target-benchmark/spider-queries · Datasets at Hugging Face

query_id int64 0 7k	database_id stringclasses 140 values	table_id listlengths 1 5	query stringlengths 16 224	answer stringlengths 18 577	difficulty stringclasses 4 values
5,300	manufactory_1	[ "manufacturers" ]	What are the names of companies with revenue less than the lowest revenue of any manufacturer in Austin?	SELECT name FROM manufacturers WHERE revenue < (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin')	hard
5,301	manufactory_1	[ "manufacturers" ]	Find the total revenue of companies whose revenue is larger than the revenue of some companies based in Austin.	SELECT sum(revenue) FROM manufacturers WHERE revenue > (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin')	hard
5,302	manufactory_1	[ "manufacturers" ]	What is the total revenue of companies with revenue greater than the lowest revenue of any manufacturer in Austin?	SELECT sum(revenue) FROM manufacturers WHERE revenue > (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin')	hard
5,303	manufactory_1	[ "manufacturers" ]	Find the total revenue of companies of each founder.	SELECT sum(revenue) , founder FROM manufacturers GROUP BY founder	medium
5,304	manufactory_1	[ "manufacturers" ]	What is the total revenue of companies started by founder?	SELECT sum(revenue) , founder FROM manufacturers GROUP BY founder	medium
5,305	manufactory_1	[ "manufacturers" ]	Find the name and revenue of the company that earns the highest revenue in each city.	SELECT name , max(revenue) , Headquarter FROM manufacturers GROUP BY Headquarter	medium
5,306	manufactory_1	[ "manufacturers" ]	What are the names and revenues of the companies with the highest revenues in each headquarter city?	SELECT name , max(revenue) , Headquarter FROM manufacturers GROUP BY Headquarter	medium
5,307	manufactory_1	[ "manufacturers" ]	Find the total revenue for each manufacturer.	SELECT sum(revenue) , name FROM manufacturers GROUP BY name	medium
5,308	manufactory_1	[ "manufacturers" ]	What is the total revenue of each manufacturer?	SELECT sum(revenue) , name FROM manufacturers GROUP BY name	medium
5,309	manufactory_1	[ "manufacturers", "products" ]	Find the average prices of all products from each manufacture, and list each company's name.	SELECT avg(T1.price) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name	medium
5,310	manufactory_1	[ "manufacturers", "products" ]	What are the average prices of products for each manufacturer?	SELECT avg(T1.price) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name	medium
5,311	manufactory_1	[ "manufacturers", "products" ]	Find the number of different products that are produced by companies at different headquarter cities.	SELECT count(DISTINCT T1.name) , T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter	medium
5,312	manufactory_1	[ "manufacturers", "products" ]	How many different products are produced in each headquarter city?	SELECT count(DISTINCT T1.name) , T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter	medium
5,313	manufactory_1	[ "manufacturers", "products" ]	Find number of products which Sony does not make.	SELECT count(DISTINCT name) FROM products WHERE name NOT IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony')	extra
5,314	manufactory_1	[ "manufacturers", "products" ]	How many products are not made by Sony?	SELECT count(DISTINCT name) FROM products WHERE name NOT IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony')	extra
5,315	manufactory_1	[ "manufacturers", "products" ]	Find the name of companies that do not make DVD drive.	SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive'	hard
5,316	manufactory_1	[ "manufacturers", "products" ]	What are the names of companies that do not make DVD drives?	SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive'	hard
5,317	manufactory_1	[ "manufacturers", "products" ]	Find the number of products for each manufacturer, showing the name of each company.	SELECT count(*) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name	medium
5,318	manufactory_1	[ "manufacturers", "products" ]	How many products are there for each manufacturer?	SELECT count(*) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name	medium
5,319	manufactory_1	[ "products" ]	Select the names of all the products in the store.	SELECT Name FROM Products	easy
5,320	manufactory_1	[ "products" ]	What are the names of all products?	SELECT Name FROM Products	easy
5,321	manufactory_1	[ "products" ]	Select the names and the prices of all the products in the store.	SELECT name , price FROM products	medium
5,322	manufactory_1	[ "products" ]	What are the names and prices of all products in the store?	SELECT name , price FROM products	medium
5,323	manufactory_1	[ "products" ]	Select the name of the products with a price less than or equal to $200.	SELECT name FROM products WHERE price <= 200	easy
5,324	manufactory_1	[ "products" ]	What are the names of products with price at most 200?	SELECT name FROM products WHERE price <= 200	easy
5,325	manufactory_1	[ "products" ]	Find all information of all the products with a price between $60 and $120.	SELECT * FROM products WHERE price BETWEEN 60 AND 120	easy
5,326	manufactory_1	[ "products" ]	What is all the information of all the products that have a price between 60 and 120?	SELECT * FROM products WHERE price BETWEEN 60 AND 120	easy
5,327	manufactory_1	[ "products" ]	Compute the average price of all the products.	SELECT avg(price) FROM products	easy
5,328	manufactory_1	[ "products" ]	What is the average price across all products?	SELECT avg(price) FROM products	easy
5,329	manufactory_1	[ "products" ]	Compute the average price of all products with manufacturer code equal to 2.	SELECT avg(price) FROM products WHERE Manufacturer = 2	easy
5,330	manufactory_1	[ "products" ]	What is the average price of products with manufacturer codes equal to 2?	SELECT avg(price) FROM products WHERE Manufacturer = 2	easy
5,331	manufactory_1	[ "products" ]	Compute the number of products with a price larger than or equal to $180.	SELECT count(*) FROM products WHERE price >= 180	easy
5,332	manufactory_1	[ "products" ]	How many products have prices of at least 180?	SELECT count(*) FROM products WHERE price >= 180	easy
5,333	manufactory_1	[ "products" ]	Select the name and price of all products with a price larger than or equal to $180, and sort first by price (in descending order), and then by name (in ascending order).	SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC	medium
5,334	manufactory_1	[ "products" ]	What are the names and prices of products that cost at least 180, sorted by price decreasing and name ascending?	SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC	medium
5,335	manufactory_1	[ "manufacturers", "products" ]	Select all the data from the products and each product's manufacturer.	SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code	easy
5,336	manufactory_1	[ "manufacturers", "products" ]	What is all the product data, as well as each product's manufacturer?	SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code	easy
5,337	manufactory_1	[ "products" ]	Select the average price of each manufacturer's products, showing only the manufacturer's code.	SELECT AVG(Price) , Manufacturer FROM Products GROUP BY Manufacturer	medium
5,338	manufactory_1	[ "products" ]	What are the average prices of products, grouped by manufacturer code?	SELECT AVG(Price) , Manufacturer FROM Products GROUP BY Manufacturer	medium
5,339	manufactory_1	[ "manufacturers", "products" ]	Select the average price of each manufacturer's products, showing the manufacturer's name.	SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name	medium
5,340	manufactory_1	[ "manufacturers", "products" ]	What are the average prices of products, grouped by manufacturer name?	SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name	medium
5,341	manufactory_1	[ "manufacturers", "products" ]	Select the names of manufacturer whose products have an average price higher than or equal to $150.	SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150	medium
5,342	manufactory_1	[ "manufacturers", "products" ]	What are the names and average prices of products for manufacturers whose products cost on average 150 or more?	SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150	medium
5,343	manufactory_1	[ "products" ]	Select the name and price of the cheapest product.	SELECT name , price FROM Products ORDER BY price ASC LIMIT 1	medium
5,344	manufactory_1	[ "products" ]	What is the name and price of the cheapest product?	SELECT name , price FROM Products ORDER BY price ASC LIMIT 1	medium
5,345	manufactory_1	[ "manufacturers", "products" ]	Select the name of each manufacturer along with the name and price of its most expensive product.	SELECT T1.Name , max(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name	medium
5,346	manufactory_1	[ "manufacturers", "products" ]	For each manufacturer name, what are the names and prices of their most expensive product?	SELECT T1.Name , max(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name	medium
5,347	manufactory_1	[ "products" ]	Select the code of the product that is cheapest in each product category.	SELECT code , name , min(price) FROM products GROUP BY name	medium
5,348	manufactory_1	[ "products" ]	What are the codes and names of the cheapest products in each category?	SELECT code , name , min(price) FROM products GROUP BY name	medium
5,349	tracking_software_problems	[ "problem_log" ]	What is the id of the problem log that is created most recently?	SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1	medium
5,350	tracking_software_problems	[ "problem_log" ]	Which problem log was created most recently? Give me the log id.	SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1	medium
5,351	tracking_software_problems	[ "problem_log" ]	What is the oldest log id and its corresponding problem id?	SELECT problem_log_id , problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1	medium
5,352	tracking_software_problems	[ "problem_log" ]	Find the oldest log id and its corresponding problem id.	SELECT problem_log_id , problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1	medium
5,353	tracking_software_problems	[ "problem_log" ]	Find all the ids and dates of the logs for the problem whose id is 10.	SELECT problem_log_id , log_entry_date FROM problem_log WHERE problem_id = 10	medium
5,354	tracking_software_problems	[ "problem_log" ]	For the problem with id 10, return the ids and dates of its problem logs.	SELECT problem_log_id , log_entry_date FROM problem_log WHERE problem_id = 10	medium
5,355	tracking_software_problems	[ "problem_log" ]	List all the log ids and their descriptions from the problem logs.	SELECT problem_log_id , log_entry_description FROM problem_log	medium
5,356	tracking_software_problems	[ "problem_log" ]	What are the log id and entry description of each problem?	SELECT problem_log_id , log_entry_description FROM problem_log	medium
5,357	tracking_software_problems	[ "problem_log", "staff" ]	List the first and last names of all distinct staff members who are assigned to the problem whose id is 1.	SELECT DISTINCT staff_first_name , staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1	medium
5,358	tracking_software_problems	[ "problem_log", "staff" ]	Which staff members are assigned to the problem with id 1? Give me their first and last names.	SELECT DISTINCT staff_first_name , staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1	medium
5,359	tracking_software_problems	[ "problem_log", "staff" ]	List the problem id and log id which are assigned to the staff named Rylan Homenick.	SELECT DISTINCT T2.problem_id , T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick"	extra
5,360	tracking_software_problems	[ "problem_log", "staff" ]	Which problem id and log id are assigned to the staff named Rylan Homenick?	SELECT DISTINCT T2.problem_id , T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick"	extra
5,361	tracking_software_problems	[ "problems", "product" ]	How many problems are there for product voluptatem?	SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem"	medium
5,362	tracking_software_problems	[ "problems", "product" ]	How many problems did the product called "voluptatem" have in record?	SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem"	medium
5,363	tracking_software_problems	[ "problems", "product" ]	How many problems does the product with the most problems have? List the number of the problems and product name.	SELECT count() , T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count() DESC LIMIT 1	extra
5,364	tracking_software_problems	[ "problems", "product" ]	Which product has the most problems? Give me the number of problems and the product name.	SELECT count() , T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count() DESC LIMIT 1	extra
5,365	tracking_software_problems	[ "problems", "staff" ]	Give me a list of descriptions of the problems that are reported by the staff whose first name is Christop.	SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop"	medium
5,366	tracking_software_problems	[ "problems", "staff" ]	Which problems are reported by the staff with first name "Christop"? Show the descriptions of the problems.	SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop"	medium
5,367	tracking_software_problems	[ "problems", "staff" ]	Find the ids of the problems that are reported by the staff whose last name is Bosco.	SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco"	medium
5,368	tracking_software_problems	[ "problems", "staff" ]	Which problems are reported by the staff with last name "Bosco"? Show the ids of the problems.	SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco"	medium
5,369	tracking_software_problems	[ "problems" ]	What are the ids of the problems which are reported after 1978-06-26?	SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"	easy
5,370	tracking_software_problems	[ "problems" ]	Find the ids of the problems reported after 1978-06-26.	SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"	easy
5,371	tracking_software_problems	[ "problems" ]	What are the ids of the problems which are reported before 1978-06-26?	SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"	easy
5,372	tracking_software_problems	[ "problems" ]	Which problems are reported before 1978-06-26? Give me the ids of the problems.	SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"	easy
5,373	tracking_software_problems	[ "product", "problems" ]	For each product which has problems, what are the number of problems and the product id?	SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id	medium
5,374	tracking_software_problems	[ "product", "problems" ]	For each product with some problems, list the count of problems and the product id.	SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id	medium
5,375	tracking_software_problems	[ "product", "problems" ]	For each product that has problems, find the number of problems reported after 1986-11-13 and the product id?	SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id	hard
5,376	tracking_software_problems	[ "product", "problems" ]	What are the products that have problems reported after 1986-11-13? Give me the product id and the count of problems reported after 1986-11-13.	SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id	hard
5,377	tracking_software_problems	[ "product" ]	List the names of all the distinct product names in alphabetical order?	SELECT DISTINCT product_name FROM product ORDER BY product_name	easy
5,378	tracking_software_problems	[ "product" ]	Sort all the distinct product names in alphabetical order.	SELECT DISTINCT product_name FROM product ORDER BY product_name	easy
5,379	tracking_software_problems	[ "product" ]	List all the distinct product names ordered by product id?	SELECT DISTINCT product_name FROM product ORDER BY product_id	easy
5,380	tracking_software_problems	[ "product" ]	What is the list of distinct product names sorted by product id?	SELECT DISTINCT product_name FROM product ORDER BY product_id	easy
5,381	tracking_software_problems	[ "problems", "staff" ]	What are the id of problems reported by the staff named Dameon Frami or Jolie Weber?	SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber"	extra
5,382	tracking_software_problems	[ "problems", "staff" ]	Which problems were reported by the staff named Dameon Frami or Jolie Weber? Give me the ids of the problems.	SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber"	extra
5,383	tracking_software_problems	[ "problems", "staff" ]	What are the product ids for the problems reported by Christop Berge with closure authorised by Ashley Medhurst?	SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst"	extra
5,384	tracking_software_problems	[ "problems", "staff" ]	For which product was there a problem reported by Christop Berge, with closure authorised by Ashley Medhurst? Return the product ids.	SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst"	extra
5,385	tracking_software_problems	[ "problems", "staff" ]	What are the ids of the problems reported before the date of any problem reported by Lysanne Turcotte?	SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte" )	extra
5,386	tracking_software_problems	[ "problems", "staff" ]	Which problems were reported before the date of any problem reported by the staff Lysanne Turcotte? Give me the ids of the problems.	SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte" )	extra
5,387	tracking_software_problems	[ "problems", "staff" ]	What are the ids of the problems reported after the date of any problems reported by Rylan Homenick?	SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick" )	extra
5,388	tracking_software_problems	[ "problems", "staff" ]	Find the ids of the problems reported after the date of any problems reported by the staff Rylan Homenick.	SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick" )	extra
5,389	tracking_software_problems	[ "product", "problems" ]	Find the top 3 products which have the largest number of problems?	SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3	extra
5,390	tracking_software_problems	[ "product", "problems" ]	What are the three products that have the most problems?s	SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3	extra
5,391	tracking_software_problems	[ "product", "problems" ]	List the ids of the problems from the product "voluptatem" that are reported after 1995?	SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995"	medium
5,392	tracking_software_problems	[ "product", "problems" ]	What are the ids of the problems that are from the product "voluptatem" and are reported after 1995?	SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995"	medium
5,393	tracking_software_problems	[ "product", "problems", "staff" ]	Find the first and last name of the staff members who reported problems from the product "rem" but not "aut"?	SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut"	extra
5,394	tracking_software_problems	[ "product", "problems", "staff" ]	Which staff members who reported problems from the product "rem" but not "aut"? Give me their first and last names.	SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut"	extra
5,395	tracking_software_problems	[ "product", "problems", "staff" ]	Find the products which have problems reported by both Lacey Bosco and Kenton Champlin?	SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin"	extra
5,396	tracking_software_problems	[ "product", "problems", "staff" ]	Which products have problems reported by both the staff named Lacey Bosco and the staff named Kenton Champlin?	SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin"	extra
5,397	shop_membership	[ "branch" ]	How many branches where have more than average number of memberships are there?	SELECT count(*) FROM branch WHERE membership_amount > (SELECT avg(membership_amount) FROM branch)	hard
5,398	shop_membership	[ "branch" ]	What is the number of branches that have more than the average number of memberships?	SELECT count(*) FROM branch WHERE membership_amount > (SELECT avg(membership_amount) FROM branch)	hard
5,399	shop_membership	[ "branch" ]	Show name, address road, and city for all branches sorted by open year.	SELECT name , address_road , city FROM branch ORDER BY open_year	medium

5,300

manufactory_1

[ "manufacturers" ]

What are the names of companies with revenue less than the lowest revenue of any manufacturer in Austin?

SELECT name FROM manufacturers WHERE revenue < (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin')

hard

5,301

manufactory_1

[ "manufacturers" ]

Find the total revenue of companies whose revenue is larger than the revenue of some companies based in Austin.

SELECT sum(revenue) FROM manufacturers WHERE revenue > (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin')

hard

5,302

manufactory_1

[ "manufacturers" ]

What is the total revenue of companies with revenue greater than the lowest revenue of any manufacturer in Austin?

SELECT sum(revenue) FROM manufacturers WHERE revenue > (SELECT min(revenue) FROM manufacturers WHERE headquarter = 'Austin')

hard

5,303

manufactory_1

[ "manufacturers" ]

Find the total revenue of companies of each founder.

SELECT sum(revenue) , founder FROM manufacturers GROUP BY founder

medium

5,304

manufactory_1

[ "manufacturers" ]

What is the total revenue of companies started by founder?

SELECT sum(revenue) , founder FROM manufacturers GROUP BY founder

medium

5,305

manufactory_1

[ "manufacturers" ]

Find the name and revenue of the company that earns the highest revenue in each city.

SELECT name , max(revenue) , Headquarter FROM manufacturers GROUP BY Headquarter

medium

5,306

manufactory_1

[ "manufacturers" ]

What are the names and revenues of the companies with the highest revenues in each headquarter city?

SELECT name , max(revenue) , Headquarter FROM manufacturers GROUP BY Headquarter

medium

5,307

manufactory_1

[ "manufacturers" ]

Find the total revenue for each manufacturer.

SELECT sum(revenue) , name FROM manufacturers GROUP BY name

medium

5,308

manufactory_1

[ "manufacturers" ]

What is the total revenue of each manufacturer?

SELECT sum(revenue) , name FROM manufacturers GROUP BY name

medium

5,309

manufactory_1

[ "manufacturers", "products" ]

Find the average prices of all products from each manufacture, and list each company's name.

SELECT avg(T1.price) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name

medium

5,310

manufactory_1

[ "manufacturers", "products" ]

What are the average prices of products for each manufacturer?

SELECT avg(T1.price) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name

medium

5,311

manufactory_1

[ "manufacturers", "products" ]

Find the number of different products that are produced by companies at different headquarter cities.

SELECT count(DISTINCT T1.name) , T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter

medium

5,312

manufactory_1

[ "manufacturers", "products" ]

How many different products are produced in each headquarter city?

SELECT count(DISTINCT T1.name) , T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter

medium

5,313

manufactory_1

[ "manufacturers", "products" ]

Find number of products which Sony does not make.

SELECT count(DISTINCT name) FROM products WHERE name NOT IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony')

extra

5,314

manufactory_1

[ "manufacturers", "products" ]

How many products are not made by Sony?

SELECT count(DISTINCT name) FROM products WHERE name NOT IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony')

extra

5,315

manufactory_1

[ "manufacturers", "products" ]

Find the name of companies that do not make DVD drive.

SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive'

hard

5,316

manufactory_1

[ "manufacturers", "products" ]

What are the names of companies that do not make DVD drives?

SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive'

hard

5,317

manufactory_1

[ "manufacturers", "products" ]

Find the number of products for each manufacturer, showing the name of each company.

SELECT count(*) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name

medium

5,318

manufactory_1

[ "manufacturers", "products" ]

How many products are there for each manufacturer?

SELECT count(*) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name

medium

5,319

manufactory_1

[ "products" ]

Select the names of all the products in the store.

SELECT Name FROM Products

easy

5,320

manufactory_1

[ "products" ]

What are the names of all products?

SELECT Name FROM Products

easy

5,321

manufactory_1

[ "products" ]

Select the names and the prices of all the products in the store.

SELECT name , price FROM products

medium

5,322

manufactory_1

[ "products" ]

What are the names and prices of all products in the store?

SELECT name , price FROM products

medium

5,323

manufactory_1

[ "products" ]

Select the name of the products with a price less than or equal to $200.

SELECT name FROM products WHERE price <= 200

easy

5,324

manufactory_1

[ "products" ]

What are the names of products with price at most 200?

SELECT name FROM products WHERE price <= 200

easy

5,325

manufactory_1

[ "products" ]

Find all information of all the products with a price between $60 and $120.

SELECT * FROM products WHERE price BETWEEN 60 AND 120

easy

5,326

manufactory_1

[ "products" ]

What is all the information of all the products that have a price between 60 and 120?

SELECT * FROM products WHERE price BETWEEN 60 AND 120

easy

5,327

manufactory_1

[ "products" ]

Compute the average price of all the products.

SELECT avg(price) FROM products

easy

5,328

manufactory_1

[ "products" ]

What is the average price across all products?

SELECT avg(price) FROM products

easy

5,329

manufactory_1

[ "products" ]

Compute the average price of all products with manufacturer code equal to 2.

SELECT avg(price) FROM products WHERE Manufacturer = 2

easy

5,330

manufactory_1

[ "products" ]

What is the average price of products with manufacturer codes equal to 2?

SELECT avg(price) FROM products WHERE Manufacturer = 2

easy

5,331

manufactory_1

[ "products" ]

Compute the number of products with a price larger than or equal to $180.

SELECT count(*) FROM products WHERE price >= 180

easy

5,332

manufactory_1

[ "products" ]

How many products have prices of at least 180?

SELECT count(*) FROM products WHERE price >= 180

easy

5,333

manufactory_1

[ "products" ]

Select the name and price of all products with a price larger than or equal to $180, and sort first by price (in descending order), and then by name (in ascending order).

SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC

medium

5,334

manufactory_1

[ "products" ]

What are the names and prices of products that cost at least 180, sorted by price decreasing and name ascending?

SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC

medium

5,335

manufactory_1

[ "manufacturers", "products" ]

Select all the data from the products and each product's manufacturer.

SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code

easy

5,336

manufactory_1

[ "manufacturers", "products" ]

What is all the product data, as well as each product's manufacturer?

SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code

easy

5,337

manufactory_1

[ "products" ]

Select the average price of each manufacturer's products, showing only the manufacturer's code.

SELECT AVG(Price) , Manufacturer FROM Products GROUP BY Manufacturer

medium

5,338

manufactory_1

[ "products" ]

What are the average prices of products, grouped by manufacturer code?

SELECT AVG(Price) , Manufacturer FROM Products GROUP BY Manufacturer

medium

5,339

manufactory_1

[ "manufacturers", "products" ]

Select the average price of each manufacturer's products, showing the manufacturer's name.

SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name

medium

5,340

manufactory_1

[ "manufacturers", "products" ]

What are the average prices of products, grouped by manufacturer name?

SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name

medium

5,341

manufactory_1

[ "manufacturers", "products" ]

Select the names of manufacturer whose products have an average price higher than or equal to $150.

SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150

medium

5,342

manufactory_1

[ "manufacturers", "products" ]

What are the names and average prices of products for manufacturers whose products cost on average 150 or more?

SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150

medium

5,343

manufactory_1

[ "products" ]

Select the name and price of the cheapest product.

SELECT name , price FROM Products ORDER BY price ASC LIMIT 1

medium

5,344

manufactory_1

[ "products" ]

What is the name and price of the cheapest product?

SELECT name , price FROM Products ORDER BY price ASC LIMIT 1

medium

5,345

manufactory_1

[ "manufacturers", "products" ]

Select the name of each manufacturer along with the name and price of its most expensive product.

SELECT T1.Name , max(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name

medium

5,346

manufactory_1

[ "manufacturers", "products" ]

For each manufacturer name, what are the names and prices of their most expensive product?

SELECT T1.Name , max(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name

medium

5,347

manufactory_1

[ "products" ]

Select the code of the product that is cheapest in each product category.

SELECT code , name , min(price) FROM products GROUP BY name

medium

5,348

manufactory_1

[ "products" ]

What are the codes and names of the cheapest products in each category?

SELECT code , name , min(price) FROM products GROUP BY name

medium

5,349

tracking_software_problems

[ "problem_log" ]

What is the id of the problem log that is created most recently?

SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1

medium

5,350

tracking_software_problems

[ "problem_log" ]

Which problem log was created most recently? Give me the log id.

SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1

medium

5,351

tracking_software_problems

[ "problem_log" ]

What is the oldest log id and its corresponding problem id?

SELECT problem_log_id , problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1

medium

5,352

tracking_software_problems

[ "problem_log" ]

Find the oldest log id and its corresponding problem id.

SELECT problem_log_id , problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1

medium

5,353

tracking_software_problems

[ "problem_log" ]

Find all the ids and dates of the logs for the problem whose id is 10.

SELECT problem_log_id , log_entry_date FROM problem_log WHERE problem_id = 10

medium

5,354

tracking_software_problems

[ "problem_log" ]

For the problem with id 10, return the ids and dates of its problem logs.

SELECT problem_log_id , log_entry_date FROM problem_log WHERE problem_id = 10

medium

5,355

tracking_software_problems

[ "problem_log" ]

List all the log ids and their descriptions from the problem logs.

SELECT problem_log_id , log_entry_description FROM problem_log

medium

5,356

tracking_software_problems

[ "problem_log" ]

What are the log id and entry description of each problem?

SELECT problem_log_id , log_entry_description FROM problem_log

medium

5,357

tracking_software_problems

[ "problem_log", "staff" ]

List the first and last names of all distinct staff members who are assigned to the problem whose id is 1.

SELECT DISTINCT staff_first_name , staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1

medium

5,358

tracking_software_problems

[ "problem_log", "staff" ]

Which staff members are assigned to the problem with id 1? Give me their first and last names.

SELECT DISTINCT staff_first_name , staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1

medium

5,359

tracking_software_problems

[ "problem_log", "staff" ]

List the problem id and log id which are assigned to the staff named Rylan Homenick.

SELECT DISTINCT T2.problem_id , T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick"

extra

5,360

tracking_software_problems

[ "problem_log", "staff" ]

Which problem id and log id are assigned to the staff named Rylan Homenick?

SELECT DISTINCT T2.problem_id , T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick"

extra

5,361

tracking_software_problems

[ "problems", "product" ]

How many problems are there for product voluptatem?

SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem"

medium

5,362

tracking_software_problems

[ "problems", "product" ]

How many problems did the product called "voluptatem" have in record?

SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem"

medium

5,363

tracking_software_problems

[ "problems", "product" ]

How many problems does the product with the most problems have? List the number of the problems and product name.

SELECT count(*) , T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count(*) DESC LIMIT 1

extra

5,364

tracking_software_problems

[ "problems", "product" ]

Which product has the most problems? Give me the number of problems and the product name.

SELECT count(*) , T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count(*) DESC LIMIT 1

extra

5,365

tracking_software_problems

[ "problems", "staff" ]

Give me a list of descriptions of the problems that are reported by the staff whose first name is Christop.

SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop"

medium

5,366

tracking_software_problems

[ "problems", "staff" ]

Which problems are reported by the staff with first name "Christop"? Show the descriptions of the problems.

SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop"

medium

5,367

tracking_software_problems

[ "problems", "staff" ]

Find the ids of the problems that are reported by the staff whose last name is Bosco.

SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco"

medium

5,368

tracking_software_problems

[ "problems", "staff" ]

Which problems are reported by the staff with last name "Bosco"? Show the ids of the problems.

SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco"

medium

5,369

tracking_software_problems

[ "problems" ]

What are the ids of the problems which are reported after 1978-06-26?

SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"

easy

5,370

tracking_software_problems

[ "problems" ]

Find the ids of the problems reported after 1978-06-26.

SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"

easy

5,371

tracking_software_problems

[ "problems" ]

What are the ids of the problems which are reported before 1978-06-26?

SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"

easy

5,372

tracking_software_problems

[ "problems" ]

Which problems are reported before 1978-06-26? Give me the ids of the problems.

SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"

easy

5,373

tracking_software_problems

[ "product", "problems" ]

For each product which has problems, what are the number of problems and the product id?

SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id

medium

5,374

tracking_software_problems

[ "product", "problems" ]

For each product with some problems, list the count of problems and the product id.

SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id

medium

5,375

tracking_software_problems

[ "product", "problems" ]

For each product that has problems, find the number of problems reported after 1986-11-13 and the product id?

SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id

hard

5,376

tracking_software_problems

[ "product", "problems" ]

What are the products that have problems reported after 1986-11-13? Give me the product id and the count of problems reported after 1986-11-13.

SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id

hard

5,377

tracking_software_problems

[ "product" ]

List the names of all the distinct product names in alphabetical order?

SELECT DISTINCT product_name FROM product ORDER BY product_name

easy

5,378

tracking_software_problems

[ "product" ]

Sort all the distinct product names in alphabetical order.

SELECT DISTINCT product_name FROM product ORDER BY product_name

easy

5,379

tracking_software_problems

[ "product" ]

List all the distinct product names ordered by product id?

SELECT DISTINCT product_name FROM product ORDER BY product_id

easy

5,380

tracking_software_problems

[ "product" ]

What is the list of distinct product names sorted by product id?

SELECT DISTINCT product_name FROM product ORDER BY product_id

easy

5,381

tracking_software_problems

[ "problems", "staff" ]

What are the id of problems reported by the staff named Dameon Frami or Jolie Weber?

SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber"

extra

5,382

tracking_software_problems

[ "problems", "staff" ]

Which problems were reported by the staff named Dameon Frami or Jolie Weber? Give me the ids of the problems.

SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber"

extra

5,383

tracking_software_problems

[ "problems", "staff" ]

What are the product ids for the problems reported by Christop Berge with closure authorised by Ashley Medhurst?

SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst"

extra

5,384

tracking_software_problems

[ "problems", "staff" ]

For which product was there a problem reported by Christop Berge, with closure authorised by Ashley Medhurst? Return the product ids.

SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst"

extra

5,385

tracking_software_problems

[ "problems", "staff" ]

What are the ids of the problems reported before the date of any problem reported by Lysanne Turcotte?

SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte" )

extra

5,386

tracking_software_problems

[ "problems", "staff" ]

Which problems were reported before the date of any problem reported by the staff Lysanne Turcotte? Give me the ids of the problems.

SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte" )

extra

5,387

tracking_software_problems

[ "problems", "staff" ]

What are the ids of the problems reported after the date of any problems reported by Rylan Homenick?

SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick" )

extra

5,388

tracking_software_problems

[ "problems", "staff" ]

Find the ids of the problems reported after the date of any problems reported by the staff Rylan Homenick.

SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick" )

extra

5,389

tracking_software_problems

[ "product", "problems" ]

Find the top 3 products which have the largest number of problems?

SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3

extra

5,390

tracking_software_problems

[ "product", "problems" ]

What are the three products that have the most problems?s

SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3

extra

5,391

tracking_software_problems

[ "product", "problems" ]

List the ids of the problems from the product "voluptatem" that are reported after 1995?

SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995"

medium

5,392

tracking_software_problems

[ "product", "problems" ]

What are the ids of the problems that are from the product "voluptatem" and are reported after 1995?

SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995"

medium

5,393

tracking_software_problems

[ "product", "problems", "staff" ]

Find the first and last name of the staff members who reported problems from the product "rem" but not "aut"?

SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut"

extra

5,394

tracking_software_problems

[ "product", "problems", "staff" ]

Which staff members who reported problems from the product "rem" but not "aut"? Give me their first and last names.

SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut"

extra

5,395

tracking_software_problems

[ "product", "problems", "staff" ]

Find the products which have problems reported by both Lacey Bosco and Kenton Champlin?

SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin"

extra

5,396

tracking_software_problems

[ "product", "problems", "staff" ]

Which products have problems reported by both the staff named Lacey Bosco and the staff named Kenton Champlin?

SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin"

extra

5,397

shop_membership

[ "branch" ]

How many branches where have more than average number of memberships are there?

SELECT count(*) FROM branch WHERE membership_amount > (SELECT avg(membership_amount) FROM branch)

hard

5,398

shop_membership

[ "branch" ]

What is the number of branches that have more than the average number of memberships?

SELECT count(*) FROM branch WHERE membership_amount > (SELECT avg(membership_amount) FROM branch)

hard

5,399

shop_membership

[ "branch" ]

Show name, address road, and city for all branches sorted by open year.

SELECT name , address_road , city FROM branch ORDER BY open_year

medium