subject
stringclasses 1
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mathematics
|
The ratio of spinsters to cats is 2 to 7. If there are 35 more cats than spinsters, how many spinsters are there?
|
[
"14",
"21",
"28",
"35",
"42"
] |
Let 2x be the number of spinsters. Then 7x is the number of cats.
7x-2x=35
x=7 and the number of spinsters is 2(7)=14.
The answer is A.
The answer is: A
|
A
|
mathematics
|
The cost of an article (which is composed of raw materials and wages) was 3 times the value of raw materials used. The cost of raw materials increased in the ratio 3 : 7 and wages increased in the ratio 4 : 9. Find the present cost of the article if its original cost was Rs. 18.
|
[
"Rs. 41",
"Rs. 30",
"Rs. 40",
"Rs. 46",
"Rs. 56"
] |
Assume the raw materials’ cost as Rs.150, then the total cost will be Rs. 450, (Thus, wages cost is Rs. 300)
Since, the cost of raw materials goes up in the ratio of 3 : 7, the new raw material cost would become Rs. 350
The new wages cost would be in the ratio 4 : 9 as Rs. 675.
The new total cost would become, Rs. 1025.
Since Rs 450 become Rs. 1025 (change in total cost),
Unitary method calculation would give us that Rs. 18 would become Rs. 41.
ANSWER:A
The answer is: A
|
A
|
mathematics
|
What is the solution of the equations x - y = 5 and 5(x + y)-1 = 2 ?
|
[
"x = 3.75, y = 1.25",
"x = 1, y = 0.1",
"x = 2, y = 1.1",
"x = 1.2, y = 0.3",
"None"
] |
Answer
x - y = 5 ...(i)
and 11(x + y)-1=2
⇒ 5/ (x + y) = 2
⇒ 2(x + y) =5
⇒ x + y = 5/2 ...(ii)
On solving Eqs.(i) and (ii),we get
x = 3.75
and y = 1.25
Correct Option: A
The answer is: A
|
A
|
mathematics
|
The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 100 metres?
|
[
"16 seconds",
"20 seconds",
"14 seconds",
"12 seconds",
"15 seconds"
] |
Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 100 m = 100/5
= 20 seconds.
Answer: B
The answer is: B
|
B
|
mathematics
|
A tap can fill a tank in 16 minutes and another can empty it in 8 minutes. If the tank is already 1/2 full and both the taps are opened together, will the tank be filled or emptied? How long will it take before the tank is either filled completely or emptied completely as the case may be? .
|
[
"Emptied; 16 mins",
"Filled; 8 mins",
"Emptied; 12 mins",
"Filled; 12 mins",
"None of These"
] |
if A and B open together
since B can empty faster than A so tank will empty not fill.
the whole tank will empty in 16*8/(16-8)
=16 min
since tank is half so it will take only 8 min to empty.
ANSWER:E
The answer is: E
|
E
|
mathematics
|
A car traveling at a certain constant speed takes 10 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 40 kilometers per hour. At what speed, in kilometers per hour, is the car traveling?
|
[
"35",
"35.5",
"36",
"36.5",
"37"
] |
40 * T = 1 km => T = 1/40 km/h
V*(T+10/3600) = 1
V (1/40 + 10/3600) = 1
V (100/3600) = 1
V = 36 km/h
The answer is C.
The answer is: C
|
C
|
mathematics
|
At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/9 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?
|
[
"1/2",
"2/5",
"3/4",
"4/5",
"5/8"
] |
Method: X = No. of boxes loaded by day crew.
Boxes by night crew = 3/4 * 4/9 X = 1/3 X
% loaded by day crew = X/(X + 1/3X) = 3/4
Answer C
The answer is: C
|
C
|
mathematics
|
Which one of the following numbers is exactly divisible by 11?
|
[
"235641",
"245642",
"315624",
"415624",
"Done"
] |
(4 + 5 + 2) - (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) - (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 4) = 0, So, 415624 is divisible by 11.
D)
The answer is: D
|
D
|
mathematics
|
The sum of two numbers is 35. Their difference is 5. The bigger number is
|
[
"20",
"25",
"30",
"35",
"45"
] |
X + Y = 35
X - Y = 5
Adding 2X = 40 ==> X = 20 and Y = 35 - 20 = 15
Bigger number is X = 20
Answer A.
The answer is: A
|
A
|
mathematics
|
In how many ways can 4 black and 4 white chess pieces be arranged in a row such that they occupy alternate places? Assume that the pieces are distinct.
|
[
"144",
"24",
"576",
"48",
"16"
] |
4 black chess pieces can be arranged in 4! ways and 4 white pieces can be arranged in 4! ways.
W_W_W_W
Number of ways = 4!*4! = 24 * 24 = 576
Answer C
The answer is: C
|
C
|
mathematics
|
A perfect square is defined as the square of an integer and a perfect cube is defined as the cube of an integer. How many positive integers n are there such that n is less than 30,000 and at the same time n is a perfect square and a perfect cube?
|
[
"4",
"5",
"6",
"7",
"8"
] |
If n is a perfect square and a perfect cube, then n = a^6 for some integer a.
The numbers are 1^6=1, 2^6=64, 3^6= 729, 4^6=4096, 5^6=15,625.
The answer is B.
The answer is: B
|
B
|
mathematics
|
A boat running downstream covers a distance of 22 km in 4 hours while for covering the same distance upstream, it takes 5 hours. What is the speed of the boat in still water?
|
[
"2.75",
"5.95",
"7.95",
"3.25",
"4.95"
] |
Speed downstream =22/4 = 5.5 kmph
Speed upstream =22/5 = 4.4 kmph
Speed of the boat in still water=(5.5+4.4)/2= 4.95 kmph
Answer: E
The answer is: E
|
E
|
mathematics
|
a,b and c are positive integers less than or equal to 9. If a,b and c are assembled into the six-digit number aabbcc, which of the following must be a factor of aabbcc?
|
[
"9",
"3",
"7",
"11",
"None of these"
] |
The sum of the digits in place 1,3 and 5 is a+b+c is equal to the sum of the digits in place 2,4 and 6 which is a+b+c. thus the number abcabc is divisible by 11. thus 11 must be a factor of abcabc.
Answer: D
The answer is: D
|
D
|
mathematics
|
A train 400 m long can cross an electric pole in 40 sec and then find the speed of the train?
|
[
"36 Kmph",
"40 Kmph",
"42 Kmph",
"45 Kmph",
"38 Kmph"
] |
Length = Speed * time
Speed = L/T
S = 400/40
S = 10 M/Sec
Speed= 10*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 36 Kmph
ANSWER:A
The answer is: A
|
A
|
mathematics
|
Mike weighs twice as much as Mary. Mike's weight is 150% of Michelle's weight. Alan weighs 140% of Charlie's weight. Charlie weighs 180% of Mary's weight. Which of these 5 people weighs the highest?
|
[
"Mary",
"Mike",
"Michelle",
"Alan",
"Charlie"
] |
Mary < Michelle < Mike
Charlie < Alan
Let x be Mary's weight.
Mike's weight is 2x and Alan's weight is 1.4*1.8x = 2.52x.
The answer is D.
The answer is: D
|
D
|
mathematics
|
Each of three investments has a 20% of becoming worthless within a year of purchase, independently of what happens to the other two investments. If Simone invests an equal sum in each of these three investments on January 1, the approximate chance that by the end of the year, she loses no more than 1/3 of her original investment is
|
[
"90%",
"80%",
"70%",
"60%",
"40%"
] |
Since amount invested is same for all 3 , and probability of investment turning worthless is 20%, the required probability is
80%×80%×80% + 20%×80%×80×\frac{3!}{2!}
=89.6%
Answer A
The answer is: A
|
A
|
mathematics
|
Find the total number of prime factors in the expression (4)11 x (7)5 x (11)2.
|
[
"22",
"29",
"19",
"5",
"2"
] |
(4)11x (7)5 x (11)2 = (2 x 2)11 x (7)5 x (11)2 = 211 x 211 x75x 112
= 222 x 75 x112
Total number of prime factors = (22 + 5 + 2)
= 29.
ANSWER B 29
The answer is: B
|
B
|
mathematics
|
(((13!)^16)-((13!)^8))/(((13!)^8)+((13!)^4))=a
then what is the units digit for a/((13!)^4)=
|
[
"7",
"8",
"9",
"6",
"5"
] |
(((13!)^16)-((13!)^8))/(((13!)^8)+((13!)^4))=a
solving it , we get
a/((13!)^4)= ((13!)^4-1)
last digit of (13!)^4 will be 0.
so last digit of ((13!)^4-1) will be 9.
ANSWER:C
The answer is: C
|
C
|
mathematics
|
Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.88 at the candy store. What is John’s weekly allowance?
|
[
"$2.70",
"$3.00",
"$3.30",
"$3.60",
"$3.90"
] |
x = 3x/5 + 1/3*2x/5 + 88
4x/15 = 88
x = 330 = $3.30
The answer is C.
The answer is: C
|
C
|
mathematics
|
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
|
[
"5 kmph",
"6 kmph",
"6.25 kmph",
"7.5 kmph",
"7 kmph"
] |
Let Abhay's speed be x km/hr.
Then,30/x -30/2x = 3
6x = 30
x = 5 km/hr
Answer:A
The answer is: A
|
A
|
mathematics
|
Aman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?
|
[
"12:15:17",
"12:15:16",
"12:15:10",
"12:15:155",
"12:15:11"
] |
Aman : Rakhi : Sagar = (70000 * 36) : (105000 * 30) : (140000 * 24)
= 12:15:16
Answer: B
The answer is: B
|
B
|
mathematics
|
A is faster than B. A and B each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then, A's speed is equal to?
|
[
"6 km/hr",
"3 km/hr",
"1 km/hr",
"9 km/hr",
"4 km/hr"
] |
Let A's speed = x km/hr. Then, B's speed = (7 - x) km/ hr.
So, 24/x + 24/(7 - x) = 14
x2 - 98x + 168 = 0
(x - 3)(x - 4) = 0 => x = 3 or 4.
Since, A is faster than B, so A's speed = 4 km/hr and B's speed = 3 km/hr.
Answer: B
The answer is: B
|
B
|
mathematics
|
Two men and 7 children complete a certain piece of work in 4 days while 4 men and 4 children complete the same work in only 3 days. The number of days required by 1 man to complete the work is
|
[
"60 days",
"15 days",
"6 days",
"51 days",
"50 days"
] |
Two men and 7 children complete a certain piece of work in 4 days
or 8 men and 28 children complete a certain piece of work in 1 days
4 men and 4 children complete the same work in only 3 days.
or 12 men and 12 children complete the same work in only 3 days.
so 8 men +28 children = 12 men +12 children
1Man = 4 children
4 men and 4 children complete the same work in only 3 days
or 4 men and 1 man ( in place of 4 children ) complete the same work in only 3 days
or 5 men complete the same work in 3 days
or 1 man will complete the same work in 5* 3 =15 days
ANSWER:B
The answer is: B
|
B
|
mathematics
|
The average of six numbers is 3.85. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers ?
|
[
"4.3",
"4.6",
"4.2",
"4.1",
"4.9"
] |
Explanation:
Sum of the remaining two numbers = (3.85 * 6) - [(3.4 * 2) + (3.85 * 2)]
= 23.10 - (6.8 + 7.7) = 23.10 - 14.5 = 8.60.
Required average = (8.6 / 2) = 4.3.
Answer: A) 4.3
The answer is: A
|
A
|
mathematics
|
A salesman sold twice as much pears in the afternoon than in the morning. If he sold 360 kilograms of pears that day, how many kilograms did he sell in the morning and how many in the afternoon?
|
[
"150",
"190",
"100",
"240",
"280"
] |
Let x be the number of kilograms he sold in the morning.Then in the afternoon he sold 2x kilograms. So, the total is x+2x=3x This must be equal to 360.
3x=360
x=360/3
x=120
Therefore, the salesman sold 120 kg in the morning and 2⋅120=240 kg in the afternoon.
The answer is: D
|
D
|
mathematics
|
A single discount equivalent to the discount series of 20%, 10% and 5% is?
|
[
"31.6",
"31.9",
"31.6",
"31.4",
"31.1"
] |
100*(80/100)*(90/100)*(95/100) = 68.4
100 - 68.4 = 31.6
Answer: A
The answer is: A
|
A
|
mathematics
|
Connie paid a sales tax of 8 percent on her purchase. If the sales tax had been only 5 percent, she would have paid $12 less in sales tax on her purchase. What was the total amount that Connie paid for her purchase including sales tax?
|
[
"$368",
"$380",
"$400",
"$420",
"$432"
] |
Connie paid x dollar before sales tax
so,
1.08x - 1.05x = 12
0.03x = 12
x = 400
sales tax 400*8% = 32
Connie paid = 400+32= $432
Ans. E
The answer is: E
|
E
|
mathematics
|
The no. of girls in a class are seven times the no. of boys, which value can neverbe the of total students?
|
[
"4",
"5",
"8",
"10",
"12"
] |
Let the boys are X, then girls are 7X, total = X+7X = 8X
So it should be multiple of 8, 30 is not a multiple of 8.
C
The answer is: C
|
C
|
mathematics
|
John traveled 80% of the way from Yellow-town to Green-fields by train at an average speed of 80 miles per hour. The rest of the way John traveled by car at an average speed of v miles per hour. If the average speed for the entire trip was 60 miles per hour, what is v in miles per hour?
|
[
"30",
"40",
"50",
"55",
"70"
] |
Let distance be D.
We can find the total time & equate it, which comes as:
0.8D / 80 + 0.2D / v = D / 60
=> v = 30
ANSWER:A
The answer is: A
|
A
|
mathematics
|
A train 130 m long passes a man,running at 6 kmph in the direction opposite to that of the train,in 6 seconds.The speed of the train is
|
[
"54 kmph",
"60 kmph",
"66 kmph",
"72 kmph",
"82 kmph"
] |
speed of train relative to man: 130/6 * 18/5 km/hr
= 78 km/hr
let speed of train= x
therefore x+6 = 78
x= 78-6
x=72 km/hr
ANSWER:D
The answer is: D
|
D
|
mathematics
|
The total marks obtained by a student in Mathematics and Physics is 32 and his score in Chemistry is 20 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together.
|
[
"40",
"26",
"27",
"28",
"22"
] |
Let the marks obtained by the student in Mathematics, Physics and Chemistry be M, P and C respectively.
Given , M + C = 32 and C - P = 20 M + C / 2 = [(M + P) + (C - P)] / 2 = (32 + 20) / 2 = 26.Answer:B
The answer is: B
|
B
|
mathematics
|
24 oz of juice P and 25 oz of juice V are mixed to make smothies R and Y . The ratio of p to V in smothie R is 4 is to 1 and that in Y is 1is to 5.How many ounces of juice P are contained in the smothie R?
|
[
"5",
"10",
"15",
"20",
"25"
] |
The ratio of p to V in smothie R is 4 is to 1 and that in Y is 1is to 5. p1 + p2 = 24
v1 + v2 = 25
p1 = 4v1
p2 = v2/5
4v1 + v2/5 = 24
v1 + v2 = 25
4v2 - v2/5 = 76
19v2/5 = 76 => v2 = 20
=> v1 = 5
=> p1 = 20
Answer - D
The answer is: D
|
D
|
mathematics
|
A man can row 5 kmph in still water. When the river is running at 2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
|
[
"5.75",
"5.7",
"5.76",
"4.2",
"5.71"
] |
M = 5
S = 2
DS = 7
US = 3
x/7 + x/3 = 1
x = 2.1
D = 2.1 * 2 = 4.2 Answer: D
The answer is: D
|
D
|
mathematics
|
The amount of time that three people worked on a special project was in the ratio of 1 to 2 to 3. If the project took 120 hours, how many more hours did the hardest working person work than the person who worked the least?
|
[
"35 hours",
"40 hours",
"36 hours",
"38 hours",
"42 hours"
] |
Let the persons be A, B, C.
Hours worked:
A = 1*120/6 = 20 hours
B = 2*120/6 = 40 hours
C = 3*120/6 = 60 hours
C is the hardest worker and A worked for the least number of hours. So the difference is 60-20 = 40 hours.
Answer : B
The answer is: B
|
B
|
mathematics
|
A and B can do a piece of work in 8 days. B and C can do it in 12 days and A and C in 16 days. Working together they will complete the work in how many days?
|
[
"7.78 days",
"7.88 days",
"7.38 days",
"7.38 days",
"7.36 days"
] |
A + B = 1/8
B + C = 1/12
C + A = 1/16
-------------------------------
2(A + B +C) = 1/8 + 1/12 + 1/16 = 13/48
A + B +C = 13/96
96/13 = 7.38 days
Answer: D
The answer is: D
|
D
|
mathematics
|
Sandy bought 65 books for $1380 from one shop and 55 books for $900 from another shop. What is the average price that Sandy paid per book?
|
[
"$13",
"$15",
"$17",
"$19",
"$21"
] |
average price per book = (1380 + 900) / (65 + 55) = 2280 / 120 = $19
The answer is D.
The answer is: D
|
D
|
mathematics
|
A gets 3 times as much money as B gets, B gets only Rs.25 more then what C gets. The three gets Rs.675 in all. Find the share of B?
|
[
"287",
"219",
"168",
"140",
"779"
] |
A+B+C = 675
A = 3B
3B+B+B-25 = 675
5B = 700
B = 140
Answer: D
The answer is: D
|
D
|
mathematics
|
575.104 x 15.98 ÷ 9.001 + 21.25 = ?
|
[
"983.578",
"1043.65",
"1033.65",
"656.112",
"456.512"
] |
Explanation:
? = 575.104 x 15.98 ÷ 9.001 + 21.25
≈ (575.104 x 16/9) + 21.25 ≈ 1022.40 + 21.25 ≈ 1043.65
Answer: Option B
The answer is: B
|
B
|
mathematics
|
P is a set of four numbers 1, 2, 3 and 1. In every step, one is added to any two numbers in the set P. In how many such steps is it possible to make all the four numbers in the set P equal?
|
[
"4",
"5",
"6",
"1",
"2"
] |
If all the four numbers are equal, then their sum in the end of the process must be multiple of 4.
Now the sum of the given numbers is equal to 7. Each time we are adding 1 to two of any two numbers, so the sum increases by 2 each time. So the sum never becomes a multiple of 4 as odd + even = always odd.
Answer:A
The answer is: A
|
A
|
mathematics
|
If N = 2^0.15 and N^b = 1, b must equal
|
[
"3/80",
"20/3",
"4",
"5/3",
"80/3"
] |
15/100 = 3/20
N = 2 ^ 3/20
N^b = 2^1
(2^3/20)^b = 2^1
b = 20/3
Answer: B
The answer is: B
|
B
|
mathematics
|
A began business with 10000 and is joined afterwards by B with 20000. When did B join, if the profits at the end of the year are divided equally?
|
[
"8 months",
"9 months",
"6 months",
"7 months",
"None of these"
] |
Let B join after x months of the start of the business so that B’s money is invested for (12 – x) months.
∴ Profit ratio is 12 × 10000 : (12 – x) × 20000
or 12 : 2(12 – x)
Since profit is equally divided so
12 = 2(12 – x) or x = 6. Thus B joined after 8 months.
Answer C
The answer is: C
|
C
|
mathematics
|
What should be added to 4872 so that it may become a perfect square?
|
[
"24",
"25",
"26",
"27",
"28"
] |
70x70=4900
4900-4872 = 28
If added to 28 get perfect square
answer =E
The answer is: E
|
E
|
mathematics
|
Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both. If 62 percent of these who attended the meeting were stockholders and 51 percent were employees. What percent were stockholders, who were not employees?
|
[
"52",
"49",
"54",
"55",
"56"
] |
I came up with the same answer choice B, but my approach was slightly different!
51% were employees which shall cover those who were only employees and those who were both shareholders and employees.
Thus, the number of attendants who were only shareholders is 100% - 51% = 49%.
The answer is: B
|
B
|
mathematics
|
Mary invested a certain sum of money in a bank that paid simple interest. The amount grew to $260 at the end of 2 years. She waited for another 3 years and got a final amount of $350. What was the principal amount that she invested at the beginning?
|
[
"$220",
"$230",
"$240",
"$200",
"$250"
] |
What shall be the rate of interest.? Does that is not required for the calculation?
Not really!
Keep in mind that the interest earned each year will be the same in Simple Interest.
At the end of 2 years, Amount = $260
At the end of 5 years, Amount = $350
This means she earned an interest of $90 in 3 years. Or $30 in each year.
We know that the interest earned each year will be the same.
Therefore she must have earned $60 in 2 years.
Hence Principal Amount = $260 - $60 = $200 Option D
The answer is: D
|
D
|
mathematics
|
Three workers have a productivity ratio of 2 to 4 to 8. All three workers are working on a job for 4 hours. At the beginning of the 5th hour, the slowest worker takes a break. The slowest worker comes back to work at the beginning of the 9th hour and begins working again. The job is done in ten hours. What was the ratio of the work performed by the fastest worker as compared to the slowest?
|
[
"20 to 3",
"6 to 1",
"5 to 1",
"1 to 6",
"1 to 5"
] |
The fastest worker who does 8 units of job worked for all 10 hours, so he did 8*10=80 units of job;
The slowest worker who does 2 unit of job worked for only 4+2=6 hours (first 4 hours and last 2 hours), so he did 2*6=12 units of job;
The ratio thus is 80 to 12, or 20 to 3.
Answer: A.
The answer is: A
|
A
|
mathematics
|
If $500 was invested at an annual interest rate of 5.6% compounded annually, which of the following represents the amount the investment was worth after 3 years?
|
[
"500 (1.056)(3)",
"500 (3+1.056)",
"500 (1+3(0.056))",
"500 (1.056)^3",
"500 (1+(0.056)^3)"
] |
the formula is CI=P(1+r/100)^t
in this case i think D is the ans
The answer is: D
|
D
|
mathematics
|
W and X start a business with Rs.5000 and Rs.20000 respectively. Hoe should they share their profits at the end of one year?
|
[
"4:1",
"1:3",
"1:4",
"1:5",
"2:1"
] |
They should share the profits in the ratio of their investments.
The ratio of the investments made by W and X =
5000 : 20000 => 1:4 .
Answer:C
The answer is: C
|
C
|
mathematics
|
The operation # is defined for all nonzero d and y by d#y = d + d/y. If a>0, then 1#(1#a) =
|
[
"a",
"a+1",
"a/(a+1)",
"(a+2)/(a+1)",
"(2a+1)/(a+1)"
] |
d#y = d + d/y. If a>0, then 1#(1#a) =
You can see that a stands for y and 1 stands for d. I like to work with numbers so I did d=1 a=2 and a=y so y=2
1#a= 1+(1/2)=1.5 so now a is 1.5 --> 1+(1/1.5)=1 2/3 = 5/3
So now you can check by filling in a, which is 2:
A. a --> 2
B. a+1 --> 2+1=3
C. a/(a+1)-->2/(2+1)=2/3
D. (a+2)/(a+1)-->(2+2)/(2+1)=4/3
E. (2a+1)/(a+1)-->(2*2+1)/(2+1)=5/3
So E is the answer.
The answer is: E
|
E
|
mathematics
|
A type W machine can complete a job in 5 hours and a type B machine can complete the job in 7 hours. How many hours will it take 2 type W machines and 3 type B machines working together and independently to complete the job?
|
[
"1/5",
"29/35",
"5/6",
"35/29",
"35/12"
] |
now D should be the answer.
W need 5 hours to complete
and B needs 7 hours to compete
so 2W + 3B will complete 2/5 + 3/7 or 29/35 portion of the job in 1 hour
so the whole job will take 35/29 hours....=D
The answer is: D
|
D
|
mathematics
|
In a village of 100 households, 85 have at least one DVD player, 90 have at least one cell phone, and 55 have at least one MP3 player. If x and y are respectively the greatest and lowest possible number of households that have all three of these devices, x – y is:
|
[
"65",
"55",
"45",
"35",
"25"
] |
Am I missing something here??? it seems straightforward......
The obvious maximum that have all 3 is 55, because you are limited by the SMALLEST number.
The minimum is simply the sum of the max of each people who DONT have the product, so:
100-90 = 10 don't have Cell
100-85 = 15 don't have DVD
and 100-55 = 45 don't have MP3
SO a total of 10+15+45 = 70 combined who might NOT have SOME combination of the 3 products. So subtract that from 100, to give you the minimum of the people who COULD have all 3 and you get 100-70 = 30.
55-30 = 25
E
The answer is: E
|
E
|
mathematics
|
What is the greatest prime factor of (11!10!) + (11!12!)?
|
[
"11",
"17",
"19",
"23",
"29"
] |
11!10! + 11!12!
= 11!10! (1+11*12)
= 12!11!(133)
= 12!11!(7*19)
The greatest prime factor is 19.
The answer is C.
The answer is: C
|
C
|
mathematics
|
The average weight of 8 person's increases by 4.2 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person?
|
[
"75 Kg",
"50 Kg",
"85 Kg",
"80 Kg",
"98.6 KG"
] |
Explanation:
Total increase in weight = 8 × 4.2 = 33.6
If x is the weight of the new person, total increase in weight = x−65
=> 33.6 = x - 65
=> x = 33.6 + 65 = 98.6
Answer: Option E
The answer is: E
|
E
|
mathematics
|
Divide Rs. 5500 among A, B and C so that A receives 1/3 as much as B and C together and B receives 1/5 as A and C together. A's share is?
|
[
"1227",
"1268",
"1375",
"1200",
"1210"
] |
A+B+C = 5500
A = 1/3(B+C); B = 1/5(A+C)
A/(B+C) = 1/3
A = 1/4 * 5500 => 1375
Answer: C
The answer is: C
|
C
|
mathematics
|
A flight takes off at 2.00 a.m. from a place at 18N 10E and landed 10 hours later at a place with co-ordinates 36N 70W. What is the local time when the plane landed?
|
[
"6.00 a.m.",
"6.40 a.m.",
"7.00 a.m.",
"7.40 a.m.",
"8.00 a.m."
] |
Time difference between places will be 4*(70+10) minutes = 320 min =
5 hrs 20 min
as change of 1 degree in longitude cause change of 4 minutes in time.
and that change is 80 degrees here.
so when plane land. time will be = 2.00 + 10.00 -5.20 = 6.40 a.m.
ANSWER:B
The answer is: B
|
B
|
mathematics
|
A motor boat takes 12 hours to go downstream and it takes 24 hours to return the same distance. what is the time taken by boat in still water?
|
[
"26 h",
"16 h",
"86 h",
"96 h",
"66 h"
] |
Explanation:
If t1 and t2 are the upstream and down stream times. Then time taken in still water is given by
\inline \frac{2\times t1\times t2}{t1+t2}=\frac{2\times 12\times 24}{36}=16h
Answer: B
The answer is: B
|
B
|
mathematics
|
A cyclist rides a bicycle over a route which is 1/3 uphill, 1/3 level, and 1/3 downhill. If the cyclist covers the uphill part of the route at the rate of 8 km per hour and the level part at the rate of 12 km per hour, what rate in km per hour would the cyclist have to travel the downhill part of the route in order to average 12 km per hour for the entire route?
|
[
"16",
"20",
"24",
"28",
"32"
] |
Let V be the speed on the downhill section.
Let D be the distance of each of the three equal sections.
Total time T = T1+T2+T3 and 3D/T = 12 km/hour
3D / (D/8 + D/12 + D/V) = 12
1/4 = 1/8 + 1/12 + 1/V
1/V = 1/24 and so V = 24 km/h
The answer is C.
The answer is: C
|
C
|
mathematics
|
if x+y+z=9 and both y and z are positive integers greater than zero, then the maximum value x can take is?
|
[
"7",
"3",
"8",
"6",
"data insufficient"
] |
if y=z=1, then x will be equal to 7.
ANSWER:A
The answer is: A
|
A
|
mathematics
|
A grocer has a sale of Rs. 2500, Rs. 4000, Rs. 3540 for 3 consecutive months. How much sale must he have in the fourth month so that he gets an average sale of Rs. 2890?
|
[
"Rs.3500",
"Rs. 1520",
"Rs. 4996",
"Rs. 4000",
"Rs. 900"
] |
Total sale for 5 months = Rs. ( 2500 + 4000 + 3540) = Rs. 10040.
Required sale = Rs. [ (2890 x 4) -10040 ]
= Rs. (11560 - 10040)
= Rs. 1520.
B)
The answer is: B
|
B
|
mathematics
|
If b is the sum of consecutive even integers w, x, y, and z, where w < x < y < z, all of the following must be true EXCEPT
|
[
"z - w = 3(y - x)",
"b is divisible by 8",
"The average of w, x, y, and z is odd",
"b is divisible by 4",
"w + x + 8 = y + z"
] |
Just assume that the numbers are 2a, 2a+2, 2a+4 and 2a+6.
b = 2a + 2a+2 + 2a+4 + 2a+6 = 8a + 12
Focus on the easiest options first. You see that b is not divisible by 8. Answer (B)
The answer is: B
|
B
|
mathematics
|
What is the ratio whose terms differ by 40 and the measure of which is 2⁄7
|
[
"16 : 56",
"14 : 56",
"15 : 56",
"16 : 72",
"None of these"
] |
Let the ratio be x: (x + 40).Then,
x/(x+40)=2/7 ⇒ 2x + 80 ⇒ x = 16.
∴ Required ratio = 16 : 56.
Answer A
The answer is: A
|
A
|
mathematics
|
If 2805 / 2.55 = 1100, then 280.5 / 25.5 is equal to ?
|
[
"1.01",
"1.1",
"0.11",
"11",
"None"
] |
Answer
Given expression 280.5 / 25.5 = 2805 / 255
= 2805 / (2.55 x 100)
= 1100 / 100
=11
Correct Option: D
The answer is: D
|
D
|
mathematics
|
If three machines working at the same rate can do 3/4 of a job in 30 minutes, how many minutes would it take two machines working at the same rate to do 3/5 of the job?
|
[
"36",
"60",
"75",
"80",
"100"
] |
using the std formula
m1d1h1/w1=m2d2h2/w2
substituting the values we have
3*1/2*4/3=2*5/3*x (converted 30 min into hours =1/2)
2=10/3*x
x=3/5 hour
so 36 minutes
ANSWER:A
The answer is: A
|
A
|
mathematics
|
At present, the ratio between the ages of Amit and Dhiraj is 5 : 4. After 6 years, Amit’s age will be 26 years. What is the age of Dhiraj at present?
|
[
"16",
"77",
"566",
"197",
"161"
] |
Explanation:
Let the present ages of Amit and Dhiraj be 5x years and 4x years respectively. Then,
5x + 6 = 26
5x = 20
x = 4
Dhiraj’s age = 4x = 16 years
ANSWER: A
The answer is: A
|
A
|
mathematics
|
Cindy has her eye on a sundress but thinks it is too expensive. It goes on sale for 15% less than the original price. Before Cindy can buy the dress, however, the store raises the new price by 25%. If the dress cost $85 after it went on sale for 15% off, what is the difference between the original price and the final price?
|
[
"$0.00",
"$1.00",
"$3.40",
"$5.00",
"$6.25"
] |
0.85*{Original Price} = $85 --> {Original Price} = $100.
{Final Price} = $85*1.25 = $106.25.
The difference = $106.25 - $100 = $6.25.
Answer: E.
The answer is: E
|
E
|
mathematics
|
If 8 spiders make 4 webs in 9 days, then how many days are needed for 1 spider to make 1 web?
|
[
"10",
"20",
"12",
"16",
"18"
] |
Explanation:
Let, 1 spider make 1 web in x days.
More spiders, Less days (Indirect proportion)
More webs, more days (Direct proportion)
Hence we can write as
(spiders)8:1
(webs) 1:9}::x:4
⇒8×1×9=1×4 × x
⇒x=18
Answer: Option E
The answer is: E
|
E
|
mathematics
|
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively . If they cross each other in 23 seconds, what is the ratio of their speeds?
|
[
"3/2",
"1/2",
"4/3",
"3/4",
"1/5"
] |
Let the speed of the trains be x and y respectively
length of train1 = 27x
length of train2 = 17y
Relative speed= x+ y
Time taken to cross each other = 23 s
=> (27x + 17 y)/(x+y) = 23
=> (27x + 17 y)/ = 23(x+y)
=> 4x = 6y
=> x/y = 6/4 = 3/2
Answer is A.
The answer is: A
|
A
|
mathematics
|
At a certain organisation, the number of male members went up by 15% in the year 2001 from year 2000, and the number of females members went down by 6% in the same time period. If the total membership at the organisation went up by 1.2% from the year 2000 to 2001, what was the ratio of male members to female members in the year 2000?
|
[
"1:2",
"1:3",
"2:3",
"3:2",
"2:1"
] |
men increase by 15% ==> 1.15M = males in 2001
women decrease by 6% ==> 0.94F = women in 2001
total employees increase by 1.2% ==> 1.012*(M + F) = total number of employees in 2001
Obviously
(males in 2001) + (females in 2001) = total number of employees in 2001
1.15M + 0.94F = 1.012*(M + F)
1.15M + 0.94F = 1.012M + 1.012F
1.15M - 1.012M = 1.012F - 0.94F
0.138M = 0.072F
M/F = (0.072)/(0.138) = 72/138 = 1/2
Answer =(A)
The answer is: A
|
A
|
mathematics
|
What Is The Next Number
12 13 15 17 111 113 ?
|
[
"154",
"220",
"129",
"428",
"117"
] |
117
These are the first 10 prime numbers (2, 3, 5...) prefixed with a 1
Answer : E
The answer is: E
|
E
|
mathematics
|
The third proportional to 1 and 3 is?
|
[
"9",
"10",
"11",
"12",
"13"
] |
(3*3)/1 = 9
ANSWER:A
The answer is: A
|
A
|
mathematics
|
The H.C.F. and L.C.M. of two numbers are 10 and 5040 respectively If one of the numbers is 144, find the other number
|
[
"400",
"256",
"350",
"420",
"None of these"
] |
Explanation:
Solve this question by using below formula.
Product of 2 numbers = product of their HCF and LCM
144 * x = 10 * 5040
x = (10*5040)/144 = 350
Option C
The answer is: C
|
C
|
mathematics
|
A sum of Rs. 4000 amounts to Rs. 4600 in 5 years at a certain rate of simple interest. What would be the amount, if the rate of interest is increased by 3 %.
|
[
"Rs. 5202",
"Rs. 5200",
"Rs. 5228",
"Rs. 5212",
"Rs. 5182"
] |
Explanation:
Principal = Rs. 4000, Amount = Principal + SI = Rs. 4600
SI = Amount – Principal = 4600 – 4000 = Rs. 600
Given : Principal = Rs. 4000, Time = T = 5 years and SI = Rs. 600
SI =PRT/100
600 = 4000 *R * 5/100
600 = 200R
R = 3 % p.a.
Now the new interest rate is = 3% + 3% = 6 % p.a.
SI = PRT/ 100 = 4000 * 6 * 5/ 100 = Rs. 1200
Amount = Principal + SI
= 4000 + 1200
= 5200
ANSWER:B
The answer is: B
|
B
|
mathematics
|
A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has?
|
[
"90",
"70",
"50",
"80",
"60"
] |
Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
16x = 480
x = 30.
Hence, total number of notes = 3x = 90.
Answer is A.
The answer is: A
|
A
|
mathematics
|
What is the probability that a two digit number selected at random will be a multiple of '3' and not a multiple of '5'?
|
[
"2/15",
"4/15",
"1/15",
"4/90",
"5/60"
] |
Solution:
There are a total of 90 two digit numbers. Every third number will be divisible by '3'. Therefore, there are 30 of those numbers that are divisible by '3'.
Of these 30 numbers, the numbers that are divisible by '5' are those that are multiples of '15'. i.e. numbers that are divisible by both '3' and '5'.
There are 6 such numbers -- 15,30,45,60,75 and 90.
We need to find out numbers that are divisible by '3' and not by '5', which will be:
30−6=24
24 out of the 90 numbers are divisible by '3' and not by '5'.
The required probability is therefore,
=24/90
=4/15
ANSWER IS B
The answer is: B
|
B
|
mathematics
|
The overall ages of Kumar, Hathim and Rahul is 93 years. 1 decade ago, the ratio of their ages was 2 : 3 : 4. What is the current age of Rahul?
|
[
"38",
"37",
"34",
"35",
"33"
] |
A
38
If the ages of Kumar, Hathim and Rahul 1 decade ago be 2A, 3A and 4A years correspondingly
Then, (2A + 10) + (3A + 10) + (4A + 10) = 93
9A = 93-30
9A = 63
A = 7
Rahul’s current age = (4A + 10)
= 38 years.
The answer is: A
|
A
|
mathematics
|
A person crosses a 1080 m long street in 12 minutes. What is his speed in km per hour?
|
[
"4.1",
"4.5",
"4.8",
"5.4",
"5.5"
] |
Speed = 1080/(12x60) m/sec
= 1.5 m/sec.
Converting m/sec to km/hr =1.5 x(18/5) km/hr
= 5.4 km/hr.
ANSWER :D
The answer is: D
|
D
|
mathematics
|
A garrison of 2000 men has provisions for 65 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement?
|
[
"1977",
"1893",
"1979",
"3000",
"1278"
] |
2000 ---- 65
2000 ---- 50
x ----- 20
x*20 = 2000*50
x = 5000
2000
-------
3000
Answer: D
The answer is: D
|
D
|
mathematics
|
In a class, the average age of 25 boys is 10 years and the average of 18 girls is 10 years. what is the average age of the whole class?
|
[
"10 Years",
"12.6 Years",
"13 Years",
"13.5 Years",
"14 Years"
] |
Total age of 43 students
(25X 10+18 X 10) = 430
Average = 430/43 = 10 Years
A)
The answer is: A
|
A
|
mathematics
|
A parallelogram has a base that is four time the size of it's height. The total area of this parallelogram is 2,304 Sq ft. What is the height of the parallelogram?
|
[
"19",
"23",
"24",
"16",
"17"
] |
4x * x = 2304 => x
= 24
Answer: C
The answer is: C
|
C
|
mathematics
|
Which of the following is equal to 3^k*5^(k-1)?
|
[
"3*15^(k-1)",
"5*10^(k-1)",
"15^k",
"3*15^k",
"15^(2k-1)"
] |
3^k*5^(k-1) = 3*3^(k-1)*5^(k-1) = 3*15^(k-1)
The answer is A.
The answer is: A
|
A
|
mathematics
|
There is 60% increase in an amount in 6 years at S.I. What will be the C.I. of Rs. 12,000 after 3 years at the same rate?
|
[
"2387",
"2978",
"3972",
"2671",
"1871"
] |
Explanation:
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R = (100 * 60)/(100 * 6) = 10% p.a.
Now, P = Rs. 12000, T = 3 years and R = 10% p.a.
C.I. = [12000 * {(1 + 10/100)3 - 1}]
= 12000 * 331/1000 = Rs. 3972
Answer: C
The answer is: C
|
C
|
mathematics
|
Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $7 more than 1/4 of the fine and Peter paid $7 less than 1/3 of the fine, leaving pay $12 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?
|
[
"$65",
"$55",
"$50",
"$60",
"$45"
] |
Call the fine F. Joe paid (1/4)F + 4 and Peter paid (1/3)F – 4, leaving (1/2)F – 5 left. If we add those three up, they should add up to F.
F = [(1/4)F + 7] + [(1/3)F – 7] + [(1/2)F – 12]
F = (1/4)F + (1/3)F + (1/2)F – 12
Multiply all terms by 12 to clear the fractions.
12F = 3F + 4F + 6F – 144
12F = 13 F – 144
–F = – 144
F = 144
Well, if the fine cost $144, then Sam paid the part not covered by Joe or Peter. Half the fine is $72, and Sam paid $12 less than this: $60.
Answer = D
The answer is: D
|
D
|
mathematics
|
What will be the ratio of simple interest earned by certain amount at the same rate of interest for 3 years and that for 9 years?
|
[
"1 : 3",
"2 : 3",
"1 : 2",
"3 : 2",
"1 : 4"
] |
Let the principal be P and rate of interest be R%.
Required ratio =
(P x R x 3)/100 DIVIDED BY (P x R x 9)/100
= 3PR/9PR = 3/9 = 1 : 3.
ANSWER : A
The answer is: A
|
A
|
mathematics
|
Three partners A, B, C in a business invested money such that 3(A’s capital) = 6(B’s capital) = 9(C’s capital) then, The ratio of their capitals is
|
[
"63 : 45 : 34",
"6 : 3 : 2",
"36 : 54 : 28",
"63 : 45 : 35",
"None of these"
] |
Explanation:
Let3(A’s capital) = 6(B’s capital) = 9(C’s capital) = Rs.x
Then, A’s capital = Rs x/3, B’s capital = Rs. x/6 and C’s capital = Rs. x/9.
A : B : C = x/3 : x/6 : x/9
6 : 3 : 2
Answer: Option B
The answer is: B
|
B
|
mathematics
|
If xy is an integer, which of the following must also be an integer?
I. x/y
II. y/x
III. y
|
[
"I alone",
"II alone",
"III alone",
"None of the above",
"I and II"
] |
Lets take X = 8/3 and Y = 3/2
Then XY = 4 which is an integer.
But X/Y = 8/3 divided by 3/2 = 16/9 --> Not an integer.
Y/X = 3/2 divided by 8/3 = 9/16 --> Not an integer.
Y alone is 3/2. Not an integer.
Hence D. None of the above.
The answer is: D
|
D
|
mathematics
|
A fair price shopkeeper takes 10% profit on his goods. He lost 60% goods during theft. His loss percent is:
|
[
"72%",
"42%",
"56%",
"12%",
"22%"
] |
Explanation:
Suppose he has 100 items. Let C.P. of each item be Re. 1.
Total cost = Rs. 100. Number of items left after theft = 40.
S.P. of each item = Rs. 1.10
Total sale = 1.10 * 40 = Rs. 44
Hence, loss % = 56/100 * 100 = 56%
Answer:C
The answer is: C
|
C
|
mathematics
|
The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is:
|
[
"153600 m^2",
"153660 m^2",
"153700 m^2",
"153800 m^2",
"153900 m^2"
] |
Perimeter = Distance covered in 8 min. = 12000 x 8 m = 1600 m.
60
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 1600 or x = 160.
Length = 480 m and Breadth = 320 m.
Area = (480 x 320) m2 = 153600 m^2.
A
The answer is: A
|
A
|
mathematics
|
The perimeter of one square is 48 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
|
[
"13√6",
"13√2",
"13√9",
"13√1",
"13√5"
] |
4a = 48 4a = 20
a = 12 a = 5
a2 = 144 a2 = 25
Combined area = a2 = 169 => a = 13
d = 13√2
Answer: B
The answer is: B
|
B
|
mathematics
|
10^25 - 360 is divisible by all of the following except:
|
[
"A.7",
"B.8",
"C.5",
"D.4",
"E.2"
] |
The last three digits ( 1000 - 360 ) 640
640 is divisible by 2,4,8,5
640 is not evenly divisible by 7 so the answer is A) 7
The answer is: A
|
A
|
mathematics
|
The average of 25 result is 18.The average of 1st 12 of them is 14 & that of last 12 is 17.Find the 13th result.
|
[
"57",
"48",
"36",
"78",
"52"
] |
Clearly 13th result=(sum of 25 results)-(sum of 24 results)
=(18*25)-(14*12)+(17*12)
=450-(168+204)
=450-372
=78.
Ans: D
The answer is: D
|
D
|
mathematics
|
The perimeter of one square is 48 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
|
[
"13√2",
"15",
"48",
"75",
"23"
] |
xplanation:
4a = 48 4a = 20
a = 12 a = 5
a2 = 144 a2 = 25
Combined area = a2 = 169 => a = 13
d = 13√2
Answer: A
The answer is: A
|
A
|
mathematics
|
What annual payment will discharge a debt of Rs. 1050 due in 2 years at the rate of 5% compound interest?
|
[
"993.2",
"551.25",
"534.33",
"543.33",
"564.69"
] |
Explanation:
Let each installment be Rs. x. Then,
x/(1 + 5/100) + x/(1 + 5/100)2 = 1050
820x + 1050 * 441
x = 564.69
So, value of each installment = Rs. 564.69
Answer: Option E
The answer is: E
|
E
|
mathematics
|
The number of degrees that the hour hand of a clock moves through between noon and 2.30 in the afternoon of the same day is?
|
[
"38",
"27",
"75",
"28",
"21"
] |
Explanation:
The hour hand moves from pointing to 12 to pointing to half way between 2 and 3. The angle covered between each hour marking on the clock is 360/12 = 30. Since the hand has covered 2.5 of these divisions the angle moved through is 75.
Answer: C
The answer is: C
|
C
|
mathematics
|
If k^2 = t^2, which of the following must be true?
|
[
"|k| = |t|",
"k = -m",
"k = |m|",
"k = -|m|",
"k = m"
] |
Solution:
We are given that k^2 = t^2, and we can start by simplifying the equation by taking the square root of both sides.
√k^2 = √t^2
When we take the square root of a variable squared, the result is the absolute value of that variable. Thus:
√k^2 = √t^2 is |k| = |t|
Note that answer choices A through D could all be true, but each of them would be true only under specific circumstances. Answer choice E is the only one that is universally true.
Answer: A
The answer is: A
|
A
|
mathematics
|
It is dark in my bedroom and I want to get two socks of the same color from my drawer, which contains 24 red and 24 blue socks. How many socks do I have to take from the drawer to gate at least two socks of the same color?
|
[
"2",
"3",
"48",
"25",
"26"
] |
let
if first is red
and by luck if 2nd is not red then we u hav to take 3rd one.
which will be either red or blue.
but u will get 2 socks of same color,either red or blue.
ANSWER:B
The answer is: B
|
B
|
mathematics
|
If it is 7:19 in the evening on a certain day, what time in the morning was it exactly 2,880,705 minutes earlier? (Assume standard time in one location.)
|
[
"7:25",
"7:34",
"7:43",
"7:47",
"7:52"
] |
7:19 minus 2,880,705 must end with 4, the only answer choice which ends with 4 is B.
Answer : B.
The answer is: B
|
B
|
mathematics
|
If the sides of a square are multiplied by sqrt(20), the area of the original square is how many times as large as the area of the resultant square?
|
[
"2%",
"5%",
"20%",
"50%",
"150%"
] |
Let x be the original length of one side.
Then the original area is x^2.
The new square has sides of length sqrt(20)*x, so the area is 20x^2.
The area of the original square is 1/20 = 5% times the area of the new square.
The answer is B.
The answer is: B
|
B
|
mathematics
|
The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 7967 for a computer table, then what was the cost price of the computer table?
|
[
"6425",
"6887",
"6728",
"6725",
"2871"
] |
:
CP = SP * (100/(100 + profit%))
= 7967(100/124) = Rs. 6425.
Answer: A
The answer is: A
|
A
|
mathematics
|
6 points are marked on a straight line and another 7 points are marked on a second straight line with no points in common. How many triangles can be constructed with vertices from among the above points?
|
[
"9",
"105",
"196",
"21",
"14"
] |
assuming that the top line can have either 2 points or 1 point...
6! / 1!5! - 6! / 2! 4! yields 9.
A
The answer is: A
|
A
|
mathematics
|
The number of even factors of 21600 is
|
[
"32",
"42",
"60",
"25",
"52"
] |
Make a prime factorization of the number: 21,600=25∗33∗52
According to the above the number of factors is (5+1)(3+1)(2+1)=72
Now, get rid of powers of 2 as they give even factors --> you'll have 33∗52 which has (3+1)(2+1)=12 factors. All the remaining factors will be odd, therefore 21,600 has 72-12=60 even factors.
Answer: C.
The answer is: C
|
C
|
mathematics
|
The rate of Interest on a sum of money is 11% p.a. for the first 3 years, 4% p.a. for the next 4 years, and 5% for the period beyond 7 years. If the S.I, Occured on the sum for the total period of 8 years is Rs. 540/-, the sum is
|
[
"1,000",
"2,000",
"2,100",
"2,250",
"2,540"
] |
Explanation:
I1 = (P x 3 x 11)/100 = P/3
I2 = (P x 4 x 4)/100 = 4P/25
I3 = (P x 1 x 5)/100 = P/20
P/3 + 4P/25 + P/20 = 540
27P/50 = 540
P = 1000
Answer: Option A
The answer is: A
|
A
|
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