subject
stringclasses 1
value | question
stringlengths 3
1.14k
| options
listlengths 5
5
| solution
stringlengths 18
3.7k
| answer
stringclasses 5
values |
|---|---|---|---|---|
mathematics
|
John needs 4 balls out of 10 balls.How many ways are possible?
|
[
"1050",
"220",
"630",
"540",
"720"
] |
The possible way is 10C4
10C4=10!/6!*4!=10*9*8*7*6!/6!*4*3*2*1
=630 ways
Ans:option C
The answer is: C
|
C
|
mathematics
|
The speed of a boat in upstream is 40 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
|
[
"10 kmph.",
"17 kmph.",
"18 kmph.",
"11 kmph.",
"20 kmph."
] |
Speed of the boat in still water = (40+80)/2 = 60 kmph. Speed of the stream = (80-40)/2
= 20 kmph.
Answer:E
The answer is: E
|
E
|
mathematics
|
Griffin has a bag of marbles that contains 7 black marbles and 4 red marbles. If he removes 3 marbles at random without replacing any of the marbles, what is the probability that all 3 marbles selected will be red?
|
[
"2/55",
"3/85",
"4/105",
"4/165",
"8/165"
] |
P(3 red marbles) = 4/11*3/10*2/9 = 4/165
The answer is D.
The answer is: D
|
D
|
mathematics
|
A sum of 13,400 amounts to 14,400 in 2 years at the rate of simple interest. What is the rate of interest?
|
[
"2%",
"1%",
"6%",
"4%",
"8%"
] |
D
4%
S.I. = (14400 - 13400) = 1000.
Rate = (100 x 1000)/(13400x2)% = 4%
The answer is: D
|
D
|
mathematics
|
The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
|
[
"432",
"456",
"546",
"258",
"277"
] |
2(3x + x)
= 96
l = 36
b = 12
lb = 36 * 12
= 432
Answer: A
The answer is: A
|
A
|
mathematics
|
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
|
[
"30",
"39",
"87",
"27",
"91"
] |
Let the side of the square(ABCD) be x meters.
Then, AB + BC = 2x metres.
AC = = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = = 30% (approx)
Answer:A
The answer is: A
|
A
|
mathematics
|
Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
|
[
"27 7/6 m",
"27 7/4 m",
"27 7/2 m",
"27 7/9 m",
"27 7/7 m"
] |
Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9 = 27 7/9 m.Answer:D
The answer is: D
|
D
|
mathematics
|
Which of the following numbers should not be included in the set?
331, 482, 551, 263, 385, 242, 111
|
[
"263",
"385",
"242",
"111",
"None of these"
] |
Solution
In each number except 385,the product of first and third digits is the middle one. Answer B
The answer is: B
|
B
|
mathematics
|
The product of two numbers is 192 and the sum of these two numbers is 28. What is the smaller of these two numbers?
|
[
"10",
"12",
"14",
"15",
"16"
] |
Solution
Let the number be x and (28 - x) = Then,
x (28 - x) = 192
‹=›x2 - 28x + 192 = 0.
‹=›(x - 16) (x - 12) = 0
‹=›x = 16 or x = 12.
Answer B
The answer is: B
|
B
|
mathematics
|
A and B are walking with 25 kmph and 30 kmph. A is walking towards east and B is towards south. They both started at 7:00 A.M at what time they are 130 metres apart.
|
[
"130m",
"140m",
"150m",
"160m",
"170m"
] |
let after t sec they are 130m apart then
(25* 5/18 *t)^2 + (30* 5/18 *t)^2 = 130^2
=> t * (5/18) * 5 * √ 61 = 130
=> t = 12.98425 sec ~ 13 sec
so, at 7:00:13 AM they are 130m apart.
ANSWER:A
The answer is: A
|
A
|
mathematics
|
A farmer has a rose garden. Every day he either plucks 7 or 6 or 24 or 23 roses. The rose plants are intelligent and when the farmer plucks these numbers of roses, the next day 37 or 36 or 9 or 18 new roses bloom in the garden respectively. On Monday, he counts 189 roses in the garden. He plucks the roses as per his plan on consecutive days and the new roses bloom as per intelligence of the plants mentioned above. After some days which of the following can be the number of roses in the garden?
|
[
"6",
"7",
"6",
"4",
"1"
] |
If he plucks 23, then only 18 grows the next day. This means total roses get decreases by 5. So after n days assume the number of roses got decreased 185 where n = 37, then 4 roses left.
Answer:D
The answer is: D
|
D
|
mathematics
|
How many integers are divisible by 3 between 10! and 10! + 40 inclusive?
|
[
"6",
"7",
"8",
"13",
"10"
] |
D - 7
10! is divisible by 3
There are 12 numbers between 10! and 10!+40 that are divisible by 3.
Hence 13
The answer is: D
|
D
|
mathematics
|
Abby and Bobby type at constant rates of 80 words per minute and 60 words per minute, respectively. Bobby begins typing before Abby and has typed 500 words when Abby begins typing at 1:30 pm. If they continue typing at their respective rates, at what time will Abby have typed exactly 200 more words than Bobby?
|
[
"1:40 PM",
"1:50 PM",
"2:05 PM",
"2:10 PM",
"2:20 PM"
] |
Say time needed for Abby to type 200 more words than Bobby is t. In that time she would type 80t words and Bobby would type 60t words.
Now, total words typed by Bobby would be 500+60t and we want that number to be 200 less than 80t: 500+60t=80t-200 --> t=35.
1:30 PM + 35 minutes = 2:05 PM.
Answer: C.
The answer is: C
|
C
|
mathematics
|
If the arithmetic mean of p and q is 10 and the arithmetic mean of q and r is 26, what is the value of r-p?
|
[
"20",
"10",
"32",
"40",
"5"
] |
Arithmetic mean expression for p and q:
(p+q)/2=10 ; p+q=20 ----eq1
Arithmetic mean expression for q and r:
(q+r)/2=20 ; q+r=52 ----eq2
Subtracting eq1 from eq2 we get: r-p=32
Hence, the correct answer is C
The answer is: C
|
C
|
mathematics
|
In a mixture of milk and water, the proportion of milk by weight was 70%. If, in a 200-gram mixture, 40 grams of pure milk is added, what would be the percentage of milk in the resulting mixture?
|
[
"71%",
"72%",
"73%",
"74%",
"75%"
] |
The amount of milk is 0.7(200) + 40 = 180 grams.
The proportion is 180/240 = 0.75 which is 75%
The answer is E.
The answer is: E
|
E
|
mathematics
|
Find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 772.
|
[
"120 ,122 , 124 ,126",
"120 ,122 , 124 ,128",
"120 ,121 , 122 ,123",
"125 , 127 ,129, 131",
"None of these"
] |
Let x, x + 2, x + 4 and x + 6 be the four integers. The sum of the first two
x + (x + 2)
twice the sum of the last two is written as
2 ((x + 4) + (x + 6)) = 4 x + 20
sum of the first two added to twice the sum of the last two is equal to 772 is written as
x + (x + 2) + 4 x + 20 = 772
Solve for x and find all four numbers
x = 125 , x + 2 = 127 , x + 4 = 129 , x + 6 = 131
Answer D
The answer is: D
|
D
|
mathematics
|
The probability that a number selected at random from the first 50 natural numbers is a composite number is ?
|
[
"17/29",
"17/25",
"17/265",
"17/252",
"17/21"
] |
The number of exhaustive events = ⁵⁰C₁ = 50.
We have 15 primes from 1 to 50.
Number of favourable cases are 34.
Required probability = 34/50 = 17/25.
Answer: B
The answer is: B
|
B
|
mathematics
|
23 × 19 × ? ÷ 19 ÷ 17 = 115
|
[
"65",
"75",
"85",
"95",
"45"
] |
Explanation:
23 × 19 × ? ÷ 19 ÷ 17 = 115
=> (23 × 19 × ?)/(19 × 17) = 115
=> ? = (115 × 19 × 17)/(23 × 19) = 85
Answer: Option C
The answer is: C
|
C
|
mathematics
|
A man swims downstream 45 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?
|
[
"2",
"8",
"9",
"10",
"10.5"
] |
45 --- 3 DS = 15
? ---- 1
18 ---- 3 US = 6
? ---- 1 M = ?
M = (15 + 6)/2 = 10.5
Answer: E
The answer is: E
|
E
|
mathematics
|
Micheal and Adam can do together a piece of work in 20 days. After they have worked together for 11 days Micheal stops and Adam completes the remaining work in 10 days. In how many days Micheal complete the work separately.
|
[
"80 days",
"100 days",
"120 days",
"110 days",
"200 days"
] |
Rate of both = 1/20
Together they do = 1/20*11 = 11/20
Left work = 1 - 11/20 = 9/20
Adam completes 9/20 work in 10 day
so he took 10*20/9 = 200/9 days to complete the left work alone.
Thus the rate of adam is 9/200
Rate of Micheal = 1/20 - 9/200 = 1/200
Thus micheal takes 200 days to complete the whole work.
ans. E.
The answer is: E
|
E
|
mathematics
|
From 6 positive numbers and 6 negative numbers, how many groups Z of 4 numbers, yielding a positive product, can be formed?
|
[
"720",
"625",
"30",
"960",
"255"
] |
Potential combinations of 4 numbers that will yield positive product
++++ 4C6
---- 4C6
++-- 2C6*2C6
4C6 + 4C6 + 2C6*2C6
Z=15 +15 + 15*15 = 255=E
The answer is: E
|
E
|
mathematics
|
If 0.75: x :: 5:9, then x is equal to:
|
[
"1.12",
"1.16",
"1.2",
"1.35",
"None of these"
] |
Explanation:
(x * 5) = (0.75 *9)
X=6.75/5 = 1.35
Answer: D
The answer is: D
|
D
|
mathematics
|
David and Rachel are getting married. The extended family wants to have its picture taken, but David's father is unwilling to stand next to Rachel's mother. How many options does the photographer have to arrange the 7 family members in a row for the picture?
|
[
"9!",
"9×8!",
"8×9!",
"10!/2!",
"5x6!"
] |
In how many ways David's father and Rachel's mother can stand together? Consider them as one unit: {F, M}. So, we'd have 9 units {F, M}, 1, 2, 3, 4, 5, which can be arranged in 9! ways. David's father and Rachel's mother within their unit can be arranged in 2! ways. Therefore, David's father and Rachel's mother can stand together in 6!*2! ways.
Total - Restriction =
= 7! - 6!*2! =
= 6!(7 - 2!) =
= 5*6!.
Answer: E.
The answer is: E
|
E
|
mathematics
|
Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
Year Item of Expenditure
Salary Bonus Transport Fuel Interest on Loans Taxes
1998 288 98 3.00 23.4 83
1999 342 112 2.52 32.5 108
2000 324 101 3.84 41.6 74
2001 336 133 3.68 36.4 88
2002 420 142 3.96 49.4 98
The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?
|
[
"A)1%",
"B)1.5%",
"C)1.25%",
"D)3%",
"E)4%"
] |
Required percentage
=(288 + 342 + 324 + 336 + 420)
= [ 17 x 100 ] %
1710
~= 1%.
Answer : A
The answer is: A
|
A
|
mathematics
|
The sub-duplicate ratio of 25:49 is
|
[
"4:3",
"5:7",
"6:4",
"1:4",
"2:3"
] |
root(25):root(49)=5:7
ANSWER:B
The answer is: B
|
B
|
mathematics
|
How many Books each of Volume 100 meter cube can be packed into a crate of volume 3000 meter cube?
|
[
"50",
"cannot be determined",
"150",
"300",
"350"
] |
Gud question with a simple concept.
In geo if we want to insert one shape into another we need to know the dimensions of the two shapes.
In above with volume given , we can come up with different shapes, so we cant know the answer
For ex :3000 m3 can be 300*10 or 30*100 or just 3000*1 we don't know , so we cant calculate
Answer : B
The answer is: B
|
B
|
mathematics
|
There are three places P, Q and R such that 3 roads connects P and Q and 4 roads connects Q and R. In how many ways can one travel from P to R?
|
[
"12",
"24",
"32",
"64",
"82"
] |
Number of ways in which one can travel from P to R
=3×4=12=3×4=12
ANSWER A 12
The answer is: A
|
A
|
mathematics
|
Find the mean proportional of the following pairs of numbers 6 and 24.
|
[
"27",
"28",
"29",
"23",
"12"
] |
Required number of trees
= 24/36 * 42
= 28.
Answer:B
The answer is: B
|
B
|
mathematics
|
What is the present worth of Rs. 143 due in 2 years at 5% simple interest per annum
|
[
"110",
"120",
"130",
"140",
"None of these"
] |
Explanation:
Let the present worth be Rs.x
Then,S.I.= Rs.(143 - x)
= (x*5*2/100) = 143 - x
= 10x = 14300 - 100x
= 110x = 14300
x= 130
Answer: C
The answer is: C
|
C
|
mathematics
|
The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women?
|
[
"39",
"27",
"30",
"26",
"29"
] |
20 + 24 + 8 * 2 = 60/2 = 30
Answer: C
The answer is: C
|
C
|
mathematics
|
Two trains 151 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
|
[
"7.19",
"7.18",
"7.16",
"7.84",
"7.12"
] |
T = (151 + 165)/ (80 + 65) * 18/5
T = 7.84
Answer: D
The answer is: D
|
D
|
mathematics
|
What will come in place of the x in the following Number series? 68, 36, 20, 12, 8, x
|
[
"6",
"4",
"2",
"1",
"0"
] |
68
68 / 2 + 2 = 36
36 / 2 + 2 = 20
20 / 2 + 2 = 12
12 / 2 + 2 = 8
8 / 2 + 2 = 6 A
The answer is: A
|
A
|
mathematics
|
Which of the following is the sum of all the even numbers between 3 and 99, inclusive?
|
[
"2550",
"2449",
"2600",
"2499",
"2652"
] |
This question can be solved withbunching.
We're asked for the SUM of all of the EVEN integers from 1 to 99, so we really want the sum of 2, 4, 6, 8.....98.
If you take the next smallest and next biggest numbers, you have...
4+96 = 100
This pattern will continue on, so we're going to have a bunch of 100s, BUT we have to be careful to make sure that we don't miss a number if it'sin the middleand doesn't get paired up. Since we know that the sum of each pair is 100, we can 'jump ahead' to find the last few pairs...
44+56 = 100
46+54 = 100
48+52 = 100
There IS a middle number: 50; this number does NOT get paired up.
Since 48 is the 24th even integer, we know there are twenty-four 100s + one 50. 2400+50-1 = 2449
Final Answer:
B
The answer is: B
|
B
|
mathematics
|
If abc = ab^3 = 180 where a, b and c are positive integers, what is the value of `c’?
|
[
"0",
"1",
"2",
"3",
"4"
] |
abc = a(b^3) = 180
on solving abc = a(b^3) we get c = b^2
and for a(b^3) = 180 , there is only one possibility a = 180 and b = 1 so c = 1^2 = 1
ANSWER:B
The answer is: B
|
B
|
mathematics
|
What is 15 percent of 44?
|
[
"6.6",
"7.8",
"8.9",
"9.4",
"10.2"
] |
(15/100) * 44 = 6.6
The answer is A.
The answer is: A
|
A
|
mathematics
|
W is the set of all positive integers x such that x^2 is a multiple of both 27 and 375. Which of the following integers must be a divisor of every integer x in W?
I. 9
II. 15
III. 27
|
[
"I only",
"II only",
"I and II only",
"I and III only",
"I, II, and III"
] |
Ans: C
W->{x} where x^2 is a multiple of both 27 and 375 means 3^3 and (5^3)*3
means x must contain 3^2 and 5^2
so with these conditions we know that 9=3^2 and 15=3*5 both have required factors for the divisibility of lowest int for x which is 9*25
but 27 is not a divisor because it can't divide 9*25 fully.
so Ans : C
The answer is: C
|
C
|
mathematics
|
A code is to be made by arranging 6 letters. Three of the letters used will be the letter A, two of the letters used will be the letter B and one of the letters used will be the letter C . If there is only one way to present each letter, how many different codes are possible?
|
[
"230",
"360",
"420",
"840",
"5,040"
] |
we have 6 letters out of which 3 are of one kind, 2 are of another kind..
so total ways = 6!/2!1!=360
ans B
The answer is: B
|
B
|
mathematics
|
A bookseller has two display windows. She plans to display 5 new fiction books in the left window, and 3 new non-fiction books in the right window. Assuming she can put the three fiction books in any order, and separately, the three non-fiction books in any order, how many total configurations will there be for the two display windows?
|
[
"240",
"720",
"144",
"336",
"420"
] |
Two displays books could be arranged n! # of total arrangements are combinations multiplied together,
5!*3! =120*6=720
Answer is B
The answer is: B
|
B
|
mathematics
|
In a certain game, each player scores either 2 points or 5 points. If n players score 2 points and m players score 5 points, and the total number of points scored is 50, what is the least possible positive E difference between n and m?
|
[
"1",
"3",
"5",
"7",
"9"
] |
We have equation 2n + 5m = 50
We have factor 2 in first number and we have factor 5 in second number.
LCM(2, 5) = 10
So we can try some numbers and we should start from 5 because it will be less list than for 2
2 * 5 = 10 and n should be equal 20
4 * 5 = 20 and n should be equal 15
6 * 5 = 30 and n should be equal 10
8 * 5 = 40 and n should be equal 5
10 * 5 = 50 and n should be equal 0
third variant give us the mininal difference
n - m = 10 - 6 = 4
And there is some mistake in my way of thinking because we don't have such answer )
If we change the task and will seek for difference between m and n
than minimal result E will be 8 - 5 = 3
And answer B
The answer is: B
|
B
|
mathematics
|
You have 59 cubic blocks. What is the minimum number that needs to be taken away in order to construct a solid cube with none left over?
|
[
"27",
"43",
"11",
"32",
"45"
] |
D
32
The next cube number below 64(4 ×4 ×4) is 27(3 ×3 ×3).
In order to construct a solid cube, therefore, with none left over,
59 – 27 = 32 blocks need to be taken away.
The answer is: D
|
D
|
mathematics
|
An article when sold at a gain of 5% yields Rs. 15 more than when sold at a loss of 5%. The cost price of the article is:
|
[
"Rs. 200",
"Rs. 150",
"Rs. 80",
"Rs. 64",
"None of these"
] |
10/100 × x = 15 ⇒ x=150
As the loss and profit both are earned on the cost price.
Answer: B
The answer is: B
|
B
|
mathematics
|
It takes David 30 minutes to walk to the car park and 60 to drive to work. At what time should he get out of the house in order to get to work at 9:00 a.m.?
|
[
"7:30 a.m",
"5:50 a.m",
"7:50 a.m",
"6:50 a.m",
"9:50 a.m"
] |
The time it takes David to get to work: time to walk to car park + time to drive
30 + 60 = 90 minutes = 1 hour and 30 minutes
David needs to get out of the house 1 hour and 30 minutes before 9:00 am at
9:00 - 1:30 = 7:30 a.m
correct answer A
The answer is: A
|
A
|
mathematics
|
Thirty five percent of the portfolios managed by the Crocodile Brokers company (C.B.C.) hold Hatsopoulos stocks. Forty percent of the portfolios managed by C.B.C. hold McQuarrie stocks and do not hold Hatsopoulos stocks. Fifteen percent of the portfolios managed by C.B.C. hold Hatsopoulos stocks and do not hold McQuarrie stocks. What percent of the portfolios managed by C.B.C. do NOT hold McQuarrie stocks?
|
[
"20",
"25",
"40",
"60",
"65"
] |
H represent those portfolios holding Hatsopoulos stocks
M represent those portfolios holding McQuarrie stocks
35% hold H => z+x=35z+x=35
40% hold M and do not hold H => y = 40
15% hold H and not M => z = 15
We have , x = 20
x+y+z=20+40+15=75 x+y+z=20+40+15=75
There are 25% portfolios holding neither H nor M.
Portfolios that do not hold M = z+(neither H nor M)z+(neither H nor M)
= 15+25
=40
ANSWER:C
The answer is: C
|
C
|
mathematics
|
The manager of a theater noted that for every 10 admissions tickets sold, the theater sells 3 bags of popcorn at 2.75 $ each, 4 sodas at 1.50 $ each and 2 candy bars at 1.00$ each. To the nearest cent, what is the average (arithmetic mean) amount of these snacks sales per ticket sold?
|
[
"1.48$",
"1.58$",
"1.60$",
"1.63$",
"1.70$"
] |
For every 10 tickets amount of snacks sold is 3*2.75+4*1.5+2*1=$16.25, hence amount of the snacks sales per ticket is $16.25/10=~$1.63.
Answer: D.
The answer is: D
|
D
|
mathematics
|
ASvennumber is defined as a five-digit number which goes according to the following rules: the leftmost digit is even, any digit to the right of an even digit must be an odd digit, and any digit to the right of an odd digit can only be one of the digits 1 or 7. How many different 3-digit numbers areSvennumbers?
|
[
"20",
"60",
"160",
"220",
"250"
] |
ASvennumber is defined as a five-digit number which goes according to the following rules: the leftmost digit is even, any digit to the right of an even digit must be an odd digit, and any digit to the right of an odd digit can only be one of the digits 1 or 7. How many different 5-digit numbers areSvennumbers?
4/9*5/10*2/10*2/10*2/10=160/9000
B. 60
The answer is: B
|
B
|
mathematics
|
The value of 2*x+x/4+ x(xx) when x = 4 is:
|
[
"57",
"63",
"75",
"73",
"45"
] |
2*x+x/4+ x(xx)
2*4+4/4+4(4*4)
2*4+4/4+4(16)
2*4+4/4+64
2*4+1+64
8+1+64=73
answer D
The answer is: D
|
D
|
mathematics
|
Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is ?
|
[
"5/19",
"5/12",
"5/29",
"5/20",
"5/22"
] |
Using question number 11 and 12, we get the probability as
1 - (1/36 + 5/9)
= 5/12
Answer:B
The answer is: B
|
B
|
mathematics
|
If x is divisible by 2, 14, and 11, which of the following must be the least multiple of x?
|
[
"308",
"154",
"70",
"44",
"20"
] |
If x is divisible by 2,14 and 11,then x must be a multiple of 2,7 and 11.
Hence,the least multiple of x will be 2*7*11=154.
ANSWER:B
The answer is: B
|
B
|
mathematics
|
In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiples the integer on the card by the next larger integer. If each possible product is between 28 and 200, then the least and greatest integers on the card could be
|
[
"3 and 15",
"3 and 20",
"5 and 13",
"4 and 14",
"5 and 14"
] |
There child draws one number then multiplies that number by the number above it. The number must be more than 28 and less than 200.
x * (x+1)
Answer gives us choices of 3,4 and 5 (JUST ABOVE 28)
3*(3+1) =12 <- WRONG
4*(4+1) =20 <- WRONG
5*(5+1) =30 <- CORRECT AS IT IS ABOVE 28
Answer gives us choices 13,14,15 and 20 (BELOW 200)
Immediately by knowing squares you should be able to rule out 15 (225) and 20 (400). And common sense dictates that as 14^2 is 196 that 14*(14+1) is above 200.
13*(13+1)=182 <- CORRECT
Answer is C) 5 and 13
The answer is: C
|
C
|
mathematics
|
If a, q, and c are consecutive even integers and a < q < c, all of the following must be divisible by 4 EXCEPT
|
[
"a + c",
"q + c",
"ac",
"(bc)/2",
"(abc)/4"
] |
I did get the correct answer within 80 seconds and it was not by luck either. I did not pick numbers but just used the concept stated by Ian.
The 3 numbers can be written as
a, (a + 2)(a + 4).
If 'a' is divisible by 4, then even 'c' or 'a + 4' is divisible by 4. However, is 'b' is divisible by 4, then both 'a' and 'a + 4' are still divisible by 2.
A - (a + c) = a + (a + 4) = 2a + 4 = 2(a + 2) = 2q. 2q will always be divisible by 4 even if 'b' is not divisible by 4. Reason: 'q' already has a prime factorization of at least a '2'. Hence '2q' has two 2s.
C - ac = a(a+4). If, as stated above, one of them is divisible by 4, then the product is divisible. If both of them are not divisible by 4, then the product is still divisible by 4 because of the presence of two 2s again in the prime factorization.
D - qc/2 = (a + 2)(a + 4)/2. Either q or c is divisible by 2. Hence, if we assume that b is divisible by 2 and not divisible by 4, then it leaves us just one possibility. Is c divisible by 4? It has to be because c is the next consecutive even integer.
E - aqc/4 = a(a + 2)(a + 4)/4. One of these integers is divisible by 4 already. If we again assume 'q' to be that integer divisible by 4, then we are left with the question - Is a(a + 4) divisible by 4? This is the same as option C.
B - q + c = (a + 2) + (a + 4) = 2a + 6 = 2(a + 3). (a + 3) will never be divisible by 2 because it is an odd integer. Hence, 2(a + 3), although divisible by 2, will not be divisible by 4 because it has just one 2 in its prime factorization.
As a whole, whether you choose numbers (2, 46 being the easiest) or solve conceptually, the answer is still easily obtainable within 2 minutes.B
The answer is: B
|
B
|
mathematics
|
one out of ten employees are capable of doing a certain task. 40 percent of the five employees, including the one who are capable, are assigned to a project involving this task. what percentage of employees assigned to the project are not capable?
|
[
"43.33%",
"75%",
"13.33%",
"38.33%",
"23.33%"
] |
Given 40% of 10 employees including 1 who are capable of doing task.
40% of 10 employeees
= 40/100 * 10
= 4 employees
===> 1 employees who are capable of doing the task and three employee who is not capable.
percentage of employees assigned who are not capable
= 3/4 * 100
=75%
ANSWER:B
The answer is: B
|
B
|
mathematics
|
The average of first 15 natural numbers is?
|
[
"5.2",
"5.5",
"8",
"9",
"10"
] |
Sum of 15 natural no. = 240/2 = 120
Average =120/15 = 8
Answer:C
The answer is: C
|
C
|
mathematics
|
A family consists of two grandparents, two parents and 6 grandchildren. The average age of the grandparents is 60 years, that of the parents is 30 years and that of the grandchildren is 5 years. What is the average age of family?
|
[
"5/7years",
"B)21",
"C)30",
"D)33",
"E)35"
] |
Required average
= (60 x 2 + 30 x 2 + 5 x 6 )/(2 + 2 + 6)
= (120 + 60 + 30)/10
= 210/10
= 21 years.
Answer is B
The answer is: B
|
B
|
mathematics
|
The average score of a cricketer for ten matches is 38.9 runs. If the average for first six matches is 42, then average for last four matches is
|
[
"33.25",
"32.25",
"34.25",
"34.5",
"35.5"
] |
Explanation:
=(38.9×10)−(42×6)/4
=(1216−750)4=34.25
Answer: Option C
The answer is: C
|
C
|
mathematics
|
The calendar of the year 2040 can be used again in the year?
|
[
"2063",
"2061",
"2111",
"2191",
"2068"
] |
Explanation:
Given year 2040 when divided by 4, leaves a remainder 0.
NOTE: When remainder is 0, 28 is added to the given year to get the result.
So, 2040 + 28 = 2068
Answer: E
The answer is: E
|
E
|
mathematics
|
Ram and Shyam have a cube each. Ram paints four faces of cube with red color and rest with blue color. Ram asks Shyam to paint his cube as well with some sides red and some side blue. They now start rolling the cubes simultaneously. After doing this for very long Ram observes that probability of both cubes coming up with same color is 1/3. How many faces of his cube did Shyam paint red ?
|
[
"0",
"2",
"3",
"4",
"5"
] |
Explanation :
Let Shyam paints n faces of the cube red. So faces painted blue = (6-n)
Probability that both show up same color is: (probability both show red) + (probability both show blue)
= 4/6 * n/6 + 2/6 * (6-n)/6
= (2n + 6)/18
But as given, (2n + 6)/18 = 1/3 => n = 0
So Shyam hasn't painted any of the face with red color.
Answer : A
The answer is: A
|
A
|
mathematics
|
A man goes downstream at 12 kmph, and upstream8 kmph. The speed of the stream is
|
[
"2kmph",
"4kmph",
"16kmph",
"2.5kmph",
"26kmph"
] |
Speed of the stream = 1/2(12-8)kmph
=2kmph.
correct option A
The answer is: A
|
A
|
mathematics
|
Two brother X and Y appeared for an exam. The probability of selection of X is 1/3 and that of B is 2/5. Find the probability that both of them are selected.
|
[
"2/69",
"2/15",
"2/63",
"2/29",
"2/10"
] |
Explanation:
Let A be the event that X is selected and B is the event that Y is selected.
P(A) = 1/3, P(B) = 2/5.
Let C be the event that both are selected.
P(C) = P(A) × P(B) as A and B are independent events:
= (1/3) × (2/5) = 2/15
Answer: B) 2/15
The answer is: B
|
B
|
mathematics
|
In the interior of a forest, a certain number of apes equal to the square of one-eighth of the total number are playing and having great fun. The remaining sixteen apes are on a hill and the echo of their shrieks by the adjoining hills frightens them. They came and join the apes in the forest and play with enthusiasm. What is the total number of apes?
|
[
"32",
"16",
"64",
"80",
"16 or 48"
] |
Let total number be x
No in the interior = (x/8)^2
No outside = 16
So : x - (x/8)^2=16
x^2-64x+16*64=0
(x-32)^2=0
x=32
A
The answer is: A
|
A
|
mathematics
|
In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 5:6:2. If there are in all Rs.42, the number of 25 paisa coins is?
|
[
"31",
"42",
"102",
"52",
"62"
] |
Answer: Option B
5x 6x 2x
50 25 100
250x + 150x + 200x = 4200
600x = 4200
x = 7 => 6x = 42
The answer is: B
|
B
|
mathematics
|
A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit V on this shipment?
|
[
"a) $100",
"b) $115",
"c) $125",
"d) $130",
"e) $135"
] |
I recommend one should use fractions to solve this one rather than converting it into decimals
Sol:
1500 heads -> $600
1 head -> $600/1500
1 head -> $(2/5)
25% more of (2/5) -> 125/100 * 2/5 = $(1/2)
He sold 2/3*1500 = 1000 heads for $(1/2) per head
Total revenue by selling 1000 heads = 1000 * 1/2 = $500
Heads left: 500
Cost per head: 90% of the previous price: 90/100 * 1/2 = $(9/20)
Total revenue by selling 500 heads = 9/20 * 500 = 225
Total revenue after selling 1500 cabbage heads - 225+500 = $725
Money spent on the purchase: $600
Profit V= 725-600 = $125
Ans:C
The answer is: C
|
C
|
mathematics
|
What is the next number in this sequence: 39, 52, 65, 78, 91 ?
|
[
"107",
"112",
"104",
"99",
"109"
] |
By subtracting each number from the one after it, we can determine that the numbers are all multiples of 13. By adding 13 to the last number, you get the answer.
91 + 13 = 104
Answer: C
The answer is: C
|
C
|
mathematics
|
In a 200 meters race A beats B by 56 m or 7 seconds. A's time over the course is:
|
[
"22 seconds",
"12 seconds",
"10 seconds",
"18 seconds",
"28 seconds"
] |
B runs 56 m in 7 sec.
=> B runs 200 m in 7/56*200 = 25 seconds
Since A beats B by 7 seconds, A runs 200 m in (25-7) = 18 seconds
Hence, A's time over the course = 18 seconds
ANSWER:D
The answer is: D
|
D
|
mathematics
|
Two trains 160 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
|
[
"10.7",
"10.9",
"10.52",
"11.52",
"18.82"
] |
Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 160 + 160 = 320 m.
Required time = 320 * 9/250
= 11.52 sec.
Answer:D
The answer is: D
|
D
|
mathematics
|
An article is sold at a certain price. By selling it at 2/3 of that price one loses 10%. Find the gain percent at original price?
|
[
"25%",
"20%",
"35%",
"40%",
"50%"
] |
Let the original S.P. be $x
Then, New S.P. = $ 2/3 x
Loss = 10%
C.P. = 100/90 * 2/3 x = 20x/27
C.P. = 20x/27
Gain = x - 20x/27 = 7x/27
Gain% = 7x/27 * 27/20x * 100 = 35%
Answer is C
The answer is: C
|
C
|
mathematics
|
An auto assembly plant performs six functions with each frame that arrives: add axles, add wheels to the axles, install the windshield to the frame, install the instrument panel, install the steering wheel, and install the interior seating. Once those six tasks are performed, each car goes to a separate building for finishing touches. If these tasks can be arranged along a linear assembly line in any order, except that the axles must be installed before the wheels can be added, how many W ways can the assembly line be arranged?
|
[
"120",
"240",
"360",
"480",
"720"
] |
C) 360
short way: there are 6C! ways to do the six tasks. Half will have wheels before axles and half will have axles before wheels. So we want W=6C!/2 -> 720/2 = 360
The answer is: C
|
C
|
mathematics
|
About the number of pairs which have 12 as their HCF and 136 as their LCM, the conclusion can be
|
[
"no pair exist",
"only two such pairs exist",
"many such pairs exist",
"only one such pair exists",
"None of these"
] |
Explanation:
HCF is always a factor of LCM. ie., HCF always divides LCM perfectly.
Correct Option: A
The answer is: A
|
A
|
mathematics
|
There are 16 bees in the hive , then 10 more fly. How many bees are there in all?
|
[
"7",
"33",
"12",
"17",
"26"
] |
16+10=26 . Answer is E.
The answer is: E
|
E
|
mathematics
|
A marble shop contains 6 blue marbles, 7 red marbles, and 7 green marbles. If 4 marbles are purchased at random from the shop, what is the probability that the 4 marbles will be blue?
|
[
"5/19",
"9/20",
"1/57",
"15/57",
"15/684"
] |
It doesn't matter which type of card you choose, so:
Probability of choosing 1st card: 6/20
Probability of choosing 2nd card of the same type: 5/19
Probability of choosing 3rd card of the same type: 4/18
Multiply and you get 1/57
Answer C.
The answer is: C
|
C
|
mathematics
|
The average age of P, Q, R, S five years ago was 45 years. By including T, the present average age of all the five is 49 years. The present age of T is?
|
[
"64 years",
"48 years",
"45 years",
"40 years",
"None of these"
] |
Present age of P, Q, R, S = 45 x 4 + 20 = 200
Present age of P, Q, R, S and T = 49 x 5 = 245
Hence, the age of T = 245 - 200 = 45 years.
ANSWER:C
The answer is: C
|
C
|
mathematics
|
On Sunday morning, Pugsley and Wednesday are trading pet spiders. If Pugsley were to give Wednesday two of his spiders, Wednesday would then have seven times as many spiders as Pugsley does. But, if Wednesday were to give Pugsley four of her spiders, Pugsley would now have four fewer spiders than Wednesday had before they traded. How many pet spiders does Pugsley have before the trading game commences?
|
[
"2",
"4",
"6",
"8",
"10"
] |
If Pugsley were to give Wednesday two of his spiders, Wednesday would then have seven times as many spiders as Pugsley does:
(w + 2) = 7(p - 2)
If Wednesday were to give Pugsley four of her spiders, Pugsley would now have four fewer spiders than Wednesday had before they traded:
p + 4 = w - 4
Solving gives p = 4 and w = 12.
Answer: B.
The answer is: B
|
B
|
mathematics
|
Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 1 : 3?
|
[
"76.66 kmph",
"69.66 kmph",
"48 kmph",
"66.66 kmph",
"56.66 kmph"
] |
Let the distances between city A to B and B to C be 2x km and 3x km respectively.
Total time taken to cover from A to C
= (x)/40 + (3x)/60 = (3x + 6x)/120 = 9x/120 = 3x/40 Average speed = (2x + 3x)/(3x/40)
= 200/3 kmph.
=66.66 kmph
ANSWER:D
The answer is: D
|
D
|
mathematics
|
Harkamal purchased 8kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 50 per kg. How much amount did he pay to the shopkeeper?
|
[
"A)1000",
"B)1010",
"C)1065",
"D)1075",
"E)1080"
] |
Cost of 8 kg grapes = 70 × 8 = 560.
Cost of 9 kg of mangoes = 50 × 9 = 450.
Total cost he has to pay = 560 + 450 = 1010.
B)
The answer is: B
|
B
|
mathematics
|
Two children want to walk together to visit their aunt, who lives exactly 7 blocks north and 5 blocks east of their current location. If they travel only along streets and do not travel diagonally, the shortest possible route connecting the two points is exactly 12 blocks. How many different 12-block routes may they take to travel the shortest possible distance to their aunt’s house?
|
[
"12!/(7*5)",
"19!/(12!)",
"12!/(7!5!)",
"12!*7!*5!",
"7!*5!"
] |
If they need to walk 7 blocks north and 5 blocks east, we can express this route as NNNNNNNEEEEE. The question thus asks us how many ways we can arrange those letters.
The number of arrangements of 12 things is 12!
We then divide by the repetitions of N's and E's, which are 7! and 5! respectively.
The number of walking routes is 12!/(7!5!).
The answer is C.
The answer is: C
|
C
|
mathematics
|
Andrew has a certain number of coins in his pocket. He has three times as many dimes as quarters and five times as many nickels as dimes. A nickel is worth $0.05, a dime is worth $0.10 and a quarter is worth $0.25. If he has a total of $10.15, then which of the following represents the number of dimes in Andrew’s pocket?
|
[
"9",
"10",
"18",
"24",
"21"
] |
E.
Let number of quarters be q. Therefore , dimes are 3q and nickels are 18q.
Total value = 15q(.05) + 3q(0.1) + .25q =1.3q
Given total value = 10.15
therefore, 1.3q=10.15 or q=8
Number of dimes = 3q or 24
Answer : D
The answer is: D
|
D
|
mathematics
|
When the price of a pressure cooker was increased by 15%, the sale of pressure cookers decreased by 15%. What was the net effect on the sales?
|
[
"15% decrease",
"no effect",
"2.25% increase",
"2.25% decrease",
"None of these"
] |
Net effect on sale = −(common%change)2/100
= −(15)2/100= 2.25% decrease
Answer D
The answer is: D
|
D
|
mathematics
|
The number 341 is equal to the sum of the cubes of two integers. What is the product of those integers?
|
[
"8",
"15",
"21",
"30",
"39"
] |
5^3+6^3= 341 number is 5*6=30
D
The answer is: D
|
D
|
mathematics
|
When a number is divided by 6 &then multiply by 12 the answer is 11 what is the no.?
|
[
"4.5",
"5",
"5.5",
"5.8",
"6"
] |
if $x$ is the number, x/6 * 12 = 11
=> 2x = 11
=> x = 5.5
C
The answer is: C
|
C
|
mathematics
|
Ram professes to sell his goods at the cost price but he made use of 975 grms instead of a kg, what is the gain percent?
|
[
"3 22/39%",
"4 22/39%",
"2 22/39%",
"7 22/39%",
"9 22/39%"
] |
975 --- 25
25 --- ? =>
25/975 *100
= 2 22/39%
Answer: C
The answer is: C
|
C
|
mathematics
|
A new home buyer pays 4% annual interest on her first mortgage and 9% annual interest on her second mortgage. If she borrowed a total of $310,000, 80% of which was in the first mortgage, what is her approximate monthly interest payment?
|
[
"$1,292",
"$1,733",
"$3,466",
"$12,917",
"$20,796"
] |
0.04x + 0.09y = 310000 [1]
0.04x = 0.80 * 310000 = 248000 [2]
248000 + 0.09y = 310000 --> 0.09y = 62000 [3]
248000 / 12 = 258333.3333 [4]
62000 / 12 = 5166.67 [5]
Adding [4,5] we get: 25833 [6]
Dividing [6] / 2 to get an average we get 1.292,ANS A
The answer is: A
|
A
|
mathematics
|
If 9^y = 3^16, what is y?
|
[
"2",
"3",
"4",
"6",
"8"
] |
9^y = 3^2y = 3^16
2y=16
y = 8
The answer is E.
The answer is: E
|
E
|
mathematics
|
When 1/10 percent of 3,000 is subtracted from 1/10 of 3,000, the difference is
|
[
"2970",
"297",
"2997",
"300",
"30"
] |
(1/10)*3000 - (1/10)%*3000 =
300 - (1/1000)*3000 =
300 - 3 = 297
The answer is B.
The answer is: B
|
B
|
mathematics
|
If c and d are prime numbers, which of the following CANNOT be the sum of c and d?
|
[
"5",
"9",
"13",
"23",
"33"
] |
All answer choices but D are odd. In order odd number to be the sum of two prime numbers one must be even, so 2, and another odd.
Now, 23=2+21. Since 21 is not a prime then 23 cannot be written as the sum of two prime numbers.
Answer: D
The answer is: D
|
D
|
mathematics
|
A man can hit a target once in 4 shots. If he fires 4 shots in succession, what is the probability that he will hit his target?
|
[
"564/123",
"646/458",
"456/847",
"175/256",
"256/175"
] |
The man will hit the target if he hits it once or twice or thrice or all four times in the four shots that he takes.
So, the only possibility when the man will not hit the target is when he fails to hit the target in even one of the four shots that he takes.
The event of not hitting the target even once is the complement of the event of hitting the target at least once.
The probability that he will not hit the target in any given shot = 1 – 1/4 = ¾
Therefore, the probability that he will not hit the target in any of the four shots =3/4*3/4*3/4*3/4=81/256
The probability that he will hit the target at least in one of the four shots=1-81/256
=175/256
Ans: D
The answer is: D
|
D
|
mathematics
|
8^b + 8^b + 8^b + 8^b + 8^b + 8^b + 8^b + 8^8 =
|
[
"7^b",
"8^(b + 1)",
"7^(7b)",
"8^b",
"49^B"
] |
Easy one.
8*8^b = 8^(b+1)
Ans. B
The answer is: B
|
B
|
mathematics
|
A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 42 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
|
[
"229",
"288",
"787.5",
"888",
"121"
] |
D = 30 * 5 = 150
RS = 42 – 30 = 8
T = 150/8 = 18.75
D = 42 * 18.75 = 787.5 km
Answer: C
The answer is: C
|
C
|
mathematics
|
A and B start a business, with A investing the total capital of Rs.50000, on the condition that B pays A interest @ 10% per annum on his half of the capital. A is a working partner and receives Rs.1500 per month from the total profit and any profit remaining is equally shared by both of them. At the end of the year, it was found that the income of A is twice that of B. Find the total profit for the year?
|
[
"28999",
"27888",
"27838",
"59000",
"28992"
] |
Interest received by A from B = 10% of half of Rs.50000 = 10% * 25000 = 2500.
Amount received by A per annum for being a working partner = 1500 * 12 = Rs.18000.
Let 'P' be the part of the remaining profit that A receives as his share. Total income of A = (2500 + 18000 + P)
Total income of B = only his share from the remaining profit = 'P', as A and B share the remaining profit equally.
Income of A = Twice the income of B
(2500 + 18000 + P) = 2(P)
P = 20500
Total profit = 2P + 18000
= 2*20500 + 18000 = 59000
Answer: D
The answer is: D
|
D
|
mathematics
|
Cara picked a number of pears, each of which she sold, canned, or poached. If she canned 40 percent more than she poached, and she poached 80 percent less than she sold. If there were a total of 111 pears, then how many pears did she sell?
|
[
"69",
"72",
"75",
"78",
"81"
] |
Let x be the amount of pears that she sold.
Then she poached 0.2x.
Then she canned 1.4*0.2x=0.28x.
The total amount of pears is x+0.2x+0.28x=1.48x
The fraction of pears that she sold is 1/1.48=100/148=25/37.
The number of pears she sold is (25/37)*111=75.
The answer is C.
The answer is: C
|
C
|
mathematics
|
A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 20 hrs and a machine of type S does the same job in 60 hours. If the company used the same number of each type of machine to do the job in 3 hours, how many machines of type R were used?
|
[
"3",
"4",
"5",
"6",
"8"
] |
Type R completes 1/20 of the job each hour.
Type S completes 1/60 of the job each hour.
Together R and S complete 1/20 +1/60 = 1/15 of the job each hour.
Let n be the number of each type of machine.
3*n*(1/15) = 1 job completed
n = 5
The answer is C.
The answer is: C
|
C
|
mathematics
|
Given positive even integer y, which of the following CANNOT be evenly divisible by y?
|
[
"y + 2",
"y + 8",
"2y + 4",
"3y − 1",
"2y - 2"
] |
This can be easily solved by substituting values:
Assume y to be 2
A. y + 2: 4 is evenly divisible by 2
B. y + 8: 10 is evenly divisible by 2
C. 2y + 4: 8 is evenly divisible by 2
D. 3y − 1: 5 is not evenly divisible by 2
E. 2y + 2: 2 is evenly divisible by 2
Option D
The answer is: D
|
D
|
mathematics
|
Every student at Tarcy School is in at least one of three clubs: horseback riding, embroidery, and country dancing, which are the only clubs in existence at the school. The ratio of the number of students in exactly two clubs to the number of students in exactly one club is 4:3, while the ratio of the number of students in exactly two clubs to the number of students in at least two clubs is 5:7. Which of the following could be the total number of students at Tarcy School?
|
[
"63",
"69",
"74",
"82",
"86"
] |
the total number of students at Tarcy School The answer is 86 or any multiple of 43.E
The answer is: E
|
E
|
mathematics
|
The sequence a(1), a(2), …, a(n), … is such that a(n)=4a(n–1) –3 for all integers n>1. If a(3)=x, then a(1)=?
|
[
"4x–3",
"16x–15",
"(x+3)/4",
"(x+3)/16",
"(x+15)/16"
] |
Since we know a(3) we can find a(2),
if we can find a(2) we can find a(1).
a(3)=4a(2)-3 ---> x=4a(2)-3 ---> a(2)=(x+3)/4
a(2)=4a(1)-3 ---> (x+3)/4=4a(1)-3 ---> 4a(1)=(x+15)/4 ---> a(1)=(x+15)/16
The answer is E.
The answer is: E
|
E
|
mathematics
|
A library has an average of 600 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is:
|
[
"250",
"260",
"300",
"285",
"None"
] |
Since the month begins with sunday,to there will be five sundays in the month
Average required = (600x5 + 240x25) /30) = 300
Answer: Option C
The answer is: C
|
C
|
mathematics
|
A cube of side two meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
|
[
"2878",
"2778",
"1000",
"8000",
"8900"
] |
Along one edge, the number of small cubes that can be cut
=200/10 = 20
Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut
= 20 * 20 * 20 = 8000
Answer: D
The answer is: D
|
D
|
mathematics
|
A train 540 meters long is running with a speed of 54 kmph. The time taken by it to cross a tunnel 180 meters long is?
|
[
"22",
"27",
"48",
"99",
"23"
] |
D = 540 + 180 = 720
S = 54 * 5/18 = 15 mps
T = 720/15 = 48 sec
Answer: C
The answer is: C
|
C
|
mathematics
|
. By selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
|
[
"8",
"7",
"5",
"3",
"1"
] |
Explanation:
80% --- 12
120% --- ?
80/120 * 12 = 8
Answer:A
The answer is: A
|
A
|
mathematics
|
The sum of two numbers is 8 and the sum of their squares is 120. Find the product of the two numbers.
|
[
"25",
"24",
"23",
"21",
"28"
] |
Let a and b be the two numbers
(a+b)^2=a^2+2ab+b^2
Given (a+b)=8 a^2+b^2=120
So, 8^2=120+2ab
2ab=120-64
2ab=56
ab=28
Ans E
The answer is: E
|
E
|
mathematics
|
By travelling at 40 kmph, a person reaches his destination on time. He covered two-third the total distance in one-third of the total time. What speed should he maintain for the remaining distance to reach his destination on time?
|
[
"20",
"99",
"88",
"77",
"61"
] |
Let the time taken to reach the destination be 3x hours. Total distance = 40 * 3x = 120x km
He covered 2/3 * 120x = 80x km in 1/3 * 3x = x hours So, the remaining 40x km, he has to cover in 2x hours. Required speed = 40x/2x = 20 kmph.
Answer: A
The answer is: A
|
A
|
mathematics
|
Ron walks to a viewpoint and returns to the starting point by his car and thus takes a total time of 6 hours 45 minutes. He would have gained 2 hours by driving both ways. How long R would it have taken for him to walk both ways.
|
[
"8 h 45 min",
"7 h 45 min",
"6 h 45 min",
"5 h 30 min",
"None of these"
] |
1.Walking to to a viewpoint+Driving back=6 hours 45 minutes
2.Driving to a viewpoint+Driving back=6 hours 45 minutes - 2 hours=4 hours 45 minutes, thereforeone way driving=4 hours 45 minutes/2 =2 hours 22.5 minutes.
3. From 1.one way driving=6 hours 45 minutes-2 hours 22.5 minutes=4 hours 22.5 minutes.
4.Walking to to a viewpoint+Walking back R=4 hours 22.5 minutes+4 hours 22.5 minutes=8 hours 45 minutes.
Answer: A.
The answer is: A
|
A
|
mathematics
|
$700 is divided amongst A,B and C so that A may get 2/3 as much as B and C together, B may get 6/9 as much as A and C together, then the share of A is
|
[
"$100",
"$150",
"$125",
"$280",
"$250"
] |
A:(B+C) = 2:3
A's share = 700*2/5 = $280
Answer is D
The answer is: D
|
D
|
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.