Datasets:
xap
/
SelfCode

Dataset card Data Studio Files Community
1
Code Line
stringclasses
57 values
User Explanation
stringclasses
692 values
Line-Explanation in PCEX
stringclasses
131 values
Annotation Score
float64
1
5
⌀
if (values[i] > maxValue) {
Creating if condition which is fulfilled if the values[i] is greated than the maxValue variable.
If the value at that index is larger than the maximum value, then we need to set the maximum value to the value of the element at index i.
2
maxValue = values[i];
If the if condition is fulfilled, the value of maxValue will be replaced by the value in values[i].
This statement sets the maximum value to value of the element at index i of the array.
3
System.out.println("Maximum value: " + maxValue);
Statement to print the maximum value in the array values.
This statement prints the maximum value of the array to the default standard output stream.
4
Scanner scan = new Scanner(System.in);
Instance of object Scanner
To read the input value from the user, we need to define a Scanner object.
2
Scanner scan = new Scanner(System.in);
Instance of object Scanner
We need to read and process the value that the user enters.
1
System.out.println("Enter an integer for seconds: ");
Print message on console
We prompt the user to enter the seconds.
2
int seconds = scan.nextInt();
Get input from command line as integer
We need to read the seconds that the user enters and store it in a variable.
2
int seconds = scan.nextInt();
Get input from command line as integer
We read the seconds by calling the nextInt() method because this input is an integer.
2
scan.close();
Close scanner instance
We close the scanner as we do not want to process any input from the user in the rest of the program.
3
int minutes = seconds / 60;
calculate minutes by dividing by 60
To obtain the minutes in seconds, we divide the seconds by 60 because there are 60 seconds in a minute.
3
int minutes = seconds / 60;
calculate minutes by dividing by 60
Note that since both operands of division operator are integer, the fractional part of the result is truncated, if there is any.
1
int remainingSeconds = seconds % 60;
calculate the seconds, making the modulus of the integer, to obtain the rest
This is because there are 60 seconds in a minute.
2
int remainingSeconds = seconds % 60;
calculate the seconds, making the modulus of the integer, to obtain the rest
Note that the % operator returns the remainder of the division.
2
int remainingSeconds = seconds % 60;
calculate the seconds, making the modulus of the integer, to obtain the rest
To obtain the remaining seconds after taking away the minutes, we have to take the remainder of the seconds divided by 60.
3
System.out.println("Enter an integer for seconds: ");
Print message by console so that the user inserts an integer number
We prompt the user to enter the seconds.
4
System.out.println(seconds + " seconds is " + minutes + " minutes and " + remainingSeconds + " seconds.");
Print message by console with the result separated by minutes and seconds
This statement prints to the default standard output stream the minutes and remaining seconds from the input amount of time in seconds.
4
System.out.println(seconds + " seconds is " + minutes + " minutes and " + remainingSeconds + " seconds.");
Print message by console with the result separated by minutes and seconds
The printed text is followed by the end-of-line character at the end.
1
int num = 15;
Integer variable declaration num
We define variable num to store the number that we want to find its smallest divisor.
2
int num = 15;
Integer variable declaration num
We could initialize it to any positive integer greater than 1.
2
int num = 15;
Integer variable declaration num
In this program, we initialize variable num to 15.
2
int divisor = 2;
Integer variable declaration divisor
We initialize variable divisor by 2 because we want to find the smallest divisor except 1.
2
int divisor = 2;
Integer variable declaration divisor
We define variable divisor to store the smallest divisor of the number.
2
divisor += 1;
Fulfills the condition and we increase the divisor variable
When the divisor is not a factor of the number, we increment the variable divisor by 1.
3
while (num % divisor != 0) {
Loop condition, modulus between num and divisor
Since we don't know ahead of time how many times the loop will be repeated, we need to use a while loop.
2
while (num % divisor != 0) {
Loop condition, modulus between num and divisor
We need to increment the divisor repeatedly as long as the divisor is not a factor of the number.
3
while (num % divisor != 0) {
Loop condition, modulus between num and divisor
Therefore, we need to use a loop structure.
1
while (num % divisor != 0) {
Loop condition, modulus between num and divisor
The condition in the while loop tests whether the body of the loop should be repeated, so it should test whether the divisor is not a factor of the number.
1
while (num % divisor != 0) {
Loop condition, modulus between num and divisor
We could check whether the divisor is not a factor of the number by computing the remainder of the division of the number by the divisor.
2
System.out.println("The smallest divisor of " + num + " is " + divisor);
Print message by console with the result of the smallest divisor of the variable num
This statement prints to the default standard output stream the smallest divisor of the number.
4
String fullName = "John Smith"
assign the value of John Smith to the string called fullName
We define a string variable to hold the name.
2
String firstInitial = fullName.substring(0, 1);
Get the characters from position 0 to 1 of fullName and assign them to the firstInitial string
We need to extract the first letter from the first name.
4
String firstInitial = fullName.substring(0, 1);
Get the characters from position 0 to 1 of fullName and assign them to the firstInitial string
We do this by calling the substring(0,1) method.
3
String lastInitial = fullName.substring(5, 6);
Get the characters from position 5 to 6 of fullName and assign them to the lastInitial string
We need to extract the first letter from the last name.
2
String lastInitial = fullName.substring(5, 6);
Get the characters from position 5 to 6 of fullName and assign them to the lastInitial string
We do this by calling the substring(5,6) method.
3
String initials = firstInitial + lastInitial;
Combine the first initial and the last initial and assign it to the initials string
This statements concatenates the extracted initials and store the result in the string initials.
4
System.out.println(initials);
output the initials string
This statement prints the initials to the default standard output stream.
3
System.out.println(initials);
output the initials string
The printed value is followed by the end-of-line character at the end.
1
int[] values = {5, 8, 4, 78, 95, 12, 1, 0, 6, 35, 46};
create an array with the values in the brackets
We define array values to hold the specified numbers.
3
int[] values = {5, 8, 4, 78, 95, 12, 1, 0, 6, 35, 46};
create an array with the values in the brackets
We initialize the array by separating elements with a comma and enclosing the collection in braces { }.
4
int maxValue = values[0];
set the maxValue to the value at position 0 in the value array.
We need variable maxValue to store the maximum value of the array.
3
int maxValue = values[0];
set the maxValue to the value at position 0 in the value array.
We initialize this variable by the first value in the array because we initially assume that the first value is the maximum.
3
for (int i = 1; i < values.length; i++) {
Loop through the array, from position 1 to the length of the array, incrementing by 1 position each time
We use a for loop to iterate over the remaining array indexes and search for the maximum value.
3
for (int i = 1; i < values.length; i++) {
Loop through the array, from position 1 to the length of the array, incrementing by 1 position each time
We need the array indexes to start at 1 with every integer number up to but not including the array length.
3
if (values[i] > maxValue) {
check if the value at position i is greater than the maxValue
We need to compare the value at the index i of the array with the maximum value stored in variable maxValue.
3
if (values[i] > maxValue) {
check if the value at position i is greater than the maxValue
If the value at that index is larger than the maximum value, then we need to set the maximum value to the value of the element at index i.
3
maxValue = values[i];
if the value is greater than the maxValue, assign that value to the maxValue
This statement sets the maximum value to value of the element at index i of the array.
3
System.out.println("Maximum value: " + maxValue);
output the maxValue variable.
This statement prints the maximum value of the array to the default standard output stream.
3
int num = 1234;
to store integer type data. int helps in storing integer value into memory.
We need variable num to store the integer that we want to print its digits.
2
Scanner scan = new Scanner(System.in);
for obtaining the input of the int
To read the input values from the user, we need to define a Scanner object.
1
Scanner scan = new Scanner(System.in);
for obtaining the input of the int
We need to read and process the values that the user enters.
1
System.out.println("Enter the phone age in years:");
to print the sentence enclosed in the brackets display in the output screen
We prompt the user to enter the phone age in years.
1
int phoneAge = scan.nextInt();
to get the integer value and to store the int value in the integer memory
We read the phone age by calling the nextInt() method because this input is an integer.
2
int phoneAge = scan.nextInt();
to get the integer value and to store the int value in the integer memory
We need to read the phone age that the user enters and store it in a variable.
1
System.out.println("Enter whether the phone is broken (true or false):");
to print the the sentence enclosed in the quotation display on the output screen
We prompt the user to enter whether the phone is broken.
1
boolean isBroken = scan.nextBoolean();
to boolean get the value 0 or 1 and store the value in the boolean memory
We need to read whether the phone is broken and store it in a variable.
1
boolean isBroken = scan.nextBoolean();
to boolean get the value 0 or 1 and store the value in the boolean memory
The variable isBroken is true when the phone is broken, and false otherwise.
1
boolean isBroken = scan.nextBoolean();
to boolean get the value 0 or 1 and store the value in the boolean memory
We read whether the phone is broken by calling the nextBoolean() method because this input is a boolean.
2
scan.close();
to close the scanner
We close the scanner as we do not want to process any input from the user in the rest of the program.
2
boolean needPhone = isBroken || phoneAge >= 3;
to test the boolean value is true or not and store that in the needPhone memory
We use the || operator (called or) to combine the two conditions.
1
boolean needPhone = isBroken || phoneAge >= 3;
to test the boolean value is true or not and store that in the needPhone memory
The first condition is to test if the phone is broken and the second condition is to test if the phone age is at least 3 years old.
2
boolean needPhone = isBroken || phoneAge >= 3;
to test the boolean value is true or not and store that in the needPhone memory
We need two conditions to determine if it is the time for a new phone.
2
System.out.println(needPhone);
print the needPhone value in the output screen
This statement prints true/false depending on whether it is time to buy a new phone.
2
System.out.println(needPhone);
print the needPhone value in the output screen
The printed value is followed by an end-of-line character in the end.
1
int num = 1234;
to store integer type data.
We need variable num to store the integer that we want to print its digits.
2
int num = 1234;
int helps in storing integer value into memory.
We need variable num to store the integer that we want to print its digits.
2
do {
its a loop used to process the values
We need to process the digits of the integer from right to left and print them.
2
do {
its a loop used to process the values
Therefore, we need to use a loop structure.
2
do {
its a loop used to process the values
In this program, we do this by using a do loop.
1
do {
its a loop used to process the values
The do loop is more appropriate than a while loop because a positive integer always has at least one digit which results in the body of the loop performing at least once.
1
num = num / 10;
formula to obtain the value of num
Therefore, this division will remove the digit that we processed (lastDigit) and we can move on to the next digit.
1
num = num / 10;
formula to obtain the value of num
We truncate the extracted digit that we processed from the original integer by dividing the integer by 10.
1
num = num / 10;
formula to obtain the value of num
Note that this statement performs an integer division because both operand of the / operator are integer.
1
} while (num > 0);
end of the loop enclosed with condition
We need to check for termination conditions to avoid infinite loops.
3
} while (num > 0);
end of the loop enclosed with condition
The loop should terminate when we run out of digits to process.
2
} while (num > 0);
end of the loop enclosed with condition
We could check whether the are more digits left by checking whether the variable num, which gets updated in the body of the do loop, is greater than zero.
1
} while (num > 0);
end of the loop enclosed with condition
If variable num is greater than zero, then it must have at least one digit, and in that case, the body of the do loop will be repeated again.
1
} while (num > 0);
end of the loop enclosed with condition
The body of the while loop should repeat as long as there are more digits left that we have not processed yet.
1
System.out.println(num % 10);
print the num % 10 value in the output screen
Each printed digit is followed by the line separator (e.g. '\n') at the end.
1
System.out.println(num % 10);
print the num % 10 value in the output screen
We need to extract the last digit in the 1's position of the integer.
1
System.out.println(num % 10);
print the num % 10 value in the output screen
For example, if the integer is 1234, we want to extract the digit 4 that is in 1's position of the integer.
1
System.out.println(num % 10);
print the num % 10 value in the output screen
We do this by calculating the remainder of the division of the integer by 10.
4
System.out.println(num % 10);
print the num % 10 value in the output screen
Then, this statement prints the last digit of the integer to the standard output stream.
1
System.out.println("Enter whether the phone is broken (true or false):");
to print the sentence within the bracket opn oputput screen
We prompt the user to enter whether the phone is broken.
1
System.out.println("Enter whether the phone is broken (true or false):");
ti print
We prompt the user to enter whether the phone is broken.
1
String fullName = "John Smith"
to store the name John smith in the String memory
We define a string variable to hold the name.
3
String firstInitial = fullName.substring(0, 1);
getting the substring and store the data in firstInitial
We need to extract the first letter from the first name.
3
String firstInitial = fullName.substring(0, 1);
getting the substring and store the data in firstInitial
We do this by calling the substring(0,1) method.
2
String initials = firstInitial + lastInitial;
formula for join the firstInitial and lastInitial and store the answer in initials
This statements concatenates the extracted initials and store the result in the string initials.
4
String lastInitial = fullName.substring(5, 6);
getting the substring and store the data in lastInitial
We need to extract the first letter from the last name.
3
String lastInitial = fullName.substring(5, 6);
getting the substring and store the data in lastInitial
We do this by calling the substring(5,6) method.
2
System.out.println(initials);
print the initials in the output screen
This statement prints the initials to the default standard output stream.
4
System.out.println(initials);
print the initials in the output screen
The printed value is followed by the end-of-line character at the end.
1
int[] values = {5, 8, 4, 78, 95, 12, 1, 0, 6, 35, 46};
store the array of integer values in the name values
We define array values to hold the specified numbers.
4
int[] values = {5, 8, 4, 78, 95, 12, 1, 0, 6, 35, 46};
store the array of integer values in the name values
We initialize the array by separating elements with a comma and enclosing the collection in braces { }.
2
int maxValue = values[0];
initialize the array
We need variable maxValue to store the maximum value of the array.
1
int maxValue = values[0];
initialize the array
We initialize this variable by the first value in the array because we initially assume that the first value is the maximum.
1
for (int i = 1; i < values.length; i++) {
condition enclosed in the for loop to obtain the maxValue in the array
We use a for loop to iterate over the remaining array indexes and search for the maximum value.
3
for (int i = 1; i < values.length; i++) {
condition enclosed in the for loop to obtain the maxValue in the array
We need the array indexes to start at 1 with every integer number up to but not including the array length.
1
if (values[i] > maxValue) {
check the condition whether it is true or not by finding the maxValue
We need to compare the value at the index i of the array with the maximum value stored in variable maxValue.
2
if (values[i] > maxValue) {
check the condition whether it is true or not by finding the maxValue
If the value at that index is larger than the maximum value, then we need to set the maximum value to the value of the element at index i.
1