172 |
music_2
|
[
"albums"
] |
What are the different album labels listed?
|
SELECT DISTINCT label FROM Albums
|
easy
|
5,173 |
music_2
|
[
"albums"
] |
Find all the albums in 2012.
|
SELECT * FROM Albums WHERE YEAR = 2012
|
easy
|
5,174 |
music_2
|
[
"albums"
] |
return all columns of the albums created in the year of 2012.
|
SELECT * FROM Albums WHERE YEAR = 2012
|
easy
|
5,175 |
music_2
|
[
"band",
"performance"
] |
Find all the stage positions of the musicians with first name "Solveig"
|
SELECT DISTINCT T1.stageposition FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id WHERE Firstname = "Solveig"
|
medium
|
5,176 |
music_2
|
[
"band",
"performance"
] |
What are the different stage positions for all musicians whose first name is "Solveig"?
|
SELECT DISTINCT T1.stageposition FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id WHERE Firstname = "Solveig"
|
medium
|
5,177 |
music_2
|
[
"songs"
] |
How many songs are there?
|
SELECT count(*) FROM Songs
|
easy
|
5,178 |
music_2
|
[
"songs"
] |
Count the number of songs.
|
SELECT count(*) FROM Songs
|
easy
|
5,179 |
music_2
|
[
"band",
"songs",
"performance"
] |
Find all the songs performed by artist with last name "Heilo"
|
SELECT T3.Title FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T2.Lastname = "Heilo"
|
hard
|
5,180 |
music_2
|
[
"band",
"songs",
"performance"
] |
What are the names of the songs by the artist whose last name is "Heilo"?
|
SELECT T3.Title FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T2.Lastname = "Heilo"
|
hard
|
5,181 |
music_2
|
[
"songs",
"performance",
"band"
] |
Hom many musicians performed in the song "Flash"?
|
SELECT count(*) FROM performance AS T1 JOIN band AS T2 ON T1.bandmate = T2.id JOIN songs AS T3 ON T3.songid = T1.songid WHERE T3.Title = "Flash"
|
hard
|
5,182 |
music_2
|
[
"songs",
"performance",
"band"
] |
How many musicians play in the song "Flash"?
|
SELECT count(*) FROM performance AS T1 JOIN band AS T2 ON T1.bandmate = T2.id JOIN songs AS T3 ON T3.songid = T1.songid WHERE T3.Title = "Flash"
|
hard
|
5,183 |
music_2
|
[
"band",
"songs",
"performance"
] |
Find all the songs produced by artists with first name "Marianne".
|
SELECT T3.Title FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T2.firstname = "Marianne"
|
hard
|
5,184 |
music_2
|
[
"band",
"songs",
"performance"
] |
What are the names of all songs produced by the artist with the first name "Marianne"?
|
SELECT T3.Title FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T2.firstname = "Marianne"
|
hard
|
5,185 |
music_2
|
[
"band",
"songs",
"performance"
] |
Who performed the song named "Badlands"? Show the first name and the last name.
|
SELECT T2.firstname , T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Badlands"
|
hard
|
5,186 |
music_2
|
[
"band",
"songs",
"performance"
] |
What are the first and last names of the artist who perfomed the song "Badlands"?
|
SELECT T2.firstname , T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Badlands"
|
hard
|
5,187 |
music_2
|
[
"band",
"songs",
"performance"
] |
Who is performing in the back stage position for the song "Badlands"? Show the first name and the last name.
|
SELECT T2.firstname , T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Badlands" AND T1.StagePosition = "back"
|
hard
|
5,188 |
music_2
|
[
"band",
"songs",
"performance"
] |
What are the first and last names of the performer who was in the back stage position for the song "Badlands"?
|
SELECT T2.firstname , T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Badlands" AND T1.StagePosition = "back"
|
hard
|
5,189 |
music_2
|
[
"albums"
] |
How many unique labels are there for albums?
|
SELECT count(DISTINCT label) FROM albums
|
easy
|
5,190 |
music_2
|
[
"albums"
] |
What are the unique labels for the albums?
|
SELECT count(DISTINCT label) FROM albums
|
easy
|
5,191 |
music_2
|
[
"albums"
] |
What is the label that has the most albums?
|
SELECT label FROM albums GROUP BY label ORDER BY count(*) DESC LIMIT 1
|
hard
|
5,192 |
music_2
|
[
"albums"
] |
What is the label with the most albums?
|
SELECT label FROM albums GROUP BY label ORDER BY count(*) DESC LIMIT 1
|
hard
|
5,193 |
music_2
|
[
"band",
"songs",
"performance"
] |
What is the last name of the musician that have produced the most number of songs?
|
SELECT T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId GROUP BY lastname ORDER BY count(*) DESC LIMIT 1
|
extra
|
5,194 |
music_2
|
[
"band",
"songs",
"performance"
] |
What is the last name of the musician who was in the most songs?
|
SELECT T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId GROUP BY lastname ORDER BY count(*) DESC LIMIT 1
|
extra
|
5,195 |
music_2
|
[
"band",
"performance"
] |
What is the last name of the musician that has been at the back position the most?
|
SELECT T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id WHERE stageposition = "back" GROUP BY lastname ORDER BY count(*) DESC LIMIT 1
|
extra
|
5,196 |
music_2
|
[
"band",
"performance"
] |
What is the last name of the musicians who has played back position the most?
|
SELECT T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id WHERE stageposition = "back" GROUP BY lastname ORDER BY count(*) DESC LIMIT 1
|
extra
|
5,197 |
music_2
|
[
"songs"
] |
Find all the songs whose name contains the word "the".
|
SELECT title FROM songs WHERE title LIKE '% the %'
|
medium
|
5,198 |
music_2
|
[
"songs"
] |
What are the names of the songs whose title has the word "the"?
|
SELECT title FROM songs WHERE title LIKE '% the %'
|
medium
|
5,199 |
music_2
|
[
"instruments"
] |
What are all the instruments used?
|
SELECT DISTINCT instrument FROM Instruments
|
easy
|
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