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mathematics
|
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
|
[
"45km/hr",
"50 km/hr",
"54 km/hr",
"55 km/hr",
"60 km/hr"
] |
Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==> x = 50 km/hr.
ANSWER B
The answer is: B
|
B
|
mathematics
|
The difference between compound and simple interest on a certain sum of money for 3 years at 6 2/3% p.a is Rs.184. Find the sum?
|
[
"28882",
"27772",
"23123",
"13500",
"28811"
] |
P = (184*106) / [6 2/3 * 6 2/3 *(300*6 2/3)]
P = 13500
Answer: D
The answer is: D
|
D
|
mathematics
|
A and B can do a piece of work in 8 days. B and C can do it in 12 days and A and C in 16 days. Working together they will complete the work in how many days?
|
[
"5.38 days",
"9.38 days",
"7.38 days",
"3.38 days",
"9.38 days"
] |
C
7.38 days
A + B = 1/8
B + C = 1/12
C + A = 1/16
-------------------------------
2(A + B +C) = 1/8 + 1/12 + 1/16 = 13/48
A + B +C = 13/96
96/13 = 7.38 days
The answer is: C
|
C
|
mathematics
|
A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in?
|
[
"19",
"12",
"11",
"19",
"114"
] |
Suppose A, B and C take x, x/2 and x/3 respectively to finish the work.
Then, (1/x + 2/x + 3/x) = 1/2
6/x = 1/2 => x = 12
So, B takes 6 hours to finish the work.
Answer: B
The answer is: B
|
B
|
mathematics
|
Tickets numbered 1 to 50 are mixed and one ticket is drawn at random. Find the probability that the ticket drawn has a number which is a multiple of 4 or 7?
|
[
"9/25",
"9/29",
"9/26",
"9/24",
"9/21"
] |
Explanation:
S = {1, 2, 3, … , 49, 50}
E = {4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 7, 14, 21, 35, 42, 49}
n(S) = 50
n(E) = 18
P(E) = n(E)/n(S) = 18/50
= 9/25
ANSWER: A
The answer is: A
|
A
|
mathematics
|
What is 10-8+6-4+...+(-18)?
|
[
"-8",
"10",
"12",
"-4",
"16"
] |
The expression considers all even numbers between 10 and -18 with alternate addition and subtraction of the numbers.
The numbers to be used are: 10, 8, 6, 4, 2, 0, -2, -4, -6, -8, -10, -12, -14, -16, and -18.
Now, the first term is positive and the next term is subtracted. So, the required expression becomes,
10 - 8 + 6 - 4 + 2 - 0 + (-2) - (-4) + (-6) - (-8) + (-10) - (-12) + (-14) - (-16) + (-18)
= 10 - 8 + 6 - 4 + 2 - 0 - 2 + 4 - 6 + 8 - 10 + 12 - 14 + 16 - 18
= 58 - 62
= -4
Hence the correct answer choice is D.
The answer is: D
|
D
|
mathematics
|
The parameter of a square is equal to the perimeter of a rectangle of length 16 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)
|
[
"23.99 cm",
"18.98 cm",
"16.98 cm",
"17.87 cm",
"23.57 cm"
] |
Let the side of the square be a cm.
Parameter of the rectangle = 2(16 + 14) = 60 cm Parameter of the square = 60 cm
i.e. 4a = 60
A = 15
Diameter of the semicircle = 15 cm
Circimference of the semicircle
= 1/2(∏)(15)
= 1/2(22/7)(15) = 330/14 = 23.57 cm to two decimal places
Answer: E
The answer is: E
|
E
|
mathematics
|
The 100-milliliter solution of sugar and water is 15% sugar. How much water (in milliliters) must be added to make a solution that is 8% sugar?
|
[
"72.5",
"77.5",
"82.5",
"87.5",
"92.5"
] |
In the original solution the amount of sugar is 0.15*100=15 ml.
Let the volume of the new solution be V.
0.08V=15 ml.
V=187.5 ml.
The amount of water we need to add is 187.5 - 100 = 87.5 ml.
The answer is D.
The answer is: D
|
D
|
mathematics
|
A tourist purchased a total of $4,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
|
[
"$1,430",
"$2,310",
"$3,290",
"$4,270",
"$5,150"
] |
Let the number of $10 checks cashed beT
Let the number of $50 checks cashed beF
7 checks cashed;
T+F=7
Now; T can be F+1 OR T can be F-1
Let's check both conditions;
T=F+1
T+F=7
F+1+F=7
2F=6
F=3
T=4
Value cashed = 3*50+4*10=150+40=$190
Let's check the other condition as well;
T=F-1
T+F=7
F-1+F=7
2F=8
F=4
T=3
Value cashed = 4*50+3*10=200+30=$230
The more money he cashes, the less loss he incurs. Thus, we must consider the latter case.
Value cashed = $230
Value lost = 4500-230 = $4270
Ans:D
The answer is: D
|
D
|
mathematics
|
Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 18 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
|
[
"288",
"468",
"877",
"278",
"178"
] |
1h ----- 5
? ------ 60
12 h
RS = 18 + 21 = 39
T = 12
D = 39 * 12 = 468
Answer: B
The answer is: B
|
B
|
mathematics
|
Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 50 years. What is Deepak present age
|
[
"14",
"15",
"33",
"22",
"23"
] |
Explanation:
Present age is 4x and 3x,
=> 4x + 6 = 50 => x = 11
So Deepak age is = 3(11) = 33
Answer: Option C
The answer is: C
|
C
|
mathematics
|
Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together?
|
[
"5 min",
"5.5 min",
"5.2 min",
"6.2 min",
"None"
] |
LCM = 300/60 = 5 min
ANSWER:A
The answer is: A
|
A
|
mathematics
|
Find the least number with which 16200 should be multiplied, to make it a perfect cube.
|
[
"36",
"48",
"45",
"360",
"55"
] |
16200 = 23 * 34 * 52
A perfect cube has a property of having the indices of all its prime factors divisible by 3.
Required number = 32 * 5 = 45.
ANSWER:C
The answer is: C
|
C
|
mathematics
|
A man is 26 years older than his son. In two years, his age will be twice the age of his son. The
present age of his son is
|
[
"20 years",
"21 years",
"22 years",
"24 years",
"26 years"
] |
Explanation:
Let the son's present age be x years. Then, man's present age = (x + 26) years
=> (x + 26) + 2 = 2(x + 2)
=> x + 28 = 2x + 4
So, x = 24
Answer: Option D
The answer is: D
|
D
|
mathematics
|
Mohit sold an article for Rs. 18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
|
[
"15000",
"15002",
"26879",
"26992",
"12681"
] |
Let the CP be Rs. x.
Had he offered 10% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x
= Rs. 1.08x = 18000 - 10/100(18000)
= 18000 - 1800 = Rs. 16200
=> 1.08x = 16200
=> x = 15000
Answer: A
The answer is: A
|
A
|
mathematics
|
john bought a computer for $2,000 and then paid a 5 percent sales tax, and Henry bought a computer for $1,800 and then paid a 12 percent sales tax. The total amount that Henry paid, including sales tax, was what percent less than the total amount that john paid, including sales tax?
|
[
"3%",
"4%",
"7%",
"D.10%",
"12%"
] |
For john
Cost of Computer = $2000
Sales tax = (5/100)*2000 = $100
Total Cost of Computer = 2000 + 100 = 2100
For Henry
Cost of Computer = $1800
Sales tax = (12/100)*1800 = $216
Total Cost of Computer = 1800 + 216 = 2016
% that Henry paid less than john = (2100 - 2016)*100/2100 =4%
Answer: Option B
The answer is: B
|
B
|
mathematics
|
Find the number of divisors of 1080 excluding the divisors which are perfect squares.
|
[
"28",
"29",
"30",
"31",
"32"
] |
1080 = 2^3 *3^3 *5^1
total no. of divisors = (3+1)*(3+1)*(1+1) = 32
only 4 divisors 1, 2^2=4 , 3^2=9 & 2^2*3^2=36 are perfect squares
so,number of divisors excluding perfect squares divisors = 32-4 = 28
ANSWER:A
The answer is: A
|
A
|
mathematics
|
Of the 600 employees of Company X, 70 percent have been with the company for at least ten years. If y of theselong-termmembers were to retire and no other employee changes were to occur, what value of y would reduce the percent oflong-termemployees in the company to 30 percent ?
|
[
"200",
"160",
"112",
"257",
"56"
] |
Original (Long-Term is 70%)
Total = 600
Long-Term = .7(600) =420
New (Long-Term is 30%)
New Total = 800 - y
New Long-Term = 420 - y
420 - y = .3 (800 - y)
y = 257
Answer: D
The answer is: D
|
D
|
mathematics
|
A train speeds past a pole in 15 sec and a platform 150 m long in 25 sec, its length is?
|
[
"238",
"150",
"988",
"177",
"225"
] |
Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 150)/25 = x/15 => x = 225 m.
Answer: E
The answer is: E
|
E
|
mathematics
|
If p and e are positive integers such that p > e > 1, what is the remainder when 92p × 5p+e + 11e × 6pe is divided by 10?
|
[
"A.0",
"B.1",
"C.3",
"D.4",
"E.5"
] |
92p × 5p+e + 11e × 6pe--1=B
The answer is: B
|
B
|
mathematics
|
Three consecutive even numbers are such that thrice the first number exceeds double the third number by five. What is the third number?
|
[
"13",
"15",
"17",
"19",
"21"
] |
Let the three numbers be x, x+2, and x+4.
3x = 2(x+4) + 5
x = 13 and then the third number is x+4 = 17.
The answer is C.
The answer is: C
|
C
|
mathematics
|
A and B can do a work in 10 days and 15 days respectively. A starts the work and B joins him after 5 days. In how many days can they complete the remaining work?
|
[
"6 days",
"2 days",
"8 days",
"4 days",
"3 days"
] |
Work done by A in 5 days = 5/10 = 1/2
Remaining work = 1/2
Work done by both A and B in one day = 1/10 + 1/15 = 5/30 = 1/6
Remaining work = 1/2 * 6/1 = 3 days.
Answer: E
The answer is: E
|
E
|
mathematics
|
How many seconds will a 400 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
|
[
"11 sec",
"24 sec",
"77 sec",
"14 sec",
"12"
] |
Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 400 * 3/50
= 24 sec.
Answer: B
The answer is: B
|
B
|
mathematics
|
A tradesman by means of his false balance defrauds to the extent of 20%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
|
[
"46%",
"48%",
"44%",
"49%",
"42%"
] |
g% = 20 + 20 + (20*20)/100
= 44%
Answer: C
The answer is: C
|
C
|
mathematics
|
A cycle is bought for Rs.900 and sold for Rs.1440, find the gain percent?
|
[
"39%",
"20%",
"23%",
"74%",
"60%"
] |
900 ---- 540
100 ---- ? =>
60%
Answer:E
The answer is: E
|
E
|
mathematics
|
36 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work?
|
[
"18",
"24",
"22",
"20",
"19"
] |
Let the required number of days be x.
Less men,More days=27;36::18:x
27x=36*18
x=(36*18)/27
x=4*6
x=24 days.
Answer:B
The answer is: B
|
B
|
mathematics
|
A man misses a bus by 40 minutes if he travels at 30 kmph. If he travels at 40 kmph, then also he misses the bus by 10 minutes. What is the minimum speed required to catch the bus on time?
|
[
"17 kmph",
"45 kmph",
"17 kmph",
"19 kmph",
"13 kmph"
] |
Let the distance to be travelled to catch the bus be x km
x/30 - x/40 = 30/60 => (4x - 3x)/120 = 1/2 => x = 60 km
By traavelling 30 kmph time taken = 60/30 = 2 hours
By taking 2 hours, he is late by 40 min. So, he has to cover 60 km in at most speed = 60/(4/3)
= 45 kmph.
Answer: B
The answer is: B
|
B
|
mathematics
|
Compound X contains elements A and B at an approximate ratio, by weight, of 2:10. Approximately how many grams of element B are there in 222 grams of compound X?
|
[
"54",
"185",
"250",
"270",
"322"
] |
total number of fractions =2+10=12
element B constitutes =10 out of 12 parts of X
So in 222 gms of X have 222*10/12=185 gms of B
and 222-185=37 gms of A.
cross check:- A/B = 37/185 =2/10 (as given)
Ans B
The answer is: B
|
B
|
mathematics
|
2+2+2²+2³ ... +2^6
|
[
"2^9",
"2^10",
"2^16",
"2^35",
"2^7"
] |
2+2=2^2
2^2+2^2=(2^2)*(1+1)=2^3
2^3+2^3=(2^3)*(1+1)=2^4
Answer E
The answer is: E
|
E
|
mathematics
|
An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases.
|
[
"4:3",
"8 : 7",
"4 : 1",
"6 : 5",
"None of these"
] |
Explanation:
Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.
Let the dimensions of the carpet in the second case be 7y, 3y units respectively.
From the data,.
2(3x + 2x) = 2(7y + 3y)
=> 5x = 10y
=> x = 2y
Required ratio of the areas of the carpet in both the cases
= 3x * 2x : 7y : 3y
= 6x2 : 21y2
= 6 * (2y)2 : 21y2
= 6 * 4y2 : 21y2
= 8 : 7
ANSWER IS B
The answer is: B
|
B
|
mathematics
|
If the cost price of 60 articles is equal to the selling price of 50 articles, then what is the percent profit?
|
[
"10%",
"15%",
"20%",
"25%",
"30%"
] |
Let x be the cost price of one article.
Let y be the selling price of one article.
50y = 60x
y = 1.2x
The answer is C.
The answer is: C
|
C
|
mathematics
|
A train 400 m long is running at a speed of 54 km/hr. If it crosses a tunnel in 2 minutes. Then what is the length of tunnel?
|
[
"1200 m",
"1400 m",
"1600 m",
"1800 m",
"2200 m"
] |
Speed of train in m/sec = (speed of train in km/hr) x 5/18
∴ speed of train in m/sec = 54 x 5/18 = 15 m/sec
Time taken to cross the tunnel = 2 minutes = 120 sec
Therefore, Total length covered by train in crossing the tunnel = Speed of train x Time taken to cross the tunnel
= 15 m/sec x 120 sec = 1800 m
Total length covered by train in crossing the tunnel = Length of train + Length of tunnel
Given, Length of train =400m and
Calculated above, Length covered by train in crossing the tunnel = 1800 m
Therefore, Length of tunnel = 1800m- 400m = 1400m
CORRECT ANSWER : Option: B
The answer is: B
|
B
|
mathematics
|
How many liters of 20% alcohol solution should be added to 40 liters of a 50% alcohol solution to make a 30% solution?
|
[
"60 liters",
"70 liters",
"80 liters",
"90 liters",
"50 liters"
] |
Let x be the quantity of the 20% alcohol solution to be added to the 40 liters of a 50% alcohol. Let y be the quantity of the final 30% solution. Hence
x + 40 = y
We shall now express mathematically that the quantity of alcohol in x liters plus the quantity of alcohol in the 40 liters is equal to the quantity of alcohol in y liters. But remember the alcohol is measured in percentage term.
20% x + 50% * 40 = 30% y
Substitute y by x + 40 in the last equation to obtain.
20% x + 50% * 40 = 30% (x + 40)
Change percentages into fractions.
20 x / 100 + 50 * 40 / 100= 30 x / 100 + 30 * 40 / 100
Multiply all terms by 100 to simplify.
20 x + 50 * 40 = 30 x + 30 * 40
Solve for x.
x = 80 liters
80 liters of 20% alcohol is be added to 40 liters of a 50% alcohol solution to make a 30% solution
Answer C
The answer is: C
|
C
|
mathematics
|
If 5% more is gained by selling an article for Rs. 350 than by selling it for Rs. 340, the cost of the article is?
|
[
"127",
"688",
"200",
"121",
"123"
] |
Let C.P. be Rs. x.
Then, 5% of x = 350 - 340 = 10
x/20 = 10 => x = 200
Answer: C
The answer is: C
|
C
|
mathematics
|
Platinum is 19 times as heavy as bronze and silver is 9 times as heavy as bronze. In what ratio these two metals be mixed so that the alloy is 15 times as heavy as bronze is
|
[
"2:1",
"3:2",
"1:2",
"2:3",
"3:4"
] |
Let the proportion of weight of platinum in the mixture = x
then the proportion of weight of silver in the mixture = 1 - x
According to the question
19 X x + 9 (1 - x) = 15 X 1
19x + 9 - 9x = 15
10x = 15 - 9 = 6
x = 6/10 = 3/5
Therefore the proportion of weight of platinum in the mixture = x = 3/5
and the proportion of weight of silver in the mixture = 1 - x = 1 - 3/5 = 2/5
The required ratio of platinum : silver = 3/5 : 2/5
= 3 : 2
ANSWER:B
The answer is: B
|
B
|
mathematics
|
A number when divided by 899 gives a remainder 63. If the same number is divided by 29, the remainder will be
|
[
"11",
"13",
"15",
"Data inadequate",
"NOne"
] |
Sol.
Number = (31 x Q) + 29.
Given data is inadequate.
Answer D
The answer is: D
|
D
|
mathematics
|
My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age of my father when my brother was born?
|
[
"25",
"27",
"31",
"33",
"32"
] |
Father's age was 28 years when my sister was born.
My sister's age was 4 years when my brother was born.
Therefore, father's age was 28+4=32 years when my brother was born.
Answer is E.
The answer is: E
|
E
|
mathematics
|
Mangala completes a piece of work in 10 days, Raju completes the same work in 50 days. If both of them work together, then the number of days required to complete the work is?
|
[
"8 days",
"10 days",
"12 days",
"50/6 days",
"16 days"
] |
If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 × 50/60 = 50/6 days
D)
The answer is: D
|
D
|
mathematics
|
What is the next number in the sequence : 13,17,25,32,37,47,58,71__?
|
[
"78",
"79",
"71",
"76",
"73"
] |
next no. = previous + (sum of digits)
13 + (1+3) = 17
17 + (1+7) = 25
25 + (2+5) = 32
32 + (3+2) = 37
37 + (3+7) = 47
47 + (4+7) = 58
58 +(5+8) = 71
71 + (7+1) = 79
ANSWER:B
The answer is: B
|
B
|
mathematics
|
A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 98.01, the number of the member is the group is:
|
[
"57",
"67",
"77",
"99",
"97"
] |
Money collected = (98.01 x 100) paise = 9801 paise.
Number of members =Square root of 9801 = 99.
Answer: Option D
The answer is: D
|
D
|
mathematics
|
Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is:
|
[
"16 hours",
"18 hours",
"20 hours",
"24 hours",
"26 hours"
] |
speed of upstream=9-1.5=7.5kmph
speed of down stream=9+1.5=10.5kmph
total time=(105/7.5)+(105/10.5)=24hrs
ANSWER:D
The answer is: D
|
D
|
mathematics
|
The length of a rectangular plot is 10mtr more than its width. The cost of fencing the plot along its perimeter at the rate of Rs. 6.5mtr is Rs.1950. The perimeter of the plot is?
|
[
"126",
"156",
"190",
"300",
"260"
] |
Sol. Let width = x, Length = (10+x)
Perimeter = 2(x+(10+x))
= 2(2x=10)
& 2(2x+10)*6.5 = 1950
X = 70
Required perimeter = 2(70+80) = 300
D
The answer is: D
|
D
|
mathematics
|
A and B enter into partnership with capital as 7:9. At the end of 8 months, A withdraws. If they receive the profits in the ratio of 8:9 find how long B's capital was used?
|
[
"6",
"5",
"9",
"7",
"2"
] |
7 * 8 : 9 * x = 8:9
=> x= 7
Answer:D
The answer is: D
|
D
|
mathematics
|
How many prime numbers are between 15/7 and 131/6?
|
[
"3",
"4",
"5",
"6",
"7"
] |
15/7= 3-
131/6= 22-
Prime numbers between 3 and 22 are 5, 7, 11, 13, 17, and 19
- sign signifies that the number is marginally less .
Answer D
The answer is: D
|
D
|
mathematics
|
What is the greatest prime factor of 1+2+3+。。。+52?
|
[
"53",
"29",
"31",
"37",
"41"
] |
find the sum from direct formula = n(n+1)/2 = 52(52+1)/2 = 26*53...
53 is a PRIME number, so ans is 53..
A is the answer
The answer is: A
|
A
|
mathematics
|
If f(x) = ax^2 – 6x + ax + 1, then f(b) – f(-b) will equal:
|
[
"0",
"-12b+2ab",
"2ab^4 – 8b^2 – 6",
"-2ab^4 + 8b^2 + 6",
"2ab^4 – 8b^2 + 2ab – 6"
] |
f(x)=ax^2 – 6x + ax + 1
f(b) = ab^2 – 6b + ab + 1
f(-b) = ab^2 + 6b - ab + 1
f(b) - f(-b) = ab^2 – 6b + ab + 1 - ab^2 - 6b + ab - 1
=-12b+2ab
Answer B
The answer is: B
|
B
|
mathematics
|
Company T produces two kinds of stereos: basic and deluxe. Of the stereos produced by Company T last month, 2/3 were basic and the rest were deluxe. If it takes 7/5 as many hours to produce a deluxe stereo as it does to produce a basic stereo, then the number of hours it took to produce the deluxe stereos last month was what fraction of the total number of hours it took to produce all the stereos?
|
[
"8/22",
"4/22",
"6/22",
"7/22",
"5/22"
] |
# of basic stereos was 3/4 of total and # of deluxe stereos was 1/4 of total, let's assume total=16, then Basic=12 and Deluxe=4.
Now, if time needed to produce one Deluxe stereo is 1 unit than time needed to produce one Basic stereo would be 7/5 units. Total time for Basic would be 12*1=12 and total time for Deluxe would be 4*7/5=28/5 --> total time for both of them would be 12+28/5=88/5 --> deluxe/total=28/5 / 88/5= 28/88 =7/22
D
The answer is: D
|
D
|
mathematics
|
A train 700m long takes 10 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train?
|
[
"A)175kmph",
"B)257kmph",
"C)162kmph",
"D)145kmph",
"E)100kmph"
] |
Let the speed of the train be x kmph
Speed of the train relative to man = x+5 = (x+5)*5/18 m/sec
700/[(x+5)*5/18] = 10
10(x+5) = 140*18
x = 257kmph
Answer is B
The answer is: B
|
B
|
mathematics
|
What is the average of 1/2, 3/5 and 3/10?
|
[
"7/15",
"3/10",
"2/5",
"1/2",
"6/5"
] |
Sum of 1/2,3/5,3/10 =14/10
Average = 14/10*1/3 =7/15
Answer A 7/15
The answer is: A
|
A
|
mathematics
|
If an article is sold at 19% profit instead of 12% profit, then the profit would be Rs. 105 more. What is the cost price?
|
[
"Rs.1520",
"Rs.1570",
"Rs.1500",
"Rs.1550",
"Rs.1700"
] |
Let the cost price of an article be Rs. x.
(19% of x) - (12% of x) = 105
19x/100 - 12x/100 = 105 => 7x = 105 * 100
=> x = 1500
Cost price = Rs.1500
Answer:C
The answer is: C
|
C
|
mathematics
|
What is the next number of the following sequence
1,3,4,1,9...
|
[
"14",
"15",
"16",
"17",
"18"
] |
(1, 3 ,4) (1, 9, x)
square of 1st group gives 2nd group
1^2 = 1
3^2 = 9
4^2 = 16
ANSWER:C
The answer is: C
|
C
|
mathematics
|
A watch which gains uniformly is 2 minutes low at noon on monday and is 4 min.48 sec fast at 2 p.m on the following monday. when was it correct ?
|
[
"2.10 p.m on wednesday.",
"2.20 p.m on wednesday.",
"2.30 p.m on wednesday.",
"2.40 p.m on wednesday.",
"2.00 p.m on wednesday."
] |
Time from 12 p.m on monday to 2 p.m on the following monday = 7 days 2 hours = 170 hours
\therefore The watch gains \inline \left ( 2+4\frac{4}{5} \right ) min. or \inline \frac{34}{5} min. in 170 hrs.
Now, \inline \frac{34}{5} min. are gained in 170 hrs.
\inline \therefore 2 min are gained in \inline \left ( 170\times \frac{5}{34}\times 2 \right ) hrs = 50 hrs
\inline \therefore Watch is correct 2 days 2 hrs. after 12 p.m on monday i.e it will be correct at 2 p.m on wednesday.
Answer E
The answer is: E
|
E
|
mathematics
|
To asphalt 1km road, 30 men spent 12 days working 8 hours per day. How many days, 20 men will spend to asphalt a road of 2km working 14 hours a day?
|
[
"24",
"23",
"24",
"20.57",
"22"
] |
Man-hours required to asphalt 1 km road=30*12*8=2880
Man-hours required to asphalt 2 km road=2880*2=5760
Man-hours available per day=20*14=280
Therefore number of days=5760/280=20.57 days
Ans=D
The answer is: D
|
D
|
mathematics
|
Murugan, Prasanna and Arun invested Rs.8000, Rs.4000 and Rs.8000 respectively in a business. Arun left after six months .If after eight months, there was a gain of Rs.4005, then what will be the share of Prasanna?
|
[
"Rs.890",
"Rs.1335",
"Rs.1602",
"Rs. 1780",
"None"
] |
Solution
Murugan : Prasanna : Arun =(8000×6):(4000×8):(8000×8)
= 48 : 32 : 64
= 3 : 2 : 4.
Kamal's share = Rs.4005×2/9)
= Rs.890.
Answer A
The answer is: A
|
A
|
mathematics
|
Find the middle one when The sum of three consecutive even numbers is 36?
|
[
"10",
"12",
"14",
"18",
"22"
] |
3 consecutive numbers can be a - 1, a, a + 1
So sum of numbers = 3a = 36.
Hence a = 12.
B
The answer is: B
|
B
|
mathematics
|
The sequence of numbers a1, a2, a3, ..., an is defined by an = 1/n - 1/(n+2) for each integer n >= 1. What is the sum of the first 30 terms of this sequence?
|
[
"1/30-1/32",
"1 - (1/30 + 1/30)",
"(1+1/2) – (1/31 +1/ 32)",
"1 - 1/32",
"1/32-1/30"
] |
The answer would most certainly be[C]. But the question needs a slight modification.n>=1, since the answer does consider a1 under the sum.
The sequence is :
a1 = 1-1/3
a2 = 1/2 - 1/4
a3 = 1/3 - 1/5....
We can observe that the third term in the sequence cancels the negative term in the first. A similar approach can be seen on all the terms and we would be left with 1 + 1/2 from a1 and a2 along with -1/32 and -1/31 from a30 and a29 term which could not be cancelled.
Hence the sum = (1+1/2) – (1/31 +1/ 32)
Answer : C
The answer is: C
|
C
|
mathematics
|
The area of a square field is 1225 km2. How long will it take for a horse to run around at the speed of 20 km/h ?
|
[
"7 h",
"10 h",
"8 h",
"6 h",
"None of these"
] |
Explanation Area of field = 1225 km2. Then, each side of field = √1225=35km Distance covered by the horse = Perimeter of square field = 35× 4 = 140 km ∴ Time taken by horse = distances/peed=140/20=7h Answer A
The answer is: A
|
A
|
mathematics
|
If a number between 1 and 60 (inclusively) is chosen randomly, what are the odds that it is divisible by 5 or 8?
|
[
"1/4",
"7/30",
"17/60",
"3/10",
"4/15"
] |
P(5ᴜ8) = P(5) + P(8) - P(5∩8), where S denotes divisible by 5 and 8 denotes divisible by 8.
P(5ᴜ8) = 12/60 + 7/60 - 1/60
= 3/10
Answer: D
The answer is: D
|
D
|
mathematics
|
Find the natural number nearest to 9217 which completely divides 88 without giving any remainder.
|
[
"9240",
"9064",
"9184",
"9152",
"9169"
] |
Explanation:
These types of questions are to be solved by trial and error. Make sure minimum amount of time is wasted and your calculations are quick. Devote maximum 1 minute to such questions.
Here in this case clearly 9240 is the closest number which divides 88.
ANSWER: A
The answer is: A
|
A
|
mathematics
|
If Juan takes 12 seconds to run y yards, how many seconds will it take him to run x yards at the same rate?
|
[
"12x/y",
"12y/x",
"x/(12y)",
"13/(xy)",
"xy/12"
] |
This problem is testing us on the Rate x Time = Distance relationship. This relationship also tells us that Rate = Distance/Time and Time = Distance/Rate.
Ultimately, we are looking for how many seconds it will take Juan to run x yards. Thus, the equation we’ll use is: Time = Distance/Rate. We know the distance is x yards, and we need to find Juan’s rate.
We can find Juan’s rate as follows: Rate = Distance/Time = y yards/12 seconds
Using that rate, we need to determine how long it takes him to run x yards at the same rate. So we have:
Time = Distance/Rate
Time = x yards/(y yards/12 seconds)
Time = (x yards) x (12 seconds/y yards)
Time = 12x/y seconds
Answer A.
The answer is: A
|
A
|
mathematics
|
2: 5 = 4/3: x. The value of x is?
|
[
"10/3",
"2",
"3",
"4",
"5"
] |
x * 2 = 5 * 4/3
x *2= 20/3
x=10/3
ANSWER:A
The answer is: A
|
A
|
mathematics
|
In a system of coding ACCESS is coded CEEGUU, POINTFF as HHKPQRV, LIMERICK as EGKKMNOT and LAMINATE as CCGKNOPV
Waht is likely to be the word of which the code is COTUV?
|
[
"TRAPS",
"PARTS",
"SMART",
"SMARR",
"None of the above"
] |
right answer is EQVWX
SO NONE
ANSWER:E
The answer is: E
|
E
|
mathematics
|
What is the remainder when 1024*1047*1050*1053 is divided by 33?
|
[
"3",
"27",
"30",
"21",
"18"
] |
take the remainder from each of 1024/33, 1047/33 and so on..
1024/33 gives remainder = 1
1047/33 gives remainder = 24
1050/33 gives remainder = 27
1053/33 gives remainder = 30
the net remainder is the product of above individual remainders. i.e =1*24*27*30
break them into pairs 1*24/33 gives remainder 24
and 27*30/33 gives remainder 18
so 24*18/33 gives remainder 3.
A
The answer is: A
|
A
|
mathematics
|
The water level in a rectangular swimming pool measuring 20 feet by 25 feet is to be lowered by 6 inches. How many gallons of water must be removed? (1 cu ft = 7.5 gallons)
|
[
"100",
"250",
"1875",
"1200",
"5625"
] |
6 inches = 1/2 feet (there are 12 inches in a foot.), so 20*25*1/2=250 feet^3 of water must be removed, which equals to 250*7.5=1875 gallons.
Answer: C.
The answer is: C
|
C
|
mathematics
|
Salesperson A's compensation for any week is $360 plus 6 percent of the portion of A's total sales above $2,000 for that week. Salesperson B's compensation for any week is 8 percent of A's total sales for that week. For what amount of total weekly sales would both salepeople earn the same compensation?
|
[
"$12,000",
"$18,000",
"$15,000",
"$ 4,500",
"$4,000"
] |
sometime, setting up an equation is an easy way to go with:
360 + 0.06 (x - 2000) = 0.08 x
x = 12000
Ans : A
The answer is: A
|
A
|
mathematics
|
Find the next number in the Sequence
5, 14, 41, 86, ?
|
[
"146",
"145",
"149",
"143",
"148"
] |
+9 =>14
+27 =>41
+45 =>86
+63 =>149
Answer is C
The answer is: C
|
C
|
mathematics
|
Sawyer and Beth each drove from Smallville to Crown City by different routes. Sawyer drove an an average speed of 40 miles per hour and completed the trip in 30 minutes. Beth's route was 5 miles longer, and it took her 20 minutes more than Sawyer to complete the trip. How many miles per hour was Beth's average speed on this trip?
|
[
"24",
"30",
"48",
"54",
"75"
] |
Speed = Distance/Time
Distance for Sawyer = Speed * Time = 40 * 1/2 = 20 miles
Distance for Beth = Distance for Sawyer +5 = 20+5 = 25 miles
Time taken by Beth = Time taken by Sawyer + (1/3 hour) = 1/2+1/3 = 5/6
Speed of Beth = D/T = 25/(5/6) = 25*6/5 = 30 miles per hour
Hence, B is the answer.
The answer is: B
|
B
|
mathematics
|
In the manufacture of a certain product, 5 percent of the units produced are defective and 4 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale?
|
[
"0.125%",
"0.2%",
"0.8%",
"1.25%",
"2.0%"
] |
Percent of defective produced = 5%
Percent of the defective units that are shipped for sale = 4%
Percent of units produced are defective units that are shipped for sale = (4/100)*(5/100)*100%
= (20/10000)*100%
= (20/100)%
= .2 %
Answer B
The answer is: B
|
B
|
mathematics
|
How many leading zeros (zeros after the decimal point but before the first nonzero digit of a number) are in 1/4!?
|
[
"1",
"3",
"5",
"6",
"9"
] |
4! = 24
1/100 < 1/24 < 1/10
0.001 < 1/24 < 0.01
So 1/24 has 1 leading zeros
Answer: A
The answer is: A
|
A
|
mathematics
|
The product of 4 consecutive even numbers is always divisible by:
|
[
"384",
"350",
"400",
"200",
"250"
] |
The product of 4 consecutive numbers is always divisible by 4!.
Since, we have 4 even numbers, we have an additional 2 available with each number.
Now, using both the facts, we can say that the product of 4 consecutive even numbers is always divisible by,
2^4 * 4!
16 * 24 = 384
ANSWER A
The answer is: A
|
A
|
mathematics
|
TOM has 13 ten-dollar bills, 11 five-dollar bills, and 17 one-dollar bills. If TOM needs to pay exactly $128, what is the least number of bills he will need to use?
|
[
"557",
"456",
"16",
"577",
"586585"
] |
128 is the total sum of money.
as we have 13 10 dollar bills so the closest we can get to 128 using the 10 dollar bills is by using 12 * 10 dollar bils
128-120 = 8
so now we need to get 8 from either 5 dollar bills or 1 dollar bills
8 - 5 (use only 1 5 dollar bill) = 3
so we can get 3 from using 3 $1 bills.
Hence 16 ( 12+1+3 )
ANSWER IS C
The answer is: C
|
C
|
mathematics
|
A pipe can fill the tank in 5 hours. Due to leakage at the bottom it is filled in 6 hours. When the tank is full, in how much time will it be empties by the leak?
|
[
"30 hours",
"28 hours",
"27 hours",
"25 hours",
"24 hours"
] |
When there is no leakage, the pipe can fill the cistern in 5 hours.
Therefore, The pipe fills 1/5 th part of the tank in one hour.
When there is a leakage, the pipe can fill the cistern in 6 hours.
In case of leakage, the pipe fills 1/6 th part of the tank in one hour.
So, in 1 hour due to leakage (1/5 – 1/6) th
= (6 – 5)/30 th
= 1/30 th
The part of the tank is emptied.
So, the tank will be emptied by leakage in 30 hours.
answer :A
The answer is: A
|
A
|
mathematics
|
If 20% of certain quantity of work is done by A and the rest 80% by B, the work is completed in 20 days. If 80% of the work is done by A and the remaining 20% by B, then the work is completed in 30 days. How many days are required to complete the work , if A and B work together.
|
[
"11 1/9",
"10 1/9",
"12",
"15",
"Source: TIME material."
] |
Use algebra:
0.2/A + 0.8/B = 20
1 /A + 4/B = 100
0.8/A + 0.2/B = 30
4/A+ 1/B = 150
15/B = 250
B = 3/50 work per day
A = 3/100 work per day
Combined rate = 3/40 + 3/100 = 9/100
Time taken when working together = 100/9 = 11(1/9) days
Answer (A)
The answer is: A
|
A
|
mathematics
|
If a car went the first third of the distance at 80 kmh, the second third at 24 kmh, and the last third at 54kmh, what was the average speed of the car for the entire trip?
|
[
"36 kmh",
"40 kmh",
"41 kmh",
"44 kmh",
"50 kmh"
] |
Assume D/3 = 2160 (this number is convenient because it is divisible by 80, 24 and 54)
So:
2160 = 80*T1 = 27 hrs
2160 = 24*T2 = 90 hrs
2160 = 54*T3 = 40 hrs
T = T1 + T2 + T3 = 157 hrs
D = RT
(240*3) = R*157
R = 41.27
ANSWER: C
The answer is: C
|
C
|
mathematics
|
A sum of money becomes triple itself in 5 years at simple interest. How many years will it become six times at the same rate?
|
[
"12 1/2 years",
"12 1/8 years",
"17 1/2 years",
"12 3/2 years",
"15 1/2 years"
] |
100 ---- 200 ---- 5
200 ---- 5
100 ---- 2 1/2
------------------
600 ---- 12 1/2 years
Answer:A
The answer is: A
|
A
|
mathematics
|
A certain sum becomes Rs. 20720 in four years and 24080 in six years at simple interest. Find sum and rate of interest?
|
[
"11",
"12",
"44",
"66",
"81"
] |
:
Let the interest for one year be x.
As amount = Principal + Interest, we have
P + 4x = 20720 --- (1) ; P + 6x = 24080 --- (2)
Solving the equations (1) and (2), we can get
P = Rs. 14000 and x = Rs. 1680
Interest for one year on Rs. 14000 is Rs. 1680
So, R = (100 * 1680)/(14000 * 1) = 12% p.a.Answer: B
The answer is: B
|
B
|
mathematics
|
The population of a bacteria culture doubles every 4 minutes. Approximately how many minutes will it take for the population to grow from 1,000 to 500,000 bacteria
|
[
"10",
"12",
"14",
"36",
"18"
] |
This one's easy.
1000 * 2^t = 500,000
2^t = 500
Now gauging, since 2^8 = 256, then 2^9 = 512
So t = 9
But be careful, 't' is in time intervals of 4 minutes
So answer is 9*4 = 36 minutes
Answer (D)
The answer is: D
|
D
|
mathematics
|
A train 200 m long passed a pole in 20 sec. How long will it take to pass a platform 610 m long?
|
[
"46",
"54",
"92",
"76",
"81"
] |
Speed = 200/20 = 10 m/sec.
Required time = (200 + 610)/10 = 81 sec.
Answer: E
The answer is: E
|
E
|
mathematics
|
A vessel of capacity 90 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution?
|
[
"15.6 litres",
"72.9 litres.",
"22.8 litres",
"16 litres",
"92.3litres"
] |
Explanation:
Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T - y)/T]n * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 - 9)/90]2 (90) = 72.9 litres.
Answer:B
The answer is: B
|
B
|
mathematics
|
A train running at 25 km/hr takes 30 seconds to pass a platform. Next, it takes 12 seconds to pass a man walking at 5 km/hr in the same direction. Find the length of the train and that of the platform.
|
[
"a) 200/3m175/3m",
"b) 60m130m",
"c) 50m45m",
"d) 100/3 m200/3",
"e) none of these"
] |
Hi Math gurus correct me if I am wrong. I wondered i reached the answer mentioned here i.e 100m and 25m
lets solve it
To find out length of train the train, which is must cover the static point of the man as well as the distance covered the man during 12 sec.
The man covered the distance during 12sec is 5*5/30*12=10m so the train covered a distance in 12 sec= 25*5/30*12=50
so the length of the train(Lt) is 10+50=60m
Now crossing the platform means length of train+length of platform(Lt+p)= 30*25*5/30=125m Now the length of platform (Lp) is= 125-60=65m
So answer is 60m and 65m Must beBeven though its mentioned 60m and 130m thinking so typo mistake...........
The answer is: B
|
B
|
mathematics
|
Mark and Ann together were allocated n boxes of cookies to sell for a club project. Mark sold 7 boxes less than n and Ann sold 2 boxes less than n. If Mark and Ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n?
|
[
"4",
"5",
"6",
"7",
"8"
] |
if n =8
mark sold 1 box
and Ann sold 6 boxes
total 7 < 8
Answer:E
The answer is: E
|
E
|
mathematics
|
A train 120 m long crosses a platform 120 m long in 6 sec; find the speed of the train?
|
[
"144 kmph",
"58 kmph",
"54 kmph",
"94 kmph",
"59 kmph"
] |
D = 120 + 120 = 240
T = 6
S = 240/6 * 18/5 = 144 kmph
Answer: A
The answer is: A
|
A
|
mathematics
|
A train running at a speed of 36 km/h passes an electric pole in 14 seconds. In how many seconds will the whole train pass a 350-meter long platform?
|
[
"43",
"45",
"47",
"49",
"51"
] |
Let the length of the train be x meters.
When a train crosses an electric pole, the distance covered is its own length x.
speed = 36 km/h = 36000 m / 3600 s = 10 m/s
x = 14 * 10 = 140 m.
The time taken to pass the platform = (140 +350)/ 10 = 49 seconds
The answer is D.
The answer is: D
|
D
|
mathematics
|
A positive integer is divisible by 3 if and only if the sum of its digits is divisible by 3. If the six-digit integer is divisible by 3, and n is of the form 4k2,k21, where k represents a digit that occurs twice, how many values could n have?
|
[
"2",
"3",
"6",
"5",
"4"
] |
4k2k21
Taking sum of the numericals = 4 + 2 + 2 + 1 = 9
We require the values of K such that they are also divisible by 3
402021
432321
462621
492921
Answer = 4 = E
The answer is: E
|
E
|
mathematics
|
What is the cost of leveling the field in the form of parallelogram at the rate of Rs.30/10 sq.metre, whose base & perpendicular distance from the other side being 64m & 74m respectively?
|
[
"s. 6000",
"s. 6300",
"s.4736",
"s. 6480",
"s. 7000"
] |
Area of the parallelogram = Length of the base * Perpendicular height
= 64 * 74 = 4736 m.
Total cost of levelling = Rs. 4736
C
The answer is: C
|
C
|
mathematics
|
If each day a tree loses half its remaining leaves, what fraction of its leaves will it have lost after 3 days ?
|
[
"X-1/8",
"X/2",
"X/4",
"X/32",
"X/16"
] |
LET NO OF LEAVES IX X ..IST DAY X/2 ..2ND DAY X/4 ..3RD DAY X/8 , FOURTH DAY X/16 , 5TH DAY X/32 , 6TH DAY X/64 SO ON SO FOURTH.
FINALLY ON LEAVE WILL BE LEFT ..SO ON 3RD DAY LEAVE LOST IS X-1/8 ANSWER A
The answer is: A
|
A
|
mathematics
|
A circular rim 35 inches in diameter rotates the same number of inches per second as a circular rim 42 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?
|
[
"48pi/x",
"50x",
"48x",
"24x",
"x/75"
] |
C = (pi)d
C(small): (pi)*35
C(large): (pi)*42
Lets say the time horizon is 60 seconds, so during that time the smaller rim covers a distance of (pi)*35*60 = (pi)*(2100) inches
(pi)*(2100) = (pi)*(42)(x)
pi*(50) = pi*(x)
50=x
Answer: B.
The answer is: B
|
B
|
mathematics
|
By selling 150 mangoes, a fruit-seller gains the selling price of 10 mangoes. Find the gain percent?
|
[
"7%",
"25%",
"21%",
"85%",
"24%"
] |
SP = CP + g
150 SP = 150 CP + 10 SP
140 SP = 150 CP
140 --- 10 CP
100 --- ? => 7%
Answer:A
The answer is: A
|
A
|
mathematics
|
Set Q consists of the following five numbers: Q = {5, 8, 13, 21, 32}. Which of the following sets has the same standard deviation as Set Q?
I. {35, 38, 43, 51, 64}
II. {10, 16, 26, 42, 68}
III. {46, 59, 67, 72, 75}
|
[
"I only",
"III",
"IIII",
"IIIII",
"I, II,III"
] |
(1) Multiplying all the numbers change Standard Deviation
(2) Adding and subtracting all the numbers with the same number keeps the standard deviation same.
If you observe Set I and III are added versions of Set Q .
Set I: 5 has been added to the Set Q
Set III: Subtract each element from 80 and you would find a number there in the Set Q.
Set II: elements are multiplied by 2 and standard deviation changes.
Hence the answer is D.
The answer is: D
|
D
|
mathematics
|
How many boxes do you need if you have to pack 240 pairs ornamental bangles into boxes that each hold 2 dozens of bangles?
|
[
"40",
"35",
"20",
"25",
"30"
] |
C
20
240 pairs of bangles = 480 bangles =40 dozens.
40 ÷ 2 = 20 boxes.
The answer is: C
|
C
|
mathematics
|
What is the area of a square field whose diagonal of length 20 m?
|
[
"287",
"269",
"270",
"200",
"230"
] |
d2/2 = (20 * 20)/2
= 200
Answer:D
The answer is: D
|
D
|
mathematics
|
The product of all the prime numbers less than 12 is closest to which of the following powers of 10 ?
|
[
"10^7",
"10^4",
"10^8",
"10^5",
"10^9"
] |
Product of Prime numbers less than 12 is 2*3*5*7*11
2*5=10 .
10*11*3*7 = 10*10*3*10 (approximately) ~ Product will be >10^3 <10^5 i.e. 10^4
B is the answer
The answer is: B
|
B
|
mathematics
|
x/2y = 2a,then 2x/x-2ay=?
|
[
"4",
"8",
"16",
"2",
"6"
] |
x/2y=2a,
Then x = 4ay,
Now, 2x/x-2ay = (2*4ay)/(4ay-2ay) = 8ay/2ay = 4
ANSWER:A
The answer is: A
|
A
|
mathematics
|
The distance from City A to City B is 150 miles. While driving from City A to City B, Cara drives at a constant speed of 30 miles per hour. Dan leaves City A 90 minutes after Cara. What is the minimum constant speed in miles per hour that Dan must exceed in order to arrive in City B before Cara?
|
[
"42.85",
"44",
"46",
"48",
"50"
] |
The time it takes Cara to drive to City B is 150 / 30 = 5 hours.
Dan needs to take less than 3.5 hours for the trip.
Dan needs to exceed a constant speed of 150 / 3.5 = 42.85 miles per hour.
The answer is A.
The answer is: A
|
A
|
mathematics
|
Harriet planned to complete a certain task on Wednesday, January 1, but because of illness the completion date was postponed 44 days. On which day of the week in February was the task completed?
|
[
"Monday",
"Tuesday",
"Wednesday",
"Thursday",
"Friday"
] |
This type of story problem is essentially just about a repeating pattern and a 'remainder.'
We're told that Harriet planned to complete a certain task on WEDNESDAY, January 1, but because of illness the completion date was postponed 44 DAYS. We're asked on what day of the week the task was actually completed on.
Since the task was supposed to be completed on a Wednesday....
A 1 day postponement would be Thursday
A 2 day postponement would be Friday
A 3 day postponement would be Saturday
A 4 day postponement would be Sunday
A 5 day postponement would be Monday
A 6 day postponement would be Tuesday
A 7 day postponement would be Wednesday
A 8 day postponement would be Thursday
Etc.
So this question is ultimately asking how many 'groups of 7' are there, and how many 'leftover days' are there, when you postpone 44 days.
44/7 = 6 remainder 2
This means that there are 6 full weeks AND 2 extra days after a Wednesday....Thus, the task was completed on a Friday.
E
The answer is: E
|
E
|
mathematics
|
A person starts walking at a speed of 5km/hr through half the distance, rest of the distance he
covers with aspeed 2km/hr. Total time of travel is 9 hours. What is the maximum distance he
can cover?
|
[
"20km",
"40km",
"60km",
"80km",
"90km"
] |
t=d/s, so
9=x/2*1/5+x/2*1/2(because half distance with 5 km/ph, and remaining half with 2km/hr)
9=x(18/40)
x=20km
ANSWER:A
The answer is: A
|
A
|
mathematics
|
A man can do a piece of work in 5 days, but with the help of his son he can do it in 2 days. In what time can the son do it alone ?
|
[
"7 1/2 days",
"6 1/2 days",
"5 1/3 days",
"3 1/3 days",
"None of these"
] |
Explanation:
In this type of question, where we have one person work and together work done. Then we can easily
get the other person work just by subtracting them. As
Son's one day work =
(1/2−1/5)=(5−2)/10=3/10
So son will do whole work in 10/3 = 3 1/3 days
Answer: D
The answer is: D
|
D
|
mathematics
|
Today Mary’s father is four times as old as Mary. Seven years ago, he was 7 times as old. How old is Mary today?
|
[
"11",
"12",
"13",
"14",
"15"
] |
Dad's age = 4M
7*(M-7) = 4M-7
3M = 42
M = 14
The answer is D.
The answer is: D
|
D
|
mathematics
|
The total marks obtained by a student in Mathematics and Physics is 20 and his score in Chemistry is 20 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together.
|
[
"40",
"26",
"20",
"28",
"22"
] |
Let the marks obtained by the student in Mathematics, Physics and Chemistry be M, P and C respectively.
Given , M + C = 20 and C - P = 20 M + C / 2 = [(M + P) + (C - P)] / 2 = (20 + 20) / 2 = 20.Answer:C
The answer is: C
|
C
|
mathematics
|
if (64)^2 - (36)^2 = 10x, then x = ?
|
[
"280",
"210",
"330",
"220",
"200"
] |
a^2−b^2=(a−b)(a+b)
(64)^2 - (36)^2 = (64 - 36)(64 + 36) = 28 × 100
Given that (64)^2 - (36)^2 = 10x
=> 28 × 100 = 10x
=> x = 280
Answer is A
The answer is: A
|
A
|
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