subject
stringclasses 1
value | question
stringlengths 3
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stringclasses 5
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|---|---|---|---|---|
mathematics
|
If P represents the product of the first 16 positive integers, then P is NOT a multiple of
|
[
"99",
"84",
"72",
"65",
"51"
] |
Answer is E.
Since prime factor of 51 is 3x17. 17 is a prime number and not part of the first 15 positive integers.
A) 9 x 11
B) 12 x 7
C) 12 x 6
D) 13 x 5
E) 3 x 17
The answer is: E
|
E
|
mathematics
|
The sum of two numbers is 25 and their difference is 13. Find their product.
|
[
"104",
"108",
"114",
"325",
"None"
] |
Sol.
Let the numbers be x and y.
Then, x + y = 25 and x - y = 13.
4xy = (x+y)2 - (x-y)2
= (25)2 - (13)2 = 625 - 169 = 456
⇒ xy = 114.
Answer C
The answer is: C
|
C
|
mathematics
|
The present worth of Rs.169 due in 2 years at 4% per annum compound interest is
|
[
"Rs 155.25",
"Rs 156.25",
"Rs 157.25",
"Rs 158.25",
"None of these"
] |
Explanation:
In this type of question we apply formula
Amount=P /(1+R/100)n
Amount=169 /(1+4/100)2
Amount=169∗25∗25/26∗26
Amount=156.25
Option B
The answer is: B
|
B
|
mathematics
|
A bag contains 10 red and 6 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
|
[
"4/7",
"2/3",
"5/8",
"1/4",
"5/7"
] |
Total number of balls = 10+6 = 16
number of white balls = 10
Probability = 10/16 = 5/8
Answer is C
The answer is: C
|
C
|
mathematics
|
If the speed of X meters per hour is equivalent to the speed of Y kilometers per hour, what is Y in terms of X? (1 kilometer=1000 meters)
|
[
"0.1X",
"0.01X",
"0.001X",
"0.0001X",
"0.005X"
] |
X meters per hour -->
--> 1X meters per hour(as there are 3,600 seconds in one hour);
--> X/1,000=0.001X kilometers per hour (as there are 1,000 meters in one kilometer).
Answer: C.
The answer is: C
|
C
|
mathematics
|
A's speed is 20/13 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that B beats A by 80% of the length of the race?
|
[
"44%",
"48%",
"52%",
"42%",
"87%"
] |
First calculate the distance, B has covered with his speed in the time, in which A reached 20% of the race.
Then Add the remaining distance as head start for B to win the race.
Its best to apply Ratios concept here.
Since A's speed is 20/13 of B, therefore, B's speed is 13/20 of A
Distance covered by B = speed x time = (13/20) x (0.2) = 0.13%
(Which means B would have covered 0.13 of the race length during the time in which A has covered 0.2 of the race length.
Therefore to win, B needs a headstart of (1 - 0.13 = ) 0.87 of the race length.
So the answer is E
The answer is: E
|
E
|
mathematics
|
Express of the following as a fraction:
44%
|
[
"11/25",
"13/25",
"11/25",
"17/25",
"None of them"
] |
44% = 44/100= 11/25.
Answer is A.
The answer is: A
|
A
|
mathematics
|
A theater box office sold an average (arithmetic mean) of 64 tickets per staff member to a particular movie. Among the daytime staff, the average number sold per member was 80, and among the evening staff, the average number sold was 60. If there are no other employees, what was the ratio of the number of daytime staff members to the number of evening staff members?
|
[
"1:2",
"1:4",
"3:7",
"7:12",
"4:5"
] |
Deviation from the mean for the daytime staff = 80 - 64 = 16.
Deviation from the mean for the evening staff = 64 - 60 = 4.
Thus, the ratio of the number of daytime staff members to the number of evening staff members is 4:16 = 1:4.
The answer is B.
The answer is: B
|
B
|
mathematics
|
Taylor is making a bracelet. He Starts with 3 blue knots, 6 red knots, and 2 yellow knots, in that order, and repeats the pattern until there is no more string. If the last Knot is yellow which of the following could be the total number of knots on the bracelet.
|
[
"89",
"90",
"95",
"97",
"87"
] |
Repeating sequence = 3 + 6 + 2 = 11.
As the pattern ends in Y this could be the 10th thread or 11 thread (both are yellow)
Out of the answer choices, correct on should be a multiple of 11(since 11 threads are repeating) and if not, multiple of 11 + 10 (since 11 threads are repeating and last sequence end at first yellow)
none of the options is a direct multiple of 11 and only option that is multiple of 11; + 10 is 87 (11*7) + 10
Hence, answer is E
The answer is: E
|
E
|
mathematics
|
There are 6 boxes numbered 1, 2,3,4,5 and 6. Each box is to be filled up either with a red or a green ball in such a way that at least 1 box contains a green ball & the boxes containing green balls are consecutively numbered. The total no. of ways in which this can be done is?
|
[
"18",
"19",
"21",
"23",
"25"
] |
If only one of the boxes has a green ball, it can be any of the 6 boxes. So, this can be achieved in 6 ways.
If two of the boxes have green balls and then there are 5 consecutive sets of 2 boxes. 12, 23, 34, 45, 56.
Similarly, if 3 of the boxes have green balls, there will be 4 options.
If 4 boxes have green balls, there will be 3 options.
If 5 boxes have green balls, then there will be 2 options.
If all 6 boxes have green balls, then there will be just 1 options.
Total number of options = 6 + 5 + 4 + 3 + 2 + 1 = 21
C
The answer is: C
|
C
|
mathematics
|
List R contains five numbers that have an average value of 40. If the median of the numbers in the list is equal to the mean and the largest number is equal to 20 more than two times the smallest number, what is the smallest possible value in the list?
|
[
"12",
"16",
"20",
"24",
"28"
] |
The middle number is 40.
Let the smallest number be x. Then the largest number is 2x+20.
To make x as small as possible, let's make the remaining numbers as large as possible.
So the second largest = the largest = 2x+20.
The second smallest should be equal to the median.
The numbers are x, 40, 40, 2x+20, 2x+20.
x + 40 + 40 + 2x + 20 + 2x + 20 = 5*40 = 200
5x = 80
x = 16
The answer is B.
The answer is: B
|
B
|
mathematics
|
The length of the bridge, which a train 120 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
|
[
"239",
"277",
"255",
"88",
"232"
] |
Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (120 + X)/30
= 25/2 ==> 2(120 + X) = 750 ==> X = 255 m.
Answer: C
The answer is: C
|
C
|
mathematics
|
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
|
[
"33/96",
"33/91",
"33/67",
"33/28",
"33/19"
] |
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is
= ¹²C₄/¹⁵C₄
= (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12)
= 33/91
Answer: B
The answer is: B
|
B
|
mathematics
|
A can do half the work in one day where as B can do it full. B can also do half the work of C in one day. Ratio in their efficiency will be?
|
[
"3:2:4",
"2:2:4",
"1:2:4",
"4:2:4",
"5:2:4"
] |
c
1:2:4
WC of A: B = 1:2
B: C = 1:2
---------------------
A: B: C = 1:2:4
The answer is: C
|
C
|
mathematics
|
Aish started a business investing Rs. 25,000 in 2010, In 2011, he invested an additional amount of Rs. 10,000 and Roshan joined him with an amount of Rs. 35,000. In 2012, Aish invested another additional amount of Rs. 10,000 and Atul joined them with an amount of Rs. 35,000. What will be Roshan’s share in the profit of Rs. 2,40,000 earned at the end of 3 years from the start of the business in 2010?
|
[
"Rs.45000",
"Rs.50000",
"Rs.60000",
"Rs.80000",
"None of these"
] |
Explanation :
Aish : Roshan : Atul
= (25000 x 12 + 35000 x 12 + 45000 x 12) : (35000 x 24) : (35000 x 12)
= 1260000 : 840000 : 420000 = 3 : 2 : 1
Roshan's share = Rs. 240000 x 2/6
= Rs. 80000.
Answer : D
The answer is: D
|
D
|
mathematics
|
some digits were given like 0 2 2 3 3 4 4 then how many no will be there which is greater than 1 lac ,all numbers are distinct
|
[
"530",
"540",
"550",
"560",
"570"
] |
( 6*6*5*4*3*2)/(2! *2!*2!)= 540 ways
ANSWER:B
The answer is: B
|
B
|
mathematics
|
When (6767 +67) is divided by 68, the remainder is?
|
[
"58",
"59",
"62",
"66",
"67"
] |
=> (67^67 + 1) is divisible by (67 + 1)
=> (67^67 + 1) is divisible by 68
=> (67^67+1) ÷ 68 gives a remainder of 0
=> [(67^67+1) + 66] ÷ 68 gives a remainder of 66
=> (67^67 + 67) ÷ 68 gives a remainder of 66
Option D
The answer is: D
|
D
|
mathematics
|
50^51^52 /11
|
[
"6",
"4",
"7",
"3",
"5"
] |
We know that 6^1=6 or 6^2=36 so for all power of 6 unit digit is 6 now que is 50^51^52 now if we divide 50/11 then rem is 6 means 6^51=6 at unit place same for 6^52 salso give 6 at unit place now finally 50^51^52 gives 6 at unit place now 6/11=6
ANSWER:A
The answer is: A
|
A
|
mathematics
|
The greatest possible length which can be used to measure exactly the length 7m, 3m 85cm, 12 m 95 cm is
|
[
"15 cm",
"25 cm",
"35 cm",
"42 cm",
"None of these"
] |
Solution
Required length = H.C.F of 700 cm, 385 cm and 1295 cm
‹=› 35 cm.
Answer C
The answer is: C
|
C
|
mathematics
|
Joe is painting a rectangular room whose dimensions are given by a, b and c meters. Joe takes 8 hours to paint a wall with dimensions a and c. He takes 4 hours to paint a wall with dimensions b and c and 12 hours to paint the ceiling with dimensions a and b. If Joe works at a constant rate and a = 7, then what is the volume of the room?
|
[
"18 cubic meters",
"24 cubic meters",
"30 cubic meters",
"36 cubic meters",
"57.1 cubic meters"
] |
Time to paint each wall as given in problem:
AC = 8 hours
BC = 4 hours
AB = 12 hours
Since he works at constant rate and it takes him twice as long to paint AC compared to BC
AC=2BC
Plug in 6 for A and you find that B=3.5
Since painting AB takes 3 times as long compared to BC,
AB=3BC
Plug in 6 for A and 3 for B and you find that C=2.33
A*B*C=7*3.5*2.3=57.1 cubic meters
Answer: E
The answer is: E
|
E
|
mathematics
|
A boat can travel with a speed of 25km/hr in still water. If the speed of the stream is 5km/hr, find the time taken by the boat to go 90km downstream.
|
[
"1 hr",
"2 hrs",
"3 hrs",
"4 hrs",
"5 hrs"
] |
Speed downstream = (25 + 5) km/hr = 30 km/hr.
Time taken to travel 90 km downstream = 90/30 hrs = 3 hrs.
Answer : C
The answer is: C
|
C
|
mathematics
|
The ratio of the present age of Viju to that of Aju is 7:2. Four years from now, the ratio of the ages of Viju to Aju will be 5:2. What was Viju age 6 years ago ?
|
[
"10 years",
"15 years",
"20 years",
"25 years",
"30 years"
] |
Let the present age of Viju be 7x years and that of Aju be 2x years.
Then, 4 years from now
7x + 4 / 2x + 4 = 5 / 2
or 4x = 12
or x = 3
Viju present age = 7 * 3 = 21 years
Viju age 6 years ago = 21 - 6 = 15 years
answer :B
The answer is: B
|
B
|
mathematics
|
If a particular is never chosen, in how many ways can a cricketbe chosen out of 15 players?
|
[
"245",
"256",
"364",
"370",
"390"
] |
A particular players is never chosen, it means that 11 players are selected out of 14 players.
=> Required number of ways = 14C11
= 14!/11!x3! = 364
C
The answer is: C
|
C
|
mathematics
|
The area of a square field is 900 km2. How long will it take for a horse to run around at the speed of 12 km/h ?
|
[
"12 h",
"10 h",
"8 h",
"6 h",
"None of these"
] |
Explanation Area of field = 900 km2. Then, each side of field = √900=30km Distance covered by the horse = Perimeter of square field = 30 × 4 = 120 km ∴ Time taken by horse = distances/peed=120/12=10h Answer B
The answer is: B
|
B
|
mathematics
|
The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field?
|
[
"20",
"27",
"26",
"188",
"11"
] |
Explanation:
Let breadth=x meters.
Then,Length = meters
Given that,
=> x = 20
Breadth = 20
Answer: A) 20 m
The answer is: A
|
A
|
mathematics
|
The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
|
[
"26",
"56",
"22",
"29",
"21"
] |
1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 – 550
= 56
Answer:B
The answer is: B
|
B
|
mathematics
|
In a theater, the first row has 14 seats and each row has 2 more seats than previous row. If the last row has 56 seats, what is the total number of seats in the theater?
|
[
"770",
"780",
"790",
"800",
"810"
] |
The number of seats in the theater is
14 + (14+2) + ...+ (14+42)=
22(14) + 2(1+2+...+21)=
22(14) + 2(21)(22)/2=
22(14+21) = 22(35) = 770
The answer is A.
The answer is: A
|
A
|
mathematics
|
What will be the reminder when (31^31+31) is divided by 32?
|
[
"72",
"43",
"91",
"40",
"30"
] |
(x^n+1) will be divisible by (x+1) only when n is odd;
(31^31+1) will be divisible by (31+1);
(31^31+1)+30 when divided by will give 30 as remainder.
Correct Option : E
The answer is: E
|
E
|
mathematics
|
A shipment of 9 television sets contains 2 black-and-white sets and 6 color sets. If 2 television sets are to be chosen at random from this shipment, what is the probability that at least 1 of the 2 sets chosen will be a black-and-white set?
|
[
"1/7",
"1/4",
"5/14",
"11/28",
"7/12"
] |
I get 7/12, which is not in the answer choices.
the probability of getting at least one b/w TV is 1-(the probability of getting 2 color TVs)
1-C(6,2)/C(9/2)=21/36=7/12
E
The answer is: E
|
E
|
mathematics
|
55 word in the arrangement of letter PERFECT?
|
[
"CEPFERT",
"CEPFERS",
"CEPFERT",
"CEPFERJ",
"CEPFERG"
] |
arrange in ascending order CEEFPRT
CEE4*3*2*1=24
CEF4*3*2*1=24
CEPE3*2*1=6
24+24+6=54
next word will be CEPFERT
ANSWER:A
The answer is: A
|
A
|
mathematics
|
If n is a positive integer and n^3 is a multiple of 550, what is the least possible value of n?
|
[
"8",
"27",
"81",
"110",
"125"
] |
cube of a number entails having 3 copies of the original prime factors. Since 550 is a factor of n^3 the least possible value of n is 5(11)2 = 110
the answer is D.
The answer is: D
|
D
|
mathematics
|
If the average (arithmetic mean) of a and b is 45 and the average of b and c is 70, what is the value of c − a?
|
[
"25",
"50",
"90",
"140",
"It cannot be determined from the information given."
] |
the arithmetic mean of a and b =(a+b)/2=45 -- a+b=90 --1
similarly for b+c=140 --2
subtracting 1 from 2 we have
c-a=50 ANSWER:E
The answer is: E
|
E
|
mathematics
|
If an object travels at seven feet per second, how many feet does it travel in one hour?
|
[
"30",
"300",
"720",
"25200",
"18000"
] |
Speed = 7 feet per second.
1 Hour= 60X60 Seconds = 3600 Seconds.
Total no of feet traveled in 1 hour = 3600X7= 25200
Answer D
The answer is: D
|
D
|
mathematics
|
What percent of a day is four hours?
|
[
"16.67%",
"16x1/2%",
"18x2/3%",
"22x1/2%",
"None of these"
] |
Explanation :
Required percentage = (4/24100)%.
= 16.67%.
Answer : A
The answer is: A
|
A
|
mathematics
|
The largest 5 digit number exactly divisible by 91 is?
|
[
"99918",
"99919",
"99921",
"99923",
"99929"
] |
Largest 5-digit number = 99999
91) 99999 (1098
91
---
899
819
----
809
728
---
81
---
Required number = (99999 - 81)
= 99918.
Option A
The answer is: A
|
A
|
mathematics
|
Photography changed drastically _________ introduced in the market.
|
[
"when polariod",
"when polariod",
"when polariod",
"as polaroid",
"1312"
] |
Explanation:
There is no adequation information is given about details of subsequent changes. So "when" is the right word. Option a. "As" inditates reason.
Answer:D
The answer is: D
|
D
|
mathematics
|
If a certain sample of data has a mean of 24.0 and a standard deviation of 3.0, which of the following values is more than 2.5 standard deviations from the mean?
|
[
"12.0",
"13.5",
"17.0",
"23.5",
"26.5"
] |
Value ismore than 2.5SDfrom the mean means that the distance between the mean and the value must be more than 2.5*SD=7.5. So the value must be either less than 24-7.5=16.5or more than 24+7.5=31.5.
Answer: C.
The answer is: C
|
C
|
mathematics
|
The marks obtained by Vijay and Amith are in the ratio 8:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of?
|
[
"12:5",
"12:1",
"6:5",
"12:2",
"6:3"
] |
8:5
3:2
-------
24:15:10
24:10
12:5
Answer: A
The answer is: A
|
A
|
mathematics
|
How many paying stones, each measuring 2 m * 1 m are required to pave a rectangular court yard 30 m long and 16 m board?
|
[
"240",
"18",
"26",
"17",
"12"
] |
30 * 16 = 2 * 1 * x => x
= 240
Answer: A
The answer is: A
|
A
|
mathematics
|
Veena ranks 44rd from the top in a class of 182. What is her rank from the bottom if 22 students have failed the examination?
|
[
"88",
"108",
"110",
"90",
"117"
] |
total student=182
failed=22
paasd student=182-22=160
from bottom her rank is=160-44+1=117
ANSWER:E
The answer is: E
|
E
|
mathematics
|
If five persons sit in a row, then the probability that three particular persons are always together is?
|
[
"3/5",
"3/4",
"1/9",
"1/6",
"3/10"
] |
Five persons can be arranged in a row in 5! ways.
Treat the three persons to sit together as one unit then there three persons and they can be arranged in 3! ways.
Again three persons can be arranged among them selves in 3! ways.
Favourable outcomes = 3!3!
Required probability = 3!3!/5! = 3/10
Answer:E
The answer is: E
|
E
|
mathematics
|
A single discount equivalent to the discount series of 16%, 10% and 5% is?
|
[
"28.18",
"38.9",
"41.6",
"31.4",
"31.1"
] |
100*(84/100)*(90/100)*(95/100) = 71.82
100 - 71.82 = 28.18
Answer: A
The answer is: A
|
A
|
mathematics
|
A rectangular field has to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?
|
[
"80 feet",
"85 feet",
"83 feet",
"88 feet",
"90 feet"
] |
Given that area of the field = 680 sq. feet
=> lb = 680 sq. feet
Length(l) = 20 feet
=> 20 × b = 680
=> b = 680/20 = 34 feet
Required length of the fencing = l + 2b = 20 + (2 × 34) = 88 feet
Answer is D.
The answer is: D
|
D
|
mathematics
|
In a hostel there were 100 students. To accommodate 25 more students the average is decreased by some rupees. But total expenditure increased by Rs.500. If the total expenditure of the hostel now 8500, find decrease of average budget?
|
[
"20",
"15",
"12",
"18",
"24"
] |
Let average is x
100x + 500=8500
x = 80
let decrease = y
125(80– y)= 8500
y = 12
Answer:C
The answer is: C
|
C
|
mathematics
|
The mean of 50 observations was 36. It was found later that an observation 60 was wrongly taken as 23. The corrected new mean is?
|
[
"36.7",
"36.1",
"36.5",
"36.9",
"36.3"
] |
Correct sum
= (36 * 50 + 60 - 23)
= 1837.
Correct mean = 1837/50
= 36.7
Answer:A
The answer is: A
|
A
|
mathematics
|
Jim is mixing up a salad dressing. Regardless of the number of servings, the recipe requires that 5/8 of the finished dressing mix be Canola oil, 1/4 vinegar, and the remainder an even mixture of salt, pepper and sugar. If Jim accidentally doubles the vinegar and forgets the sugar altogether, what proportion of the botched dressing will be Canola oil?
|
[
"15/29",
"5/8",
"5/16",
"1/2",
"13/27"
] |
Canola oil = 5/8 = 15/24 --> 15 parts out of 24;
Vinegar = 1/4 = 6/24 --> 6 parts out of 24;
Salt + pepper + sugar = 1-(15/24+6/24)= 3/24, so each = 1/24 --> 1 part out of 24 each;
If vinegar = 12 (instead of 6) and sugar = 0 (instead of 1) then total = 15+12+1+1+0 = 29 parts out of which 15 parts are Canola oil --> proportion = 15/29.
Answer: A.
The answer is: A
|
A
|
mathematics
|
Assume that f(1)=0 and f(m+n)=f(m)+f(n)+4(9mn-1). For all natural numbers (Integers>0)m and n. What is the value of f(17)?
|
[
"4832",
"4855",
"4825",
"4895",
"4862"
] |
Explanation:
f(1) = 0
f(2) = f(1+1) = f(1)+f(1)+4(9×1×1 – 1) = 0+0+4×8 = 32
f(4) = f(2+2) = f(2)+f(2)+4(9×2×2 – 1) = 32+32+4×35 = 204
f(8) = f(4+4) = f(4)+f(4)+4(9×4×4 – 1) = 204+204+4×143 = 980
f(16) = f(8+8) = f(8)+f(8)+4(9×8×8 – 1) = 980+980+4×575 = 4260
f(17) = f(1+16) = f(16)+f(1)+4(9×16×1 –1) = 4260+0+ 4×143 = 4832
Answer:A
The answer is: A
|
A
|
mathematics
|
In a bouquet of flowers, all but two are roses, all but two are tulips, and all but two are daisies. How many flowers are in the bouquet?
|
[
"1",
"2",
"3",
"4",
"5"
] |
C
3
There are 3 flowers (1 rose, 1 tulip, and 1 daisy).
The answer is: C
|
C
|
mathematics
|
Dawson is going with 14 friends on a trip to Washington D.C for spring break. Airfare and hotel costs a total of $13500.00 for the group of 15 friends. How much does each person have to pay for their hotel and airfare?
|
[
"$900",
"$800",
"$850",
"$950",
"$920"
] |
Answer= A
The total cost of the trip ($13500.00) divided by 15 equals $900.00.
The answer is: A
|
A
|
mathematics
|
How many gallons of milk that is 10 percent butter-fat must be added to 8 gallons of milk that is 25 percent butterfat to obtain milk that is 20 percent butterfat?
|
[
"4",
"12",
"14",
"16",
"28"
] |
Equate the fat:
0.1x + 0.25*8 = 0.2(x + 8) --> x = 4.
Answer: A.
The answer is: A
|
A
|
mathematics
|
A person incurs loss for by selling a watch for Rs1140.at what price should the watch be sold to earn a 5% profit ?
|
[
"1205",
"1260",
"1300",
"1340",
"1450"
] |
let the new sp be Rsx.then
(100-loss%) : (1st sp)=(100+gain%) (2nd sp)
{(100-5)/1400}={(100+5)/x}=> x={(105*1140)/95} =1260.
ANSWER B
The answer is: B
|
B
|
mathematics
|
Rahim bought 65 books for Rs.6500 from one shop and 35 books for Rs.2000 from another. What is the average price he paid per book ?
|
[
"80",
"138",
"100",
"129",
"85"
] |
Average price per book
= (6500+ 2000) / (65 + 35)
= 8500 / 100
= Rs.85
Answer:E
The answer is: E
|
E
|
mathematics
|
The ratio of the earnings of P and Q is 9 : 10. If the earnings of P increases by one-fourth and the earnings of Q decreases by one-fourth, then find the new ratio of their earnings?
|
[
"3/9",
"3/2",
"3/5",
"3/6",
"3/1"
] |
Let the earnings of P and Q be Rs. 9x and Rs. 10x respectively.
New ration = [9x + 1/4(9x)]/[10x - 1/4(10x)]
=> [9x(1 + 1/4)]/[10x(1 - 1/4)]
= 9/10 * (5/4)/(3/4) => 3/2.
Answer:B
The answer is: B
|
B
|
mathematics
|
In a kilo meter race, if A gives B a 40 m start, A wins by 19 s. But if A gives B a 30 s start, B wins by 40 m. Find the time taken by B to run 5,000 m?
|
[
"150 s",
"450 s",
"750 s",
"825 s",
"925 s"
] |
When B is given a 40 m start then B runs 960m in T secs and A runs 1000m in T-19 secs.
When B is given a 30 second start then B runs 1000m in t secs and A runs 960m in t - 30 secs.
Assume that the speed of A (Va) and B (Vb) is constant in both situations.
Then Vb = 960 ÷ T = 1000 ÷ t, and Va = 1000 ÷ (T - 19) = 960 ÷ (t - 30)
So 960t = 1000T, and 1000t - 30000 = 960T - 18240. Then 40t = -40T + 11760, t = -T + 294.
Substituting for t in 960t = 1000T
gives : -960T + 282240 = 1000T
1960T = 282240
T = 144
B 's speed is 960 / T = 960 / 144 = 6.67 metres per second.
Assuming the same constant speed to run 5000 metres then the time taken is
5000 / 6.67 = 750 seconds
ANSWER:C
The answer is: C
|
C
|
mathematics
|
Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $9 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discounts rates is 33 percent, what is the discount rate on Pony jeans?
|
[
"9%",
"10%",
"11%",
"12%",
"65%"
] |
x discount on Pony jeans, (0.33-x) discount on Fox jeans.
Set the equation: 3*15(0.33-x)+2*18x=9 --> x=0.65=65%
Answer: E.
The answer is: E
|
E
|
mathematics
|
Which of the following numbers is between 1⁄2 and 1⁄3?
|
[
".55",
".38",
".29",
".22",
".20"
] |
1/3 = .333...
1/2 = .5
The only number between these two is 0.38.
The answer is B.
The answer is: B
|
B
|
mathematics
|
How many seconds does a train 120 meters long, traveling at 54 km/h, take to completely cross a bridge of 180 meters in length?
|
[
"18",
"20",
"22",
"24",
"26"
] |
54 km/h = 54000/3600 = 15 m/s
Time = 300 / 15 = 20 seconds
The answer is B.
The answer is: B
|
B
|
mathematics
|
As part of her MBA program, Karen applied for three different Spring Break outreach projects, each of which selects its students by a random lottery of its applicants. If the probability of her being accepted to each individual project is 30%, what is the probability that Karen will be accepted to at least one project?
|
[
"729/1000",
"657/1000",
"343/500",
"123/250",
"17/100"
] |
Since the probability of Karen's being accepted to each individual project is 30%, the probability of her not being accepted to each project is 70%. The probability that she will be accepted to none is, therefore, (7/10)*(7/10)*(7/10)=343/1000.
P(Karen will be accepted to at least one project) = 1 - (343/1000) = 657/1000.
The answer is B.
The answer is: B
|
B
|
mathematics
|
Colin has an app on his phone that generates a random integer betwen 1 and 10. He generates
10 random numbers and computes the sum. Compute the number of distinct possible sums
Colin can end up with.
|
[
"41",
"32",
"75",
"91",
"82"
] |
The maximum possible sum is 10 * 10 = 100. The minimum possible sum is 10.
Hence, there are 100 - 10 + 1 = 91 possible sums
correct answer D
The answer is: D
|
D
|
mathematics
|
A shopkeeper sells 200 metres of cloth for Rs. 12000 at a loss of Rs.12 per metre. Find his cost price for one metre of cloth?
|
[
"s.59",
"s.72",
"s.62",
"s.50",
"s.13"
] |
SP per metre = 12000/200
= Rs. 60 Loss per metre
= Rs. 12 CP per metre = 60 + 12
= Rs.72
Answer: B
The answer is: B
|
B
|
mathematics
|
How many prime numbers between 50 to 100?
|
[
"11",
"10",
"15",
"14",
"12"
] |
primes are of the form 6n+1 or 6n-1
Put n=9
6n+1=6*9+1=55 where 55 is not prime
for n=9
6n-1=6*9-1=53
for n=10 , 6n-1= 59 and 61
for n=11 , ==> 67
for n =12 ==> 73 and 71
for n =13 ==> 79
for n =14 ==> 83
for n=15 ==> 89
for n =16 ==> 97
therefore total number of prime numbers = 10
Ans - B
The answer is: B
|
B
|
mathematics
|
6 friends go out to dinner at Outback Steakhouse. The total of their meal comes to 118.60 without a tip. They decide to leave a 20% tip to the waitress. They want to split the costs if the bill including the tip evenly among them. How much does each person have to pay if the bill is split evenly?
|
[
"19.77",
"71.16",
"18.6",
"23.72",
"42.32"
] |
The amount of the tip= 118.60*.20=23.72
118.60+23.62= 142.32 = amount of bill after the tip
142.32/6=23.72= amount each person must pay
The answer is D.
The answer is: D
|
D
|
mathematics
|
At present the age of the father is 3 times that of the age of the son. Three years hence the father's age would be 2 times that of his son. Find the present age of the father?
|
[
"18years",
"12years",
"20years",
"16years",
"25years"
] |
Age of the son = (3-1)*3 / (3-2) = 6 years
Age of the father = 6*3 = 18 years
Answer is A
The answer is: A
|
A
|
mathematics
|
What is the sum of the different positive prime factors of 550?
|
[
"10",
"11",
"15",
"16",
"18"
] |
I think answer is E: 27
550 = 55 * 10 = (5 * 11) * (2 * 5)
Sum of theDIFFERENTpositive prime factors = 2 + 5 + 11 = 18
The answer is: E
|
E
|
mathematics
|
In a certain quiz that consists of 10 questions, each question after the first is worth 4 points more than the preceding question. If the 10 questions on the quiz are worth a total of 340 points, how many points is the third question worth?
|
[
"39",
"24",
"28",
"26",
"30"
] |
x
x+4
x+8
x+12
x+16
x+20
x+24
x+28
x+32
x+36
10x+180=340
10x=160
x=16
3rd question = x+8 = 16+8 = 24
Answer B
The answer is: B
|
B
|
mathematics
|
If 5x + y = 6 and 2y − 4x = 7, then what is the value of x + 3y?
|
[
"1/7",
"13",
"15",
"52/7",
"60/7"
] |
5x + y = 6
−4x + 2y = 7
Adding both the equations --> x + 3y = 13
Answer: B
The answer is: B
|
B
|
mathematics
|
The base of a right triangle is 8 and hypotenuse is 10. Its area is?
|
[
"12",
"80",
"59",
"24",
"25"
] |
Explanation:
h2=(10)2-(8)2-(6)2->h=6
1/2*8*6=24
ANSWER IS D
The answer is: D
|
D
|
mathematics
|
A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that exactly three bulbs are good.
|
[
"20/69",
"20/63",
"20/61",
"20/66",
"20/63"
] |
Explanation:
Required probability =
= (10 * 4)/126 = 20/63
Answer: B
The answer is: B
|
B
|
mathematics
|
A certain bag contains 100 balls — 10 white, 30 green, 10 yellow, 47 red, and 3 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?
|
[
"0.9",
"0.75",
"0.6",
"0.8",
"0.5"
] |
According to the stem the ball can be white, green or yellow, so the probability is (white + green + yellow)/(total) = (10 + 30 + 10)/100 = 50/100 = 0.5.
Answer is E
The answer is: E
|
E
|
mathematics
|
A individuals pledged to pay equal contributions so that a charity’s goal of $x could be reached. If d of the contributors failed to pay their share, which of the following represents the additional number of dollars that each of the remaining individuals would have to pay in order to allow the charity to reach its goal?
|
[
"dx/A(A - d)",
"dx",
"a",
"A-d",
"nA-d"
] |
Number of individuals = A
Amount paid by each individual = n
Total expected amount = Charity's goal = nA = x
n = x/A
Number of individuals who fail to pay = d
Contribution from individuals who would fail to pay = dx/A --> Additional amount
Number of individuals who are paying = A - d
Additional amount has to be divided among the (A - d) individuals --> dx/A(A - d)
A
The answer is: A
|
A
|
mathematics
|
The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 4/5. Find the fraction?
|
[
"A)2/3",
"B)5/7",
"C)4/7",
"D)5/9",
"E)None of these"
] |
Let the numerator and denominator of the fraction be 'n' and 'd' respectively.
d = 2n - 1
(n + 1)/(d + 1) = 4/5
5n + 5 = 4d + 4
5n + 5 = 4(2n - 1) + 4 => n = 5/3
d = 2n - 1 => d = 3/7
Hence the fraction is : 5/7
ANSWER:B
The answer is: B
|
B
|
mathematics
|
The ages of X and Y are in the proportion of 6:5 and total of their ages is 44 years. The proportion of their ages after 8 years will be
|
[
"8:7",
"6:9",
"4:9",
"3:6",
"1:9"
] |
A
8:7
Let current ages of X and Y correspondingly, is 6A & 5A
Given: 6A + 5A = 44
=> A = 4
Proportion of ages after 0.8 decades will be
6A + 8 : 5A + 8
or, 32:28 or, 8:7
The answer is: A
|
A
|
mathematics
|
A man gets a simple interest of Rs.400 on a certain principal at the rate of 5% p.a in two years. Find the compound interest the man will get on twice the principal in two years at the same rate?
|
[
"s.550",
"s.556",
"s.656",
"s.750",
"s.820"
] |
Let the principal be Rs.P
S.I at 5% p.a in 8 years on Rs.P = Rs.400
(P)(8)(5)/100 = 400
P = 4000
C.I on Rs.2P i.e., Rs.8000 at 5% p.a in two years
=8000{ [1 + 5/100]^2 - 1}
= 8000(41/400)
= Rs. 820
Answer:E
The answer is: E
|
E
|
mathematics
|
Let us say that a table tennis tournament was going on with knock out terms which means the one who loses the match is out of the tournament. 91 players took part in that tournament. How many matches were played?
|
[
"90 matches",
"95 matches",
"99 matches",
"85 matches",
"87 matches"
] |
A 90 matches. The number of matches will always sum up to one less than the number of players in a knock out tournament. You may calculate it in any manner. Thus 90 matches were played.
The answer is: A
|
A
|
mathematics
|
An inspector rejects 0.08% of the meters as defective. How many will he examine to reject 2?
|
[
"1200",
"1240",
"1852",
"3200",
"2500"
] |
Then, 0.08% of x = 2
(8/100)*(1/100)x = 2
x = (2*100*100)/8 = 2500
Answer is E
The answer is: E
|
E
|
mathematics
|
A warehouse is labeling computer inventory with 4-digit codes. Each code is to consist of four digits between the numbers 0 and 7. The manager is debating whether to allow any 4-digit codes to have leading zero's before a non-zero number is used. If not allowed, then numbers like0025cannot be used.
The manager wants to measure the magnitude of the number of 4-digit code possibilities that are lost if he disallows the use of leading zero's. How many such codes would be lost?
|
[
"7000",
"1000",
"1011",
"1101",
"1110"
] |
The number of codes possible if leading zero is allowed = 10*10*10*10=10^4
The number of codes possible if leading zero is NOT allowed = 7*10*10*10=9*10^3
The difference = 10^4 - 7*10^3 = 10^3(10-7) = 7*10^3.
Answer: A.
Similar questions to practice:
Hope it helps.
The answer is: A
|
A
|
mathematics
|
John deposited $10,000 to open a new savings account that earned 12 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in John’s account 6 months after the account was opened?
|
[
"$10,101",
"$10,609",
"$10,209",
"$10,601",
"$10,404"
] |
12 percent annual interest compounded quarterly --> 3% in 3 moths.
For the first 3 moths interest was 3% of $10,000, so $300;
For the next 3 moths interest was 3% of $10,000,plus9 earned on previous interest of $100, so $300+$9=$309;
Total interest for 6 months was $300+$309=$609, hence balance after 6 months was $10,000+ $609=$10,609.
Answer: B.
The answer is: B
|
B
|
mathematics
|
a car runs 10,000 miles using 5 tyres interchangably. to have equal wornout by all tyres, how many miles each tyre should have run?
|
[
"7000 miles",
"8000 miles",
"9000 miles",
"6000 miles",
"5000 miles"
] |
simply 10000*4/5=8000
or
take a,b,c,d,e are tyres then each tyre travells 8000 miles first car runs with
a,b,c,d for 2000 miles
b,c,d,e for 2000 miles
a,c,d,e for 2000 miles
a,b,d,e for 2000 miles
a,b,c,e for 2000 miles
so total distance travelled is 10000 miles and each tyre travells 8000 miles
ANSWER:B
The answer is: B
|
B
|
mathematics
|
A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.340 less than the sum lent. What was the sum lent?
|
[
"228",
"278",
"289",
"500",
"821"
] |
P - 340 = (P*4*8)/100
P = 500
Answer: D
The answer is: D
|
D
|
mathematics
|
Tough and Tricky questions: Number Properties.
If (z + 3)/6 is an integer, what is remainder when z is divided by 6?
|
[
"2",
"3",
"4",
"5",
"6"
] |
6/6=1
Ans B
The answer is: B
|
B
|
mathematics
|
After decreasing 80% in the price of an article costs Rs.320. Find the actual cost of an article?
|
[
"2777",
"2987",
"1200",
"9977",
"1600"
] |
CP* (20/100) = 320
CP= 16* 100 => CP = 1600
Answer: E
The answer is: E
|
E
|
mathematics
|
6th March, 2005 is Monday, what was the day of the week on 6th March, 2004
|
[
"wednessday",
"Thursday",
"Friday",
"Saturday",
"Sunday"
] |
Number of days from 6th March, 2004 to 5th March 2005 = 365 days
Feb 2004 has 29 days ( leap year),
365 days = 1 odd day
Given that 6th March, 2005 is Monday
Hence 6th March, 2004 = (Monday - 1 odd day) = Sunday
Answer : E
The answer is: E
|
E
|
mathematics
|
A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to contradict each other, narrating the same incident?
|
[
"30/100",
"32/100",
"35/100",
"41/100",
"None of these"
] |
Explanation :
Let A = Event that A speaks the truthB = Event that B speaks the truthThen P(A) = 75/100 = 3/4P(B) = 80/100 = 4/5P(A-lie) = 1-3/4 = 1/4P(B-lie) = 1-4/5 = 1/5Now ,A and B contradict each other =[A lies and B true] or [B true and B lies]= P(A).P(B-lie) + P(A-lie).P(B)= (3/5*1/5) + (1/4*4/5) = 7/20= (7/20 * 100) % = 35%
Answer : C
The answer is: C
|
C
|
mathematics
|
sale of Rs 6835, Rs. 9927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6900 ?
|
[
"4966",
"6477",
"7391",
"2676",
"1881"
] |
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6900 x 6) - 34009]
= Rs. (41400 - 34009)
= Rs. 7391
Answer: C
The answer is: C
|
C
|
mathematics
|
It takes ten minutes to fry a steak (five minutes for each side). You are frying the steaks in a pan that can accommodate only two steaks at one time. What is the least amount of time by which you can fry all the three steaks you have?
|
[
"13 minutes",
"14 minutes",
"15 minutes",
"16 minutes",
"17 minutes"
] |
Solution:
Fifteen Minutes.
After frying for five minutes, you can take out one steak and put the third one inside while turning the other one inside. After five more minutes, one steak is fried from both sides and you can take it out. Now put in the steak that we removed and turn the other one inside. After five more minutes, they both will also be fried from both sides.
Answer C
The answer is: C
|
C
|
mathematics
|
A certain business produced x rakes each month form November through February and shipped x/2 rakes at the beginning of each month from March through October. The business paid no storage costs for the rakes from November through February, but it paid storage costs of $0.30 per rake each month from March through October for the rakes that had not been shipped. In terms of x, what was the total storage cost, in dollars, that the business paid for the rakes for the 12 months form November through October?
|
[
"0.40x",
"4.20x",
"1.40x",
"1.60x",
"3.20x"
] |
because we have a total of 4X
Also from Mar- Oct the rakes will be deducted by 1/8 X
so
In Apr they pay for the storage 0.3 * 4X * 7/8
In May they pay for the storage 0.3 * 4X * 6/8
In Jun they pay for the storage 0.3 * 4X * 5/8
In Jul they pay for the storage 0.3 * 4X * 4/8
In Aug they pay for the storage 0.3 * 4X * 3/8
In Sep they pay for the storage 03 * 4X * 2/8
In Oct they pay for the storage 0.3 * 4X * 1/8
total = 0.3 * 4X * 1/8 * [ 1+2+3+4+5+6+7]
= 0.3 * X/2 * (28)
= 4.2X
(B)
The answer is: B
|
B
|
mathematics
|
Seven different books (A, B, C, D,E,F,G and H) are to be arranged on a shelf. Books A and B are to be arranged first and second starting from the right of the shelf. The number of different orders in which books C, D,E,F and G may be arranged is
|
[
"9!",
"12!",
"5!",
"25!",
"18!"
] |
Solution
Since books A and B are arranged first and second, only books C,D,E,F and G will change order. Therefore it an arrangement problem involving 5 items and the number of different order is given by
5!
Answer C
The answer is: C
|
C
|
mathematics
|
Three numbers are in the ratio 1:4:8 and their H.C.F is 3. The numbers are?
|
[
"3, 15, 24",
"3, 12, 27",
"3, 12, 22",
"3, 12, 24",
"3, 12, 21"
] |
Let the required numbers be x, 4x and 8x. Then, their H.C.F = x. So, x = 3.
The numbers are 3, 12, 24.
Answer: D
The answer is: D
|
D
|
mathematics
|
A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18000. A's share is?
|
[
"Rs.7500",
"Rs.7200",
"Rs.6000",
"Rs.5750",
"Rs.6750"
] |
x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 18000 = 6000
ANSWER:C
The answer is: C
|
C
|
mathematics
|
If x^2+4x+3 is odd, then which one of the following could be the value of x.
|
[
"3",
"4",
"5",
"6",
"9"
] |
for any x, 4x+3->odd
so x^2 should be even, means x should be even;
only ans we have 4 as even.
ANSWER:B
The answer is: B
|
B
|
mathematics
|
In what ratio must rice of Rs.32per kg be mixed with rice of Rs.42 per kg so that cost of mixture is Rs.20 per kg?
|
[
"13:6",
"13:5",
"11:6",
"11:5",
"12:5"
] |
(20-42)/(32-20)=22/12=11:6
ANSWER:C
The answer is: C
|
C
|
mathematics
|
A can do a piece of work in 8 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in ?
|
[
"2 days",
"5 days",
"6 days",
"7 days",
"11 days"
] |
B's 9 day's work = 9 x (1/12) = 3/4
Remaining work = (1 - 3/4) = 1/4
1/4 work is done by A in = 8 x (1/4) = 2 days.
answer : A
The answer is: A
|
A
|
mathematics
|
Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both BG, with these two children immediately adjacent to here on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations W are there for the children?
|
[
"240",
"480",
"720",
"1440",
"3600"
] |
MAGOOSHOFFICIAL SOLUTION:
First, we will consider the restricted elements — children ABG have to be in three seats in a row. How many “three in a row” seats are there in a row of seven seats?
X X X _ _ _ _
_ X X X _ _ _
_ _ X X X _ _
_ _ _ X X X _
_ _ _ _ X X X
There are five different “three in a row” locations for these three children. Now, for any given triplet of seats, we know A has to be in the middle, so the children could be seated B-A-G or G-A-B — just those two orders. This means the total number of configurations for these three children is 5*2 = 10.
Now, consider the non-restricted elements, the other four. Once ABG are seated, the remaining four children can be seated in any order among the remaining four seats — that’s a permutation of the 4 items —- 4P4 = 4! = 24. For any single configuration of ABG, there are 24 ways that the other children could be seated in the remaining seats.
Finally, we’ll combine with the Fundamental Counting Principle. We have 10 ways for the first three, and 24 ways for the remaining four. That’s a total number of configurations W of 24*10 = 240.
Answer = A
The answer is: A
|
A
|
mathematics
|
The sum of the non-prime numbers between 60 and 70, non-inclusive, is
|
[
"387",
"429",
"457",
"499",
"536"
] |
sum of consecutive integers from 61 to 69, inclusive ====> (A1 + An)/2 * # of terms = (61 + 69)/2 * 9 = 65 *9 = 585
sum of non-prime numbers b/w 60 and 70, non inclusive ===> 585 - 128 (i.e., 61 + 67, being the prime #s in the range) =457
Answer: C
The answer is: C
|
C
|
mathematics
|
There are two circles of different radii. The are of a square is 784 sq cm and its side is twice the radius of the larger circle. The radius of the larger circle is seven - third that of the smaller circle. Find the circumference of the smaller circle.
|
[
"6∏ cm",
"8∏ cm",
"12∏ cm",
"16∏ cm",
"None of these."
] |
Let the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm.
a2 = 784 = (4)(196) = (22).(142)
a = (2)(14) = 28
a = 2l, l = a/2 = 14
l = (7/3)s
Therefore s = (3/7)(l) = 6 Circumference of the smaller circle = 2∏s = 12∏ cm.
ANSWER:C
The answer is: C
|
C
|
mathematics
|
If q and t are positive integers, qt + q + t cannot be
|
[
"5",
"6",
"7",
"8",
"9"
] |
Let qt + t +q = x
Add 1 on both sides:
qt + t + q + 1 = x + 1
tq + 1) + q + 1 = x + 1
(q + 1)(t + 1) = x + 1
Minimum value of (q + 1) = 2
Minimum value of (t + 1) = 2
Hence x + 1 cannot be prime
Substitute x from the given options: 6 + 1 = 7 --> prime --> qt + t + s cannot be 6
Answer: B
The answer is: B
|
B
|
mathematics
|
A meeting has to be conducted with 6 managers. Find the number of ways in which the managers may be selected from among 9 managers, if there are 2 managers who refuse to attend the meeting together.
|
[
"36",
"40",
"42",
"45",
"49"
] |
The total number of ways to choose 6 managers is 9C6 = 84
We need to subtract the number of groups which include the two managers, which is 7C4 = 35.
84 - 35 = 49
The answer is E.
The answer is: E
|
E
|
mathematics
|
A man buys an item at Rs. 1300 and sells it at the loss of 20 percent. Then what is the selling price of that item
|
[
"Rs. 660",
"Rs. 760",
"Rs. 860",
"Rs. 1040",
"None of these"
] |
Explanation:
Here always remember, when ever x% loss,
it means S.P. = (100 - x)% of C.P
when ever x% profit,
it means S.P. = (100 + x)% of C.P
So here will be (100 - x)% of C.P.
= 80% of 1300
= 80/100 * 1300
= 1040
Option D
The answer is: D
|
D
|
mathematics
|
David biked 16 1/3 miles in 2 hours and 20 minutes. What was his average rate of speed in miles per hour?
|
[
"7",
"7 2/3",
"8 1/3",
"9",
"9 1/3"
] |
D = 16(1/3) = 49/3
T = 2(1/3) = 7/3
S = D/T = 7
Answer = A
The answer is: A
|
A
|
mathematics
|
A sum was put at SI at certain rate for 2 years.Had it been put at 3% higher rate, it would have fetched Rs.300 more.Find the Sum
|
[
"RS 4000",
"RS 5000",
"RS 6000",
"RS 7000",
"RS 8000"
] |
let P be the sum.and X be the interest rate.
(2*(X+3)*P/100) - (2*X*P/100)=300
THEREFORE 6P/100=300
P=RS 5000
ANSWER:B
The answer is: B
|
B
|
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