Code Line
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User Explanation
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Line-Explanation in PCEX
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Annotation Score
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for (int num = 2; num <= 10; num += 2) {
Since num must be <= 10 to execute what code is in the body of the function, the code in the body will execute for num = 10 as well.
To do this, we initialize variable num to 2, loop until reaching 10 (inclusive), and increment num by 2 after each iteration of the loop.
2
for (int num = 2; num <= 10; num += 2) {
Since num must be <= 10 to execute what code is in the body of the function, the code in the body will execute for num = 10 as well.
We use for loops instead of a while loop because we need to repeat the loop a certain number of times, and for loops are best-suited in cases like this when we know ahead of time the number of times that we need to repeat the loop.
1
for (int num = 2; num <= 10; num += 2) {
Since num must be <= 10 to execute what code is in the body of the function, the code in the body will execute for num = 10 as well.
Here, we want the for loop to start counting from 2 (2 is the first positive even number) with every even integer number up to (including) 10.
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int minutes = seconds / 60;
Create the variable minutes
To obtain the minutes in seconds, we divide the seconds by 60 because there are 60 seconds in a minute.
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int minutes = seconds / 60;
Create the variable minutes
Note that since both operands of division operator are integer, the fractional part of the result is truncated, if there is any.
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int remainingSeconds = seconds % 60;
Stores the missing seconds
This is because there are 60 seconds in a minute.
1
int remainingSeconds = seconds % 60;
Stores the missing seconds
Note that the % operator returns the remainder of the division.
1
int remainingSeconds = seconds % 60;
Stores the missing seconds
To obtain the remaining seconds after taking away the minutes, we have to take the remainder of the seconds divided by 60.
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System.out.println(seconds + " seconds is " + minutes + " minutes and " + remainingSeconds + " seconds.");
Output
This statement prints to the default standard output stream the minutes and remaining seconds from the input amount of time in seconds.
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System.out.println(seconds + " seconds is " + minutes + " minutes and " + remainingSeconds + " seconds.");
Output
The printed text is followed by the end-of-line character at the end.
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int num = 15;
Creates the variable num
We define variable num to store the number that we want to find its smallest divisor.
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int num = 15;
Creates the variable num
We could initialize it to any positive integer greater than 1.
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int num = 15;
Creates the variable num
In this program, we initialize variable num to 15.
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System.out.println(num + " squared = " + (num * num));
This code will print what the current num is and its squared value.
The multiplication may also be performed directly in the println statement.
1
System.out.println(num + " squared = " + (num * num));
This code will print what the current num is and its squared value.
Note that we do not necessarily have to store the squared number in a variable.
1
System.out.println(num + " squared = " + (num * num));
This code will print what the current num is and its squared value.
To square each number in the sequence, we multiply it by itself using the multiplication (*) operator.
2
System.out.println(num + " squared = " + (num * num));
This code will print what the current num is and its squared value.
In each iteration of the loop, this statement prints the square number to the default standard output stream.
3
System.out.println(num + " squared = " + (num * num));
For instance, if num is 4 it will print "4 squared = 16".
The multiplication may also be performed directly in the println statement.
1
System.out.println(num + " squared = " + (num * num));
For instance, if num is 4 it will print "4 squared = 16".
Note that we do not necessarily have to store the squared number in a variable.
1
System.out.println(num + " squared = " + (num * num));
For instance, if num is 4 it will print "4 squared = 16".
To square each number in the sequence, we multiply it by itself using the multiplication (*) operator.
1
System.out.println(num + " squared = " + (num * num));
For instance, if num is 4 it will print "4 squared = 16".
In each iteration of the loop, this statement prints the square number to the default standard output stream.
2
int divisor = 2;
Creates the variable divisor
We initialize variable divisor by 2 because we want to find the smallest divisor except 1.
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int divisor = 2;
Creates the variable divisor
We define variable divisor to store the smallest divisor of the number.
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while (num % divisor != 0) {
Loop start
Since we don't know ahead of time how many times the loop will be repeated, we need to use a while loop.
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while (num % divisor != 0) {
Loop start
We need to increment the divisor repeatedly as long as the divisor is not a factor of the number.
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while (num % divisor != 0) {
Loop start
Therefore, we need to use a loop structure.
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while (num % divisor != 0) {
Loop start
The condition in the while loop tests whether the body of the loop should be repeated, so it should test whether the divisor is not a factor of the number.
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while (num % divisor != 0) {
Loop start
We could check whether the divisor is not a factor of the number by computing the remainder of the division of the number by the divisor.
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divisor += 1;
Find the new divisor
When the divisor is not a factor of the number, we increment the variable divisor by 1.
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scan.close();
Closes the entrance
We close the scanner as we do not want to process any input from the user in the rest of the program.
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System.out.println("The smallest divisor of " + num + " is " + divisor);
Output
This statement prints to the default standard output stream the smallest divisor of the number.
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Point1 point = new Point1();
This line instantiates a brand new Point1 object.
This statement creates a Point1 object using the new keyword and empty parentheses.
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Point1 point = new Point1();
This line instantiates a brand new Point1 object.
The variable point holds a reference to a Point1 object.
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Scanner scan = new Scanner(System.in);
Set input start
To read the input value from the user, we need to define a Scanner object.
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Scanner scan = new Scanner(System.in);
Set input start
We need to read and process the integer that the user enters.
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System.out.println("Enter an integer: ");
Prints the phrase "Enter an integer:"
We prompt the user to enter an integer.
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int num = scan.nextInt();
Creates the variable "num"
We read the input integer by calling the nextInt() method because this input is an integer.
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int num = scan.nextInt();
Creates the variable "num"
We need to read the integer that the user enters and store it in a variable.
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point.setX(7);
This sets the x variable defined by the Point1 object to 7.
This statement invokes the method setX of the point to set its x-coordinate to 7.
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scan.close();
Close input
We close the scanner as we do not want to process any input from the user in the rest of the program.
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if ( num > 0 ) {
Finds "num" greater than zero
If the integer is neither positive nor negative, then we could conclude that the integer is zero.
1
if ( num > 0 ) {
Finds "num" greater than zero
The conditions that tests for the integer's sign are mutually exclusive (i.e., one and only one of the conditions can be true); therefore, their order does not matter.
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if ( num > 0 ) {
Finds "num" greater than zero
To determine the sign of the integer, we need to perform two tests: one for determining whether the integer is positive and one for determining whether the integer is negative.
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if ( num > 0 ) {
Finds "num" greater than zero
Also, it is better to use if-else if statements instead of sequential if statements because an integer has only one sign and once we find the sign, we don't need to perform more tests.
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if ( num > 0 ) {
Finds "num" greater than zero
If both of these tests fail, then we could conclude that the integer is zero.
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System.out.println("The integer is positivie.");
Prints if the number is positive
This statement prints that the integer is positive.
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System.out.println("The integer is positivie.");
Prints if the number is positive
The printed text is followed by the end-of-line character at the end.
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} else if ( num < 0 ) {
Finds "num" less than zero
If the first test fails (i.e., when the integer is not positive), we need to test if the integer is negative.
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point.translate(11, 6);
This increments the x variable from the Point1 object by 11 and also increments the y variable by 6.
This statement invokes the method translate of the point.
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point.translate(11, 6);
This increments the x variable from the Point1 object by 11 and also increments the y variable by 6.
The second parameter specifies how much we want to shift the y-coordinate of the point.
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point.translate(11, 6);
This increments the x variable from the Point1 object by 11 and also increments the y variable by 6.
The translate method receives two parameters.
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point.translate(11, 6);
This increments the x variable from the Point1 object by 11 and also increments the y variable by 6.
The first parameter specifies how much we want to shift the x-coordinate of the point.
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System.out.println("The integer is negative.");
Output if the number is negative
The printed text is followed by the end-of-line character at the end.
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System.out.println("The integer is negative.");
Output if the number is negative
This statement prints that the integer is negative.
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Scanner scan = new Scanner(System.in);
introduce a new input scanner named "scan"
To read the input value from the user, we need to define a Scanner object.
4
Scanner scan = new Scanner(System.in);
introduce a new input scanner named "scan"
We need to read and process the value that the user enters.
2
} else {
If it is not negative or positive
We need to end the above if-else if statements with an else statement that its body is executed when none of the above tests are true, that is when the integer is zero.
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System.out.println("The integer is zero.");
Prints that the number is equal to 0
The printed text is followed by the end-of-line character at the end.
1
System.out.println("The integer is zero.");
Prints that the number is equal to 0
This statement prints that the integer is zero.
5
System.out.println("Enter an integer for seconds: ");
Ask the user to input an integer for seconds
We prompt the user to enter the seconds.
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int [] arr = { 1, 2, 3};
Creates the variable "arr"
We initialize the array of type int to hold the specified numbers.
1
int [] arr = { 1, 2, 3};
Creates the variable "arr"
We initialize the array by separating elements with a comma and enclosing the collection in braces { }.
1
System.out.println("The point's coordinates: (" + point.getX() + ", " + point.getY() + ")") ;
This prints out the current point1 object's x and y variables by using .getX and .getY functions that return the data stored in those variables.
Note that we do not necessarily have to store the returned value from each of these methods in a variable.
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System.out.println("The point's coordinates: (" + point.getX() + ", " + point.getY() + ")") ;
This prints out the current point1 object's x and y variables by using .getX and .getY functions that return the data stored in those variables.
We could use the returned value of them directly in the println statement.
2
System.out.println("The point's coordinates: (" + point.getX() + ", " + point.getY() + ")") ;
This prints out the current point1 object's x and y variables by using .getX and .getY functions that return the data stored in those variables.
This statement prints the coordinates of the point to the default standard output stream.
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System.out.println("The point's coordinates: (" + point.getX() + ", " + point.getY() + ")") ;
This prints out the current point1 object's x and y variables by using .getX and .getY functions that return the data stored in those variables.
The printed text is followed by the end-of-line character at the end.
2
System.out.println("The point's coordinates: (" + point.getX() + ", " + point.getY() + ")") ;
This prints out the current point1 object's x and y variables by using .getX and .getY functions that return the data stored in those variables.
To get the point's coordinates, we invoke the method getX and getY of the point.
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System.out.println("The point's coordinates: (" + point.getX() + ", " + point.getY() + ")") ;
This prints out the current point1 object's x and y variables by using .getX and .getY functions that return the data stored in those variables.
Note that we do not necessarily have to store the returned value from each of these methods in a variable.
1
System.out.println("The point's coordinates: (" + point.getX() + ", " + point.getY() + ")") ;
This prints out the current point1 object's x and y variables by using .getX and .getY functions that return the data stored in those variables.
We could use the returned value of them directly in the println statement.
2
System.out.println("The point's coordinates: (" + point.getX() + ", " + point.getY() + ")") ;
This prints out the current point1 object's x and y variables by using .getX and .getY functions that return the data stored in those variables.
This statement prints the coordinates of the point to the default standard output stream.
4
System.out.println("The point's coordinates: (" + point.getX() + ", " + point.getY() + ")") ;
This prints out the current point1 object's x and y variables by using .getX and .getY functions that return the data stored in those variables.
The printed text is followed by the end-of-line character at the end.
2
System.out.println("The point's coordinates: (" + point.getX() + ", " + point.getY() + ")") ;
This prints out the current point1 object's x and y variables by using .getX and .getY functions that return the data stored in those variables.
To get the point's coordinates, we invoke the method getX and getY of the point.
4
int seconds = scan.nextInt();
set user input to int named "seconds"
We need to read the seconds that the user enters and store it in a variable.
4
int seconds = scan.nextInt();
set user input to int named "seconds"
We read the seconds by calling the nextInt() method because this input is an integer.
2
arr[i] += 1;
New value of "arr"
This statement increments the element at the index i of the array by 1.
1
for ( int i = 0; i < arr.length; i++ ) {
Loop start
We want to iterate over the array and increment each element in the array by 1.
2
for ( int i = 0; i < arr.length; i++ ) {
Loop start
To really change the array as we march across it, we need to use indexes so we can assign an updated value to each position as we go.
1
for ( int i = 0; i < arr.length; i++ ) {
Loop start
We need the array indexes to start at 0 (array indexes start from 0) with every integer number up to but not including the array length.
1
scan.close();
stop the scan input function
We close the scanner as we do not want to process any input from the user in the rest of the program.
2
int minutes = seconds / 60;
define integer "minutes" as "seconds" divided by 60
To obtain the minutes in seconds, we divide the seconds by 60 because there are 60 seconds in a minute.
4
int minutes = seconds / 60;
define integer "minutes" as "seconds" divided by 60
Note that since both operands of division operator are integer, the fractional part of the result is truncated, if there is any.
1
for (int num = 2; num <= 10; num += 2) {
Num will be set to two and incremented by 2 (guaranteeing even values) after the for loop executes the body in the code each time, until num reaches 10.
To do this, we need to use a loop structure.
2
for (int num = 2; num <= 10; num += 2) {
Num will be set to two and incremented by 2 (guaranteeing even values) after the for loop executes the body in the code each time, until num reaches 10.
We need to repeat the same process for each of the even positive integers that are less than or equal to 10.
4
for (int num = 2; num <= 10; num += 2) {
Num will be set to two and incremented by 2 (guaranteeing even values) after the for loop executes the body in the code each time, until num reaches 10.
To do this, we initialize variable num to 2, loop until reaching 10 (inclusive), and increment num by 2 after each iteration of the loop.
4
for (int num = 2; num <= 10; num += 2) {
Num will be set to two and incremented by 2 (guaranteeing even values) after the for loop executes the body in the code each time, until num reaches 10.
We use for loops instead of a while loop because we need to repeat the loop a certain number of times, and for loops are best-suited in cases like this when we know ahead of time the number of times that we need to repeat the loop.
2
for (int num = 2; num <= 10; num += 2) {
Num will be set to two and incremented by 2 (guaranteeing even values) after the for loop executes the body in the code each time, until num reaches 10.
Here, we want the for loop to start counting from 2 (2 is the first positive even number) with every even integer number up to (including) 10.
3
int remainingSeconds = seconds % 60;
define the remainder of seconds/60 as "remainingSeconds" integer
This is because there are 60 seconds in a minute.
1
int remainingSeconds = seconds % 60;
define the remainder of seconds/60 as "remainingSeconds" integer
Note that the % operator returns the remainder of the division.
2
int remainingSeconds = seconds % 60;
define the remainder of seconds/60 as "remainingSeconds" integer
To obtain the remaining seconds after taking away the minutes, we have to take the remainder of the seconds divided by 60.
3
System.out.println(num + " squared = " + (num * num));
This line prints the current value of num and its squared value, for instance if num = 4, it will print "4.squared = 16"
The multiplication may also be performed directly in the println statement.
1
System.out.println(num + " squared = " + (num * num));
This line prints the current value of num and its squared value, for instance if num = 4, it will print "4.squared = 16"
Note that we do not necessarily have to store the squared number in a variable.
1
System.out.println(num + " squared = " + (num * num));
This line prints the current value of num and its squared value, for instance if num = 4, it will print "4.squared = 16"
To square each number in the sequence, we multiply it by itself using the multiplication (*) operator.
3
System.out.println(num + " squared = " + (num * num));
This line prints the current value of num and its squared value, for instance if num = 4, it will print "4.squared = 16"
In each iteration of the loop, this statement prints the square number to the default standard output stream.
4
System.out.println(num + " squared = " + (num * num));
This line prints the current value of num and its squared value, for instance if num = 4, it will print "4.squared = 16"
The multiplication may also be performed directly in the println statement.
1
System.out.println(num + " squared = " + (num * num));
This line prints the current value of num and its squared value, for instance if num = 4, it will print "4.squared = 16"
Note that we do not necessarily have to store the squared number in a variable.
1
System.out.println(num + " squared = " + (num * num));
This line prints the current value of num and its squared value, for instance if num = 4, it will print "4.squared = 16"
To square each number in the sequence, we multiply it by itself using the multiplication (*) operator.
3
System.out.println(num + " squared = " + (num * num));
This line prints the current value of num and its squared value, for instance if num = 4, it will print "4.squared = 16"
In each iteration of the loop, this statement prints the square number to the default standard output stream.
3
System.out.println(seconds + " seconds is " + minutes + " minutes and " + remainingSeconds + " seconds.");
output the integers to the user
This statement prints to the default standard output stream the minutes and remaining seconds from the input amount of time in seconds.
3
System.out.println(seconds + " seconds is " + minutes + " minutes and " + remainingSeconds + " seconds.");
output the integers to the user
The printed text is followed by the end-of-line character at the end.
1
Point1 point = new Point1();
This line instantiates a new Point1 object named point.
This statement creates a Point1 object using the new keyword and empty parentheses.
4