subject
stringclasses 1
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stringlengths 3
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listlengths 5
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|---|---|---|---|---|
mathematics
|
Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.60 a kg to produce a mixture worth Rs. 6.30 a kg
|
[
"2:0",
"2:3",
"2:1",
"2:2",
"7:9"
] |
By the rule of alligation:
Cost of 1 kg rice of 1st kind Cost of 1 kg rice of 2nd kind
Required ratio = 70 : 90 = 7 : 9
Answer: E
The answer is: E
|
E
|
mathematics
|
A train A leaves Mysore at 6 a.m. and reaches Bangalore at 10 a.m. Another train leaves B Bangalore at 8 a.m. and reaches Mysore at 11.30 a.m. At what time do the two trains cross each other ?
|
[
"8.30 a.m.",
"8.45 a.m.",
"8.56 a.m.",
"9 a.m.",
"None of these"
] |
Explanation :
Solution: Let the distance between mysore and bangalore be x km and let the trains meet y hours after 8 a.m.
Clearly, A covers x km in 4 hours and B covers x km in 4.5 hrs = (7/2) hrs
.'. Speed of A = x/4 kmph, speed of B = 2x/7 kmph.
Distance covered by A in (y+2) hrs + distance covered by B in y hrs = x.
.'. x/4(y+2) + 2x/7 * y = x
=> (y+2)/4 + 2y/7 = 1
=> y = 14/15 hrs =14*60/15 = 56 min.
Hence, the trains meet at 8.56 a.m.
Answer : C
The answer is: C
|
C
|
mathematics
|
CONVERT 2.5 hectares in ares
|
[
"130 ares.",
"160 ares.",
"180 ares.",
"230 ares.",
"250 ares."
] |
2.5 hectares in ares
1 hectare = 100 ares
Therefore, 2.5 hectares = 2.5 × 100 ares
= 250 ares.
ANSWER- E
The answer is: E
|
E
|
mathematics
|
Rs. 6000 is lent out in two parts. One part is lent at 4% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
|
[
"5:1",
"5:7",
"5:2",
"5:8",
"5:2"
] |
Let the amount lent at 4% be Rs. x
Amount lent at 10% is Rs. (6000 - x)
Total interest for one year on the two sums lent
= 4/100 x + 10/100 (6000 - x) = 600 - 3x/100
=> 600 - 3/100 x = 450 => x = 2500
Amount lent at 10% = 3500
Required ratio = 5:7
Answer:B
The answer is: B
|
B
|
mathematics
|
The average of first 35 prime numbers is?
|
[
"14.54",
"15.6",
"15.8",
"14.7",
"14.8"
] |
Explanation:
Average = (2+3+5+7+11+13+17+19+23+29+31)/11= 160/11= 14.54(Approx)
Answer is A
The answer is: A
|
A
|
mathematics
|
The number of arrangements that can be made with the letters of the word JOHNNIE so that the vowels occupy the even places?
|
[
"A)122",
"B)134",
"C)144",
"D)156",
"E)176"
] |
Explanation:
The word JOHNNIE has 7 letters of which 3 are vowels.
-V-V-V-
As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.
Hence the total ways are 24 * 6 = 144.
C
The answer is: C
|
C
|
mathematics
|
Today is Sunday. The day after 59 days will be
|
[
"Monday",
"Wednesday",
"Saturday",
"Sunday",
"None of these"
] |
Explanation :
59 days = 8 weeks 3 days = 3 odd days
Hence if today is Sunday, After 59 days, it will be = (Sunday + 3 odd days)
= Wednesday. Answer : Option B
The answer is: B
|
B
|
mathematics
|
A squirrel can climb 5 metres of a pole in one minute but slips 2 metres in the next minute. How much time will the squirrel take to climb 26 metres?
|
[
"15 minutes",
"18 minutes",
"12 minutes",
"58 minutes",
"10 minutes"
] |
Explanation:
As the squirrel climbs 5 m in one minute and slips 2 metres in the next minute, it climbs 3 metres in 2 minute
To climb 26 metres, the time required is:
The squirrel will climb (26 – 5) = 21 metres = 7 * 3 metres in 7 * 2 = 14 minutes
Also, the last 5 metres it climbs in another 1 minute
Hence, total time required = 14 + 1 = 15 minutes
ANSWER:A
The answer is: A
|
A
|
mathematics
|
A taxi charges v dollars for the first two miles and c cents per quarter mile for every mile after the first two. Which equation describes cost of a taxi ride of n miles in dollars.
|
[
"vn – c/8(100)",
"cv + 4n-8/200",
"v + (4cn-8c)/100",
"v + 100cn/4",
"4cv(n-2) – 100"
] |
This is about as complicated as these types of problems come, but it is essentially the same as any problem which has an initial cost which is added to a dependent additional cost. Looking at the problem, we notice that the cost v is added to the mile dependent cost, which is some combination of the other terms listed in the problem. With just that knowledge we can eliminate all but two of the answer choices! Choices (A), (B), and (E) either do some strange calculation with the initial cost v, or subtract the additional cost from v. Both of these circumstances would be next to impossible if there is an initial cost being added to another cost. Thus, we only have to choose between choice (C) and choice (D). We can easily find the right answer by plugging in real numbers and checking which choice yields a correct answer. We can also see that answer choice (D) seems to be multiplying the cost in cents by 100, which, if the trip was 6 miles and the charge per mile was 25 cents, would make the taxi cost an additional $3750! This seems impossible, and leaves only the correct answer choice, (C).
The answer is: C
|
C
|
mathematics
|
Eighty percent of the lights at Hotel California are on at 8 p.m. a certain evening. However, forty percent of the lights that are supposed to be off are actually on and ten percent of the lights that are supposed to be on are actually off. What percent L of the lights that are on are supposed to be off?
|
[
"22(2/9)%",
"16(2/3)%",
"11(1/9)%",
"10%",
"5%"
] |
Is the Answer D.
let me try..
Let the light which are supposed to be OFF = SO
Let the light which are supposed to be ON = SN
Let the light which are ACTUALLY OFF = AO
Let the light which are ACTUALLY ON = AN
Let the total no. of lights be 100,
So ACTUALLY ON lights = 80
And ACTUALLY OFF lights = 20
Also given >> forty percent of the lights that are supposed to off are actually on >>> (40/100)*SO are ACTUALLY ON
it means >>> (60/100)*SO are ACTUALLY OFF
Also given >> ten percent of the lights that are supposed to be on are actually off >>> (10/100)*SN are ACTUALLY OFF
it means >>> (90/100)*SN are ACTUALLY ON
So, Total ACTUALLY ON lights = (40/100)*SO + (90/100)*SN = 80
and Total ACTUALLY OFF lights = (60/100)*SO + (10/100)*SN = 80
From here we get SO = 20
we need to find: What percent of the lights that are on are supposed to be off >>> So light ACTUALLY ON are 80 and light which are ACTUALLY ON, which are supposed to be OFF = (40/100)*SO = 8.
So (8/80)*100 L= 10%.D
The answer is: D
|
D
|
mathematics
|
The average of four consecutive odd numbers is 12. Which is the lowest odd number?
|
[
"9",
"3",
"5",
"Cannot be determined",
"None of these"
] |
Let the four consecutive odd nos. be
2x – 3, 2x – 1, 2x + 1 and 2x + 3.
Now, 2x = 12 or, x = 6
Lowest odd no. = 2 × 6 – 3 = 9
Answer A
The answer is: A
|
A
|
mathematics
|
A batsman scored 140 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
|
[
"50%",
"40%",
"60%",
"57%",
"80%"
] |
Number of runs made by running = 140 - (3 x 4 + 8 x 6)
= 140 - (60)
= 80
Now, we need to calculate 80 is what percent of 140.
=> 80/140 x 100 = 57 %
ANSWER:D
The answer is: D
|
D
|
mathematics
|
In the equation 2x – cy = 18, c is a constant. If the value of y is 2 when x is 6, what is the value of x when y is 3 ?
|
[
"−9/2",
"-4",
"-3",
"4",
"9/2"
] |
2x - cy = 18
x=6, y=2;
12-2c=18
c=-3
2x-cy=18
when y=3, c=-3, x=
x=9/2
ANSWER:E
The answer is: E
|
E
|
mathematics
|
It takes Beth 9 minutes to do one oil change, and it takes Logan 12 minutes. At 4:56 pm, they both finish an oil change simultaneously. If Beth and Logan both began doing oil changes at exactly the same time and worked without pausing, when did they both start doing oil changes?
|
[
"4:11 pm",
"4:20 pm",
"4:29 pm",
"4:38 pm",
"4:47 pm"
] |
Since Beth finishes s oil changes after s × 9 minutes and Logan finishes c oil changes after c × 12 minutes, they both finished doing an oil change at the same time when s × 9 = c × 12. Since s and c must be integers (they represent the number of oil changes finished) this question is asking you to find a common multiple of 9 and 12. The question asks for the first time they began a car simultaneously, so you must find the least common multiple and subtract. The least common multiple of 9 and 12 is 36, so in the context of the question, this would be 36 minutes. Therefore, they began changing the oil of a car at the same time at 4:56 - 36 minutes, or 4:20 p.m. The answer is (B).
The answer is: B
|
B
|
mathematics
|
Suresh started a business with Rs.20,000. Kiran joined him after 4 months with Rs.30,000. After 2 months, Suresh withdrew Rs.5,000 of his capital and 2 more months later, Kiran brought in Rs.20,000 more. What should be the ratio in which they should share their profits at the end of the year?
|
[
"32:21",
"22:21",
"21:32",
"31:21",
"32:28"
] |
Here capital is not the same.
Suresh invest 20000 for initial 6 months and 15000 for the next 6 months.
Hence his term of ratio
=( 20000*6 + 15000*6)
Kiran invest Rs.30000 for 4 months and Rs.50000 for next 4 months.
Hence his term of ration
= (30000*4 : 50000*4)
Suresh : Kiran = ( 20000*6 + 15000*6) : (30000*4 : 50000*4)
= (20*6 + 15*6) : (30*4 + 50*4)
= (20*3 + 15*3) : (30*2 : 50*2)
= 105:160
= 21:32
Answer is C
The answer is: C
|
C
|
mathematics
|
Find the roots of the quadratic equation: x2 + 2x - 15 = 0?
|
[
"-5, 3",
"3, 5",
"-3, 5",
"-3, -5",
"5, 2"
] |
Explanation:
x2 + 5x - 3x - 15 = 0
x(x + 5) - 3(x + 5) = 0
(x - 3)(x + 5) = 0
=> x = 3 or x = -5.
ANSWER IS A
The answer is: A
|
A
|
mathematics
|
A certain bridge is 4,024 feet long. Approximately how many minutes does it take to cross this bridge at a constant speed of 40 miles per hour? (1 mile = 5,280 feet)
|
[
"1",
"2",
"4",
"6",
"7"
] |
Distance: 4024 feet. This is (4024/5280) miles = 0.76 miles
Speed: 40 miles per hour
Time: (Distance / Speed) (0.76/40) {This will come in Hours}. Multiply by 60 to get answer in minutes. It is 1.14 minutes.
Answer to be 1 minutes.
The answer is: A
|
A
|
mathematics
|
What are the next two letters in the following series and why?
W A T N T L I T F S _ _
*Hint : Look into the title of the Riddle
|
[
"A and W",
"A and E",
"B and W",
"A and C",
"S and W"
] |
A
A and W.
The letters are the first letters of the words in the question. Thus, the next two letters are A and W.
The answer is: A
|
A
|
mathematics
|
If 20 men take 15 days to to complete a job, in how many days can 20 men finish that work?
|
[
"15",
"16",
"17",
"18",
"19"
] |
Ans. 15 days
The answer is: A
|
A
|
mathematics
|
There are 8 red, 7 blue and 6 green balls, 1 ball is picked up randomly thenwhat is the probability that neither blue nor green?
|
[
"7/22",
"7/25",
"8/21",
"8/23",
"8/25"
] |
Total number of balls = (8 + 7 + 6) = 21
Let E = event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.
C)
The answer is: C
|
C
|
mathematics
|
Find the principle on a certain sum of money at 8% per annum for 2 2/5 years if the amount being Rs.1120?
|
[
"939.6",
"928.8",
"927.78",
"926.82",
"902.1"
] |
1120 = P [1 + (8*12/5)/100]
P=939.60
Answer: A
The answer is: A
|
A
|
mathematics
|
5358 x 52 = ?
|
[
"273762",
"278616",
"273298",
"273258",
"277382"
] |
B
5358 x 52 = 5358 x (50 + 2)
= 5358 x 50 + 5358 x 2
= 267900 + 10716
= 278616.
The answer is: B
|
B
|
mathematics
|
If the perimeter of square region Z and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3 then the ratio of the area of R to the area of Z
|
[
"25:16",
"24:25",
"5:6",
"4:5",
"4:9"
] |
We know Perimeter of a square (Pz) = 4*side
Perimeter of a rectangle (Pr) = 2(length+breath)
Let us assume 40 to be the perimeter of the square (since we know each side of a square is equal and the perimeter is divisible by 4, also take in to account the length and breadth of the rectangle is in the ration 2k:3k = 5k; we can assume such a number)
Therefore,
Pz = Pr = 40
Area of the square = 100 sq. units
We know 2(length+breadth) = 40
i.e. length + breadth = 20 (or 5k = 20 given that l:b (or b:l) = 2:3)
Therefore length = 8, breath = 12
Area of the rectangle = 8*12 = 96 sq. units
Question asked = Area of the rectangle : Area of the square = 96:100 ==> 24:25=B
The answer is: B
|
B
|
mathematics
|
What is the average (arithmetic mean) of all the multiples of ten from 10 to 210 inclusive?
|
[
"90",
"95",
"100",
"105",
"110"
] |
The multiples of ten from 10 to 190 inclusive would be an evenly spaced set with 21 terms - 10, 20, 30,.......210
So average = (First term + Last Term)/2 = (10 + 210)/2 = 220/2 = 110
Hence, the correct answer is E.
The answer is: E
|
E
|
mathematics
|
If a and b are both negative and ab < b^2, which of the following must be true?
|
[
"a < b < a^2 < b^2",
"a < b < b^2 < a^2",
"b < a < a^2 < b^2",
"a^2 < b^2 < b < a",
"b^2 < a^2 < b < a"
] |
Because ab < b^2 and both are negative, I thought a < b. So I crossed off answers c), d), and e).
And because a < b , a^2 < b^2
ans C
The answer is: C
|
C
|
mathematics
|
What day of the week was 1 January 1901
|
[
"Monday",
"Tuesday",
"Saturday",
"Friday",
"Sunday"
] |
Explanation:
1 Jan 1901 = (1900 years + 1st Jan 1901)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)
Number of odd days in the period 1601-1900
= Number of odd days in 300 years
= 5 x 3 = 15 = 1
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
1st Jan 1901 = 1 odd day
Total number of odd days = (0 + 1 + 1) = 2
2 odd days = Tuesday
Hence 1 January 1901 is Tuesday.
Answer: Option B
The answer is: B
|
B
|
mathematics
|
Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?
|
[
"15",
"10",
"12",
"17",
"14"
] |
4/12 + x/15 = 1
x = 10
Answer:B
The answer is: B
|
B
|
mathematics
|
Peter has 9 candies, rina has 5 candies. Totally how many candies they have in all?
|
[
"14",
"4",
"23",
"12",
"9"
] |
9+5=14. Answer is A
The answer is: A
|
A
|
mathematics
|
Two trains are moving at 50 kmph and 70 kmph in opposite directions. Their lengths are 150 m and 100 m respectively. The time they will take to pass each other completely is?
|
[
"3 sec",
"5 sec",
"6 ½ sec",
"7 ½ sec",
"5 ½ sec"
] |
D
7 ½ sec
70 + 50 = 120 * 5/18 = 100/3 mps
D = 150 + 100 = 250 m
T = 250 * 3/100 = 15/2 = 7 ½ sec
The answer is: D
|
D
|
mathematics
|
15.06 * 0.000001 = ?
|
[
"15060000",
"0.001506",
"0.01506",
"1.506e-05",
"None of these"
] |
Explanation:
Clearly after decimal 8 digits should be there.
Option D
The answer is: D
|
D
|
mathematics
|
A photography dealer ordered 60 Model X cameras to be sold for $250 each, which represents a 10 percent markup over the dealer’s initial cost for each camera. Of the cameras ordered, 6 were never sold and were returned to the manufacturer for a refund of 50 percent of the dealer's initial cost. What was the dealer's approximate profit or loss as a percent of the dealer’s initial cost for the 60 cameras?
|
[
"7% loss",
"13% loss",
"4% profit",
"13% profit",
"15% profit"
] |
Total cost 60*($250/1.1)=54.54*250;
# of cameras sold is 60-6=54 total revenue is 54*250;
# of cameras returned is 6 total refund 6*(250/1.1)*0.5;
So, total income 54*250+ 6*(250/1.1)*0.5
The dealer's approximate profit is (54*250+ 6*(250/1.1)*0.5-54.54*250)/(54.54*250)*100=4%
Answer: C.
The answer is: C
|
C
|
mathematics
|
In a rectangular coordinate system, what is the area of a rectangle whose vertices have the coordinates (-3, 1), (1, 1), (1, -2) and (-3, -2)?
|
[
"12",
"24",
"20",
"30",
"36"
] |
Length of side 1= 3+1=4
Length of side 2= 2+1= 3
Area of rectangle= 4*3= 12
A is the answer
The answer is: A
|
A
|
mathematics
|
Incomes of two companies A and B are in the ratio of 5 : 8. Had the income of company A been more by 40 lakh, the ratio of their incomes would have been 5 : 4. What is the income of company B?
|
[
"80 lakh",
"50 lakh",
"40 lakh",
"64 lakh",
"None of these"
] |
Let the incomes of two companies A and B be 5x and 8x respectively.
From the question,
5x+40/8x=5/4 ⇒ 20x + 160 = 40x
∴ x = 8
∴ Income of company B = 8x = 64 lakh
Answer D
The answer is: D
|
D
|
mathematics
|
Each day a man meets his wife at the train station after work, and then she drives him home. She always arrives exactly on time to pick him up. One day he catches an earlier train and arrives at the station an hour early. He immediately begins walking home along the same route the wife drives. Eventually his wife sees him on her way to the station and drives him the rest of the way home. When they arrive home the man notices that they arrived 12 minutes earlier than usual. How much time did the man spend walking?
|
[
"45 minutes",
"50 minutes",
"40 minutes",
"54 minutes",
"35 minutes"
] |
As they arrived 12 minutes earlier than usual, they saved 12 minutes on round trip from home to station (home-station-home) --> 6 minutes in each direction (home-station) --> wife meets husband 6 minutes earlier the usual meeting time --> husband arrived an hour earlier the usual meeting time, so he must have spent waking the rest of the time before their meeting, which is hour-6 minutes=54 minutes.
Answer: D
The answer is: D
|
D
|
mathematics
|
1/3th of the passengers got down at first stop and 30 people got into the bus, 1/4th of the passengers got down at second stop and 12 people got into the bus.In last stop 84 people got down from the bus. What is the initial capacity of the bus?
|
[
"98",
"99",
"97",
"96",
"95"
] |
Let x be the no of initial passenger
no of passengr left in 1st stop (2x/3)+30
no of passenger in the 2nd stop 3/4((2x/3)+30) + 12
which is equal to 84 (passngr on last stop)
so final eqn....3/4((2x/3)+30) + 12 = 84
Ans x = 99
ANSWER:B
The answer is: B
|
B
|
mathematics
|
How many kg of sugar costing Rs. 9/kg must be mixed with 27kg of sugar costing Rs. 7/ kg so that there may be a gain of 10% the mixture at Rs. 9.24 per kg?
|
[
"52",
"55",
"57",
"60",
"63"
] |
Selling Price(SP) of 1 kg mixture= Rs. 9.24
Profit = 10%
Cost Price(CP) of 1 kg mixture =100(100+Profit%)×SP
=100(100+10)×9.24=100110×9.24=92.411= Rs.8.4
By rule of alligation,
CP of 1 kg sugar of 1st kind CP of 1 kg sugar of 2nd kind
Rs. 9 Rs. 7
Mean Price
Rs.8.4
8.4 - 7 = 1.4 9 - 8.4 = 0.6
i.e., to get a cost price of 8.4, the sugars of kind1 and kind2 should be mixed in the ratio 1.4 : 0.6 = 14 : 6 = 7 : 3
Suppose x
kg of kind1 sugar is mixed with 27 kg of kind2 sugar.
then x : 27 = 7 : 3
⇒3x=27×7⇒x=9×7=63
E
The answer is: E
|
E
|
mathematics
|
Find the odd man out. 3, 5, 15, 75, 1120, 84375
|
[
"84375",
"1120",
"15",
"3",
"75"
] |
Explanation :
Pattern : 1st * 2nd = 3rd, 2nd * 3rd = 4th, etc.
3
5
3 × 5 = 15
5 × 15 = 75
15 × 75 = 1125
75 × 1125 = 84375
Hence, 1120 is wrong. 1125 should have come in place of 1120
Answer : Option B
The answer is: B
|
B
|
mathematics
|
Nine people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons increased by:
|
[
"7/8",
"1/8",
"1/3",
"1/7",
"1/9"
] |
Original share of 1 person =1/9
New share of 1 person =1/8
Increase =1/8 - 1/9 =1/72
Required fraction = (1/72)/(1/9)=1/8
Answer is B.
The answer is: B
|
B
|
mathematics
|
49 × 49 × 49 × 49 x 49 × 49 × 49 × 49= 7?
|
[
"4",
"7",
"8",
"16",
"None of these"
] |
49 × 49 × 49 × 49 x 49 × 49 × 49 × 49 = 7?
or, 7(2) × 7(2) × 7(2) × 7(2) x 7(2) × 7(2) × 7(2) × 7(2)= 7^?
or 7(16) = 7? or, ? =16
Answer D
The answer is: D
|
D
|
mathematics
|
S1 = 3 S2 = 6 ... Sn = 3n + 4 For the sequence above, in which any term n is defined as 3n + 4, what is the value of n for the first term in the sequence to exceed 50?
|
[
"13",
"16",
"12",
"9",
"8"
] |
term 16 = 3*16+4 = 52
Answer : B
The answer is: B
|
B
|
mathematics
|
A two digit number is 18 less than the square of the sum of its digits. How many such numbers are there?
|
[
"22,33",
"22,22",
"221,1",
"63,82",
"23,17"
] |
Option 2
Take N = 10a+b.
Given that, (10a+b)+18 = K2 = (a+b)2
Given number = K2 - 18 = (10a+b)
That means, when we add 18 to the given number it should be a perfect square. So K2 takes the following values. 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ....
1 to 16 are ruled out as if we subtract 18 from them, the resulting number is a single digit number.
Now 25 - 18 = 7
36 - 18 = 18
49 - 18 = 31
64 - 18 = 46
81 - 18 = 63
100 - 18 = 82
121 - 18 = 103
Now 63, 82 satisfies.
Answer:D
The answer is: D
|
D
|
mathematics
|
A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth?
|
[
"Rs.90",
"Rs.76",
"Rs.98",
"Rs.18",
"Rs.02"
] |
SP of 1m of cloth = 8925/85 = Rs. 105
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 15 = Rs.90.
Answer:C
The answer is: C
|
C
|
mathematics
|
How many different ways can you select a pilot and a co pilot if you have 30 people to choose from?
|
[
"870",
"920",
"1398",
"4950",
"9900"
] |
You are not just choosing two from 30. Each of the two people chosen fills a particular slot. The first filling the pilot slot and the second filling the copilot slot is different from the first filling the copilot slot and the second filling the pilot slot.
So the answer is in a sense (30C2) x 2 = 870.
Ans A
The answer is: A
|
A
|
mathematics
|
In a City, 35% of the population is composed of migrants, 20% of whom are from rural areas. Of the local population, 48% is female while this figure for rural and urban migrants is 30% and 40% respectively. If the total population of the city is 728400, what is its female population ?
|
[
"324138",
"248888",
"378908",
"277880",
"379010"
] |
Explanation:
Total Population = 728400
Migrants = 35 % of 728400 = 254940
local population = (728400 - 254940) = 473460.
Rural migrants = 20% of 254940 = 50988
Urban migrants = (254940 - 50988) = 203952
Female population = 48% of 473460 + 30% of 50988 + 40% of 203952 = 324138
Answer: A
The answer is: A
|
A
|
mathematics
|
The sum of the present ages of two persons A and B is 90. If the age of A is twice that of B, find the sum of their ages 5 years hence?
|
[
"50",
"60",
"70",
"80",
"100"
] |
A + B = 90, A = 2B
2B + B = 90 => B = 30 then A = 60.
5 years, their ages will be 65 and 35.
Sum of their ages = 65 + 35 = 100.
ANSWER:E
The answer is: E
|
E
|
mathematics
|
Tough and Tricky questions: Word Problems.
In a rare coin collection, one in six coins is gold, and all coins are either gold or silver. If 10 silver coins were to be subsequently traded for an additional 10 gold coins, the ratio of gold coins to silver coins would be 1 to 7. Based on this information, how many gold coins would there be in this collection after the proposed trade?
|
[
"50",
"60",
"180",
"200",
"350"
] |
The correct answer is E.
The answer is: E
|
E
|
mathematics
|
How many times the keys of a writter haveto be pressedin order to write first 400 counting no.'s?
|
[
"998",
"1000",
"1092",
"1100",
"1200"
] |
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 400 = 301 * 3 = 903
-----------
1092
C
The answer is: C
|
C
|
mathematics
|
If in a race of 100m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by:
|
[
"20m",
"16m",
"11m",
"10m",
"15m"
] |
Explanation:
The difference in the timing of A and B is 5 seconds. Hence, A beats B by 5 seconds.
The distance covered by B in 5 seconds = (100 * 5) / 25 = 20m
Hence, A beats B by 20m.
ANSWER A
The answer is: A
|
A
|
mathematics
|
How much time does a train 150 metres long running at 90 km/hr take to pass a pole?
|
[
"7.9s",
"6s",
"7.5s",
"7.6s",
"7.4s"
] |
Explanation:
90 km/hr = 90 * 5/18 = 25 m/s
Speed = distance/time; v = d/t
25 = 150/t
t = 6s
ANSWER: B
The answer is: B
|
B
|
mathematics
|
For what value(s) of n is the following equation satisfied: 2n-6-5n = 5n+7-4n
|
[
"a. -5/4",
"b. -13/4",
"c. 5/4 only",
"d. No value",
"e. Any value"
] |
2n-6-5n = 5n+7-4n
-3n - 6 = n + 7
-13 = 4n,
n=13/4
Answer: B.
The answer is: B
|
B
|
mathematics
|
If (m-8) is a factor of m^2-pm-24, then p=
|
[
"3",
"5",
"6",
"11",
"16"
] |
(m-8)(m-a)=m^2-pm-24
A=-3
p=8+a=5=B
The answer is: B
|
B
|
mathematics
|
A shopkeeper labels the price of articles 20% above the cost price. If he allows 31.20 off on a bill of 312, find his profit per cent on the article?
|
[
"8",
"12 1⁄3",
"11 2⁄3",
"8 1⁄3",
"None of these"
] |
Let the CP = 100 Marked price = 120
Discount = 312⁄31.2 × 1⁄100 = 10% = 12
SP = 120 – 12 = 108 Profit% = 108 – 100 = 8%
Answer A
The answer is: A
|
A
|
mathematics
|
Insert the missing number. 12, 25, 49, 99, 197, 395, (...)
|
[
"789",
"1579",
"12",
"23",
"28"
] |
Each number is twice the previous one with 1 added or subtracted alternatively. Missing Number is 789
Answer is A
The answer is: A
|
A
|
mathematics
|
A sum fetched a total simple interest of Rs. 4016.25 at the rate of 1% p.a. in 3 years. What is the sum?
|
[
"122762",
"132877",
"122882",
"133875",
"132887"
] |
Principal = (100 * 4016.25) / (1 * 3)
= Rs.133875.
Answer:D
The answer is: D
|
D
|
mathematics
|
A merchant purchased a jacket for $210 and then determined a selling price that equaled the purchase price of the jacket plus a markup that was 25 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale?
|
[
"$0",
"$3",
"$4",
"$12",
"$14"
] |
Let selling price = x
So, x = 210 + 25x/100
Calculating above, x = 280
Selling price = 280
20% Discount on Selling price = 224
So, profit = 224-210 = 14 Answer = E
The answer is: E
|
E
|
mathematics
|
Albert invested amount of 20000 in a fixed deposit for 2 years at compound interest rate of 5 % per annum. How much Albert will get on the maturity of the fixed deposit
|
[
"Rs. 8510",
"Rs. 22050",
"Rs. 8730",
"Rs. 8820",
"None of these"
] |
Explanation:
=>(20000×(1+5/100)2)
=>20000×21/20×21/20
=>22050
Option B
The answer is: B
|
B
|
mathematics
|
Marcella has 25 pairs of shoes. If she loses 9 individual shoes, what is the greatest number of matching pairs she could have left?
|
[
"21",
"20",
"19",
"16",
"15"
] |
greatest number of paired shoes means greatest number of lost pairs
9 shoes have 4 pairs and 1 extra shoes of a pair .so a otal of 5 pairs she loses
leftover pair=20
ANSWER:B
The answer is: B
|
B
|
mathematics
|
During the last four years, a large truck company purchased diesel at rates of $1.2, $1.4, $1.7 and $2.1 per gallon. What was the mean cost of diesel over the four-year period if the company spends the same amount of dollars on diesel each year?
|
[
"$2.5",
"$2.55",
"$1.53",
"$3.25",
"$3.0"
] |
finding the Harmonic mean here.
HM = 4/(1/12 + 1/14 + 1/17 + 1/21) = 15.31
The calculation is the same either way.
C
The answer is: C
|
C
|
mathematics
|
A boy has nine trousers and 14 shirts. In how many different ways can he select a trouser and a shirt?
|
[
"88",
"98",
"126",
"108",
"111"
] |
Explanation:
The boy can select one trouser in nine ways.
The boy can select one shirt in 14 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 14 = 126 ways
C)
The answer is: C
|
C
|
mathematics
|
If x and y are integers such that (x+1)^2 is less than or equal to 64 and (y-1)^2 is less than 64, what is the sum of the maximum possible value of xy and the minimum possible value of xy?
|
[
"-16",
"-18",
"0",
"14",
"16"
] |
(x+1)^2 <= 64
x <= 7
x >= -9
(y-1)^2 < 64
y < 9
y > -7
Max possible value of xy is -9 × -6 = 54
minimum possible value of xy is -9 × 8 = -72
-72 + 54 = -18
Answer : B
The answer is: B
|
B
|
mathematics
|
The ratio of the present age of Viju to that of Aju is 7:2. Four years from now, the ratio of the ages of Viju to Aju will be 5:2. What was Viju age 7 years ago ? (RBI Assistant 2015)
|
[
"24",
"18",
"14",
"15",
"13"
] |
Let the present age of Viju be 7x years and that of Aju be 2x years.
Then, 4 years from now
7x + 4 / 2x + 4 = 5 / 2
or 4x = 12
or x = 3
Viju present age = 7 * 3 = 21 years
Viju age 7 years ago = 21 - 7 = 14 years
answer :C
The answer is: C
|
C
|
mathematics
|
A person purchased a TV set for Rs. 16000 and a DVD player for Rs. 6250. He sold both the items together for Rs. 31150. What percentage of profit did he make?
|
[
"33",
"277",
"40",
"88",
"11"
] |
The total CP = Rs. 16000 + Rs. 6250 = Rs. 22250 and SP = Rs. 31150
Profit(%) = (31150 - 22250)/22250 * 100 = 40%
Answer: C
The answer is: C
|
C
|
mathematics
|
How many multiples of 2 are less than 2400, and also multiples of 8?
|
[
"104",
"208",
"300",
"832",
"833"
] |
The LCM of 2 and 8 is 8. Divide 2400/8 = 300.xxx. So C is your answer.
The answer is: C
|
C
|
mathematics
|
How many ways are there to select a subcommittee of 7 members from among a committee of 17?
|
[
"22888",
"19448",
"28791",
"27711",
"12111"
] |
Explanation:
Since it does not matter what order the committee members are chosen in, the combination formula is used.
Committees are always a combination unless the problem states that someone like a president has higher hierarchy over another person. If the committee is ordered, then it is a permutation.
C(17,7)= 19,448
Answer: B) 19448
The answer is: B
|
B
|
mathematics
|
A bag contains 7 green and 8 white balls. If two balls are drawn simultaneously, the probability that both are of the same colour is
|
[
"7/16",
"7/12",
"7/19",
"7/12",
"7/15"
] |
Drawing two balls of same color from seven green balls can be done in ⁷C₂ ways.
Similarly from eight white balls two can be drawn in ⁸C₂ ways.
P = ⁷C₂/¹⁵C₂ + ⁸C₂/¹⁵C₂
= 7/15
Answer:E
The answer is: E
|
E
|
mathematics
|
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is?
|
[
"50",
"267",
"26",
"87",
"62"
] |
Let the actual distance traveled be x km. Then,
x/10 = (x + 20)/14
4x - 200 =>x = 50 km.
Answer:A
The answer is: A
|
A
|
mathematics
|
The toll for crossing a certain bridge is $0.75 each crossing. Drivers who frequently use the bridge may instead purchase a sticker each month for $13.00 and then pay only $0.10 each crossing during that month. If a particular driver will cross the bridge twice on each of x days next month and will not cross the bridge on any other day, what is the least value of x for which this driver can save money by using the sticker?
|
[
"12",
"15",
"16",
"28",
"29"
] |
Option #1: $0.75/crossing....Cross twice a day = $1.5/day
Option #2: $0.30/crossing....Cross twice a day = $0.6/day + $13 one time charge.
If we go down the list of possible answers, you can quickly see that 14 days will not be worth purchasing the sticker. 1.5x14 (21) is cheaper than 0.6x14 +13 (21.4)...it's pretty close so let's see if one more day will make it worth it... If we raise the number of days to 15, the sticker option looks like a better deal...1.5x15 (22.5) vs 0.6x15 + 13 (22). Answer: A
The answer is: A
|
A
|
mathematics
|
In a company of 160 employees, 90 are females. A total of 80 employees have advanced degrees and the rest have a college degree only. If 40 employees are males with college degree only, how many employees are females with advanced degrees?
|
[
"40",
"45",
"50",
"55",
"60"
] |
The number of males is 160-90=70.
The number of males with advanced degrees is 70-40=30.
The number of females with advanced degrees is 80-30=50.
The answer is C.
The answer is: C
|
C
|
mathematics
|
A train 120 m long passed a pole in 12 sec. How long will it take to pass a platform 380 m long?
|
[
"25 sec",
"50 sec",
"75 sec",
"100 sec",
"125 sec"
] |
Speed = 120/12 = 10 m/sec.
Required time = (120 + 380)/10 = 50 sec
Answer:B
The answer is: B
|
B
|
mathematics
|
Approximately how many revolutions will be made by a car tire with a 10-inch diameter if the car travels 1⁄2 mile?
|
[
"120",
"180",
"1003",
"1000",
"1,440"
] |
Diameter of car tire = 10 inches
Radius of car tire = 5 inches = 5*2.54 cm = 12.7 cm
Circumference of the car tire = 2*pi * 12.7 = 2 *3.14 *12.7= 79.76 cm
Distance traveled by car = .5 mile = .5 *1.6 km = .8 km = 800 m = 8 * 10^4 cm
Number of revolutions =Distance traveled / Circumference of tire = 8 * 10^4 / 79.76 = 1003
Since the answer choices are far apart we should use estimation in this question .
Ideally ,in the GMAT the conversion between units would be provided .
Answer C
The answer is: C
|
C
|
mathematics
|
4 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
|
[
"4 days",
"6 days",
"7 days",
"9 days",
"1 days"
] |
1 women's 1 day work = 1/28
1 child's 1 day work = 1/140
(5 women + 10 children)'s 1 day work
= (5/28 + 10/140) = 1/4
5 women and 10 children will complete the work in 4 days.
Answer: A
The answer is: A
|
A
|
mathematics
|
A watch passes through three hands and each gains 25%. If the 3rd sells it for Rs250, what did the 1st pay for it?
|
[
"100",
"110",
"128",
"134",
"156"
] |
First Purchased = 250 Wes= 128
C
The answer is: C
|
C
|
mathematics
|
. A car covers a distance of 1028 km in 4 hours. Find its speed?
|
[
"104",
"255",
"266",
"257",
"276"
] |
1028/4= 257 kmph
Answer: D
The answer is: D
|
D
|
mathematics
|
If f and g are distinct prime numbers less than 10, which of the following cannot be the product of f and g?
|
[
"6",
"9",
"10",
"14",
"15"
] |
prime numbers less than 10 are 2, 3, 5, 7
all except 9 is product of any two numbers picked from above set.
Ans: B
The answer is: B
|
B
|
mathematics
|
Speed of boat in water is 12km/hr. and the speed of the stream is 3km/hr. Find the time taken by the boat to go upstream a distance of 45km.
|
[
"3",
"4",
"5 hrs.",
"6",
"2"
] |
US =speed of the boat - speed of the stream 12-3 =9km/hr. Time taken to cover 45km =45/9 = 5hrs. Answer : C
The answer is: C
|
C
|
mathematics
|
A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 50 kmph. When and at what distance from Mumbai do the two trains meet?
|
[
"287",
"279",
"200",
"278",
"379"
] |
When the second train leaves Mumbai the first train covers 40 * 1 = 40 km
So, the distance between first train and second train is 40 km at 10.00am
Time taken by the trains to meet
= Distance / relative speed = 40 / (50 -40) = 4 hours
So, the two trains meet at 2 p.m. The two trains meet 4 * 50 = 200 km away from Mumbai.
Answer:C
The answer is: C
|
C
|
mathematics
|
John makes $60 a week from his job. He earns a raise andnow makes $70 a week. What is the % increase?
|
[
"16%",
"16.66%",
"17.9%",
"18.12%",
"18%"
] |
Increase = (10/60)*100 = (1/6)*100 = 16.66%.
B
The answer is: B
|
B
|
mathematics
|
5301 x 13 =?
|
[
"89136",
"31986",
"68910",
"53113",
"68913"
] |
Append 0 before and after: 053010
Calculation:
1 x 3 + 0 = 3 (take 3 as ones digit of the product)
0 x 3 + 1 = 1 (take 1 tens digit of the product)
3 x 3 + 0 = 9 (take 9 hundreds digit of the product)
5 x 3 + 3 = 18 (take 8 as thousands digit of the product, carry over 1)
0 x 3 + 5 = 5; 5 + 1 = 6 (take 6 as ten thousands digits of the product)
So, 5301 x 13 = 68913
Answer is E.
The answer is: E
|
E
|
mathematics
|
The cost of a one-family home was $ 120,000 in 1980. In 1988, the price had increased to $ 174,000. What was the percent increase in the cost of the home?
|
[
"60%",
"50%",
"55%",
"40%",
"45%"
] |
Increase = 174000-120000 = 54000
% increase = 54000*100/120000 = 45%
Answer: option E
The answer is: E
|
E
|
mathematics
|
Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 90 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
|
[
"12 sec",
"24 sec",
"30 sec",
"60 sec",
"62 sec"
] |
Relative speed = 90 + 30 = 120 km/hr.
120 * 5/18 = 100/3 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 3/100 = 30 sec.
ANSWER:C
The answer is: C
|
C
|
mathematics
|
A committee of 5 is to be selected from among 5 boys and 5 girls. I how many ways can this be done if the committee is to consist of at-least one Girl?
what is the answer choice and how?
|
[
"105",
"250",
"230",
"350",
"455"
] |
I'm sure there is some problem with the question.
R U sure its atleast one boy and not atleast 1 boy and 1 girl?
if its 1 boy and 1 girl
5C1*5C4 + 5C2*5C3 + 5C3*5C2 + 5C4*5C1
5*5 + 10*10 + 10*10 + 5*5
25 + 100 + 100 + 25
250
B
The answer is: B
|
B
|
mathematics
|
A certain number when divided by 65 leaves a remainder 25, what is the remainder if the same no.be divided by 15?
|
[
"4",
"5",
"6",
"8",
"9"
] |
Explanation:
65 + 25 =90/15 =6 (Remainder)
C
The answer is: C
|
C
|
mathematics
|
A boat M leaves shore A and at the same time boat B leaves shore B. They move across the river.
They met at 500 yards away from A and after that they met 300 yards away from shore B without
halting at shores. Find the distance between the shore A & B
|
[
"1100 yards",
"1200 yards",
"1300 yards",
"1400 yards",
"None of these"
] |
Explanation :
The boats first met after 500yards from A.
Let the total distance between A and B be x.
Then,
500/a = x - 500 / b, ------------(1)
where, a = speed of A,
b = speed of B.
Assuming both boats are coming back to their original start place without halting at the shores,
Distance coverred by A = x + 300
Distance covered by B = 2x - 300
x+300/a = 2x-300/b -----------------------(2)
From above,
500/x-500 = x+300/2x-300
Solve, for x = 1200
Answer : B
The answer is: B
|
B
|
mathematics
|
A telephone number contains 10 digit, including a 3-digit area code. Bob remembers the area code and the next 5 digits of the number. He also remembers that the remaining digits are not 0, 1, 2, 7, or 9. If Bob tries to find the number by guessing the remaining digits at random, the probability that he will be able to find the correct number in at most 2 attempts is closest to which of the following ?
|
[
"51/625",
"50/625",
"4/625",
"25/625",
"53/625"
] |
I think most of the answers are missing a point. Let me try to put it across:
Total number of possible numbers are : 5x5 = 25
Correct number =1
Case 1: When he gets it right in first attempt: P(E1) = 1/25
Case 2: He gets 1st attempt wrong and second right:
When he gets it wrong then the probability of getting wrong is 24/25.
Now there are 24 cases with him and he chooses the right one this time.
Probability of right case is 1/24
Thus, P(E2) = 24/25 x 1/24
=1/25
Probability of getting it right in at most two cases = P(E1) + P(E2)
= 1/25 + 1/25
= 2/25
= 50/625
Option (B) is therefore right as most of you mentioned but the method employed was wrong.
The answer is: B
|
B
|
mathematics
|
The relationship between quantities m and n is expressed by the equation 11m = 5(n - 52). If the difference between the two chosen values of n is 40, what is the difference in the corresponding values of m?
|
[
"200/11",
"42/11",
"60/11",
"150/11",
"14"
] |
Another Simple way
11m=5(n-52)
Assume n = 52 to make one side equal to 0
then 11m=0
and m = 0
Repeat it by assuming n as 52+40 i.e 92
11m= 5(92-52)
11m=200
m=200/11
diff = 200/11 - 0 = 200/11
Answer : A
The answer is: A
|
A
|
mathematics
|
Find the distance covered by a man walking for 10min at a speed of 6km/hr?
|
[
"1km",
"2km",
"3km",
"1.5km",
"4km"
] |
Distance = 6*10/60 = 1km
Answer is A
The answer is: A
|
A
|
mathematics
|
If x is 11 percent greater than 70, then x =
|
[
"77.7",
"91.0",
"88.0",
"70.9",
"71.2"
] |
11% of 70 = (70*0.11) = 7.7
11% greater than 70 = 70 + 7.7 = 77.7
Answer is clearly A.
The answer is: A
|
A
|
mathematics
|
In a colony the municipality decided to number the houses and the shops. They want to number the shops with the numbers containing 3 between 1-100. The houses are 10-20 floored and at the back of the houses 8 feet is left for fire exit. How many shops can be numbered?
|
[
"19",
"20",
"21",
"22",
"23"
] |
3numbers containing 3
--->3,13,23,... = 10 numbers
---->30,31,32... = 10 numbers
total = 20 -1 = 19
ANSWER:A
The answer is: A
|
A
|
mathematics
|
Oil cans x and y are right circular cylinders and the height and radius of y are each twice those of x. If the oil in can x filled to capacity sells for $3, how much does the oil in y sell for if y is only half filled?
|
[
"$11",
"$12",
"$13",
"$14",
"$18"
] |
formula for vol of a cyl is PI*r^2*h
so Vy = 8*Vy
y when half filled will cost 4 times x so ans is B
The answer is: B
|
B
|
mathematics
|
Out of 400 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ?
|
[
"120",
"150",
"100",
"180",
"220"
] |
n(A)=325,n(B)=175,n(AuB)=400-50=350.
Required number = n(AnB)=n (A)+n (B)-n(AuB)=325+175-350=150.
Answer is B
The answer is: B
|
B
|
mathematics
|
What will be the difference in simple and compound interest on 3000 after three years at the rate of 10 percent per annum?
|
[
"93",
"42",
"62",
"20",
"None of these"
] |
For 3 years:
Diff.=Sum×(rate)2(300+rate)/(100)3
= 3000×10×10×310/100×100×100 = 93
Answer A
The answer is: A
|
A
|
mathematics
|
20 % of 2 is equal to
|
[
"0.2",
"0.4",
"0.6",
"0.7",
"0.9"
] |
20 % of 2 = (20 / 100) * 2 = 0.4
Answer: Option B
The answer is: B
|
B
|
mathematics
|
Richard has to paint a mural with seven horizontal stripes. He only has enough paint for four brown stripes, four green stripes, four pink stripes, four red stripes, four blue stripes, four white stripes, four black stripes, and four yellow stripes. If his patron wants at most two different colors in the mural, how many different ways can he paint the wall?
|
[
"120",
"350",
"700",
"1,960",
"5,040"
] |
Number of ways to choose 2 colors among 8 - 8c2
Number of ways that the chosen colors can be painted for 7 horizontal stripes - 2 (either (4,3) or (3,4))
Now the order,
the number of ways in which a particular color among the 2 chosen colors can be painted for 4 stripes is - 7c4
[Note: We don't need to calculate the ways for the remaining 3 stripes as they are obvious and already counted under this]
Total number of combinations -8c2 * 2* 7c4 = 1960
D
The answer is: D
|
D
|
mathematics
|
x^2 + rx + 72 = 0 has two distinct integer roots; how many values are possible for r?
|
[
"3",
"6",
"8",
"12",
"24"
] |
For a quadratic equation ax^2+rx+c=0, we know that -r/a is sum of roots and c/a is product of roots.
The quadratic equation here is x^2 + rx + 72 = 0, where product of roots is 72.
If we find all the factors of 72, we have the answer.
By prime factorization, we get 72= 2^3*3^2.
We know that total factors are (3+1)*(2+1) = 12 (Reason: with 2^n, we have n+1 possibilities. n^0 to n^n. so n+1)=D
The answer is: D
|
D
|
mathematics
|
Find the perimeter and area of the rectangle of length 15 cm and breadth 13 cm.
|
[
"71 cm2",
"121 cm2",
"141 cm2",
"195 cm2",
"221 cm2"
] |
length = 15 cm, breadth = 13 cm
Perimeter of rectangle = 2 (length + breadth)
= 2 (15 + 13) cm
= 2 × 28 cm
= 56 cm
We know that the area of rectangle = length × breadth
= (15 × 13) cm22
= 195 cm2
ANSWER : D
The answer is: D
|
D
|
mathematics
|
Set #1 = {A, B, O, D, E}
Set #2 = {K, L, M, N, U, P}
There are these two sets of letters, and you are going to pick exactly one letter from each set. What is the probability of picking at least one vowel?
|
[
"1/6",
"1/4",
"1/2",
"1/3",
"2/3"
] |
At least questions are best solved by taking the opposite scenario and subtracting it from 1. Probability of choosing no vowel from set 1 is 2/5 and set 2 is 5/6. Multiply these to get 1/3. Therefore, probability of picking at least one vowel = 1-1/3=2/3.
ANSWER =E
The answer is: E
|
E
|
mathematics
|
A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
|
[
"2 kmph",
"4 kmph",
"5 kmph",
"7 kmph",
"6 kmph"
] |
M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9 = 4
Answer:B
The answer is: B
|
B
|
mathematics
|
A train travelled from station P to Q in 8 hours and came back from station Q to P is 6 hours. What would be the ratio of the speed of the train while traveling from station P to Q to that from station Q to P?
|
[
"3 : 6",
"3 : 9",
"3 : 3",
"3 : 4",
"3 : 1"
] |
Since S # 1/t
S1 : S2 = 1/t1 : 1/t2 = 1/8 : 1/6 = 3 : 4
Answer:D
The answer is: D
|
D
|
mathematics
|
A train 200 m long can cross an electric pole in 20 sec and then find the speed of the train?
|
[
"17 Kmph",
"78 Kmph",
"72 Kmph",
"36 Kmph",
"19 Kmph"
] |
Length = Speed * time
Speed = L/T
S = 200/20
S = 10 M/Sec
Speed= 10*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 36 Kmph
Answer: D
The answer is: D
|
D
|
mathematics
|
The average of the two-digit numbers, which remain the same when the digits interchange their positions, is?
|
[
"56",
"86",
"55",
"87",
"88"
] |
Average = (11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99)/9
= [(11 + 99) + (22 + 88) + (33 + 77) + (44 + 66) + 55]/9
= [(4 * 110) + 55]/9 = 495/9 =55.
Answer:C
The answer is: C
|
C
|
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