subject
stringclasses 1
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mathematics
|
A trader marks his product 40% above its cost. He sells the product on credit and allows 10% trade discount. In order to ensure prompt payment, he further gives 10% discount on the reduced price. If he makes a profit of Rs. 67 from the transaction, then the cost price of the product is
|
[
"Rs. 300",
"Rs. 400",
"Rs. 325",
"Rs. 500",
"Rs. 600"
] |
M.P = C.P *1.4
Profit = S.P - C.P = C.P ( 1.4 ) ( 0.9 ) ( 0.9 ) – C.P = 67
C.P ( 1.134 – 1 ) = 67,
C.P = 500
ANSWER:D
The answer is: D
|
D
|
mathematics
|
Last year, sales at Company Dopler were 10% greater in February than in January, 5% less in March than in Feb, 5% greater in April than in March, 10% less in May than in April, and 10% greater in June than in May. In which month were sales closest to Jan?
|
[
"Feb",
"April",
"Mar",
"May",
"June"
] |
Jan = $100
10% greater in February than in January ---> Feb = $110
10% less in March than in Feb ---> Mar = $99
5% greater in April than in March ---> Apr = $103.95
10% less in May than in April ---> May $93.55
10% greater in June than in May --->Jun = $102.90
Answer : C
The answer is: C
|
C
|
mathematics
|
A parking garage rents parking spaces for $10 per week or $35 per month. How much does a person save in a year by renting by the month rather than by the week?
|
[
"$100",
"$160",
"$220",
"$240",
"$260"
] |
10$ per week!
An year has 52 weeks.
Annual charges per year = 52* 10 = 520$
35$ per month!
An year has 12 months.
Annual charges per year = 12 * 35 = 420$
520 - 420 = 100
Ans A
The answer is: A
|
A
|
mathematics
|
Venkat purchased twenty dozens of toys at the rate of 375 per dozen. He sold each one of them at the rate of 33. What was his percentage profit?
|
[
"6.5",
"5.6",
"3.5",
"4.5",
"None of these"
] |
Cost price of 20 dozen toys = 20 × 375 = 7,500
Selling price of 20 dozen toys = 20 × 33 × 12 = 7,920
Profit percentage = 7920−7500/7500×100=5.6%
Answer B
The answer is: B
|
B
|
mathematics
|
A is twice as good workman as B, and together they complete a work in 15 days. In how many days can the work be complete by B alone?
|
[
"35 days",
"65 days",
"45 days",
"75 days",
"95 days"
] |
C
45 days
The answer is: C
|
C
|
mathematics
|
A parking space have 8 different slots. 8 cars has to arrange in 8 slots. But there are exactly 4 cars between 1 specified cars. In how many ways cars can be arranged?
|
[
"1210",
"120",
"1500",
"1640",
"1440"
] |
we arranged 1 specified cars in 1 slots = 1!
remaining 5 cars in 5 slots = 5!
number of ways = 1!*5! = 120
correct option is B
The answer is: B
|
B
|
mathematics
|
A, B and C can do a work in 6, 8 and 12 days respectively doing the work together and get a payment of Rs.1800. What is B’s share?
|
[
"600",
"278",
"298",
"267",
"127"
] |
WC = 1/6:1/8:1/12 => 4:3:2
3/9 * 1800 = 600
Answer:A
The answer is: A
|
A
|
mathematics
|
Find the slope of the line perpendicular to the line y = x - 7
|
[
"1",
"2",
"-1",
"4",
"5"
] |
Two lines are perpendicular if the product of their slopes is equal to -1. The slope of the given line is equal to 1. If m is the slope of the line perpendicular to the given line, then
m × 1 = -1
Solve for m
m = - 1
correct answer C) -1
The answer is: C
|
C
|
mathematics
|
In how much time will a train of length 100 m, moving at 36 kmph cross an electric pole?
|
[
"15 sec",
"12 sec",
"10 sec",
"14 sec",
"11 sec"
] |
C
10 sec
Convert kmph to mps. 36 kmph = 36 * 5/18 = 10 mps.
The distance to be covered is equal to the length of the train.
Required time t = d/s = 100/10 = 10 sec.
The answer is: C
|
C
|
mathematics
|
The value of 1/(1-x) + 1/ (1+x) + 2/(1+x^2) + 4/(1+x^4)
|
[
"8/(1-x^8)",
"4x/(1+x^2)",
"4/(1-x^6)",
"4/(1+x^4)",
"4x/(1-x^4)"
] |
Highlighted part has mistake as the exponent of x must be 4 in last term
CORRECT QUESTION ISThe value of 1/(1-x) + 1/(1+x) + 2/(1+x^2) + 4/(1+x^4) = ?
Solution is as mentioned below...
one more way that could get the answer in the type of eqn and choices given is to substitute some value for x...
0 would be better as the eq has constant term free of term 'x'..
the Eq gives us 8 as the ans , as also only choice A..
The answer is: A
|
A
|
mathematics
|
The number of girls in a class are 7 times the number of boys, which value can never be the of total students
|
[
"40",
"48",
"24",
"30",
"34"
] |
Explanation:
Let the boys are X, then girls are 7X, total = X+7X = 8X
So it should be multiple of 8, 30 is not a multiple of 8.
Option D
The answer is: D
|
D
|
mathematics
|
Andrew travelling to 7 cities. Gasoline prices varied from city to city. What is the median gasoline price?
|
[
"$1",
"$1.84",
"$2.54",
"$2.65",
"$3"
] |
Ordering the data from least to greatest, we get:
$1.61, $1.75, $1.79, $1.84, $1.96, $2.09, $2.11
The median gasoline price is $1.84. (There were 3 states with higher gasoline prices and 3 with lower prices.)
B
The answer is: B
|
B
|
mathematics
|
In how many ways can 10 Frenchmen, 10 Spanish be seated along a circle so that they are alternate?
|
[
"8!*7!",
"10!*9!",
"5!*9!",
"10!*5!",
"11!9!"
] |
Required number is = 10!*9!
Answer is B
The answer is: B
|
B
|
mathematics
|
A set of data consists of the following 6 numbers: 0, 2, 4, 6,10 and 8. Which two numbers, if added to create a set of 7 numbers, will result in a new standard deviation that is close to the standard deviation for the original 5 numbers?
|
[
"-1 and 9",
"4 and 4",
"3 and 5",
"2 and 6",
"0 and 8"
] |
If you are in for some calculations , this is how I got to it
mean = 4
sd = \sqrt{8} = 2.8
Expected values for the SD to not change are - One value below SD from mean is (4 - 2.8) = 1.2 , and one value above SD is (4 + 2.8) = 6.8
This would mean , adding 1.2 ans 6.8 would have no impact on the SD . SD remains the same when these two numbers are added. Now for SD to change the least , we need to add two values that are closest to these two values.
Hence any two values that are closest to 1.2 and 6.8 would change the SD , the least.
1. -1 , 9
distance between (1,9) and (1.2 and 6.8) is 2.2 and 2.2
2. 4 , 4
distance etween (4,4) and (1.2 , 6.8) is 2.8 and 2.8
3. 3 , 5
Distance is - 1.8 and 1.8
4. 2 , 6
Distance is - 0.8 and 0.8
5. 0 , 8
Distnace is - 1.2 and 1.2
Hence from above , we see that adding 0 and 8 , results in a value that would change the SD to the least. Hence E
The answer is: E
|
E
|
mathematics
|
A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
|
[
"900 km",
"800 km",
"600 km",
"690 km",
"609 km"
] |
Explanation:
D = 30 * 5 = 150
RS = 40 – 30 = 10
T = 150/10 = 15
D = 40 * 15 = 600 km
Answer: Option C
The answer is: C
|
C
|
mathematics
|
During a Thanksgiving weekend, a car rental company rented six-tenths of their vehicles, including two-fifths of the 4WDs that it had. If 60% of the vehicles are 4WDs, then what percent of the vehicles that were not rented were not 4WDs?
|
[
"10%",
"15%",
"20%",
"25%",
"30%"
] |
4/10 of all the vehicles were not rented.
(3/5)(3/5) = 9/25 of all the vehicles are 4WDs that were not rented.
(9/25) / (4/10) = 9/10 is the fraction of non-rented vehicles that were 4WDs
1 - 9/10 = 10% of non-rented vehicles were not 4WDs.
The answer is A.
The answer is: A
|
A
|
mathematics
|
Find the fourth proportion to 6,12,18
|
[
"24",
"12",
"36",
"8",
"15"
] |
Explanation:
6:12 :: 18:x
=> 6/12= 18/x
=> x = 18*12/6
=> x = 24
Answer:C
The answer is: C
|
C
|
mathematics
|
What will be the compound interest on a sum of Rs.25,000 after 3 years at the rate of 12 p.c.p.a?
|
[
"Rs.9000.30",
"Rs. 9720",
"Rs. 10123.20",
"Rs. 10483.20",
"None"
] |
Solution
Amount = Rs.(25000x(1+12/100)³
=Rs.(25000x28/25x28/25x28/25)
= Rs. 35123.20.
C.I =Rs(35123.20-25000)
=Rs.10123.20.
Answer C
The answer is: C
|
C
|
mathematics
|
Twelve people are planning to share equally the cost of a rental van. If one person withdraws from the arrangement and the others share equally the cost of the rental van, then the share of each of the remaining people will increase by...?
|
[
"1/12",
"1/8",
"1/11",
"12/11",
"10/11"
] |
Let P = total cost of the rental van.
The original share per person is P/12.
The new share per person is P/11.
P/11 = P/12 * 12/11 = (1 + 1/11)*original share
The answer is C.
The answer is: C
|
C
|
mathematics
|
A sum of money at simple interest amounts to Rs. 1717 in 1 year and to Rs. 1734 in 2 years. The sum is:
|
[
"Rs. 1200",
"Rs. 1690",
"Rs. 1600",
"Rs. 1700",
"Rs. 1500"
] |
S.I. for 1 year = Rs. (1734 - 1717) = Rs. 17.
Principal = Rs. (1717 - 17) = Rs. 1700.
Answer: Option D
The answer is: D
|
D
|
mathematics
|
In a school there are 4 sections in LKG. Average students of the section is 30. A, B, C sections have 28, 30, 34 students respectively. Therefore how much students in section D?
|
[
"30",
"29",
"35",
"32",
"28"
] |
EXPLANATION
Total students of 3 sections = (28 + 30 + 34) = 92
Students of section D = [ (30 x 4) – 92 ]
= (120 – 92)
= 28
Answer E
The answer is: E
|
E
|
mathematics
|
In May, the groundskeeper at Spring Lake Golf Club built a circular green with an area of 70π square feet. In August, the groundskeeper doubled the distance from the center of the green to the edge of the green. What is the total area of the renovated green?
|
[
"1000π",
"400π",
"280π",
"200π",
"20π"
] |
Area = πR^2, so doubling the radius results in an area that is 4 times the original area.
4(70π) = 280π
The answer is C.
The answer is: C
|
C
|
mathematics
|
In a100m race A beats B by 25m B beats C by 4 then A beats C by
|
[
"24 m",
"25m",
"26m",
"27m",
"28m"
] |
A : B = 100 : 75
B : C = 100 : 96.
A : C = (A/B x B/C) = (100/75 x 100/96) = 100/72 = 100 : 72.
A beats C by (100 - 72) m = 28 m.
ANSWER:E
The answer is: E
|
E
|
mathematics
|
What is the probability of randomly selecting one of the shortest diagonals from all the diagonals of a regular 9-sided polygon)?
|
[
"1/2",
"1/3",
"1/4",
"1/6",
"1/9"
] |
From any vertex, there are two vertices on sides, which do not make a diagonal but a side.
So the remaining n-3 vertices make diagonals.
There are 2 of these diagonals which are the shortest.
The probability of choosing one of the shortest diagonals is 2/6 = 1/3.
The answer is B.
The answer is: B
|
B
|
mathematics
|
In a group of 25, 13 can speak Latin, 15 can speak French, and 6 don't speak either. How many of these speak both Latin and French?
|
[
"9",
"10",
"11",
"12",
"8"
] |
let no.of persons who speeks booth latin and french = x
so, no.of persons who speeks only latin = 13-x
no.of persons who speeks only french= 15-x
no.of persons who speeks dont speek any lag = 6
therefore (13-x)+(15-x)+x+6=25
34-x=25
x=9
ANSWER:A
The answer is: A
|
A
|
mathematics
|
A collector collects stamps from foreign countries. In June, she gave 20 percent of her stamps to her friend. In July, she gave 35 percent of her remaining stamps to another friend. If these were the only changes in the number of stamps in the stamp collection during those two months, what percent of her collection at the beginning of June did she give to away in June and July?
|
[
"32%",
"36%",
"40%",
"44%",
"48%"
] |
Let x be the number of stamps in the original collection.
The percentage of the collection given away is:
0.2x + 0.35(0.8x) = 0.2x + 0.28x = 0.48x = 48%
The answer is E.
The answer is: E
|
E
|
mathematics
|
When positive integer N is divided by positive integer J, the remainder is 16. If N/J = 134.08, what is value of J?
|
[
"22",
"56",
"78",
"112",
"200"
] |
When a number is divided by another number, we can represent it as : Dividend = Quotient * Divisor + Remainder
So, Dividend/Divisor = Quotient + Remainder/Divisor
Given that N/J = 134.08
Here 134 is the quotient.
Given that Remainder = 16
So, 134.08 = 134 + 16/J
So, J = 200 ANS E
The answer is: E
|
E
|
mathematics
|
The product of a and b is equal to 10 more than twice the sum of a and b. If b = 9, what is the value of b - a?
|
[
"2",
"5",
"7",
"24",
"35"
] |
ab= 10 + 2(a+b)
9a= 10+2a +18
7a= 28
a=4
b-a= 9-4=5
B is the answer
The answer is: B
|
B
|
mathematics
|
Diana is painting statues. She has 1/2 of a gallon of paint remaining. Each statue requires 1/4 gallon of paint. How many statues can she paint?
|
[
"2",
"20",
"28",
"14",
"19"
] |
number of statues=all the paint÷amount used per statue
=1/2 ÷ 1/4
=1/2*4/1
=2
Answer is A
The answer is: A
|
A
|
mathematics
|
The fourth proportional to 12, 14 and 12 is?
|
[
"14",
"66",
"77",
"88",
"99"
] |
(14*12)/12 = 14
Answer: A
The answer is: A
|
A
|
mathematics
|
A rower can row upstream at 7 km/hr and downstream at 14 km/hr. What is the rower's rate in still water?
|
[
"9.5 km/hr",
"10.0 km/hr",
"10.5 km/hr",
"11.0 km/hr",
"11.5 km/hr"
] |
The rate in still water is 1/2 * (14 + 7) = 10.5 km/hr
The answer is C.
The answer is: C
|
C
|
mathematics
|
The ratio of incomes of two person P1 and P2 is 5 : 4 and the ratio of their expenditures is 3 : 2. If at the end of the year, each saves Rs.1600, then what is the income of P1?
|
[
"Rs.800",
"Rs.2400",
"Rs.4000",
"Rs.3200",
"Rs.4200"
] |
Let the income of P1 and P2 be Rs. 5x and Rs.4x respectively and let their
expenditures be Rs.3y and 2y respectively.
Then, 5x – 3y = 1600 …(i) and 4x – 2y = 1600 ……..(ii)
On multiplying (i) by 2, (ii) by 3 and subtracting, we get : 2x = 1600 -> x = 800
P1’s income = Rs 5*800 = Rs.4000
ANSWER:C
The answer is: C
|
C
|
mathematics
|
The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
|
[
"21",
"56",
"18",
"25",
"23"
] |
1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 – 550 = 56
Answer:B
The answer is: B
|
B
|
mathematics
|
If Jack walked 9 miles in 1 hour and 15 minutes, what was his rate of walking in miles per hour?
|
[
"4",
"4.5",
"6",
"6.25",
"7.2"
] |
Distance walked in 1 hour and 15 mins = 9 miles
Speed per hour = Distance/Time = 9/(5/4) = 7.2 miles per hour
Answer E
The answer is: E
|
E
|
mathematics
|
The average salary of Raj and Roshan is Rs. 4000 but the average salary of Raj, Roshan and Thomas is Rs. 5000. What is the salary of Thomas?
|
[
"4000",
"5000",
"6000",
"7000",
"8000"
] |
Total salary of Raj and Roshan= 2x4000=8000
Total salary of Raj Roshan and Thomas= 3x5000=15000
Salary of Thomas= 15000-8000= Rs. 7000
Answer: D
The answer is: D
|
D
|
mathematics
|
What will be the fraction of 75%
|
[
"3/4",
"1/5",
"1/10",
"1/11",
"None of above"
] |
Explanation:
It will 75*1/100 = 3/4
Option A
The answer is: A
|
A
|
mathematics
|
A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 45 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container?
|
[
"3.0",
"5.0",
"5.5",
"6.5",
"6.75"
] |
Construct an equation: 15/100=x/45-> x=6.75
Answer: E.
The answer is: E
|
E
|
mathematics
|
At Pat's Pet Shop, 25 cups of bird seed are used every 5 days to feed 20 parakeets. How many cups of bird seed would be required to feed 15 parakeets for 7 days?
|
[
"35.25",
"15",
"64",
"104",
"26 1/4"
] |
Let's go step-by-step.
25 cups are used over a 5 day period, which means 5 cups a day. This feeds 20 parakeets, which means each parakeet needs 1/4 of a cup every day.
For 15 parakeets, we need 15*1/4 cups = 3 3/4 cups a day. Over 7 days, we need 26 1/4 cups. Choice E.
The answer is: E
|
E
|
mathematics
|
A train passes a platform in 44 seconds. The same train passes a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, The length of the platform is
|
[
"240",
"250",
"360",
"230",
"220"
] |
Speed of the train = 54 km/hr = (54×10)/36 m/s = 15 m/s
Length of the train = speed × time taken to cross the man = 15×20 = 300 m
Let the length of the platform = L
Time taken to cross the platform = (300+L)/15
=> (300+L)/15 = 36
=> 300+L = 15×44 = 660
=> L = 660-300 = 360 meter
Answer is C.
The answer is: C
|
C
|
mathematics
|
It takes John 25 minutes to walk to the car park and 45 to drive to work. At what time should he get out of the house in order to get to work at 9:00 a.m.?
|
[
"5:40 a.m",
"7:50 a.m",
"6:55 a.m",
"8:00 a.m",
"4:25 a.m"
] |
The time it takes John to get to work: time to walk to car park + time to drive
25 + 45 = 70 minutes = 1 hour and 10 minutes
John needs to get out of the house 1 hour and 10 minutes before 9:00 am at
9:00 - 1:10 = 7:50 a.m
correct answer B
The answer is: B
|
B
|
mathematics
|
A rectangular tiled patio is composed of 30 square tiles. The rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles. After the change in layout, the patio will still have 30 tiles, and it will still be rectangular. How many rows are in the tile patio before the change in layout?
|
[
"5",
"6",
"10",
"13",
"28"
] |
Suppose there are c columns and there are r rows
Original Situation
So, Number of tiles = c*r = 30
Also. Reach column has r tiles and each row has c tiles
New Situation
Number of tiles in each column is r-2 and number of tiles in each row is c+4
So, number of rows = r-2 and number of columns is c+4
So, Number of tiles = (r-2)*(c+4) = 30
Comparing both of them we get
c*r = (r-2)*(c+4)
=> 4r -2c = 8
c = 2r - 4
Putting it in c*r=30
(2r-4)*r = 30
2r^2 - 4r - 30=0
r cannot be negative so r =5
and c = 6
So, Answer will be A
The answer is: A
|
A
|
mathematics
|
If the cost price is 96% of the selling price, then what is the profit percent?
|
[
"4.17%",
"5%",
"6.12%",
"3.25%",
"5.75%"
] |
Let S.P. = $100
C.P. = $96
Profit = $4
Profit% = 4/96 * 100 = 25/6 = 4.17%
Answer is A
The answer is: A
|
A
|
mathematics
|
A train covers a distance of 100km in 1 hour. If its speed is decreased by 30km/hr, the time taken by the car to cover the same distance will be?
|
[
"1hr",
"1hr 25min",
"50min",
"1hr 30min",
"1hr 45min"
] |
Speed = 100/1 = 100km/hr
New speed = 100-30 = 70 km/hr
Time taken = 100/70 = 1hr 25min
Answer is B
The answer is: B
|
B
|
mathematics
|
A fruit seller had some oranges. He sells 40% oranges and still has 480 oranges. How many oranges he had originally?
|
[
"800",
"710",
"720",
"730",
"740"
] |
60% of oranges = 480
100% of oranges =(480×100)/6=800
total oranges = 700
ANSWER : A
The answer is: A
|
A
|
mathematics
|
At the opening of a trading day at a certain stock exchange, the price per share of stock M was $25. If the price per share of stock M was $28 at the closing of the day, what was the percent increase in the price per share of stock M for that day?
|
[
"1.4%",
"5.9%",
"12%",
"12.5%",
"23.6%"
] |
Opening = 25
Closing = 28
Rise in price = 3
So, percent increase = 3/25*100 = 12
Answer : C
The answer is: C
|
C
|
mathematics
|
The L.C.M. of two numbers is 36. The numbers are in the ratio 2 : 3. Then sum of the number is:
|
[
"28",
"30",
"40",
"53",
"54"
] |
Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 36 or x = 6.
The numbers are 12 and 18.
Hence, required sum = (12 + 18) = 30.
Answer: Option B
The answer is: B
|
B
|
mathematics
|
There are six cards in which it has two king cards. all cards are turned down and two cards are opened what is the possibility to get two kings.
|
[
"1/15",
"2/15",
"3/15",
"4/15",
"6/15"
] |
P0SSIBLITY TO GET TWO KINGS IS 2C2/6C2=1/15
ANSWER:A
The answer is: A
|
A
|
mathematics
|
John makes $30 a week from his job. He earns a raise and now makes $40 a week. What is the % increase?
|
[
"16%",
"16.66%",
"18%",
"21%",
"33.33%"
] |
Increase = (10/30)*100 = 33.33%.
E
The answer is: E
|
E
|
mathematics
|
n^(n/2)=4 is true when n=4 in the same way what is the value of n if n^(n/2) =8?
|
[
"4",
"8",
"2",
"6",
"10"
] |
n^(n/2)=8
Apply log
N/2logn=log8
nlogn=2log8=log8^2=log64
Logn=log64
Now apply antilog
n=64/n
Now n=8.
ANSWER:B
The answer is: B
|
B
|
mathematics
|
A can have a piece of work done in 5 days, B can work three times faster than the A, C can work four times faster than A. How many days will they take to do the work together ?
|
[
"3 days",
"8/9 days",
"3/2 days",
"can't say",
"none"
] |
A's 1 day work is 1/12
B's 1 day work is 3/12
C's 1 day work is 4/12
(A+B+C)'s 1 day work(1/12+3/12+4/12) is 2/3
so, they can finish the work in 3/2 days
ANSWER:C
The answer is: C
|
C
|
mathematics
|
A three digit number divisible by 7 becomes divisible by 3 when 16 is subtracted from it. The largest such number is :
|
[
"994",
"981",
"963",
"951",
"942"
] |
Out of all the 5 options, only 994 is NOT divisible by 3. All others are divisible
So Answer = A (No further calculation required)
Addition of any two non-divisible numbers by 3 gives the resultant divisible by 3
16 is non-divisible by 3; we are subtracting a number from that so that the resultant becomes divisible by 3
Applying the above rule,It means that the number which we are going to add should be non-divisible by 3
So comes the answer = 994
Answer : A
The answer is: A
|
A
|
mathematics
|
What will be in unit's place digit of 3 to the power 34.
|
[
"1",
"6",
"3",
"0",
"9"
] |
as the unit place digit of 3 to the power of 1 is 3, to the power of 2 is 9.to the power of 3 is 7 ,to the power of 4 is 1 and it'll be repeated again in the same order.... so the unit place digit of 3 to the power of 34 is 9..
ANSWER:E
The answer is: E
|
E
|
mathematics
|
A sum fetched total simple interest of 4016.25 at the rate of 10 p.c.p.a. in 5 years. What is the sum?
|
[
"8925",
"8032.5",
"4462.5",
"8900",
"None of these"
] |
Let the sums be P.
Now, 50% of P = 4016.25
or, P = 8032.5
Answer B
The answer is: B
|
B
|
mathematics
|
Robert is travelling on his cycle andhas calculated to reach point A at 2 PM. if he travels at 10 kmph, he will reach there at 12Pm if he travels at 15 kmph. At what speed musthe travel to reach A at 1 PM?
|
[
"8 kmph",
"10 kmph",
"12 kmph",
"16 kmph",
"18 kmph"
] |
Let the distance travelled by x km.
Then, x - x = 2
10 15
3x - 2x = 60
x = 60 km.
Time taken to travel 60 km at 10 km/hr = 60 hrs = 6 hrs.
10
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
Required speed = 60 kmph. = 12 kmph.
5
C
The answer is: C
|
C
|
mathematics
|
A batsman makes a score of 83 runs in the 17th inning and thus increases his averages by 3.Find his average after 17th inning?
|
[
"19",
"29",
"35",
"49",
"59"
] |
let the average after 17th inning =x
Then average after 16th inning=(x-3)
Therefore 16(x-3)+83=17x
Therefore x=35
ANSWER:C
The answer is: C
|
C
|
mathematics
|
In a bag there are 3 Snicker's bars and 2 Milky Way bars. What is the probability of choosing at least one Snickers when choosing two consecutive candy bars randomly?
|
[
"9/10",
"16/20",
"2/5",
"3/5",
"½"
] |
P(at least one Snicker's Bar) = 1 - P(no Snicker's Bar, so 2 Milky Way Bars) = 1- 2/5*1/4 = 9/10.
Answer: A.
The answer is: A
|
A
|
mathematics
|
If the sides of a triangle are 65 cm, 60 cm and 25 cm, what is its area?
|
[
"120 cm2",
"750 cm2",
"216 cm2",
"197 cm2",
"275 cm2"
] |
The triangle with sides 65 cm, 60 cm and 25 cm is right angled, where the hypotenuse is 65 cm.
Area of the triangle
= 1/2 * 60 * 25
= 750 cm2
Answer:B
The answer is: B
|
B
|
mathematics
|
A chemical lab is scheduled to go through two air ventilation systems, a basic system and a more advanced system that takes half an hour and 1.5 hours respectively to fully ventilate the room. If both ventilation systems were to operate at the same time with their respective constant rates, how many hours would it take to fully ventilate the chemical lab?
|
[
"1/4",
"1/3",
"2/5",
"5/4",
"3/8"
] |
The rate of the basic system is 1 room/half hour = 2 rooms per hour
The rate of the advanced system is 1 room/1.5 hours = 2/3 of a room per hour
The combined rate is 8/3 rooms per hour.
The time to ventilate one room is 3/8 of an hour.
The answer is E.
The answer is: E
|
E
|
mathematics
|
In what time will a railway train 50 m long moving at the rate of 36 kmph pass a telegraph post on its way?
|
[
"5 sec",
"4 sec",
"3 sec",
"6 sec",
"1 sec"
] |
T = 50/36 * 18/5 = 5 sec
Answer: A
The answer is: A
|
A
|
mathematics
|
Of the total amount that Jill spent on a shopping trip, excluding taxes, she spent 50 percent on clothing, 25 percent on food, and 25 percent on other items. If Jill paid a 10 percent tax on the clothing, no tax on the food, and an 20 percent tax on all other items, then the total tax that she paid was what percent of the total amount that she spent, excluding taxes?
|
[
"5",
"10",
"15",
"20",
"25"
] |
Assume she has $200 to spend.
TAX
Clothing = 50% = $100= $10.00
Food = 25% = $ 50 = $0.00
Items = 25% = $ 50 = $ 10.00
Total tax = $20.00
% of total amount = 20/200 * 100 = 10%
Answer B
The answer is: B
|
B
|
mathematics
|
Two cyclists are running on a circular track of 500m.They start from the same point A at the same time.If they meet for the first time at a point 300 m from A, which of the following could be the possible ratio of their speeds?
|
[
"1:3",
"2:3",
"3:2",
"5:7",
"7:11"
] |
well, the key aspect of this question is the distance mentioned, when they met for the first time, which is 300m away from the starting point. This distance between their first meeting can be less than 500 in only two circumstance.
1) if both are travelling in the same direction and one of them has been given a head start say by few meters.
2) or if both are travelling in the opposite direction.
now since they start their journey at the same time. hence option 1 is ruled out. hence they must be running in the opposite direction. hence answer should be 3:2
Why?? here is a solution
As here time is constant, therefore, distance traveled will be directly proportional to the the respective velocities/speed of the two runners.(d1/d2=v1/v2)
now one of them has covered 300m, therefore other must have covered 200m, therefore ratio of their speeds/velocities will be 3:2
C
The answer is: C
|
C
|
mathematics
|
If n = 9^11 – 9, what is the units digit of n?
|
[
"0",
"1",
"4",
"6",
"8"
] |
Always divide the power (incase 11) by 4 and use the remainder as the new power. The question now becomes 9^3 - 9. Now 9^3 has last digit 9. , we subtract 9 from 9 , thus 9 -9 = 0 is the answer. Option A
The answer is: A
|
A
|
mathematics
|
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate Q of movement for his trip along the moving walkway?
|
[
"2 feet per second",
"2.5 feet per second",
"3 feet per second",
"4 feet per second",
"5 feet per second"
] |
A, B, and C don't make ANY sense! we know for some time...(a majority of the 300ft) Bill will walk at a pace of 6ft per second...and then at some later time he will stop and move at 3 ft per second... The average MUST bebetween3-6 ft per second or the Earth is FLAT!!!.
So we are down to DE, D doesn't make sense on a weighted averages level because we know when Bill gets on the walkway the patrons are already 40% of the way down the 300ft walkway AND they are still moving at half the rate of Bill!! So for Bill to average 4 ft per second he would have had to spend a majority of the 300 ft at 3ft per second because 4 is much closer (when you factor in the size of the values we're dealing with 2 is double 1) to 3 than to 6. We know from the information that isn't possible. Billmust havespent the majority of his time at 6 ft Q per second before he stopped walking. That leaves only answer E as plausible.
The answer is: E
|
E
|
mathematics
|
If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:
|
[
"Rs. 182",
"Rs. 190",
"Rs. 196",
"Rs. 204",
"Rs. 210"
] |
Explanation:
Given ratio =1/2:2/3:3/4=6:8:9
1st part = Rs. 782*6/23=Rs. 204
Answer is D
The answer is: D
|
D
|
mathematics
|
Last year Manfred received 26 paychecks. Each of his first 6 paychecks was $760; each of his remaining paychecks was $30 more than each of his first 6 paychecks. To the nearest dollar, what was the average (arithmetic mean) amount of his pay checks for the year?
|
[
"$752",
"$755",
"$765",
"$783",
"$775"
] |
= (760*6+ 790 *20)/26
= 783
Answer is D.
Posted from my mobile device
The answer is: D
|
D
|
mathematics
|
Ten cards numbered 1 to 10 are placed in a box, mixed up thoroughly and then one card is drawn
randomly. If it is known that the number on the drawn card is more than 3, what is the probability
that it is an even number?
|
[
"3/7",
"4/7",
"5/7",
"5/9",
"5/11"
] |
Let A be the event ‘the number on the card drawn is even’ and B be the
event ‘the number on the card drawn is greater than 3’. We have to find P(A|B).
Now, the sample space of the experiment is S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Then A = {2, 4, 6, 8, 10}, B = {4, 5, 6, 7, 8, 9, 10}
and A n B = {4, 6, 8, 10}
Also P(A) = 5/2, P(B) = 7/10 and P(A n B) = 4/10
Then P(A|B) = P(A n B)/P(B) = (4/10)/(7/10) = 4/7
B)
The answer is: B
|
B
|
mathematics
|
A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined then after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A, B and C?
|
[
"3 : 5 : 2",
"3 : 5 : 5",
"6 : 10 : 5",
"8 : 12 : 4",
"Data inadequate"
] |
Explanation:
Let the initial investments of A and B be 3x and 5x.
A : B : C = (3x x 12) : (5x x 12) : (5x x 6) = 36 : 60 : 30 = 6 : 10 : 5.
Answer is C
The answer is: C
|
C
|
mathematics
|
A worker's take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 8 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month?
|
[
"6/25",
"5/16",
"4/9",
"3/7",
"2/5"
] |
Let x be the fraction of her take-home pay that the worker saved.
Let P be the monthly pay.
12xP = 8(1-x)P
12xP = 8P - 8xP
20xP = 8P
x = 2/5
The answer is E.
The answer is: E
|
E
|
mathematics
|
A car mechanic purchased four old cars for Rs. 1 lakh. He spent total 2 lakh in the maintenance and repairing of these four cars. what is the average sale price of the rest three cars to get 90% total profit if he has already sold one of the four cars at Rs. 1.2 lakh?
|
[
"1.8 lakh",
"1.5 lakh",
"1.9 lakh",
"8.1 lakh",
"6.1 lakh"
] |
Explanation:
Total cost of 4 cars = 1+2 = 3 lakh
Total SP of 4 cars = 3 x 1.9 = 5.7 lakh
SP of 1 car = 1.2 lakh
SP of rest 3 cars = 5.7 - 1.2 = 4.5 lakh
Average SP of all the 3 cars = 1.5 lakh
Answer: B)
The answer is: B
|
B
|
mathematics
|
A meeting has to be conducted with 4 managers. Find the number of ways in which the managers be selected from among 7 managers, if 2 managers will not attend the meeting together?
|
[
"25",
"20",
"35",
"36",
"38"
] |
we can either choose all 4 people from 5 manager who have no problems or choose 3 from the 5 and 1 from the 2 managers who have a problem sitting together
so 5C4 + (5C3 * 2C1)
this is 5 + 20=25
Answer : A
The answer is: A
|
A
|
mathematics
|
A man can row upstream at 25 kmph and downstream at 31 kmph, and then find the speed of the man in still water?
|
[
"22",
"28",
"30",
"27",
"18"
] |
US = 25
DS = 31
M = (31 + 25)/2 = 28
Answer:B
The answer is: B
|
B
|
mathematics
|
117 + 1.017 + 0.117 + 1.0017 = ?
|
[
"109.3657",
"119.7563",
"119.1357",
"119.5637",
"119.6753"
] |
117
1.017
0.117
+ 1.0017
--------
119.1357
---------
Answer is C.
The answer is: C
|
C
|
mathematics
|
A, B and C start a business each investing 10,000. After 6 months A withdrew 5000, B withdrew 4000 and C invests 6000 more. At the end of the year, a total profit of 34,200 was recorded. Find the share of B.
|
[
"9,600",
"21,200",
"28,200",
"20,500",
"None of these"
] |
Ratio of the capitals of A, B and C
= 10000 × 6 + 5000 × 6 : 10000 × 6 + 6000 × 6 : 10000 × 6 + 16000 × 6
=90000 : 96000 : 156000 = 90 : 96 : 156
B’s share = (34200 × 96â„342) = 9600
Answer A
The answer is: A
|
A
|
mathematics
|
How many 1's are there preceded by 2 but not followed by 0?
5 9 3 2 1 7 4 2 6 9 7 4 2 1 3 2 8 7 0 1 3 8 3 2 5 6 7 4 3 9 5 8 2 2 1 0 7 4 6 3
|
[
"4",
"2",
"6",
"8",
"9"
] |
2 1 7
2 1 3
Only at these places 2 is preceded by 2 but not followed by 0
Answer: B
The answer is: B
|
B
|
mathematics
|
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
|
[
"10.9 sec",
"14.8 sec",
"10.6 sec",
"10.8 sec",
"20.8 sec"
] |
Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5
= 10.8 sec.
Answer: D
The answer is: D
|
D
|
mathematics
|
How many odd numbers between 10 and 1500 are the squares of integers?
|
[
"11",
"14",
"17",
"20",
"23"
] |
The numbers are the squares of 5, 7, 9,...,37 which includes 17 numbers.
The answer is C.
The answer is: C
|
C
|
mathematics
|
Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles?
|
[
"Rs.2000",
"Rs.2028",
"Rs.2020",
"Rs.2720",
"Rs.2026"
] |
(10*10)/100 = 1%loss
100 --- 99
? --- 1980 => Rs.2000
Answer:A
The answer is: A
|
A
|
mathematics
|
2,7,14,32,58,?
|
[
"112",
"154",
"123",
"132",
"144"
] |
1^2+1=2
2^2+3=7
3^2+5=14
5^2+7=32
7^2+9=58
11^2+11=132
ANSWER:D
The answer is: D
|
D
|
mathematics
|
Find the area of the square field if a train 800 metres long passes the field with a speed of 120 kmph in one minute.
|
[
"1.44 sq. km",
"4 sq. km",
"2 sq. km",
"2.64 sq. km",
"None of these"
] |
Explanation:
120 km/hr = 120 * 5/18 = 33.33 m/s
v = d/t ; 33.33 = d/60
d = 2000 m
Hence, in one minute the train travels 2000 m. But, as the train is 800 m long and it passes the field, the length of the field is 2000 – 800 = 1200 m.
Area = 1200 * 1200 = 1.44 sq. km
ANSWER: A
The answer is: A
|
A
|
mathematics
|
33 1/3% of 36 ?
|
[
"16",
"21",
"18",
"12 number",
"18"
] |
Explanation:
33 1/3 % = 1/3
1/3 * 36 = 12
Answer: Option D
The answer is: D
|
D
|
mathematics
|
What is the minimum number of years upon which SI on Rs 2600 at 6.67% interest rate will be in whole number?
|
[
"2",
"6",
"3",
"4",
"5"
] |
Explanation:
Simple Interest =Principal * Rate * Time
Principal = 2600 Rs
Interest Rate = 6.67%
=> SI = 2600 * (20/3)*Time
SI of the number will be a whole number for the first time when time is three as denominator of rate is 3.
Hence time should be set to 3 years.
ANSWER C
The answer is: C
|
C
|
mathematics
|
A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 150, the runs scored by B are?
A. 15 B. 18
|
[
"22",
"18",
"99",
"36",
"24"
] |
A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 150 = 36
Answer: D
The answer is: D
|
D
|
mathematics
|
A car engine is half filled and holds 15 litres of petrol.what fraction of the engine is full if it contains 18 litres of petrol?
|
[
"1/4",
"2/3",
"2/5",
"3/5",
"4/5"
] |
half of the car engine filed with 15 ltrs means full engine filed with 30 ltrs so the fraction will be=18/30=6/10=3/5
ANSWER:D
The answer is: D
|
D
|
mathematics
|
A train with 120 wagons crosses John who is going in the same direction, in 36 seconds. It travels for half an hour from the time it starts overtaking the John ( he is riding on the horse) before it starts overtaking the Mike(who is also riding on his horse) coming from the opposite direction in 24 seconds. In how much time (in secs) after the train has crossed the Mike do the John meets to Mike?
|
[
"2534 s",
"5435 s",
"7645 s",
"7456 s",
"3576 s"
] |
Let the length of the train be L metres and speeds of the train Arun and Sriram be R, A and S respectively, then
---------- (i)
and ---------(ii)
From eq.(i) and (ii)
3(R - A ) = 2 (R + K)
R = 3A + 2K
In 30 minutes (i.e 1800 seconds), the train covers 1800R (distance) but the Arun also covers 1800 A (distance) in the same time. Therefore distance between Arun and Sriram, when the train has just crossed Sriram
= 1800 ( R - A) - 24 ( A + K)
Time required =
= (3600 - 24) = 3576 s
E
The answer is: E
|
E
|
mathematics
|
Kelly and Jody packed boxes with books. If Jody packed 30% of the total number of boxes, what was the ratio of the number of boxes Kelly packed to the number that Jody packed?
|
[
"1 to 6",
"1 to 4",
"3 to 7",
"3 to 5",
"2 to 3"
] |
Explanation:
If Jody packed 30% of the boxes then Kelly packed 70%. The ratio of the number of boxes Kelly packed to the number Jody packed is thus 30%/70%=3/7
Answer: Option C
The answer is: C
|
C
|
mathematics
|
I flew my tiny seaplane to visit my mother. On the flight up, I flew at 140 mph. On the way home, I flew 88 mph. What was my average speed for the trip?
|
[
"114 mph",
"110 mph",
"88 mph",
"100 mph",
"99 mph"
] |
(140 mph +88 mph)/2= 114 mph
Correct answer is: A
The answer is: A
|
A
|
mathematics
|
A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 50 kmph. When and at what distance from Mumbai do the two trains meet?
|
[
"111",
"771",
"200",
"873",
"811"
] |
When the second train leaves Mumbai the first train covers 40 * 1 = 40 km
So, the distance between first train and second train is 40 km at 10.00am
Time taken by the trains to meet
= Distance / relative speed = 40 / (50 -40) = 4 hours
So, the two trains meet at 2 p.m. The two trains meet 4 * 50 = 200 km away from Mumbai.
Answer: C
The answer is: C
|
C
|
mathematics
|
Robin's average (arithmetic mean) test score on 9 tests is 82. What must be Robin's score on a 10th test for his average score on the 10 tests to be 83?
|
[
"92",
"82",
"72",
"62",
"52"
] |
(9*82+x)/10=83
x=(10*83)-(9*82)
x= 830 - 738
total score required 830 - 738=92
Correct answer is A
The answer is: A
|
A
|
mathematics
|
If n > 2, then the sum, S, of the integers from 1 through n can be calculated by the following formula: S = n(n + 1)/2. Which one of the following statements about S must be true?
|
[
"S is always odd.",
"S is always even.",
"S must be a prime number",
"S must not be a prime number",
"S must be a perfect square"
] |
If n > 2, then the sum, S, of the integers from 1 through n can be calculated by the following formula: S = n(n + 1)/2. Which one of the following statements about S must be true?
A. S is always odd.
B. S is always even.
C. S must be a prime number
D. S must not be a prime number
E. S must be a perfect square
Notice that we are askedwhich of the following MUST be true, not COULD be true. For such kind of questionsif you can prove that a statement is NOT truefor one particular set of numbers, it will mean that this statement is not always true and hence not a correct answer.
A. S is always odd --> not necessarily true if n=3 then 1+2+3=6=even.
B. S is always even --> not necessarily true if n=5 then 1+2+3+4+5=15=odd.
C. S must be a prime number --> not true if n=3 then 1+2+3=6=not prime.
E. S must be a perfect square --> not necessarily true if n=3 then 1+2+3=6=not a perfect square.
Only choice D is left.
Answer: D.
The answer is: D
|
D
|
mathematics
|
The triplicate ratio of 1:2 is?
|
[
"1:7",
"1:8",
"1:3",
"1:1",
"1:2"
] |
13: 23 = 1:8
Answer: B
The answer is: B
|
B
|
mathematics
|
Some of 50%-intensity red paint is replaced with 25% solution of red paint such that the new paint intensity is 30%. What fraction of the original paint was replaced?
|
[
"1/30",
"1/5",
"2/3",
"3/4",
"4/5"
] |
Let total paint = 1
Let amount replaced = x
50 (1-x) + 25x = 30
x = 4/5
ANSWER:E
The answer is: E
|
E
|
mathematics
|
The mean daily profit made by a shopkeeper in a month of 30 days was Rs. 350. If the mean profit for the first fifteen days was Rs. 225, then the mean profit for the last 15 days would be
|
[
"Rs. 200",
"Rs. 350",
"Rs. 475",
"Rs. 425",
"None of these"
] |
Average would be : 350 = (225 + x)/2
On solving, x = 475.
Answer: C
The answer is: C
|
C
|
mathematics
|
If the consumer price index for a sample of goods and services purchased in Dallas rose from 100 at the end of 1967 to x at the end of 1985, what was the average R (arithmetic mean) annual increase in the index over this period?
|
[
"(x + 100)/18",
"x/18",
"(100 − x)/18",
"(x − 100)/18",
"100x/18"
] |
CPI in end of 1967 = 100
CPI in end of 1985 = x
Number of years = 18
Average annual increase in CPI R= (x-100)/18
Answer D
The answer is: D
|
D
|
mathematics
|
A coin is weighted so that the probability of heads on any flip is 0.2, while the probability of tails is 0.8. If the coin is flipped 5 times independently, which of the following represents the probability that tails will appear no more than twice?
|
[
"(0.2)^5 + 5(0.2)^4(0.8) + 10(0.2)^3(0.8)^2",
"(0.3)^5 + 4(0.3)^4(0.8) + 6(0.3)^3(0.8)^2",
"(0.3)^5 + 3(0.3)^4(0.8) + 2(0.3)^3(0.8)^2",
"(0.3)^5 + 2(0.3)^4(0.8) + (0.3)^3(0.8)^2",
"(0.6)^5 + (0.6)^4(0.4) + (0.6)^3(0.4)^2"
] |
Probability of Head, P(H) = 0.2
Probability of Tail, P(T) = 0.8
Tail will appear NO more than twice
i.e. favourable cases
2 Tails and 3 Heads, Probability = 5C2*(0.2)^3*(0.8)^2
1 Tail and 4 Heads, Probability = 5C1*(0.2)^4*(0.8)^2
0 Tail and 5 Heads, Probability = (0.2)^5
Required Probability = Sum of all Favourable cases = (0.2)^5 + 5(0.2)^4(0.8) + 10(0.2)^3(0.8)^2
Answer: option A
The answer is: A
|
A
|
mathematics
|
The sum of 9 hours 25 minutes and 4 hours 35 minutes is approximately what percent of a day?
|
[
"64%",
"56%",
"58%",
"48%",
"72%"
] |
Since the question is asking for an approximate percentage
9:25+4:35 = 14 hours
% of day = 14*100/24 = 7*100/25 ~ 58%
Answer is C.
The answer is: C
|
C
|
mathematics
|
If 10 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a four-percent vinegar solution, what was the concentration of the original solution?
|
[
"20%",
"24%",
"25%",
"28%",
"30%"
] |
Let x be the concentration of the original solution.
10x = 0.04(60)
x = 0.24
The answer is B.
The answer is: B
|
B
|
mathematics
|
In how many ways Chief Minister and Minister be elected from a team of 12 members?
|
[
"128",
"134",
"132",
"167",
"169"
] |
To do this, if captain is elected first, then we have 12 ways of doing this.
For election of vice-captain, we have only 11 ways left, coz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 12*11 = 132 ways.
C
The answer is: C
|
C
|
mathematics
|
Light glows for every 13 seconds . How many max. times did it glow between 1:57:58 and 3:20:47 am.
|
[
"380 times",
"381 times",
"382 times",
"392 times",
"482 times"
] |
Time difference is 1hr,22min,49sec=4969sec. So, light glows floor(4969/13)=382 times.
ANSWER:C
The answer is: C
|
C
|
mathematics
|
An exam consists of 200 questions to be solved in 3 hours, out of which 50 are maths questions. It is suggested that twice as much time be spent on each math question as for each other question. How many minutes should be spent on maths problems?
|
[
"36/25 minutes",
"36/24 minutes",
"36/26 minutes",
"35/25 minutes",
"34/25 minutes"
] |
x=time for each math problem
y= time for every other problem
50x+150y=180 minutes
x=2y because spent twic as much time on the math problems as the other
50(2y)+150y=180
100y+150y=180
250y=180
y= 180/250=18/25 of a minute per problem on the other questions
x=2(18/25)
x=36/25 minutes
ANSWER:A
The answer is: A
|
A
|
mathematics
|
Each of the integers from 1 to 14 is written on the a seperate index card and placed in a box. If the cards are drawn from the box at random without replecement, how many cards must be drawn to ENSURE that the product of all the integers drawn is even?
|
[
"19",
"12",
"11",
"10",
"8"
] |
Out of the 14 integers: 7 are odd and 7 are even.
If we need to make sure that the product of all the integers withdrawn is even then we need to make sure that we have at least one even number. In the worst case:
1. we will end up picking odd numbers one by one, so we will pick all 7 odd numbers first
2. 8th number will be the first even number
So we need to withdraw at least 8 numbers to make sure that we get one even number and the product of all the integers picked is even.
So, answer will be 8. (E)
The answer is: E
|
E
|
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