Code Line
stringclasses 57
values | User Explanation
stringclasses 692
values | Line-Explanation in PCEX
stringclasses 131
values | Annotation Score
float64 1
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Scanner scan = new Scanner(System.in); | creates a new Scanner instance which points to the input stream passed as argument. | To read the input value from the user, we need to define a Scanner object. | 4 |
Scanner scan = new Scanner(System.in); | creates a new Scanner instance which points to the input stream passed as argument. | We need to read and process the value that the user enters. | 2 |
Scanner scan = new Scanner(System.in); | In this case the steam is Standard input stream | To read the input value from the user, we need to define a Scanner object. | 2 |
Scanner scan = new Scanner(System.in); | In this case the steam is Standard input stream | We need to read and process the value that the user enters. | 2 |
System.out.println("Enter an integer for seconds: "); | prints the argument ("Enter an integer for second: ") passed to the standard console and a newline | We prompt the user to enter the seconds. | 4 |
int seconds = scan.nextInt(); | scaner object reads in a string of digits (characters) and converts them into an int type, and put them in variable entitled "seconds" | We need to read the seconds that the user enters and store it in a variable. | 4 |
int seconds = scan.nextInt(); | scaner object reads in a string of digits (characters) and converts them into an int type, and put them in variable entitled "seconds" | We read the seconds by calling the nextInt() method because this input is an integer. | 4 |
scan.close(); | closes scan the input that has been opened | We close the scanner as we do not want to process any input from the user in the rest of the program. | 3 |
int minutes = seconds / 60; | creates varible entitled "minutes" which contain calculation of variable "second" divided by 60 | To obtain the minutes in seconds, we divide the seconds by 60 because there are 60 seconds in a minute. | 4 |
int minutes = seconds / 60; | creates varible entitled "minutes" which contain calculation of variable "second" divided by 60 | Note that since both operands of division operator are integer, the fractional part of the result is truncated, if there is any. | 2 |
int remainingSeconds = seconds % 60; | creates varible entitled "remainingSeconds" which contain calculation of variable "second" modulus by 60 | This is because there are 60 seconds in a minute. | 2 |
int remainingSeconds = seconds % 60; | creates varible entitled "remainingSeconds" which contain calculation of variable "second" modulus by 60 | Note that the % operator returns the remainder of the division. | 2 |
int remainingSeconds = seconds % 60; | creates varible entitled "remainingSeconds" which contain calculation of variable "second" modulus by 60 | To obtain the remaining seconds after taking away the minutes, we have to take the remainder of the seconds divided by 60. | 3 |
System.out.println(seconds + " seconds is " + minutes + " minutes and " + remainingSeconds + " seconds."); | prints in the console line the character passed inside the argument | This statement prints to the default standard output stream the minutes and remaining seconds from the input amount of time in seconds. | 2 |
System.out.println(seconds + " seconds is " + minutes + " minutes and " + remainingSeconds + " seconds."); | prints in the console line the character passed inside the argument | The printed text is followed by the end-of-line character at the end. | 1 |
int num = 15; | create variable integer entitled "num" with value 5 | We define variable num to store the number that we want to find its smallest divisor. | 3 |
int num = 15; | create variable integer entitled "num" with value 5 | We could initialize it to any positive integer greater than 1. | 2 |
int num = 15; | create variable integer entitled "num" with value 5 | In this program, we initialize variable num to 15. | 2 |
int divisor = 2; | creates variable integer entitled "division" with initial value 2 | We initialize variable divisor by 2 because we want to find the smallest divisor except 1. | 3 |
int divisor = 2; | creates variable integer entitled "division" with initial value 2 | We define variable divisor to store the smallest divisor of the number. | 2 |
int num = 15; | creates variable integer entitled "num" with initial value 5 | We define variable num to store the number that we want to find its smallest divisor. | 2 |
int num = 15; | creates variable integer entitled "num" with initial value 5 | We could initialize it to any positive integer greater than 1. | 2 |
int num = 15; | creates variable integer entitled "num" with initial value 5 | In this program, we initialize variable num to 15. | 2 |
int divisor = 2; | creates variable integer entitled "divisor" with initial value 2 | We initialize variable divisor by 2 because we want to find the smallest divisor except 1. | 3 |
int divisor = 2; | creates variable integer entitled "divisor" with initial value 2 | We define variable divisor to store the smallest divisor of the number. | 3 |
while (num % divisor != 0) { | creates looping "while" with condition while variable num modulus by the value of divisor is not null then execute the below code | Since we don't know ahead of time how many times the loop will be repeated, we need to use a while loop. | 3 |
while (num % divisor != 0) { | creates looping "while" with condition while variable num modulus by the value of divisor is not null then execute the below code | We need to increment the divisor repeatedly as long as the divisor is not a factor of the number. | 1 |
while (num % divisor != 0) { | creates looping "while" with condition while variable num modulus by the value of divisor is not null then execute the below code | Therefore, we need to use a loop structure. | 4 |
while (num % divisor != 0) { | creates looping "while" with condition while variable num modulus by the value of divisor is not null then execute the below code | The condition in the while loop tests whether the body of the loop should be repeated, so it should test whether the divisor is not a factor of the number. | 2 |
while (num % divisor != 0) { | creates looping "while" with condition while variable num modulus by the value of divisor is not null then execute the below code | We could check whether the divisor is not a factor of the number by computing the remainder of the division of the number by the divisor. | 2 |
divisor += 1; | add divisor variable by + 1 | When the divisor is not a factor of the number, we increment the variable divisor by 1. | 3 |
System.out.println("The smallest divisor of " + num + " is " + divisor); | prints the character to the console with the argument inside it. | This statement prints to the default standard output stream the smallest divisor of the number. | 2 |
Scanner scan = new Scanner(System.in); | defines a new scanner, named "scan" and inputs System.in | To read the input value from the user, we need to define a Scanner object. | 3 |
Scanner scan = new Scanner(System.in); | defines a new scanner, named "scan" and inputs System.in | We need to read and process the integer that the user enters. | 2 |
System.out.println("Enter an integer: "); | Asks user to enter an integer | We prompt the user to enter an integer. | 5 |
int num = scan.nextInt(); | sets the user input as "num" | We read the input integer by calling the nextInt() method because this input is an integer. | 2 |
int num = scan.nextInt(); | sets the user input as "num" | We need to read the integer that the user enters and store it in a variable. | 4 |
scan.close(); | terminates the input | We close the scanner as we do not want to process any input from the user in the rest of the program. | 2 |
System.out.println("The integer is positivie."); | outputs "The integer is positive" if num is greater than o | This statement prints that the integer is positive. | 5 |
System.out.println("The integer is positivie."); | outputs "The integer is positive" if num is greater than o | The printed text is followed by the end-of-line character at the end. | 1 |
} else if ( num < 0 ) { | if num is not greater than 0, condition num less than zero is next | If the first test fails (i.e., when the integer is not positive), we need to test if the integer is negative. | 4 |
if ( num > 0 ) { | begins an if-else condition, with num being larger than 0 as the first option | If the integer is neither positive nor negative, then we could conclude that the integer is zero. | 2 |
if ( num > 0 ) { | begins an if-else condition, with num being larger than 0 as the first option | The conditions that tests for the integer's sign are mutually exclusive (i.e., one and only one of the conditions can be true); therefore, their order does not matter. | 2 |
if ( num > 0 ) { | begins an if-else condition, with num being larger than 0 as the first option | To determine the sign of the integer, we need to perform two tests: one for determining whether the integer is positive and one for determining whether the integer is negative. | 3 |
if ( num > 0 ) { | begins an if-else condition, with num being larger than 0 as the first option | Also, it is better to use if-else if statements instead of sequential if statements because an integer has only one sign and once we find the sign, we don't need to perform more tests. | 2 |
if ( num > 0 ) { | begins an if-else condition, with num being larger than 0 as the first option | If both of these tests fail, then we could conclude that the integer is zero. | 1 |
System.out.println("The integer is negative."); | if num is less than zero, output "The integer is negative" | The printed text is followed by the end-of-line character at the end. | 1 |
System.out.println("The integer is negative."); | if num is less than zero, output "The integer is negative" | This statement prints that the integer is negative. | 4 |
} else { | if the num hasn't met the first two conditions, proceed | We need to end the above if-else if statements with an else statement that its body is executed when none of the above tests are true, that is when the integer is zero. | 4 |
System.out.println("The integer is zero."); | output "The integer is zero," | The printed text is followed by the end-of-line character at the end. | 1 |
System.out.println("The integer is zero."); | output "The integer is zero," | This statement prints that the integer is zero. | 5 |
int [] arr = { 1, 2, 3}; | creates an int array with three integers defined | We initialize the array of type int to hold the specified numbers. | 4 |
int [] arr = { 1, 2, 3}; | creates an int array with three integers defined | We initialize the array by separating elements with a comma and enclosing the collection in braces { }. | 3 |
for ( int i = 0; i < arr.length; i++ ) { | runs i from i equal to 0 the next line, adding 1 to i each time until i reaches the array length | We want to iterate over the array and increment each element in the array by 1. | 3 |
for ( int i = 0; i < arr.length; i++ ) { | runs i from i equal to 0 the next line, adding 1 to i each time until i reaches the array length | To really change the array as we march across it, we need to use indexes so we can assign an updated value to each position as we go. | 2 |
for ( int i = 0; i < arr.length; i++ ) { | runs i from i equal to 0 the next line, adding 1 to i each time until i reaches the array length | We need the array indexes to start at 0 (array indexes start from 0) with every integer number up to but not including the array length. | 5 |
arr[i] += 1; | adds 1 to array position each iteration | This statement increments the element at the index i of the array by 1. | 4 |
int num = 1234; | the number that will be printed | We need variable num to store the integer that we want to print its digits. | 3 |
do { | loop start | We need to process the digits of the integer from right to left and print them. | 1 |
do { | loop start | Therefore, we need to use a loop structure. | 3 |
do { | loop start | In this program, we do this by using a do loop. | 2 |
do { | loop start | The do loop is more appropriate than a while loop because a positive integer always has at least one digit which results in the body of the loop performing at least once. | 2 |
System.out.println(num % 10); | number output | Each printed digit is followed by the line separator (e.g. '\n') at the end. | 2 |
System.out.println(num % 10); | number output | We need to extract the last digit in the 1's position of the integer. | 1 |
System.out.println(num % 10); | number output | For example, if the integer is 1234, we want to extract the digit 4 that is in 1's position of the integer. | 1 |
System.out.println(num % 10); | number output | We do this by calculating the remainder of the division of the integer by 10. | 1 |
System.out.println(num % 10); | number output | Then, this statement prints the last digit of the integer to the standard output stream. | 3 |
num = num / 10; | go to the next number | Therefore, this division will remove the digit that we processed (lastDigit) and we can move on to the next digit. | 3 |
num = num / 10; | go to the next number | We truncate the extracted digit that we processed from the original integer by dividing the integer by 10. | 1 |
num = num / 10; | go to the next number | Note that this statement performs an integer division because both operand of the / operator are integer. | 1 |
} while (num > 0); | loop condition | We need to check for termination conditions to avoid infinite loops. | 3 |
} while (num > 0); | loop condition | The loop should terminate when we run out of digits to process. | 2 |
} while (num > 0); | loop condition | We could check whether the are more digits left by checking whether the variable num, which gets updated in the body of the do loop, is greater than zero. | 2 |
} while (num > 0); | loop condition | If variable num is greater than zero, then it must have at least one digit, and in that case, the body of the do loop will be repeated again. | 2 |
} while (num > 0); | loop condition | The body of the while loop should repeat as long as there are more digits left that we have not processed yet. | 1 |
int num = 1234; | sets "num" to the integer 1234 | We need variable num to store the integer that we want to print its digits. | 2 |
do { | initiates a do/while task | We need to process the digits of the integer from right to left and print them. | 1 |
do { | initiates a do/while task | Therefore, we need to use a loop structure. | 2 |
do { | initiates a do/while task | In this program, we do this by using a do loop. | 3 |
do { | initiates a do/while task | The do loop is more appropriate than a while loop because a positive integer always has at least one digit which results in the body of the loop performing at least once. | 2 |
System.out.println(num % 10); | print the remainder of num divided by 10 | Each printed digit is followed by the line separator (e.g. '\n') at the end. | 1 |
System.out.println(num % 10); | print the remainder of num divided by 10 | We need to extract the last digit in the 1's position of the integer. | 3 |
System.out.println(num % 10); | print the remainder of num divided by 10 | For example, if the integer is 1234, we want to extract the digit 4 that is in 1's position of the integer. | 1 |
System.out.println(num % 10); | print the remainder of num divided by 10 | We do this by calculating the remainder of the division of the integer by 10. | 4 |
System.out.println(num % 10); | print the remainder of num divided by 10 | Then, this statement prints the last digit of the integer to the standard output stream. | 3 |
System.out.println(num % 10); | print the remainder of num divided by 10 | Each printed digit is followed by the line separator (e.g. '\n') at the end. | 1 |
System.out.println(num % 10); | print the remainder of num divided by 10 | We need to extract the last digit in the 1's position of the integer. | 3 |
System.out.println(num % 10); | print the remainder of num divided by 10 | For example, if the integer is 1234, we want to extract the digit 4 that is in 1's position of the integer. | 2 |
System.out.println(num % 10); | print the remainder of num divided by 10 | We do this by calculating the remainder of the division of the integer by 10. | 4 |
System.out.println(num % 10); | print the remainder of num divided by 10 | Then, this statement prints the last digit of the integer to the standard output stream. | 3 |
num = num / 10; | reset num to num divided by 10 | Therefore, this division will remove the digit that we processed (lastDigit) and we can move on to the next digit. | 3 |
num = num / 10; | reset num to num divided by 10 | We truncate the extracted digit that we processed from the original integer by dividing the integer by 10. | 3 |
num = num / 10; | reset num to num divided by 10 | Note that this statement performs an integer division because both operand of the / operator are integer. | 2 |
} while (num > 0); | continue do-task while num is greater than zero | We need to check for termination conditions to avoid infinite loops. | 2 |
} while (num > 0); | continue do-task while num is greater than zero | The loop should terminate when we run out of digits to process. | 3 |
} while (num > 0); | continue do-task while num is greater than zero | We could check whether the are more digits left by checking whether the variable num, which gets updated in the body of the do loop, is greater than zero. | 4 |
} while (num > 0); | continue do-task while num is greater than zero | If variable num is greater than zero, then it must have at least one digit, and in that case, the body of the do loop will be repeated again. | 4 |
} while (num > 0); | continue do-task while num is greater than zero | The body of the while loop should repeat as long as there are more digits left that we have not processed yet. | 3 |
Scanner scan = new Scanner(System.in); | define a new Scanner named "scan" using sytem input | To read the input values from the user, we need to define a Scanner object. | 3 |
Scanner scan = new Scanner(System.in); | define a new Scanner named "scan" using sytem input | We need to read and process the values that the user enters. | 2 |
Subsets and Splits